Math I · A-REI.10

Understanding a Graph as the Set of All Solutions to a Two-Variable Equation

Seeing a graph as a solution set helps students understand that a line or curve is not a decoration; it is every possible input-output pair that makes a statement true.

Concept Algebra
Domain Reasoning with Equations and Inequalities
Read time 11 minutes

What this learning objective is really asking you to learn

This objective is about one of the most important translations in all of mathematics: the translation between an equation and a picture. When you see an equation like \(y = 2x + 3\), it is tempting to think of it as a rule for calculating y-values. That is true, but it is not the full idea. The deeper idea is that the equation describes a whole collection of ordered pairs \((x, y)\) that make the statement true. The graph is not a drawing that merely decorates the equation. The graph is the visual form of the solution set.

An ordered pair is a pair of numbers written in a specific order, such as \((4, 11)\). In the coordinate plane, the first number tells how far to move horizontally, and the second tells how far to move vertically. For the equation \(y = 2x + 3\), the pair \((4, 11)\) is a solution because substituting \(x = 4\) gives \(y = 2(4) + 3 = 11\). The pair \((4, 10)\) is not a solution because 10 is not equal to \(2(4) + 3\). The graph of \(y = 2x + 3\) is the set of every point whose coordinates pass this test.

This sounds simple, but it changes the meaning of graphing. Graphing is not just plotting a few points and drawing a line because the teacher said so. Graphing is representing an infinite collection of solutions in a way the eye can understand. A line is not just a mark on paper. It is a compressed image of infinitely many number pairs. Each point on the line is a true statement. Each point off the line is a false statement for that equation.

The same idea works beyond lines. The equation \(y = x^2\) has a graph shaped like a parabola. The equation \(x^2 + y^2 = 25\) has a graph shaped like a circle. The equation \(y = 2^x\) has a graph shaped like exponential growth. The shapes differ, but the meaning is the same: the graph is the set of ordered-pair solutions. Every point on the graph makes the equation true. Every point not on the graph does not.

In Integrated Math I, the main focus is usually on linear and exponential relationships, with the idea being learned as a general principle. That general principle is the real treasure. You are learning that algebra and geometry are not separate worlds. Algebra gives symbols. Geometry gives shape. The coordinate plane lets them speak to each other.

Why students should learn this math

Students often ask, “Why do I need to graph this?” A strong answer is that graphs let human beings see relationships that would be hard to understand from numbers alone. A table gives sample values. An equation gives a rule. A graph gives the shape of the entire relationship. It shows direction, steepness, intercepts, trends, boundaries, and unusual behavior. It turns a relationship into something your visual system can process.

Think about a phone battery. The equation might estimate battery percentage as a function of time. A table might show the battery after 1 hour, 2 hours, and 3 hours. But the graph immediately shows whether the battery drains steadily, suddenly drops, levels off, or reaches zero before the day ends. That visual information helps a person make a decision. Should I charge now? Can I make it through the trip? Is something wrong with the device?

A graph of solutions is also one of the foundations of modeling. If a business models revenue with \(R = 20t\), where \(t\) is the number of tickets sold and \(R\) is revenue, then every point on the line represents a possible sales situation. \((10, 200)\) means 10 tickets produce $200. \((50, 1000)\) means 50 tickets produce $1,000. The line is a map of all possible outcomes under that model. If the actual data points do not fall near the line, the model may be wrong. That is how equations and real life argue with each other.

This matters in nearly every technical field. In physics, a position-time graph represents possible states of motion. In economics, a supply or demand curve represents combinations of quantity and price. In medicine, a graph might show concentration of a drug in the bloodstream over time. In engineering, a stress-strain graph shows how materials respond to force. In computer graphics, equations define curves and surfaces. In climate science, graphs represent relationships among temperature, carbon dioxide, time, location, and energy. In app design, graphs can show user growth, retention, and revenue.

The reason this objective is so important is that graphs protect you from treating algebra as symbol manipulation only. A student can solve for \(y\), plug in values, and still not understand what the equation is saying. The graph forces a bigger question: what does the entire set of solutions look like? Is it increasing or decreasing? Does it cross an axis? Are all values possible? Does the relationship make sense in context? If the equation describes the height of a ball, negative time may appear algebraically but make no real-world sense. If the equation describes cost, negative dollars may or may not be meaningful depending on whether a refund or profit is involved. The graph makes these questions visible.

