Math I · A-CED.3

Representing Constraints, Systems, and Viable Solutions in Context

Constraints teach students that real life usually has more than one condition, and good math separates possible choices from impossible or irresponsible ones.

Concept Algebra
Domain Creating Equations
Read time 9 minutes

What this learning objective is really asking you to learn

This objective is about the mathematics of possible choices. A constraint is a condition that limits what can happen. It might be a budget, a deadline, a calorie target, a weight limit, a minimum score, a maximum speed, a staffing requirement, a storage capacity, a legal rule, or a design specification. Constraints turn math from “find the answer” into “find what is allowed.”

An equation can represent a constraint when something must be exactly true. For example, if a container must hold exactly 2 liters, the volume equation is a constraint. An inequality can represent a constraint when something must be below, above, no more than, or at least a certain amount. For example, a suitcase must weigh no more than 50 pounds: \(w \le 50\). A student must earn at least 70% to pass: \(s \ge 70\). A building part must be between two lengths: \(lower limit \le length \le upper limit\).

A system is a collection of constraints that must all be true at the same time. One inequality might represent a budget. Another might represent time. Another might represent minimum quality. Another might represent physical capacity. The solutions to the system are the choices that satisfy every condition simultaneously.

A viable solution is a mathematically valid solution that also makes sense in the situation. A non-viable solution may satisfy some algebraic statement but fail because of context. If a system says you can buy 3.5 buses, the math may have produced a number, but the real-world decision does not allow half a bus. If a solution uses negative hours, it fails the context. If a food plan meets a calorie target but requires a negative number of apples, it is not viable.

This objective trains students to think like modelers, planners, engineers, and decision-makers. The job is not only to solve. The job is to decide which solutions are possible, meaningful, and useful.

Why students should learn this math

Most real decisions happen under constraints. You rarely get unlimited money, unlimited time, unlimited space, unlimited energy, or unlimited risk. The world is not a blank page; it is a set of limits.

A family planning a vacation has a budget, dates, transportation limits, hotel availability, and personal preferences. A city planning a bus route has fuel costs, driver schedules, traffic patterns, passenger demand, and accessibility requirements. A coach planning a lineup has player positions, stamina, rules, and strategy. A business planning production has labor, materials, machine time, shipping capacity, and customer demand. A student planning a week has homework, sleep, practice, chores, and social life. All of these are constraint problems.

Students often ask, “When will I ever use systems of equations or inequalities?” The direct answer is: whenever you need to choose under multiple conditions. A single equation might tell you what happens under one rule. A system tells you what can happen under several rules at once.

This is also the beginning of optimization, one of the most important applied branches of mathematics. Optimization asks: among all viable solutions, which one is best? The best might mean cheapest, fastest, safest, strongest, healthiest, fairest, or most profitable. Before you can optimize, you have to know what is feasible. A-CED.3 builds that foundation.

It also teaches intellectual honesty. A number that comes out of algebra is not automatically a good answer. Real-life constraints matter. Units matter. Whole-number requirements matter. Physical limits matter. Ethical limits matter. Context can reject a mathematically neat answer.

The historical machinery: from practical constraints to operations research

Constraint thinking is ancient. Builders had to work within material limits. Merchants had to balance goods, prices, and weights. Farmers had to divide land and water. Governments had to collect taxes and allocate resources. Long before modern notation, people were solving constraint problems in practical language.

In the twentieth century, constraint mathematics became central to a field known as operations research. During large-scale military, industrial, and logistical planning, decision-makers had to allocate limited resources efficiently. How should supplies be shipped? How should workers be scheduled? How should machines be used? How could planners satisfy many requirements while improving a goal?

Linear programming became one of the major mathematical tools for this kind of problem. In linear programming, constraints are often linear inequalities, and the feasible solutions form a region. George Dantzig’s simplex method, developed in the 1940s, became a powerful method for optimizing a linear objective subject to linear constraints. The school version of graphing systems of linear inequalities is a small but genuine doorway into that world.

This history is useful for students because it shows that systems of inequalities are not decorative algebra. They are the math behind airline scheduling, delivery routes, factory production, diet planning, investment portfolios, staffing, energy distribution, and many other systems where choices must satisfy multiple limits.

Where this fits in the big map of mathematics

A-CED.3 connects algebra to systems, graphing, modeling, and optimization.

In A-CED.1, you learned to solve one condition with one variable. In A-CED.2, you learned to represent relationships between variables. In A-CED.3, you combine multiple relationships and constraints. This is a major conceptual upgrade. You are no longer looking at a single rule. You are looking at an environment of rules.

In coordinate geometry, each linear equation is a line. Each linear inequality is a half-plane: one side of a boundary line. A system of inequalities is the overlap of several half-planes. That overlap is called the feasible region. Every point inside it satisfies all the inequalities. Every point outside it violates at least one constraint.

