Math I · A-CED.1

Creating and Solving One-Variable Equations and Inequalities from Real Situations

Equations and inequalities let students turn messy real situations into decisions: how much, how many, how far, how safe, or when a limit has been crossed.

Concept Algebra
Domain Creating Equations
Read time 10 minutes

What this learning objective is really asking you to learn

This objective is about turning a messy real-life situation into a clean mathematical statement with one unknown quantity. That unknown might be the number of hours you can work, the number of miles you can travel, the number of points you need on the next test, the temperature range a machine can safely operate in, or the price at which a plan becomes affordable. The one unknown is usually represented by a variable such as \(x\), \(t\), \(m\), \(h\), or \(p\). The letter is not the point. The letter is a handle. It lets your mind hold a quantity that you do not know yet.

An equation says that two quantities are equal. It is the mathematics of an exact condition: the total cost is exactly $50; the distance is exactly 120 miles; the two plans cost the same; the volume reaches exactly 2 liters. An equation asks, “What value makes this statement true?”

An inequality says that one quantity is greater than, less than, at least, or at most another quantity. It is the mathematics of limits and acceptable ranges: spend no more than $50; drive at least 120 miles; keep the temperature below 75 degrees; earn more than 900 points; arrive before 8:00. An inequality asks, “What values are allowed?”

An absolute-value equation or inequality describes distance from a target. The expression \(|x - 70|\) means the distance between \(x\) and 70 on a number line. It does not care whether \(x\) is above or below 70; it cares how far away it is. That makes absolute value a natural language for tolerances, error, deviation, and “close enough” conditions. If a thermostat should keep a room within 3 degrees of 70, the model is \(|T - 70| \le 3\). If a manufactured part must be within 0.02 inches of the target size, the model is \(|s - target| \le 0.02\). If a student’s score differs from a goal by exactly 5 points, the model is \(|score - goal| = 5\).

So the objective is not merely “solve for x.” It is a full modeling skill. You are learning how to read a situation, choose the important quantity, define it clearly, build an equation or inequality that represents the situation, solve it, and interpret the answer back in the real world.

Why students should learn this math

This is one of the first places where math becomes a practical language for decision-making. Arithmetic answers questions when all numbers are known. Algebra answers questions when something is unknown but the relationships are known. Real life is full of that second kind of problem.

Suppose you have $42 and want to buy notebooks that cost $3.50 each. Arithmetic lets you calculate the cost of 5 notebooks or 8 notebooks. Algebra asks the more useful question: “How many can I buy?” The model is \(3.50n \le 42\), and the solution tells you the range of possible choices. That is a decision, not just a calculation.

Suppose a rideshare charges a $4 base fee plus $1.75 per mile, and you have $30. You could try random distances until you find one that works, but algebra gives the structure: \(4 + 1.75m \le 30\). The solution is \(m \le 14.857...\), so in real terms you can afford about 14.8 miles, maybe less depending on fees and rounding. That kind of thinking appears in budgeting, travel planning, shipping, event planning, construction, nutrition, fitness, energy use, and work scheduling.

The “why” matters because students often experience equations as artificial puzzles. But an equation is not naturally a puzzle. Historically and practically, an equation is a tool for answering questions about unknown quantities. If a farmer knows area and width and wants length, that is algebra. If a doctor calculates dosage from patient weight, that is algebra. If an engineer checks whether a bridge part is within tolerance, that is algebra. If a business estimates how many sales are needed to cover costs, that is algebra. If a programmer writes a condition like \(if temperature \le max_safe_temperature\), that is an inequality.

Absolute value is especially important because the real world is rarely about being perfect. It is about being within tolerance. Machines vibrate. Measurements have error. Digital images have pixel differences. Weather forecasts miss by a few degrees. A basketball shot is not judged by whether it is at one exact point in space; it is judged by whether it falls within a physical opening. A car lane assist system does not ask whether the car is exactly centered; it asks whether the car is too far from the center. Absolute value is the mathematics of “how far from the target?”

Learning this objective also builds a mental habit: do not ask only “What is the answer?” Ask “What does the answer mean?” If the solution of a ticket problem is \(x = 18.4\), and \(x\) means the number of people, then 18.4 people is not possible. The algebraic result has to be interpreted. Maybe 18 people fit the budget, or maybe you need 19 tickets and more money. The real world talks back to the math.

The historical machinery: why equations became central to mathematics

The story of algebra is largely the story of humans learning to manage unknowns. Ancient civilizations solved practical problems involving land, trade, inheritance, taxation, and measurement long before modern algebraic notation existed. They often wrote problems in words. Instead of writing \(x + 7 = 20\), a text might say something like, “A quantity and seven make twenty; find the quantity.” That is algebraic thinking without algebraic symbols.

A major historical step was the development of systematic equation solving. The word algebra comes from Arabic, especially from the phrase al-jabr, associated with the work of Muhammad ibn Musa al-Khwarizmi in the ninth century. His work organized methods for solving equations, especially linear and quadratic equations, in a way that treated equation solving as a general method rather than a collection of isolated tricks. In modern school language, “balancing” an equation is the descendant of a very old idea: restore, complete, and transform an equation while preserving its truth.