There is also a mental benefit. When students understand that a graph is a solution set, they stop thinking of math as a pile of isolated procedures. Plotting points, checking solutions, finding intercepts, building tables, and interpreting equations become parts of one idea. A graph is not a separate assignment after algebra. It is algebra seen through space.

The historical machinery: how equations became pictures

For much of human history, arithmetic, geometry, and algebra developed as related but partly separate activities. Geometry grew from measuring land, constructing buildings, studying shapes, and proving relationships among points, lines, angles, and circles. Algebra grew from solving problems involving unknown numbers. Both were powerful, but they were not always written in one common language.

A huge turning point came with analytic geometry, often associated with René Descartes and Pierre de Fermat in the seventeenth century. The basic move was revolutionary: place a coordinate system on a plane, then use numbers to describe points. Once a point could be represented by an ordered pair, a geometric shape could be represented by an equation. A line, circle, or curve was no longer only a drawn object; it could be encoded symbolically.

This was one of the great unifications in mathematics. Before coordinates, geometry often depended on diagrams and pure spatial reasoning. After coordinates, geometric problems could be attacked with algebra. If you wanted to know where two curves met, you could solve equations. If you wanted to prove something about a shape, you could assign coordinates and compute. If you wanted to create a curve, you could write an equation and plot its solutions.

This bridge between algebra and geometry eventually became essential to calculus. Calculus asks questions about changing quantities: slope at a point, area under a curve, accumulation over time, and motion through space. Those ideas depend heavily on graphs of equations and functions. Later, the same bridge became essential to physics, engineering, computer animation, statistics, machine learning, navigation, robotics, and almost every science that uses mathematical models.

The coordinate plane is easy to take for granted because students meet it early. But it is one of the most powerful inventions in intellectual history. It lets a line be both a geometric object and a set of solutions. It lets a circle be both a shape and an equation like \((x - h)^2 + (y - k)^2 = r^2\). It lets a data cloud be compared to a model. It turns visual space into numerical structure.

When you understand that a graph is the set of all solutions, you are participating in this historical unification. You are not just learning how to draw a line. You are learning the language that made modern science mathematical.

Where this fits in the big map of mathematics

This objective sits at a central crossroads. On one side is algebra: variables, equations, substitution, and solution sets. On another side is geometry: points, lines, curves, distance, and space. On another side is functions: input-output relationships and how quantities change together. On another side is statistics: data displayed in a coordinate plane and compared with models.

A two-variable equation is one of the first places where students meet a solution set that is not just a single number. In a one-variable equation such as \(2x + 3 = 11\), the solution might be \(x = 4\). That is one number. In a two-variable equation such as \(y = 2x + 3\), there are infinitely many solutions: \((0, 3)\), \((1, 5)\), \((2, 7)\), \((10, 23)\), and so on. The graph gives shape to that infinity.

This idea later grows into systems of equations. If one equation produces one graph, then two equations produce two graphs. The solution to the system is where both graphs are true at once. For two lines, that may be one intersection point. For a line and a parabola, it may be zero, one, or two points. For two identical lines, it may be infinitely many points. This is why the graph-as-solution-set idea must be clear before systems make full sense.

It also grows into inequalities. The graph of a two-variable inequality is not usually a line but a region. The boundary line marks where equality holds, and one side of the line contains the points that satisfy the inequality. That idea is objective 8 in this batch. Without understanding that points can be solutions, half-plane regions seem like shading rules. With this objective, they become logical solution sets.

Later, in calculus, the graph of an equation or function becomes a landscape of change. Slope becomes rate of change. Area becomes accumulation. Intersections become solutions to equations. Tangents become local linear approximations. In linear algebra, solution sets become lines, planes, and higher-dimensional spaces. In optimization, feasible regions become places where solutions are allowed. The simple act of seeing a graph as all ordered-pair solutions is the doorway to a much larger map.

How to execute the skill technically

The technical skill begins with substitution. Given an equation in two variables, you should be able to test whether a point is a solution. For example, for \(3x - 2y = 8\), test \((4, 2)\): \(3(4) - 2(2) = 12 - 4 = 8\), so \((4, 2)\) is a solution. Test \((2, 1)\): \(3(2) - 2(1) = 6 - 2 = 4\), not 8, so \((2, 1)\) is not a solution. Every graphing idea rests on this truth test.