In later mathematics, this idea expands. In three variables, constraints create regions in space. In linear algebra, systems become matrix equations and higher-dimensional solution sets. In calculus and optimization, constraints define where maximum and minimum values can occur. In statistics and machine learning, constraints can control model fitting. In computer science, constraint satisfaction problems appear in scheduling, puzzles, artificial intelligence, and resource allocation.

The school graph of a shaded region may look simple, but it is a two-dimensional picture of a profound idea: possible worlds are shaped by constraints.

How to execute the skill technically

The first step is to define variables. In a problem about buying apples and oranges, you might let \(a\) be the number of apples and \(o\) be the number of oranges. Include units. Are these individual pieces of fruit, pounds, boxes, or dollars? The variable definition determines the meaning of every equation.

The second step is to list the constraints in words before writing symbols. For example:

  • apples and oranges cannot be negative;
  • total cost must be at most $20;
  • total fruit must be at least 10 pieces;
  • apples may need to be at least 4 pieces.

The third step is to translate each constraint into an equation or inequality. If apples cost $1 each and oranges cost $2 each, the budget constraint is \(a + 2o \le 20\). If there must be at least 10 pieces of fruit, then \(a + o \ge 10\). If at least 4 apples are required, then \(a \ge 4\). Nonnegative quantities give \(a \ge 0\) and \(o \ge 0\).

The fourth step is to solve or graph the system. For two-variable linear inequalities, graph each boundary line, decide which side satisfies the inequality, and shade the overlap. A solid boundary line means the boundary is included (\(\le\) or \(\ge\)). A dashed boundary line means the boundary is not included (\(<\) or \(>\)).

The fifth step is to interpret the feasible region. Every point in the region is mathematically allowed. But context may add additional requirements. If \(a\) and \(o\) are individual fruits, then only whole-number points are viable. The point \((4.5, 7.5)\) may be inside the shaded region, but it is not viable if you cannot buy half a fruit.

The sixth step is to test candidate solutions. If the question asks whether a particular option is viable, substitute the values into every constraint. A candidate must pass all constraints, not just one.

A worked example: designing snack packs

A club is making snack packs with granola bars and fruit cups. A granola bar costs $1 and has 100 calories. A fruit cup costs $2 and has 80 calories. Each pack must cost no more than $8 and must contain at least 400 calories. The club wants at least one of each item. What combinations are viable?

Let \(g\) be the number of granola bars and \(f\) be the number of fruit cups.

Cost constraint:

\[g + 2f \le 8\].

Calorie constraint:

\[100g + 80f \ge 400\].

At least one of each:

\(g \ge 1\), \(f \ge 1\).

Whole-number context:

\(g\) and \(f\) must be integers.

Now test some points. \((4, 1)\) means 4 granola bars and 1 fruit cup. Cost: \(4 + 2(1) = 6\), which is within $8. Calories: \(100(4) + 80(1) = 480\), which is at least 400. It uses at least one of each. This is viable.

\((1, 1)\) costs \(1 + 2 = 3\), but calories are \(100 + 80 = 180\), which is too low. It is not viable.

\((2, 4)\) has calories \(200 + 320 = 520\), but cost is \(2 + 8 = 10\), which is too high. It is not viable.

\((3.2, 1.5)\) might satisfy the inequalities numerically, but it is not viable if snack items must be whole objects.

This example shows the difference between solving algebra and making a real decision. The feasible region is necessary, but the context filters it further.

Equations versus inequalities in systems

Equations are boundaries of exactness. Inequalities are regions of permission.

If a problem says the total number of items must be exactly 12, then the constraint is \(x + y = 12\). The solutions lie on a line. If a problem says the total number of items must be at most 12, then the constraint is \(x + y \le 12\). The solutions fill one side of the line. That difference matters.

A system with two equations often has a single intersection point, no intersection, or infinitely many intersections. A system with inequalities often has a region. A system mixing equations and inequalities may have a line segment, a ray, or selected points. The shape of the solution set reflects the kind of constraints involved.

This is why graphing is powerful. It shows whether constraints conflict. If the shaded regions never overlap, there is no feasible solution. That is not failure; it is information. It means the requirements cannot all be met at once. In real life, this is often the most important conclusion. A budget, deadline, and quality requirement may be incompatible. Mathematics can reveal that before time and money are wasted.

Viable and non-viable solutions

The phrase “viable solution” is one of the most important parts of this objective. A solution can fail for many contextual reasons.

It might fail because of units. If the variable represents hours, the answer should be in hours, not dollars. It might fail because of sign. Negative distance, negative people, or negative material may be impossible in the situation. It might fail because of discreteness. Some quantities must be whole numbers. It might fail because of physical limits. A container cannot hold more than its capacity. It might fail because of policy or ethics. A mathematically efficient schedule may be unfair or illegal.