Another major step was notation. Diophantus, working in Alexandria many centuries earlier, used abbreviated symbolism for unknowns and powers of unknowns. Later, mathematicians such as François Viète and René Descartes helped push mathematics toward the symbolic language students now see every day. This mattered enormously. Symbols made algebra portable. A word problem about money, a geometry problem about length, and a physics problem about speed could all be represented by similar structures.

That is one reason students should not dismiss variables as “just letters.” The invention of symbolic algebra is one of the great compression technologies in human thought. It lets one method apply to thousands of situations. You do not need a separate method for every budget problem, every travel problem, every temperature problem, and every measurement problem. You learn the structure once, and then you adapt it.

Inequalities developed as mathematicians and scientists needed language not only for exact equality but also for bounds, estimates, and comparisons. In applied work, exact equality is often less common than constraints. A bridge must support at least a certain load. A medication must stay below a harmful dose. A project must stay under budget. A manufacturing part must not deviate too far from a target. Inequality language is how mathematics enters the world of safety, feasibility, and design.

Where this fits in the big map of mathematics

This objective sits near the entrance to high-school algebra, but it connects to nearly everything after it.

In arithmetic, you mostly calculate known quantities. In algebra, you describe relationships involving unknown quantities. In functions, you study how one quantity changes with another. In systems, you study multiple conditions at once. In statistics, you model patterns with variation and uncertainty. In calculus, you study change continuously. In optimization, you find the best choice under constraints. One-variable equations and inequalities are the first clean version of all of that.

A one-variable equation is like a single lock with one key. You are looking for the value that makes the relationship true. A one-variable inequality is like a gate: many values may pass through, but not all of them. An absolute-value inequality is like a zone around a target. You are not finding one point; you are finding a region of acceptable distance.

This matters because the larger map of math is not a pile of unrelated topics. Equations become graphs. Graphs become functions. Functions become models. Models become predictions and decisions. Inequalities become constraints. Constraints become feasible regions. Feasible regions become optimization. Absolute value becomes distance, error, residuals, and eventually more advanced ideas such as norms in linear algebra and analysis. The small symbol \(|x - a|\) is the beginning of a much bigger idea: measuring how far something is from something else.

How to execute the skill technically

The technical process has several parts. Skipping the first or last part is where many mistakes happen.

First, define the variable. Do not just write \(x\). Write what \(x\) means and include units. For example, “Let \(m\) be the number of miles traveled” or “Let \(h\) be the number of hours worked.” This is not a teacher’s formality. It is how you prevent yourself from solving for the wrong thing.

Second, identify the relationship. Look for words that describe operations: total, difference, per, each, more than, less than, at least, no more than, within, twice, half, remaining. “Per” often signals multiplication by a rate. “Total” often signals addition. “At most” means \(\le\). “At least” means \(\ge\). “Within” often signals absolute value.

Third, write the equation or inequality. This is the modeling step. For a rideshare with a $4 base fee and $1.75 per mile, the cost is \(4 + 1.75m\). If the budget is $30, the condition is \(4 + 1.75m \le 30\).

Fourth, solve using legal transformations. For an equation, you can add, subtract, multiply, or divide both sides by the same nonzero quantity. For an inequality, the same rules apply, except that multiplying or dividing by a negative number reverses the inequality sign. That rule is not arbitrary. On a number line, multiplying by a negative reflects values across zero, reversing their order. Since \(2 < 5\), multiplying by -1 gives \(-2 > -5\).

Fifth, interpret the result. If \(m \le 14.857\), say what that means in the situation. Do not stop at the symbol. “The trip can be at most about 14.86 miles before extra fees.” If the real-world system only allows whole numbers, round in the direction that keeps the condition true.

Sixth, check the answer. Substitute a boundary value and a nearby value if needed. For inequalities, test whether the boundary is included. If the original statement said “less than,” the boundary is not included. If it said “at most,” the boundary is included.

Absolute value has its own technical pattern. For \(|x - 70| = 3\), the quantity inside the absolute value can be 3 or -3. So \(x - 70 = 3\) or \(x - 70 = -3\), giving \(x = 73\) or \(x = 67\). For \(|x - 70| \le 3\), the value is within 3 units of 70, so \(67 \le x \le 73\). For \(|x - 70| \ge 3\), the value is at least 3 units away, so \(x \le 67\) or \(x \ge 73\). A helpful memory is: less-than absolute value creates an inside interval; greater-than absolute value creates outside rays. But do not rely only on memory. Think about distance.

A worked example: planning under a budget

A school club has $250 for a field trip. The bus reservation costs $85, and each student ticket costs $12. How many students can attend?

Let \(s\) be the number of students. The total cost is the fixed bus cost plus the ticket cost per student: \(85 + 12s\). The club can spend at most $250, so

\[85 + 12s \le 250\].

Subtract 85 from both sides:

\[12s \le 165\].