Next, you should be able to generate points. If the equation is written as \(y = 2x - 5\), choose x-values and calculate y-values. If \(x = 0\), then \(y = -5\); if \(x = 3\), then \(y = 1\); if \(x = 5\), then \(y = 5\). Plot those ordered pairs and look for the pattern. For a linear equation, two points determine the line, though a third point is useful for checking. For a nonlinear equation, more points may be needed to see the shape.

You should also understand intercepts. The y-intercept is where the graph crosses the y-axis, so \(x = 0\). The x-intercept is where the graph crosses the x-axis, so \(y = 0\). Intercepts are not just graph features. They are solution pairs with one coordinate equal to zero. If \(y = 2x - 5\), then the y-intercept is \((0, -5)\). The x-intercept comes from \(0 = 2x - 5\), so \(x = 2.5\), giving \((2.5, 0)\). In a context, these may have real meanings: initial value, break-even point, starting amount, zero height, empty tank, or no cost.

Scale matters. A graph is only useful if the axes are chosen responsibly. If one square represents 1 unit on one graph and 100 units on another, the same relationship can look very different. A student who understands graphs as solution sets knows that the scale does not change which points are solutions, but it does change how easily the solution set can be read. Poor scales can hide important features.

Domain and context also matter. Algebraically, \(y = 2x + 3\) allows every real x-value. But if \(x\) represents the number of tickets sold, negative x-values are not meaningful. If tickets must be whole numbers, only integer x-values make sense. A real-world graph may be a set of separate points even when the algebraic model is drawn as a continuous line. This is a subtle but important distinction. The mathematical equation may be continuous, but the context may restrict which points are viable.

Finally, you should be able to explain the graph in words. A good explanation might say: “This line shows every combination of hours and earnings that satisfies the pay rule. Points on the line are possible under the model. Points above the line would mean earning more than the model predicts. Points below the line would mean earning less.” That explanation proves that you understand the graph as a set of solutions, not just a picture.

A worked example: cost as a graph of solutions

Suppose a gym charges a $25 sign-up fee plus $15 per month. Let \(m\) be the number of months and \(C\) be the total cost in dollars. The equation is \(C = 15m + 25\).

The ordered pair \((0, 25)\) is a solution because before any monthly payments, the sign-up fee is $25. The pair \((3, 70)\) is a solution because \(15(3) + 25 = 70\). The pair \((3, 75)\) is not a solution because the model says 3 months should cost $70, not $75.

The graph of this equation is the set of all points \((m, C)\) that satisfy the rule. In pure algebra, the graph is a line. In the real context, it may make sense to show only whole-number months: 0, 1, 2, 3, and so on. If the gym bills by full months, \((2.5, 62.50)\) may not be a possible billing state even though it lies on the continuous line. This is exactly why interpreting the graph matters.

The line rises because cost increases as months increase. The y-intercept is 25, which represents the initial sign-up fee. The slope is 15, which represents the monthly charge. The graph is a visual map of the payment rule.

Common mistakes and how to avoid them

A common mistake is thinking that only the points you plotted are solutions. If you plot three points on a line, those points are examples. The full line represents all solutions. Another common mistake is treating points off the line as “near enough.” In measurement or data modeling, near a line may mean a model fits reasonably well. But for an exact equation, a point either satisfies the equation or it does not.

Students also sometimes reverse coordinates. The point \((2, 7)\) is not the same as \((7, 2)\). In a real situation, reversing coordinates may completely change the meaning. Two hours and seven dollars is not the same as seven hours and two dollars.

Another mistake is ignoring units and axis labels. A graph without labels is a shape without a story. If \(x\) is time in hours and \(y\) is distance in miles, the slope has units of miles per hour. If \(x\) is items and \(y\) is dollars, the slope has units of dollars per item. Units turn graph features into meaning.

The biggest mistake is believing that graphing is separate from solving. It is not. A graph is a solution set. Every time you graph an equation, you are solving it in a visual form.

What students should be able to say

A student who has mastered this objective should be able to say: “The graph of a two-variable equation is all the ordered pairs that make the equation true. I can test a point by substituting its coordinates. I can create points by choosing one variable and calculating the other. I understand that points on the graph are solutions and points off the graph are not. I can explain what the graph means in context, including the meaning of intercepts, slope, axis labels, scale, and any restrictions from the real situation.”