Students should learn to ask: Does this answer satisfy the symbolic constraints? Does it make sense with the units? Does it fit the domain? Does it respect the real-world meaning? Is it actually possible?

That habit is what separates answer-getting from modeling.

Common mistakes and how to avoid them

A common mistake is translating constraints backward. “No more than 8” means \(\le 8\), not \(\ge 8\). “At least 400” means \(\ge 400\), not \(\le 400\). If you are unsure, test a simple value. If the cost must be no more than 8, then 6 should work and 10 should not. Which inequality makes that true?

Another mistake is graphing the wrong side of a boundary line. Always test a point not on the line, often \((0,0)\) if it is convenient. Substitute it into the inequality. If it makes the statement true, shade the side containing that point. If not, shade the other side.

Students also forget nonnegative constraints. In real contexts, variables like number of items, pounds of material, or hours worked often cannot be negative. The constraints \(x \ge 0\) and \(y \ge 0\) are easy to overlook, but they shape the feasible region.

Another mistake is treating every point in a shaded region as viable even when the context requires whole numbers. If the variables count objects, the viable solutions may be lattice points, not every point in the region.

The big takeaway

This objective teaches the mathematics of possible choices. Equations and inequalities represent constraints. Systems combine constraints. The feasible region shows what satisfies the math. Context determines what is viable. This is one of the clearest answers to “Why am I learning this?” Because real decisions are made under limits, and algebra is one of the best tools humans have invented for understanding those limits before acting.

Problem Library

Problems in the App From This Objective

180 problems across 15 archetypes in the app.

model capacity, budget, or time constraint.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

You can spend at most 60 dollars on shirts costing 12 dollars each. Write a single inequality constraint.

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Problem 2

A box can hold no more than 40 pounds with each item weighing 5 pounds. Write a single inequality constraint.

Problem 3

You need at least 120 minutes of practice at m minutes per day for d days. Write a single inequality constraint.

Problem 4

You can spend at most 200 dollars on books, each costing 25 dollars. Write a single inequality constraint.

Problem 5

A truck can carry a maximum of 2000 pounds. Each package weighs 50 pounds. Write a single inequality constraint.

Problem 6

To pass the exam, you need a score of at least 70 points. Each question is worth 5 points. Write a single inequality constraint.

Problem 7

You have a maximum of 4 hours to complete a task that takes 30 minutes per unit. Write a single inequality constraint.

Problem 8

You need at least 50 grams of flour for a recipe, and each scoop contains 10 grams. Write a single inequality constraint.

Problem 9

A shelf can hold a maximum total width of 20 inches. Each book is 2 inches wide. Write a single inequality constraint.

Problem 10

You want to earn at least 500 dollars. You earn 20 dollars per hour. Write a single inequality constraint.

Problem 11

You can drive no more than 300 miles on a full tank. Your car gets 30 miles per gallon. Write a single inequality constraint.

Problem 12

A class requires a minimum of 15 students to run. Currently, there are s students. Write a single inequality constraint.

combine item-count and cost/resource constraints.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Buy x notebooks at 3 dollars and y pens at 2 dollars, spending at most 30 dollars and buying at most 12 items. Write a system of inequalities for the constraints.

Problem 14

Make x small posters and y large posters using at most 40 minutes if small takes 2 minutes and large takes 5 minutes, with at least 10 posters total. Write a system of inequalities for the constraints.

Problem 15

Sell x sandwiches at 4 dollars and y salads at 6 dollars, earning at least 48 dollars while preparing at most 14 total items. Write a system of inequalities for the constraints.

Problem 16

A baker makes x cakes and y pies. Each cake requires 2 cups of flour and each pie requires 3 cups of flour. The baker has at most 24 cups of flour. Each cake takes 30 minutes to bake and each pie takes 20 minutes to bake. The baker has at most 300 minutes for baking. Write a system of inequalities for the constraints.

Problem 17

A company produces x widgets and y gadgets. Each widget costs $5 to produce and each gadget costs $8. The company wants to spend at most $400. Each widget requires 1 hour of labor and each gadget requires 2 hours of labor. The company has at most 80 hours of labor available. Write a system of inequalities for the constraints.

Problem 18

A student needs to study x hours for math and y hours for science. They want to study at least 15 hours total. Each hour of math study improves their score by 3 points, and each hour of science study improves it by 4 points. They want to improve their total score by at least 50 points. Write a system of inequalities for the constraints.

Problem 19

A farmer plants x acres of corn and y acres of soybeans. They have at most 100 acres available. Corn requires 10 gallons of water per acre and soybeans require 8 gallons per acre. The farmer has at most 900 gallons of water. Write a system of inequalities for the constraints.

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Problem 20

A store sells x small t-shirts and y large t-shirts. They want to sell at least 20 t-shirts in total. Each small t-shirt costs $10 and each large t-shirt costs $15. The store wants to earn at least $250 from t-shirt sales. Write a system of inequalities for the constraints.