Divide by 12:

\[s \le 13.75\].

The algebra says any number up to 13.75 works, but students are counted in whole people. The club can bring at most 13 students. Rounding to 14 would break the budget because \(85 + 12(14) = 253\).

That final interpretation is the point. The solution is not “13.75.” The real answer is “13 students, unless the club raises more money or changes the cost structure.”

A worked example: absolute-value tolerance

A science incubator should stay within 1.5°C of 37°C. What temperature range is acceptable?

Let \(T\) be the incubator temperature in degrees Celsius. “Within 1.5 of 37” means the distance between \(T\) and 37 is no more than 1.5:

\[|T - 37| \le 1.5\].

This means

\[-1.5 \le T - 37 \le 1.5\].

Add 37 to all three parts:

\[35.5 \le T \le 38.5\].

The acceptable range is from 35.5°C to 38.5°C, inclusive. The absolute value symbol has translated a real-life tolerance into a precise interval.

Common mistakes and how to avoid them

One common mistake is choosing the wrong variable. If the problem asks for the number of months, do not let \(x\) mean total cost unless you have a reason. Another mistake is reversing “at most” and “at least.” “At most 20” means 20 or less: \(\le 20\). “At least 20” means 20 or more: \(\ge 20\).

Students also often forget to reverse the inequality sign when multiplying or dividing by a negative. Instead of memorizing fearfully, remember that negative multiplication reverses order. If you are unsure, test a simple number.

With absolute value, the most common mistake is dropping the two-sided nature of distance. \(|x - 5| = 2\) has two solutions, 7 and 3. Both are 2 units from 5. For inequalities, students sometimes write only one side. But \(|x - 5| \le 2\) means \(3 \le x \le 7\), not just \(x \le 7\).

The deepest mistake is solving correctly but interpreting badly. Algebra gives candidates. Context decides meaning. A negative time, a fractional person, or a ticket count of 13.75 may be algebraically produced but contextually impossible.

The big takeaway

This objective teaches you how to turn reality into a solvable structure. Equations answer exact target questions. Inequalities answer allowable-range questions. Absolute value answers distance-from-target questions. Together, they form one of the most useful toolkits in all of school mathematics. When students ask, “Why am I learning this?” the honest answer is: because much of adult life is deciding what is possible, affordable, safe, fair, close enough, or exactly required when one important quantity is unknown.

Problem Library

Problems in the App From This Objective

180 problems across 15 archetypes in the app.

identify unknown, write equation, solve, interpret.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Four notebooks cost 28 dollars total. Write and solve a one-variable equation to find the cost of one notebook.

Problem 2

A rope is cut into 5 equal pieces totaling 45 feet. Write and solve a one-variable equation to find the length of each piece.

Problem 3

Six identical tickets cost 72 dollars. Write and solve a one-variable equation to find the price of one ticket.

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Problem 4

A stack of 7 identical books has a total of 1400 pages. Write and solve a one-variable equation to find the number of pages in one book.

Problem 5

There are 8 bags, each containing the same number of apples, for a total of 96 apples. Write and solve a one-variable equation to find the number of apples in one bag.

Problem 6

A runner completed 4 laps of a track, covering a total distance of 1600 meters. Write and solve a one-variable equation to find the length of one lap.

Problem 7

12 boxes of pencils contain a total of 144 pencils. Write and solve a one-variable equation to find the number of pencils in each box.

Problem 8

5 jars hold an equal number of cookies, with 105 cookies in total. Write and solve a one-variable equation to find the number of cookies in one jar.

Problem 9

A worker earned 280 dollars for working 8 hours at a constant hourly rate. Write and solve a one-variable equation to find the hourly rate.

Problem 10

Sarah divided 63 pieces of candy equally among 9 friends. Write and solve a one-variable equation to find the number of pieces each friend received.

Problem 11

A tower is built with 15 identical blocks and measures 180 cm tall. Write and solve a one-variable equation to find the height of one block.

Problem 12

10 packs of gum cost 20 dollars total. Write and solve a one-variable equation to find the cost of one pack of gum.

build `ax + b = c`, solve, attach units.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

A bike rental costs 12 dollars plus 8 dollars per hour. The total is 44 dollars. Write and solve an equation of the form ax + b = c.

Problem 14

A club charges a 20 dollar sign-up fee plus 5 dollars per visit. The total paid is 65 dollars. Write and solve an equation of the form ax + b = c.

Problem 15

A delivery fee is 6 dollars plus 3 dollars per mile. The total is 30 dollars. Write and solve an equation of the form ax + b = c.

Problem 16

A taxi ride costs 5 dollars plus 2 dollars per mile. The total fare is 25 dollars. Write and solve an equation of the form ax + b = c.

Problem 17

A phone plan has a 30 dollar monthly fee plus 4 dollars per GB of data used. The total bill is 50 dollars. Write and solve an equation of the form ax + b = c.

Problem 18

A plumber charges a 75 dollar service fee plus 50 dollars per hour. The total bill is 225 dollars. Write and solve an equation of the form ax + b = c.