That is a major step. It means the student is no longer just drawing graphs. The student is reading equations as maps.

Problem Library

Problems in the App From This Objective

144 problems across 12 archetypes in the app.

substitute x and y.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Does the ordered pair (4,14) satisfy the equation y = 3x + 2? Show substitution.

Problem 2

Does the ordered pair (3,4) satisfy the equation 2x + y = 9? Show substitution.

Problem 3

Does the ordered pair (-2,7) satisfy the equation y = -x + 5? Show substitution.

Problem 4

Does the ordered pair (5,9) satisfy the equation y = 2x - 1? Show substitution.

Problem 5

Does the ordered pair (2,0) satisfy the equation 3x - y = 7? Show substitution.

Problem 6

Does the ordered pair (-3,9) satisfy the equation y = x^2? Show substitution.

Problem 7

Does the ordered pair (4,2) satisfy the equation x + 2y = 10? Show substitution.

Problem 8

Does the ordered pair (1,-4) satisfy the equation y = -4x? Show substitution.

Problem 9

Does the ordered pair (4,6) satisfy the equation y = 1/2 x + 3? Show substitution.

Problem 10

Does the ordered pair (7,7) satisfy the equation x - y = 0? Show substitution.

Problem 11

Does the ordered pair (6,0) satisfy the equation y = x/3 - 1? Show substitution.

Open in simulator
Problem 12

Does the ordered pair (-1,3) satisfy the equation 5x + 2y = 1? Show substitution.

compute outputs and form pairs.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Generate 3 ordered-pair solutions for y = 2x + 1 using the input values -1, 0, 2.

Problem 14

Generate 3 ordered-pair solutions for y = -3x + 4 using the input values 0, 1, 3.

Problem 15

Generate 3 ordered-pair solutions for x + y = 6 using the input values 0, 2, 5.

Problem 16

Generate 3 ordered-pair solutions for y = x - 5 using the input values 0, 5, 10.

Problem 17

Generate 3 ordered-pair solutions for y = 4x using the input values -1, 0, 1.

Problem 18

Generate 3 ordered-pair solutions for y = -x + 7 using the input values 1, 7, -2.

Problem 19

Generate 3 ordered-pair solutions for 2x + y = 8 using the input values 0, 4, 1.

Open in simulator
Problem 20

Generate 3 ordered-pair solutions for y = (1/2)x + 3 using the input values -2, 0, 4.

Problem 21

Generate 3 ordered-pair solutions for y = -5x - 2 using the input values -1, 0, 1.

Problem 22

Generate 3 ordered-pair solutions for 3x - y = 9 using the input values 0, 3, 1.

Problem 23

Generate 3 ordered-pair solutions for y = x/3 + 2 using the input values -3, 0, 6.

Problem 24

Generate 3 ordered-pair solutions for y = 6 - x using the input values -1, 3, 6.

connect graph to solution set.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Explain why every point on the graph of y = 2x + 3 is a solution to the equation.

Problem 26

Explain why every point on the graph of x + y = 10 is a solution to the equation.

Problem 27

Explain why every point on the graph of y = -x + 4 is a solution to the equation.

Problem 28

Explain why every point on the graph of y = x is a solution to the equation.

Problem 29

Explain why every point on the graph of y = 5 is a solution to the equation.

Problem 30

Explain why every point on the graph of x = -2 is a solution to the equation.

Problem 31

Explain why every point on the graph of 2x - y = 7 is a solution to the equation.

Problem 32

Explain why every point on the graph of y = (1/2)x - 1 is a solution to the equation.

Open in simulator
Problem 33

Explain why every point on the graph of y = -3x is a solution to the equation.

Problem 34

Explain why every point on the graph of 3x + 2y = 6 is a solution to the equation.

Problem 35

Explain why every point on the graph of y = 4x - 2 is a solution to the equation.

Problem 36

Explain why every point on the graph of x + 2y = 4 is a solution to the equation.

distinguish points on/off the graph.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

From the points (0,2), (3,5), and (4,7), identify which listed points are not solutions of y = x + 2.

Problem 38

From the table rows (1,6), (2,4), and (3,1), identify which listed points are not solutions of 2x + y = 8.