Problem 21

A factory produces x chairs and y tables. Each chair requires 2 units of wood and 1 unit of metal. Each table requires 5 units of wood and 3 units of metal. The factory has at most 50 units of wood and at most 30 units of metal. Write a system of inequalities for the constraints.

Problem 22

A nutritionist is creating a meal plan with x servings of fruit and y servings of vegetables. They want the total servings to be at least 8. Each serving of fruit has 60 calories and each serving of vegetables has 25 calories. The total calories should be at most 300. Write a system of inequalities for the constraints.

Problem 23

An artist is making x small sculptures and y large sculptures. Each small sculpture takes 4 hours to make and each large sculpture takes 7 hours. The artist has at most 50 hours available. Each small sculpture uses 3 kg of clay and each large sculpture uses 6 kg of clay. The artist has at most 60 kg of clay. Write a system of inequalities for the constraints.

Problem 24

A charity is collecting x canned goods and y articles of clothing. They want to collect at least 100 items in total. Each canned good weighs 0.5 kg and each article of clothing weighs 0.2 kg. The total weight must be at most 40 kg for transport. Write a system of inequalities for the constraints.

substitute into every constraint and interpret.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Test whether (4, 5) is viable for the system 3x + 2y <= 25, x + y <= 10, x >= 0, y >= 0 in context.

Problem 26

Test whether (6, 4) is viable for the system 5x + 3y <= 35, x + y <= 12, x >= 0, y >= 0 in context.

Problem 27

Test whether (-1, 6) is viable for the system x + y <= 10, x >= 0, y >= 0 in context.

Problem 28

Test whether (2, 3) is viable for the system x + y <= 5, 2x - y >= 1, x >= 0, y >= 0 in context.

Problem 29

Test whether (5, 2) is viable for the system x + y <= 6, x - y >= 0, x >= 0, y >= 0 in context.

Problem 30

Test whether (1, 5) is viable for the system x + y <= 10, 3x - y >= 0, x >= 0, y >= 0 in context.

Problem 31

Test whether (-2, 1) is viable for the system x + 2y <= 5, x >= 0, y >= 0 in context.

Problem 32

Test whether (3, -1) is viable for the system 2x + y <= 5, x >= 0, y >= 0 in context.

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Problem 33

Test whether (1, 1) is viable for the system x + 3y <= 5, 2x - y <= 1, x >= 0, y >= 0 in context.

Problem 34

Test whether (3, 0) is viable for the system x + y < 3, x >= 0, y >= 0 in context.

Problem 35

Test whether (3, 0) is viable for the system x + y <= 3, x >= 0, y >= 0 in context.

Problem 36

Test whether (10, 10) is viable for the system x + y <= 5, x >= 0, y >= 0 in context.

boundary lines, shading, overlap.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Graph the feasible region for x + y <= 6, x >= 0, y >= 0. Describe the boundary lines and shaded overlap.

Problem 38

Graph the feasible region for y >= 2x + 1, y <= 5, x >= 0. Describe the boundary lines and shaded overlap.

Problem 39

Graph the feasible region for x <= 4, y <= 3, x + y >= 2, x >= 0, y >= 0. Describe the boundary lines and shaded overlap.

Problem 40

Graph the feasible region for y > x, x >= 0. Describe the boundary lines and shaded overlap.

Problem 41

Graph the feasible region for x < 3, y >= 1, x >= 0, y <= 4. Describe the boundary lines and shaded overlap.

Problem 42

Graph the feasible region for y <= -x + 5, x > 0. Describe the boundary lines and shaded overlap.

Problem 43

Graph the feasible region for x + y < 4, x > 0. Describe the boundary lines and shaded overlap.

Problem 44

Graph the feasible region for y >= x - 2, y <= -x + 4, x < 3. Describe the boundary lines and shaded overlap.

Problem 45

Graph the feasible region for y >= x, x + y >= -2, y < 2. Describe the boundary lines and shaded overlap.

Problem 46

Graph the feasible region for x > -1, x < 2, y >= -2, y <= 1. Describe the boundary lines and shaded overlap.

Problem 47

Graph the feasible region for y < -x + 3, y > 2x - 3. Describe the boundary lines and shaded overlap.

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Problem 48

Graph the feasible region for x + 2y <= 8, 3x + y <= 9, x >= 0, y >= 0. Describe the boundary lines and shaded overlap.

account for discrete quantities and nonnegative constraints.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

List feasible integer solutions for x + y <= 4, x >= 0, y >= 0 under x and y are whole numbers.

Problem 50

List feasible integer solutions for 2x + y <= 5, x >= 0, y >= 0 under x and y are whole numbers.