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Problem 19

A gym membership costs a 40 dollar enrollment fee plus 25 dollars per month. The total paid is 140 dollars. Write and solve an equation of the form ax + b = c.

Problem 20

T-shirt printing has a 15 dollar setup fee plus 7 dollars per shirt. The total cost is 85 dollars. Write and solve an equation of the form ax + b = c.

Problem 21

A party venue charges a 100 dollar base fee plus 10 dollars per guest. The total cost is 250 dollars. Write and solve an equation of the form ax + b = c.

Problem 22

A car rental has a 50 dollar flat fee plus 30 dollars per day. The total cost is 170 dollars. Write and solve an equation of the form ax + b = c.

Problem 23

A fundraiser starts with a 25 dollar initial donation plus 3 dollars for each item sold. The total raised is 55 dollars. Write and solve an equation of the form ax + b = c.

Problem 24

A repair service charges a 45 dollar diagnostic fee plus 60 dollars per hour for labor. The total bill is 165 dollars. Write and solve an equation of the form ax + b = c.

model grouped quantities, distribute, solve.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Three identical packs each contain x pencils and 2 bonus pencils. There are 24 pencils total. Write and solve an equation using parentheses.

Problem 26

Four tables each seat x students plus 1 extra chair. There are 28 seats total. Write and solve an equation using parentheses.

Problem 27

Five gift bags each have x candies plus 3 stickers. There are 60 items total. Write and solve an equation using parentheses.

Problem 28

Two boxes each contain x books and 4 magazines. There are 20 items total. Write and solve an equation using parentheses.

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Problem 29

Six baskets each hold x apples and 2 pears. There are 30 fruits total. Write and solve an equation using parentheses.

Problem 30

Seven classrooms each have x students and 5 empty desks. There are 49 spots total. Write and solve an equation using parentheses.

Problem 31

Eight shelves each display x trophies and 3 medals. There are 40 items total. Write and solve an equation using parentheses.

Problem 32

Nine teams each have x players and 1 coach. There are 45 people total. Write and solve an equation using parentheses.

Problem 33

Four classes each started with x students but 2 transferred out. There are 32 students remaining. Write and solve an equation using parentheses.

Problem 34

Three gardens each have x rose bushes and 5 sunflower plants. There are 30 plants total. Write and solve an equation using parentheses.

Problem 35

Five trays each contain x cookies and 4 brownies. There are 45 baked goods total. Write and solve an equation using parentheses.

Problem 36

Two groups each had x members, but 3 left. There are 14 members remaining. Write and solve an equation using parentheses.

choose inequality direction and interpret solution set.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

You can spend at most 40 dollars on notebooks that cost 5 dollars each. Write and solve an inequality, then interpret the solution.

Problem 38

A bus must carry at least 36 students with 12 students per van. Write and solve an inequality, then interpret the solution.

Problem 39

A score needs to be more than 90 after earning 6 points per question. Write and solve an inequality, then interpret the solution.

Problem 40

A charity needs to raise at least 500 dollars, with each donation being 25 dollars. Write and solve an inequality, then interpret the solution.

Problem 41

You can carry at most 15 kilograms in your backpack, and each book weighs 1.5 kilograms. Write and solve an inequality, then interpret the solution.

Problem 42

A car needs to travel more than 300 miles. It travels 60 miles per hour. Write and solve an inequality, then interpret the solution.

Problem 43

The maximum capacity of a venue is 200 people. Each group has 25 people. Write and solve an inequality, then interpret the solution.

Problem 44

You need to save less than 100 dollars for a small item. You save 10 dollars per week. Write and solve an inequality, then interpret the solution.

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Problem 45

A factory must produce at least 150 widgets per day. Each machine produces 30 widgets per hour. Write and solve an inequality, then interpret the solution.

Problem 46

A recipe requires less than 4 cups of sugar. Each serving uses 0.25 cups. Write and solve an inequality, then interpret the solution.

Problem 47

A student needs to score at least 85 points on a test. Each question is worth 5 points. Write and solve an inequality, then interpret the solution.

Problem 48

The budget for advertising is at most 1200 dollars. Each advertisement costs 150 dollars. Write and solve an inequality, then interpret the solution.

represent lower and upper bounds simultaneously.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

A safe refrigerator temperature is at least 34 degrees and at most 40 degrees. Write a compound inequality for the acceptable values.

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Problem 50

A part is acceptable if its length is from 9.8 cm to 10.2 cm inclusive. Write a compound inequality for the acceptable values.

Problem 51

A contest score must be greater than 70 but less than 90. Write a compound inequality for the acceptable values.

Problem 52

The optimal pH level for a certain chemical reaction is between 6.5 and 7.5, inclusive. Write a compound inequality for the acceptable values.

Problem 53

For a package to be shipped via express, its weight must be more than 1 kg but less than 10 kg. Write a compound inequality for the acceptable values.

Problem 54

A student must score at least 75 on the exam to pass, but a score of 100 is not possible due to a bonus question limit. Write a compound inequality for the acceptable values.