Problem 39

From the points (-1,2), (0,0), and (2,3), identify which listed points are not solutions of y = -2x.

Problem 40

From the points (1,2), (2,5), and (3,7), identify which listed points are not solutions of y = 3x - 1.

Problem 41

From the points (5,5), (4,6), and (3,8), identify which listed points are not solutions of x + y = 10.

Open in simulator
Problem 42

From the points (0,5), (1,4), and (2,2), identify which listed points are not solutions of y = -x + 5.

Problem 43

From the table rows (2,-1), (3,2), and (4,4), identify which listed points are not solutions of 3x - y = 7.

Problem 44

From the points (2,2), (4,3), and (6,3), identify which listed points are not solutions of y = x/2 + 1.

Problem 45

From the points (1,4), (2,3), and (3,1), identify which listed points are not solutions of y = 5 - x.

Problem 46

From the points (0,0), (1,4), and (2,9), identify which listed points are not solutions of y = 4x.

Problem 47

From the table rows (1,1), (2,2), and (3,4), identify which listed points are not solutions of x - y = 0.

Problem 48

From the points (0,4), (3,2), and (6,1), identify which listed points are not solutions of 2x + 3y = 12.

verify multiple pairs.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Choose which table matches the equation y = 4x + 1: A=(0,1), (1,5), (2,9), B=(0,4), (1,5), (2,6).

Problem 50

Choose which table matches the equation y = 10 - 2x: A=(0,10), (1,8), (3,4), B=(0,8), (1,10), (3,16).

Problem 51

Choose which table matches the equation x + y = 7: A=(1,6), (2,5), (5,2), B=(1,7), (2,7), (5,7).

Problem 52

Choose which table matches the equation y = 3x: A=(0,0), (1,3), (2,6), B=(0,3), (1,4), (2,5).

Problem 53

Choose which table matches the equation y = x + 5: A=(0,5), (1,6), (3,8), B=(0,0), (1,5), (3,15).

Open in simulator
Problem 54

Choose which table matches the equation y = -x + 2: A=(0,2), (1,1), (2,0), B=(0,2), (1,3), (2,4).

Problem 55

Choose which table matches the equation y = 2x - 1: A=(0,0), (1,1), (2,3), B=(0,-1), (1,1), (2,3).

Problem 56

Choose which table matches the equation y = 5: A=(0,5), (1,5), (2,5), B=(0,0), (1,5), (2,10).

Problem 57

Choose which table matches the equation 2x + y = 10: A=(0,10), (1,9), (2,8), B=(0,10), (1,8), (2,6).

Problem 58

Choose which table matches the equation y = x/2 + 1: A=(0,1), (2,2), (4,3), B=(0,1), (1,1.5), (2,3).

Problem 59

Choose which table matches the equation y = -3x - 2: A=(0,-2), (1,-5), (2,-7), B=(0,-2), (1,-5), (2,-8).

Problem 60

Choose which table matches the equation y = 5x - 3: A=(0,-3), (1,2), (2,7), B=(0,-3), (1,3), (2,8).

connect symbolic and visual representations.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Match the equation to the graph features: slope 2 and y-intercept 3.

Problem 62

Match the equation to the graph features: y-intercept -4 and slope -1.

Problem 63

Match the equation to the graph features: x-intercept 5 and y-intercept 10.

Problem 64

Match the equation to the graph features: slope 3 and y-intercept 5.

Problem 65

Match the equation to the graph features: y-intercept 7 and slope -2.

Problem 66

Match the equation to the graph features: slope 1 and y-intercept -6.

Problem 67

Match the equation to the graph features: slope 0 and y-intercept 8.

Problem 68

Match the equation to the graph features: x-intercept 2 and y-intercept 6.

Problem 69

Match the equation to the graph features: x-intercept -3 and y-intercept 9.

Open in simulator
Problem 70

Match the equation to the graph features: x-intercept 4 and y-intercept -8.

Problem 71

Match the equation to the graph features: slope -5 and y-intercept -1.

Problem 72

Match the equation to the graph features: y-intercept 0 and slope 4.

attach meaning and units to x and y.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

In the context C = 6n gives total cost C in dollars for n sandwiches, interpret the ordered-pair solution (4,24).