Problem 51

List feasible integer solutions for x + 2y <= 6, x >= 0, y >= 0 under x and y are whole numbers.

Problem 52

List feasible integer solutions for x + y <= 3, x >= 0, y >= 0 under x and y are whole numbers.

Problem 53

List feasible integer solutions for x + 3y <= 6, x >= 0, y >= 0 under x and y are whole numbers.

Problem 54

List feasible integer solutions for 3x + y <= 6, x >= 0, y >= 0 under x and y are whole numbers.

Problem 55

List feasible integer solutions for x + y <= 3, x - y >= 0, x >= 0, y >= 0 under x and y are whole numbers.

Problem 56

List feasible integer solutions for x + y <= 4, y - x >= 0, x >= 0, y >= 0 under x and y are whole numbers.

Problem 57

List feasible integer solutions for x + y >= 2, x + y <= 4, x >= 0, y >= 0 under x and y are whole numbers.

Problem 58

List feasible integer solutions for 2x + 3y <= 6, x >= 0, y >= 0 under x and y are whole numbers.

Problem 59

List feasible integer solutions for 3x + 2y <= 6, x >= 0, y >= 0 under x and y are whole numbers.

Problem 60

List feasible integer solutions for x + y <= 5, x >= 1, y >= 1 under x and y are whole numbers.

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explain what equality means in context.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Interpret the boundary point (4, 3) for the constraint 5x + 10y <= 50 in context: x small items cost 5 dollars and y large items cost 10 dollars with 50 dollars available.

Problem 62

Interpret the boundary point (6, 2) for the constraint x + y >= 8 in context: at least 8 total workers are needed.

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Problem 63

Interpret the boundary point (5, 2) for the constraint 4x + 6y <= 32 in context: x wood pieces use 4 inches each and y metal pieces use 6 inches each with 32 inches available.

Problem 64

Interpret the boundary point (6, 4) for the constraint 2x + 3y <= 24 in context: x hours spent on task A at 2 dollars/hour and y hours on task B at 3 dollars/hour with a budget of 24 dollars.

Problem 65

Interpret the boundary point (4, 3) for the constraint 3x + 2y >= 18 in context: x large boxes weighing 3 kg each and y small boxes weighing 2 kg each, needing at least 18 kg total for shipping.

Problem 66

Interpret the boundary point (4, 3) for the constraint x + 2y <= 10 in context: a truck can carry x small packages and y large packages (large packages take up twice the space of small ones), with a total capacity of 10 'small package units'.

Problem 67

Interpret the boundary point (6, 6) for the constraint 1.5x + y <= 15 in context: x reports taking 1.5 hours each and y presentations taking 1 hour each, with 15 hours available this week.

Problem 68

Interpret the boundary point (5, 6) for the constraint 2x + 5y <= 40 in context: x square tiles of 2 sq ft each and y rectangular tiles of 5 sq ft each, to cover an area of 40 sq ft.

Problem 69

Interpret the boundary point (7, 5) for the constraint x + y >= 12 in context: x units produced by machine A and y units by machine B, needing at least 12 units total.

Problem 70

Interpret the boundary point (6, 8) for the constraint 0.5x + 0.25y <= 5 in context: x grams of ingredient A (0.5 units per gram) and y grams of ingredient B (0.25 units per gram), with 5 units of a compound available.

Problem 71

Interpret the boundary point (9, 8) for the constraint 20x + 15y <= 300 in context: x trips of 20 miles each and y trips of 15 miles each, with enough fuel for 300 miles.

Problem 72

Interpret the boundary point (5, 4) for the constraint 10x + 5y >= 70 in context: x correct answers on 10-point questions and y correct answers on 5-point questions, needing at least 70 points to pass.

evaluate candidate solutions against goal after constraints.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Given feasible options point=(2,5), value=29; point=(4,3), value=31; point=(6,1), value=27 and goal 'maximize profit', choose the best option.

Problem 74

Given feasible options point=(1,8), value=18; point=(3,4), value=14; point=(5,2), value=16 and goal 'minimize cost', choose the best option.

Problem 75

Given feasible options point=(1,6), value=34; point=(3,3), value=30; point=(5,1), value=26 and goal 'maximize total score', choose the best option.

Problem 76

Given feasible options point=(10,2), value=120; point=(8,4), value=130; point=(6,6), value=110 and goal 'maximize revenue', choose the best option.

Problem 77

Given feasible options point=(7,1), value=45; point=(5,3), value=40; point=(3,5), value=50 and goal 'minimize time', choose the best option.

Problem 78

Given feasible options point=(0,10), value=500; point=(2,8), value=520; point=(4,6), value=480 and goal 'maximize production', choose the best option.

Problem 79

Given feasible options point=(9,0), value=75; point=(7,2), value=70; point=(5,4), value=80 and goal 'minimize waste', choose the best option.