Problem 55

The minimum safe operating voltage for a device is strictly above 10V, and the maximum is 15V. Write a compound inequality for the acceptable values.

Problem 56

The acceptable range for the temperature of the oven is no less than 350 degrees F and no more than 400 degrees F. Write a compound inequality for the acceptable values.

Problem 57

To qualify for the advanced class, a student's age must be strictly between 16 and 18 years. Write a compound inequality for the acceptable values.

Problem 58

A certain medication dosage must be at least 5 mg but less than 15 mg. Write a compound inequality for the acceptable values.

Problem 59

The speed limit on a highway is greater than 60 mph but no more than 75 mph. Write a compound inequality for the acceptable values.

Problem 60

The ideal humidity level for storing artifacts is from 45% to 55%. Write a compound inequality for the acceptable values.

interpret absolute value as distance and solve two cases.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

A temperature is 6 degrees away from a target of 72 degrees. Write and solve an absolute-value equation.

Problem 62

A measurement is 0.4 cm away from 10 cm. Write and solve an absolute-value equation.

Problem 63

A score is 5 points away from 80. Write and solve an absolute-value equation.

Problem 64

A weight is 2 pounds away from 15 pounds. Write and solve an absolute-value equation.

Problem 65

An altitude is 100 feet away from 5000 feet. Write and solve an absolute-value equation.

Problem 66

A time is 3 minutes away from 30 minutes. Write and solve an absolute-value equation.

Problem 67

A length is 0.5 inches away from 12 inches. Write and solve an absolute-value equation.

Problem 68

A volume is 7 mL away from 250 mL. Write and solve an absolute-value equation.

Problem 69

A speed is 8 mph away from 60 mph. Write and solve an absolute-value equation.

Problem 70

A price is $1.50 away from $25.00. Write and solve an absolute-value equation.

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Problem 71

A population count is 50 away from 1000. Write and solve an absolute-value equation.

Problem 72

A voltage is 0.1 volts away from 12 volts. Write and solve an absolute-value equation.

distinguish within/at least distance and graph interval or rays.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

A machine part must be within 0.2 cm of 5 cm. Write the absolute-value inequality and describe its graph on a number line.

Problem 74

A score must be at least 10 points away from 70. Write the absolute-value inequality and describe its graph on a number line.

Problem 75

A temperature must stay within 3 degrees of 68. Write the absolute-value inequality and describe its graph on a number line.

Problem 76

A measurement must be within 0.5 inches of 12 inches. Write the absolute-value inequality and describe its graph on a number line.

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Problem 77

A security perimeter must be at least 50 feet away from the central building at 100 feet. Write the absolute-value inequality and describe its graph on a number line.

Problem 78

The acceptable weight of a product is within 0.1 kg of 2.5 kg. Write the absolute-value inequality and describe its graph on a number line.

Problem 79

A satellite's altitude must be at least 100 km away from its target altitude of 500 km. Write the absolute-value inequality and describe its graph on a number line.

Problem 80

The ideal pH level for a solution is within 0.3 of 7.0. Write the absolute-value inequality and describe its graph on a number line.

Problem 81

A car's speed must be at least 20 mph away from the average speed of 60 mph. Write the absolute-value inequality and describe its graph on a number line.

Problem 82

The allowed error for a resistor's resistance is within 5 ohms of 100 ohms. Write the absolute-value inequality and describe its graph on a number line.

Problem 83

A player's score must be at least 25 points away from the average score of 150. Write the absolute-value inequality and describe its graph on a number line.

Problem 84

The acceptable range for a voltage reading is within 0.1 volts of 12.5 volts. Write the absolute-value inequality and describe its graph on a number line.

detect which equation/inequality matches the story and reject distractors.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

For A plan costs 10 dollars plus 4 dollars per gigabyte, choose the model that matches: C = 10 + 4g or C = 4 + 10g. Explain the rejected model's error.

Problem 86

For A theater has a 5 dollar fee plus 12 dollars per ticket, choose the model that matches: C = 12t + 5 or C = 5t + 12. Explain the rejected model's error.

Problem 87

For A budget allows at most 50 dollars for items costing 8 dollars each, choose the model that matches: 8x <= 50 or 8x >= 50. Explain the rejected model's error.

Problem 88

For A cell phone plan costs 25 dollars per month plus 0.10 dollars per text message., choose the model that matches: C = 25 + 0.10t or C = 0.10 + 25t. Explain the rejected model's error.

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Problem 89

For To qualify for a discount, a customer must spend at least 75 dollars., choose the model that matches: S >= 75 or S <= 75. Explain the rejected model's error.

Problem 90

For A student can take no more than 5 classes per semester., choose the model that matches: C <= 5 or C >= 5. Explain the rejected model's error.

Problem 91

For A candle is 15 cm tall and burns down 0.5 cm per hour., choose the model that matches: H = 15 - 0.5t or H = 0.5 - 15t. Explain the rejected model's error.