Problem 74

In the context h = 50 - 5t gives height h in gallons after t minutes of draining, interpret the ordered-pair solution (6,20).

Open in simulator
Problem 75

In the context d = 30t gives distance d in miles after t hours, interpret the ordered-pair solution (3,90).

Problem 76

In the context T = 20 + 3h gives temperature T in degrees Celsius after h hours, interpret the ordered-pair solution (5,35).

Problem 77

In the context A = 1000 - 50w gives amount A in milliliters of medicine remaining after w weeks, interpret the ordered-pair solution (10,500).

Problem 78

In the context R = 15x gives total revenue R in dollars for selling x items, interpret the ordered-pair solution (7,105).

Problem 79

In the context F = 1.8C + 32 gives temperature F in Fahrenheit for C degrees Celsius, interpret the ordered-pair solution (20,68).

Problem 80

In the context V = 200 - 25m gives volume V in liters of water in a tank after m minutes, interpret the ordered-pair solution (4,100).

Problem 81

In the context E = 0.5k gives energy E in joules stored in a spring with displacement k in meters, interpret the ordered-pair solution (10,5).

Problem 82

In the context P = 1000 + 50t gives population P of a town after t years, interpret the ordered-pair solution (8,1400).

Problem 83

In the context W = 7.5h gives total wages W in dollars for working h hours, interpret the ordered-pair solution (12,90).

Problem 84

In the context B = 500 - 20d gives bank balance B in dollars after d days, interpret the ordered-pair solution (15,200).

reason about constant x or constant y.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Explain the solution set of the line x = 4 in coordinate terms.

Problem 86

Explain the solution set of the line y = -2 in coordinate terms.

Problem 87

Explain the solution set of the line x = 0 in coordinate terms.

Problem 88

Explain the solution set of the line y = 5 in coordinate terms.

Problem 89

Explain the solution set of the line x = -3 in coordinate terms.

Problem 90

Explain the solution set of the line y = 1/2 in coordinate terms.

Open in simulator
Problem 91

Explain the solution set of the line x = 2.5 in coordinate terms.

Problem 92

Explain the solution set of the line y = -10 in coordinate terms.

Problem 93

Explain the solution set of the line x = 1 in coordinate terms.

Problem 94

Explain the solution set of the line y = 0 in coordinate terms.

Problem 95

Explain the solution set of the line x = -1/4 in coordinate terms.

Problem 96

Explain the solution set of the line y = 7.5 in coordinate terms.

infer the shared relationship from points.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Find an equation that fits the plotted solution points (0,2), (1,5), (2,8).

Problem 98

Find an equation that fits the plotted solution points (0,6), (2,2), (3,0).

Problem 99

Find an equation that fits the plotted solution points (1,1), (2,4), (3,9).

Problem 100

Find an equation that fits the plotted solution points (0,0), (1,3), (2,6).

Problem 101

Find an equation that fits the plotted solution points (0,10), (1,8), (2,6).

Problem 102

Find an equation that fits the plotted solution points (0,-1), (1,1), (2,3).

Open in simulator
Problem 103

Find an equation that fits the plotted solution points (0,1), (1,2), (2,5).

Problem 104

Find an equation that fits the plotted solution points (0,0), (1,2), (2,8).

Problem 105

Find an equation that fits the plotted solution points (0,5), (1,5), (2,5).

Problem 106

Find an equation that fits the plotted solution points (0,4), (2,0), (4,-4).

Problem 107

Find an equation that fits the plotted solution points (1,0), (2,3), (3,8).

Problem 108

Find an equation that fits the plotted solution points (0,0), (1,1), (2,2).

test all rows and locate violations.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Determine whether every row in (0,1), (2,5), (3,8) is a solution to y = 2x + 1. If not, locate the violation.

Problem 110

Determine whether every row in (1,8), (4,5), (6,3) is a solution to x + y = 9. If not, locate the violation.

Problem 111

Determine whether every row in (0,4), (2,2), (5,0) is a solution to y = -x + 4. If not, locate the violation.

Problem 112

Determine whether every row in (0,0), (1,1), (2,4) is a solution to y = 3x - 2. If not, locate the violation.

Problem 113

Determine whether every row in (0,3), (2,4), (4,5) is a solution to y = x/2 + 3. If not, locate the violation.