Problem 80

Given feasible options point=(1,1), value=15; point=(2,2), value=25; point=(3,3), value=20 and goal 'maximize efficiency', choose the best option.

Problem 81

Given feasible options point=(10,10), value=100; point=(12,8), value=95; point=(14,6), value=105 and goal 'minimize error rate', choose the best option.

Problem 82

Given feasible options point=(0,0), value=0; point=(1,0), value=5; point=(0,1), value=3 and goal 'maximize output', choose the best option.

Problem 83

Given feasible options point=(100,0), value=200; point=(0,100), value=150; point=(50,50), value=180 and goal 'minimize distance', choose the best option.

Problem 84

Given feasible options point=(5,5), value=55; point=(6,4), value=60; point=(4,6), value=50 and goal 'maximize yield', choose the best option.

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add nonnegative, integer, upper/lower-bound, or context restrictions.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

The model 3x + 2y <= 30 is incomplete for x and y are numbers of items bought. Identify a missing constraint.

Problem 86

The model x + y <= 20 is incomplete for at least 5 volunteers are required. Identify a missing constraint.

Problem 87

The model 2x + 4y <= 100 is incomplete for no more than 10 large items y can be stored. Identify a missing constraint.

Problem 88

The model C = 50 + 10h is incomplete for C is the cost of renting a boat for h hours, and hours cannot be negative. Identify a missing constraint.

Problem 89

The model x + y <= 50 is incomplete for A project requires a minimum of 10 workers in total, where x and y are types of workers. Identify a missing constraint.

Problem 90

The model P = 10a + 5b is incomplete for You can produce at most 20 units of item 'a' due to material limits. Identify a missing constraint.

Problem 91

The model Total score = x + y + z is incomplete for A student must score at least 60 points on component 'x' to pass. Identify a missing constraint.

Problem 92

The model x + y = 100 is incomplete for The amount of ingredient 'x' must be at least twice the amount of ingredient 'y' for the recipe to work. Identify a missing constraint.

Problem 93

The model Items produced: x + y is incomplete for The total cost of production, with item x costing $10 and item y costing $15, must not exceed $500. Identify a missing constraint.

Problem 94

The model Number of packages = x + y is incomplete for The combined weight of package type x (2kg each) and package type y (3kg each) must be at least 250kg for shipping. Identify a missing constraint.

Problem 95

The model Area = length * width is incomplete for Length and width represent physical dimensions, so they must be positive. Identify a missing constraint.

Open in simulator
Problem 96

The model Total employees = x + y is incomplete for The number of male employees (x) must be equal to the number of female employees (y) to maintain balance. Identify a missing constraint.

move from graph/region language to symbolic constraints.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Translate the region description 'points in the first quadrant on or below the line y = -2x + 8' into inequalities.

Problem 98

Translate the region description 'points above y = x + 1 and left of x = 5' into inequalities.

Problem 99

Translate the region description 'points between y = 2 and y = 6, including both boundaries' into inequalities.

Problem 100

Translate the region description 'points below y = -x + 3 and to the right of x = -2' into inequalities.

Problem 101

Translate the region description 'points in the second quadrant on or above the line y = 3x + 5' into inequalities.

Problem 102

Translate the region description 'points between x = -1 and x = 4, not including the boundaries' into inequalities.

Problem 103

Translate the region description 'points below y = 2x + 1 and above y = x - 3' into inequalities.

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Problem 104

Translate the region description 'points in the third quadrant, including the axes' into inequalities.

Problem 105

Translate the region description 'points to the right of x = 0 and to the left of x = 10, including both boundaries' into inequalities.

Problem 106

Translate the region description 'points above y = -5 and below y = -1' into inequalities.

Problem 107

Translate the region description 'points strictly in the fourth quadrant' into inequalities.

Problem 108

Translate the region description 'points on or above y = -x + 1 and on or to the left of x = 7' into inequalities.

distinguish algebraic solution from real-world viability.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

The point (2.5, 4) satisfies the algebraic constraints, but may be invalid for numbers of tables and chairs. Explain.

Problem 110

The point (-1, 8) satisfies the algebraic constraints, but may be invalid for numbers of items produced. Explain.

Problem 111

The point (12, 3) satisfies the algebraic constraints, but may be invalid for a plan allowing at most 10 workers of type x. Explain.

Problem 112

The point (3.75, 10) satisfies the algebraic constraints, but may be invalid for number of cars in a parking lot. Explain.

Problem 113

The point (5, 0.5) satisfies the algebraic constraints, but may be invalid for number of complete batches of cookies. Explain.

Problem 114

The point (1/3, 7) satisfies the algebraic constraints, but may be invalid for number of students in a class. Explain.

Problem 115

The point (5, -2) satisfies the algebraic constraints, but may be invalid for height of a building. Explain.

Problem 116

The point (-0.5, 10) satisfies the algebraic constraints, but may be invalid for weight of an object. Explain.