Problem 92

For You buy apples for 3 dollars each and oranges for 2 dollars each. The total cost is 18 dollars., choose the model that matches: 3a + 2o = 18 or 2a + 3o = 18. Explain the rejected model's error.

Problem 93

For The speed limit on the highway is more than 60 mph., choose the model that matches: S > 60 or S < 60. Explain the rejected model's error.

Problem 94

For The temperature outside is less than 10 degrees Celsius., choose the model that matches: T < 10 or T > 10. Explain the rejected model's error.

Problem 95

For A savings account starts with 100 dollars and adds 20 dollars each week., choose the model that matches: A = 100 + 20w or A = 20 + 100w. Explain the rejected model's error.

Problem 96

For A store sells shirts for 20 dollars each, with a 5 dollar discount on the total purchase., choose the model that matches: C = 20s - 5 or C = 5s - 20. Explain the rejected model's error.

represent competing plans and solve break-even style equation.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Plan A costs 20 dollars plus 5 dollars per month. Plan B costs 8 dollars plus 8 dollars per month. Write and solve an equation with the variable on both sides.

Problem 98

One account starts with 50 dollars and adds 10 dollars per week. Another starts with 20 dollars and adds 15 dollars per week. Write and solve an equation with the variable on both sides.

Problem 99

A rental company charges 30 dollars plus 12 dollars per hour. Another charges 18 dollars plus 15 dollars per hour. Write and solve an equation with the variable on both sides.

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Problem 100

Gym A charges a 50 dollar enrollment fee plus 25 dollars per month. Gym B charges a 20 dollar enrollment fee plus 30 dollars per month. Write and solve an equation with the variable on both sides.

Problem 101

Tree P is 10 feet tall and grows 0.5 feet per year. Tree Q is 4 feet tall and grows 1.5 feet per year. Write and solve an equation with the variable on both sides.

Problem 102

Student X has read 120 pages and reads 15 pages per day. Student Y has read 60 pages and reads 25 pages per day. Write and solve an equation with the variable on both sides.

Problem 103

Delivery service A charges a 5 dollar flat fee plus 0.75 dollars per mile. Delivery service B charges a 2 dollar flat fee plus 1.25 dollars per mile. Write and solve an equation with the variable on both sides.

Problem 104

Tutor R charges a 40 dollar initial consultation fee plus 30 dollars per hour. Tutor S charges a 10 dollar initial consultation fee plus 35 dollars per hour. Write and solve an equation with the variable on both sides.

Problem 105

Subscription box Alpha costs 60 dollars initially then 15 dollars per month. Subscription box Beta costs 30 dollars initially then 20 dollars per month. Write and solve an equation with the variable on both sides.

Problem 106

Venue A charges a 50 dollar base price plus 5 dollars per ticket. Venue B charges a 20 dollar base price plus 8 dollars per ticket. Write and solve an equation with the variable on both sides.

Problem 107

Person X weighs 180 pounds and loses 3 pounds per week. Person Y weighs 150 pounds and gains 2 pounds per week. Write and solve an equation with the variable on both sides.

Problem 108

Plant A is 5 inches tall and grows 1.5 inches per week. Plant B is 2 inches tall and grows 2 inches per week. Write and solve an equation with the variable on both sides.

decide whether fractional, negative, or boundary values make sense.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

The mathematical solution is x = 3.5 for number of buses needed. Interpret whether it makes sense in context.

Problem 110

The mathematical solution is x = -2 for number of tickets sold. Interpret whether it makes sense in context.

Problem 111

The mathematical solution is x = 6 for hours worked. Interpret whether it makes sense in context.

Problem 112

The mathematical solution is x = 7.2 for number of full cartons required to ship eggs. Interpret whether it makes sense in context.

Problem 113

The mathematical solution is x = 4.9 for number of complete cakes that can be baked with available ingredients. Interpret whether it makes sense in context.

Problem 114

The mathematical solution is x = -10 for weight of an object in kilograms. Interpret whether it makes sense in context.

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Problem 115

The mathematical solution is x = 250 for maximum capacity of a concert hall (capacity 200 people). Interpret whether it makes sense in context.

Problem 116

The mathematical solution is x = 0.75 for liters of paint used. Interpret whether it makes sense in context.

Problem 117

The mathematical solution is x = 0 for number of errors found in a perfect code review. Interpret whether it makes sense in context.

Problem 118

The mathematical solution is x = -50 for change in bank account balance in dollars. Interpret whether it makes sense in context.

Problem 119

The mathematical solution is x = 3.1 for number of teams needed for a competition. Interpret whether it makes sense in context.

Problem 120

The mathematical solution is x = 1.5 for minimum number of years of experience required for a job (minimum 2 years). Interpret whether it makes sense in context.

represent percent multiplier and solve for original or final amount.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

A jacket after a 20 percent discount costs 48 dollars. Find the original price. Write and solve an equation involving percent increase or decrease.

Problem 122

A price after 8 percent tax is 54 dollars. Find the pre-tax price. Write and solve an equation involving percent increase or decrease.