Problem 114

Determine whether every row in (3,1), (2,0), (4,3) is a solution to 2x - y = 5. If not, locate the violation.

Problem 115

Determine whether every row in (0,7), (1,5), (3,1) is a solution to y = -2x + 7. If not, locate the violation.

Problem 116

Determine whether every row in (6,0), (9,1), (3,1) is a solution to x - 3y = 6. If not, locate the violation.

Problem 117

Determine whether every row in (0,0), (1,5), (2,10) is a solution to y = 5x. If not, locate the violation.

Problem 118

Determine whether every row in (0,5), (2,3), (4,0) is a solution to 3x + 2y = 12. If not, locate the violation.

Problem 119

Determine whether every row in (5,0), (6,1), (10,5) is a solution to y = x - 5. If not, locate the violation.

Open in simulator
Problem 120

Determine whether every row in (1,0), (0,-1), (-1,0) is a solution to y = -x - 1. If not, locate the violation.

distinguish drawn sample points from complete solution set.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Explain why the graph of y = x + 1 contains infinitely many solutions, even if only some points are labeled.

Problem 122

Explain why the graph of y = 2x contains infinitely many solutions, even if only some points are labeled.

Problem 123

Explain why the graph of x + y = 5 contains infinitely many solutions, even if only some points are labeled.

Problem 124

Explain why the graph of y = 3x - 2 contains infinitely many solutions, even if only some points are labeled.

Open in simulator
Problem 125

Explain why the graph of y = -x + 4 contains infinitely many solutions, even if only some points are labeled.

Problem 126

Explain why the graph of 2x - y = 1 contains infinitely many solutions, even if only some points are labeled.

Problem 127

Explain why the graph of y = 1/2 x + 3 contains infinitely many solutions, even if only some points are labeled.

Problem 128

Explain why the graph of y = 5 contains infinitely many solutions, even if only some points are labeled.

Problem 129

Explain why the graph of x = -2 contains infinitely many solutions, even if only some points are labeled.

Problem 130

Explain why the graph of y = -3x contains infinitely many solutions, even if only some points are labeled.

Problem 131

Explain why the graph of 3x + 2y = 6 contains infinitely many solutions, even if only some points are labeled.

Problem 132

Explain why the graph of y = x contains infinitely many solutions, even if only some points are labeled.

verify consistency across representations.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Show that the equation y = 2x + 3, table (0,3), (1,5), (2,7), and graph feature slope 2 and y-intercept 3 represent the same solution set.

Problem 134

Show that the equation y = -x + 6, table (0,6), (2,4), (5,1), and graph feature slope -1 and y-intercept 6 represent the same solution set.

Problem 135

Show that the equation y = 3x - 2, table (0,-2), (1,1), (2,4), and graph feature slope 3 and y-intercept -2 represent the same solution set.

Problem 136

Show that the equation y = x + 1, table (0,1), (1,2), (2,3), and graph feature slope 1 and y-intercept 1 represent the same solution set.

Open in simulator
Problem 137

Show that the equation y = -2x + 4, table (0,4), (1,2), (2,0), and graph feature slope -2 and y-intercept 4 represent the same solution set.

Problem 138

Show that the equation y = 0.5x, table (0,0), (2,1), (4,2), and graph feature slope 0.5 and y-intercept 0 represent the same solution set.

Problem 139

Show that the equation y = -3x - 1, table (0,-1), (1,-4), (-1,2), and graph feature slope -3 and y-intercept -1 represent the same solution set.

Problem 140

Show that the equation y = x - 5, table (0,-5), (5,0), (1,-4), and graph feature slope 1 and y-intercept -5 represent the same solution set.

Problem 141

Show that the equation y = 4x, table (0,0), (1,4), (-1,-4), and graph feature slope 4 and y-intercept 0 represent the same solution set.

Problem 142

Show that the equation y = -0.5x + 3, table (0,3), (2,2), (4,1), and graph feature slope -0.5 and y-intercept 3 represent the same solution set.

Problem 143

Show that the equation y = 2x - 4, table (0,-4), (1,-2), (2,0), and graph feature slope 2 and y-intercept -4 represent the same solution set.

Problem 144

Show that the equation y = -x - 2, table (0,-2), (1,-3), (-1,-1), and graph feature slope -1 and y-intercept -2 represent the same solution set.