Problem 117

The point (-10, 20) satisfies the algebraic constraints, but may be invalid for length of a rope. Explain.

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Problem 118

The point (15, 2) satisfies the algebraic constraints, but may be invalid for a class with a maximum capacity of 12 students. Explain.

Problem 119

The point (7, 200) satisfies the algebraic constraints, but may be invalid for a budget allowing at most $150 for expenses. Explain.

Problem 120

The point (0.5, 1.2) satisfies the algebraic constraints, but may be invalid for a probability value. Explain.

recognize incompatible inequalities or context constraints.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Determine whether the system x >= 8, x <= 5 has any feasible solution. Explain.

Problem 122

Determine whether the system x + y <= 3, x + y >= 7 has any feasible solution. Explain.

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Problem 123

Determine whether the system x >= 0, y >= 0, x + y <= 5 has any feasible solution. Explain.

Problem 124

Determine whether the system x > 7, x < 5 has any feasible solution. Explain.

Problem 125

Determine whether the system x >= 1, x <= 10 has any feasible solution. Explain.

Problem 126

Determine whether the system 2x + y = 5, 2x + y = 8 has any feasible solution. Explain.

Problem 127

Determine whether the system x >= 0, y <= 10 has any feasible solution. Explain.

Problem 128

Determine whether the system x - y > 3, y - x > 0 has any feasible solution. Explain.

Problem 129

Determine whether the system x = 2, y = -1 has any feasible solution. Explain.

Problem 130

Determine whether the system x >= 0, y >= 0, z >= 0, x + y + z = -2 has any feasible solution. Explain.

Problem 131

Determine whether the system x >= 0, y >= 0, z >= 0, x + y + z <= 10 has any feasible solution. Explain.

Problem 132

Determine whether the system x = 5, x > 6 has any feasible solution. Explain.

evaluate candidate points and choose based on context goal.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Use the feasible candidate plans cost=26, name=A, output=7, point=(3,4); cost=24, name=B, output=7, point=(5,2) to choose the better plan for same output at lower cost.

Problem 134

Use the feasible candidate plans name=A, output=8, point=(2,6), time=10; name=B, output=7, point=(4,3), time=9 to choose the better plan for maximum output.

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Problem 135

Use the feasible candidate plans name=A, output=8, point=(1,7), time=12; name=B, output=8, point=(3,5), time=12 to choose the better plan for same output with fewer large items.

Problem 136

Use the feasible candidate plans name=A, output=100, point=(1,1), time=50; name=B, output=100, point=(2,2), time=45 to choose the better plan for same output in less time.

Problem 137

Use the feasible candidate plans cost=150, name=A, point=(3,3), quality=7; cost=150, name=B, point=(4,4), quality=9 to choose the better plan for same cost for higher quality.

Problem 138

Use the feasible candidate plans distance=120, name=A, point=(5,5), speed=60; distance=110, name=B, point=(6,6), speed=60 to choose the better plan for same speed with shorter distance.

Problem 139

Use the feasible candidate plans name=A, output=20, point=(7,7), time=4; name=B, output=27, point=(8,8), time=5 to choose the better plan for higher output per unit time.

Problem 140

Use the feasible candidate plans cost=100, name=A, output=50, point=(8,10); cost=90, name=B, output=50, point=(7,10) to choose the better plan for same output with less of the first resource.

Problem 141

Use the feasible candidate plans cost=75, name=A, point=(2,15), time=10; cost=75, name=B, point=(2,18), time=12 to choose the better plan for same cost for more items of the second type.

Problem 142

Use the feasible candidate plans name=A, output=15, point=(3,4), quality=8; name=B, output=15, point=(2,6), quality=7 to choose the better plan for same output with fewer total items (x+y).

Problem 143

Use the feasible candidate plans cost=30, name=A, point=(1,1), revenue=100; cost=40, name=B, point=(2,2), revenue=120 to choose the better plan for maximum profit.

Problem 144

Use the feasible candidate plans defects=10, name=A, point=(3,3), volume=500; defects=8, name=B, point=(4,4), volume=500 to choose the better plan for same production volume with fewer defects.

convert ratio language into inequality form.
12 problems Warmup Practice Mixed Review Assessment
Problem 145

Write an inequality for the ratio requirement: There must be at least 1 adult for every 8 students, with a adults and s students.

Problem 146

Write an inequality for the ratio requirement: A juice mix must be at least 30 percent concentrate, with c liters concentrate and t total liters.

Problem 147

Write an inequality for the ratio requirement: At most 2 red tiles for every 5 total tiles, with r red tiles and t total tiles.

Problem 148

Write an inequality for the ratio requirement: There must be at least 2 dogs for every 3 cats, with d dogs and c cats.