Problem 123

A population after a 10 percent increase is 330. Find the original population. Write and solve an equation involving percent increase or decrease.

Problem 124

A shirt after a 25 percent discount costs 30 dollars. Find the original price. Write and solve an equation involving percent increase or decrease.

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Problem 125

The bill for a meal after a 15 percent tip is 69 dollars. Find the original bill. Write and solve an equation involving percent increase or decrease.

Problem 126

The number of students in a club increased by 20 percent to 72. Find the original number of students. Write and solve an equation involving percent increase or decrease.

Problem 127

A car's value decreased by 10 percent to 18,000 dollars. Find its original value. Write and solve an equation involving percent increase or decrease.

Problem 128

A store's sales increased by 30 percent to 2600 dollars this month. What were the sales last month?. Write and solve an equation involving percent increase or decrease.

Problem 129

After a 5 percent price reduction, a book costs 19 dollars. What was the original price?. Write and solve an equation involving percent increase or decrease.

Problem 130

A worker's salary increased by 4 percent to 3120 dollars per month. What was their original salary?. Write and solve an equation involving percent increase or decrease.

Problem 131

After losing 12 percent of its weight, an object weighs 88 pounds. What was its original weight?. Write and solve an equation involving percent increase or decrease.

Problem 132

A factory increased its production by 25 percent to 500 units per day. How many units did it produce originally?. Write and solve an equation involving percent increase or decrease.

combine parts into total or average relationship.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

A student has test scores 80 and 90. What third score x gives an average of 85?. Write an equation for the mixture or weighted average and solve.

Problem 134

Mix 2 liters of 10 percent solution with x liters of 40 percent solution to make 20 percent solution in 5 liters total. Write an equation for the mixture or weighted average and solve.

Problem 135

Three items average 12 dollars. Two cost 10 and 14 dollars. Find the third cost. Write an equation for the mixture or weighted average and solve.

Problem 136

A student has grades of 75, 82, and 90 on three assignments. What score x on the fourth assignment is needed to achieve an average of 85?. Write an equation for the mixture or weighted average and solve.

Problem 137

How many ounces of a 60% acid solution must be added to 10 ounces of a 10% acid solution to produce a 20% acid solution?. Write an equation for the mixture or weighted average and solve.

Problem 138

A coffee blend is made by mixing 5 pounds of coffee beans costing $8 per pound with x pounds of coffee beans costing $12 per pound. If the total blend costs $10 per pound, what is x?. Write an equation for the mixture or weighted average and solve.

Problem 139

The average weight of 4 students is 150 pounds. If three students weigh 140, 160, and 155 pounds, what is the weight of the fourth student?. Write an equation for the mixture or weighted average and solve.

Problem 140

A chemist mixes 3 liters of a 25% saline solution with 7 liters of a 45% saline solution. What is the percentage of saline in the resulting mixture?. Write an equation for the mixture or weighted average and solve.

Problem 141

A portfolio consists of 100 shares of stock A at $20 per share and 150 shares of stock B at x dollars per share. If the average price per share for the entire portfolio is $26, what is x?. Write an equation for the mixture or weighted average and solve.

Problem 142

A car travels at 50 mph for 2 hours and then at 60 mph for x hours. If the average speed for the entire trip is 55 mph, how long did the car travel at 60 mph?. Write an equation for the mixture or weighted average and solve.

Problem 143

The average height of 5 players on a basketball team is 75 inches. If a new player joins, and the average height of the 6 players becomes 76 inches, what is the height of the new player?. Write an equation for the mixture or weighted average and solve.

Problem 144

A farmer wants to mix two types of feed. One costs $0.20 per pound and the other costs $0.35 per pound. How many pounds of the $0.35 feed should be mixed with 100 pounds of the $0.20 feed to get a mixture costing $0.25 per pound?. Write an equation for the mixture or weighted average and solve.

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identify which condition applies before solving.
12 problems Warmup Practice Mixed Review Assessment
Problem 145

Shipping costs 5 dollars for orders up to 2 pounds and 3 dollars per pound for orders over 2 pounds. A package weighs 4 pounds. Choose the correct equation branch and solve.

Problem 146

Overtime pay is 15 dollars per hour for up to 40 hours and 22.50 dollars per hour after 40 hours. An employee works 45 hours. Choose the correct equation branch and solve.

Problem 147

A parking garage charges 4 dollars for the first hour and 2 dollars for each additional hour. A car parks 3 hours. Choose the correct equation branch and solve.

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Problem 148

A library charges 0.50 dollars per day for overdue books, up to a maximum of 5 dollars. A book is 7 days overdue. Choose the correct equation branch and solve.

Problem 149

A library charges 0.50 dollars per day for overdue books, up to a maximum of 5 dollars. A book is 12 days overdue. Choose the correct equation branch and solve.

Problem 150

A mobile data plan includes 5 GB for 20 dollars and charges 2 dollars per GB for usage over 5 GB. A user consumes 7 GB of data. Choose the correct equation branch and solve.

Problem 151

A mobile data plan includes 5 GB for 20 dollars and charges 2 dollars per GB for usage over 5 GB. A user consumes 3 GB of data. Choose the correct equation branch and solve.

Problem 152

A salesperson earns a 10% commission on sales up to 1000 dollars and 15% on sales exceeding 1000 dollars. The salesperson makes 800 dollars in sales. Choose the correct equation branch and solve.

Problem 153

A salesperson earns a 10% commission on sales up to 1000 dollars and 15% on sales exceeding 1000 dollars. The salesperson makes 1500 dollars in sales. Choose the correct equation branch and solve.

Problem 154

A car rental company charges 30 dollars per day for the first 3 days, then 25 dollars per day for each additional day. A customer rents a car for 5 days. Choose the correct equation branch and solve.

Problem 155

A car rental company charges 30 dollars per day for the first 3 days, then 25 dollars per day for each additional day. A customer rents a car for 2 days. Choose the correct equation branch and solve.

Problem 156

Tickets to a show cost 20 dollars each for individual purchases. For groups of 10 or more, tickets are 18 dollars each. A group of 12 people buys tickets. Choose the correct equation branch and solve.

translate visual quantities into algebraic relationships.
12 problems Warmup Practice Mixed Review Assessment
Problem 157

A diagram or layout is described: A rectangle has width 5 and length x. Its perimeter is 30. Write an equation or inequality and solve for the unknown.

Problem 158

A diagram or layout is described: Two adjacent angles measure x and 35 degrees and form a straight angle. Write an equation or inequality and solve for the unknown.

Problem 159

A diagram or layout is described: A shelf can hold at most 50 pounds. Each box weighs 8 pounds. Write an equation or inequality and solve for the unknown.

Problem 160

A diagram or layout is described: A square has a side length of x units. Its perimeter is 60 units. Write an equation or inequality and solve for the unknown.

Problem 161

A diagram or layout is described: A triangle has side lengths x, x+3, and 12. Its perimeter is 45. Write an equation or inequality and solve for the unknown.

Problem 162

A diagram or layout is described: The three angles in a triangle are x, 2x, and 60 degrees. Write an equation or inequality and solve for the unknown.

Problem 163

A diagram or layout is described: Two angles are complementary. One angle measures x degrees, and the other measures 2x degrees. Write an equation or inequality and solve for the unknown.

Problem 164

A diagram or layout is described: A pie is cut into three slices. The angles of two slices are 100 degrees and 120 degrees. The third slice has an angle of x degrees. Write an equation or inequality and solve for the unknown.

Problem 165

A diagram or layout is described: A line segment AC is 40 units long. Point B is between A and C. Segment AB is x units and BC is x + 10 units. Write an equation or inequality and solve for the unknown.

Problem 166

A diagram or layout is described: A box can hold a maximum of 100 marbles. Each marble weighs 0.5 ounces. Write an equation or inequality and solve for the unknown.

Problem 167

A diagram or layout is described: A rectangular garden has a length of 20 feet and a perimeter of 70 feet. What is its width, w?. Write an equation or inequality and solve for the unknown.

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Problem 168

A diagram or layout is described: A 2-meter long plank is cut into two pieces. One piece is 'y' cm long, and the other is 'y + 40' cm long. Write an equation or inequality and solve for the unknown.

convert units before or during equation setup.
12 problems Warmup Practice Mixed Review Assessment
Problem 169

A job takes 2 hours plus x minutes and totals 150 minutes. Write and solve a one-variable equation, converting units as needed.

Problem 170

A board is 9 feet long. After cutting off x inches, 72 inches remain. Write and solve a one-variable equation, converting units as needed.

Problem 171

A price is x cents plus 3 dollars and totals 425 cents. Write and solve a one-variable equation, converting units as needed.

Problem 172

A rope is 5 yards long. If x feet are cut off, 9 feet remain. Write and solve a one-variable equation, converting units as needed.

Problem 173

A task takes 3 minutes and x seconds, totaling 200 seconds. Write and solve a one-variable equation, converting units as needed.

Problem 174

A package weighs 2 pounds. After adding x ounces, the total weight is 40 ounces. Write and solve a one-variable equation, converting units as needed.

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Problem 175

A container holds 4 gallons. If x quarts are removed, 12 quarts remain. Write and solve a one-variable equation, converting units as needed.

Problem 176

A ribbon is 3 meters long. x centimeters are added, making it 350 centimeters long. Write and solve a one-variable equation, converting units as needed.

Problem 177

A project took x hours plus 2 days, totaling 60 hours. Write and solve a one-variable equation, converting units as needed.

Problem 178

A recipe calls for 0.5 kilograms of flour. If x grams are used, 300 grams remain. Write and solve a one-variable equation, converting units as needed.

Problem 179

John has 7 euros. He spends x cents and has 650 cents left. Write and solve a one-variable equation, converting units as needed.

Problem 180

A path is 1 mile long. After walking x feet, 4280 feet are left. Write and solve a one-variable equation, converting units as needed.