Problem 149

Write an inequality for the ratio requirement: The number of fiction books must be at most half the number of non-fiction books, with f fiction books and n non-fiction books.

Problem 150

Write an inequality for the ratio requirement: A survey found that at least 60 percent of respondents preferred coffee, with c coffee lovers and r total respondents.

Problem 151

Write an inequality for the ratio requirement: The error rate should be no more than 2 percent, with e errors and t total trials.

Problem 152

Write an inequality for the ratio requirement: The number of successful experiments must be greater than 3 times the number of failed experiments, with s successful and f failed experiments.

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Problem 153

Write an inequality for the ratio requirement: The cost of materials must be less than one-fourth the total budget, with m material cost and b total budget.

Problem 154

Write an inequality for the ratio requirement: For every 5 employees, there should be at least 1 manager, with e employees and m managers.

Problem 155

Write an inequality for the ratio requirement: Less than 10 percent of the population has a certain rare condition, with c people with condition and p total population.

Problem 156

Write an inequality for the ratio requirement: The amount of sugar should be at most two-thirds the amount of flour, with s sugar and f flour.

determine which inequalities do not affect the feasible region.
12 problems Warmup Practice Mixed Review Assessment
Problem 157

In the system x <= 10, x <= 15, x >= 0, identify any redundant constraint and explain why.

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Problem 158

In the system y >= 3, y >= 1, x >= 0, identify any redundant constraint and explain why.

Problem 159

In the system x + y <= 8, x + y <= 10, x >= 0, y >= 0, identify any redundant constraint and explain why.

Problem 160

In the system x >= 5, x >= 2, y <= 10, identify any redundant constraint and explain why.

Problem 161

In the system y <= -2, y <= 0, x >= 0, identify any redundant constraint and explain why.

Problem 162

In the system x - y <= 5, x - y <= 7, x >= 0, identify any redundant constraint and explain why.

Problem 163

In the system 2x >= 10, 2x >= 8, y <= 5, identify any redundant constraint and explain why.

Problem 164

In the system 3y <= 6, 3y <= 9, x >= 0, identify any redundant constraint and explain why.

Problem 165

In the system x + 2y >= 10, x + 2y >= 5, x <= 10, identify any redundant constraint and explain why.

Problem 166

In the system x <= -5, x <= -3, y >= 0, identify any redundant constraint and explain why.

Problem 167

In the system y >= -1, y >= -4, x <= 0, identify any redundant constraint and explain why.

Problem 168

In the system x + y >= 12, x + y >= 10, x >= 0, y >= 0, identify any redundant constraint and explain why.

describe all possible solutions, not just one point.
12 problems Warmup Practice Mixed Review Assessment
Problem 169

Explain what the feasible region for 3x + 2y <= 30, x >= 0, y >= 0 means in the context buying x notebooks and y pens with 30 dollars.

Problem 170

Explain what the feasible region for 2x + 5y <= 40, x + y >= 10, x >= 0, y >= 0 means in the context making x small posters and y large posters.

Problem 171

Explain what the feasible region for 4x + 6y >= 48, x + y <= 14, x >= 0, y >= 0 means in the context selling x sandwiches and y salads while meeting a revenue minimum and item limit.

Problem 172

Explain what the feasible region for x + y <= 10, 3x + 2y <= 24, x >= 0, y >= 0 means in the context baking x cakes and y pies with limited flour and sugar.

Problem 173

Explain what the feasible region for x + y >= 5, x <= 8, y <= 7, x >= 0, y >= 0 means in the context a factory producing x small widgets and y large widgets daily.

Problem 174

Explain what the feasible region for 10x + 5y <= 100, x + y >= 12, x >= 0, y >= 0 means in the context purchasing x books and y magazines with 100 dollars, needing at least 12 items.

Problem 175

Explain what the feasible region for 2x + y <= 16, x + 3y <= 20, x >= 0, y >= 0 means in the context a craftsman making x wooden chairs and y wooden tables.

Problem 176

Explain what the feasible region for 50x + 100y >= 500, 10x + 5y >= 60, x >= 0, y >= 0 means in the context planning a meal with x servings of food A and y servings of food B.

Problem 177

Explain what the feasible region for x + y <= 10000, x >= 1000, y >= 2000, x >= 0, y >= 0 means in the context investing x dollars in stock A and y dollars in stock B.

Problem 178

Explain what the feasible region for x + y <= 500, 2x + y <= 800, x >= 0, y >= 0 means in the context loading a truck with x boxes of type A and y boxes of type B.

Problem 179

Explain what the feasible region for x + y >= 100, 15x + 20y <= 2000, x >= 0, y >= 0 means in the context planning a party with x adult guests and y child guests.

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Problem 180

Explain what the feasible region for x + y <= 30, 100x + 50y >= 1500, x >= 0, y >= 0 means in the context running an advertising campaign with x TV ads and y radio ads.