Math I · A-REI.11

Solving `f(x) = g(x)` by Finding Intersections of Graphs and Tables

Intersections explain break-even points, equal outcomes, and moments when two models agree, even when exact symbolic solving is difficult or unnecessary.

Concept Algebra
Domain Reasoning with Equations and Inequalities
Read time 11 minutes

What this learning objective is really asking you to learn

This objective is about recognizing that an equation can be solved by comparing two relationships. The equation \(f(x) = g(x)\) asks for the input values where two functions produce the same output. If you graph \(y = f(x)\) and \(y = g(x)\), the solutions are the x-coordinates of the points where the two graphs intersect. At an intersection, the two functions have the same x-value and the same y-value. That is exactly what equality means.

For example, suppose \(f(x) = 2x + 5\) and \(g(x) = 17\). Solving \(2x + 5 = 17\) can be seen as finding where the line \(y = 2x + 5\) reaches the horizontal line \(y = 17\). Algebra gives \(x = 6\). Graphically, the two lines intersect at \((6, 17)\). The x-coordinate, 6, is the solution to the equation. The y-coordinate, 17, is the common value of the two expressions at that solution.

This idea becomes more powerful when exact algebra is difficult or impossible. Consider \(2^x = x + 10\). There is no simple middle-school style inverse operation that solves this neatly. But you can graph \(y = 2^x\) and \(y = x + 10\), then look for where they cross. You can make a table and narrow the interval. You can use technology to approximate the intersection. The answer may not be a clean integer, but it can still be found and interpreted.

The objective is not saying that algebra is unnecessary. It is saying that solving has multiple representations. You can solve symbolically, graphically, numerically, and contextually. A symbolic solution manipulates expressions. A graphical solution finds intersections. A numerical solution uses tables or approximation. A contextual solution explains what the equality means in the real situation. Strong mathematical thinking moves among all of these.

This objective also teaches the meaning of the word “approximately.” Not every answer in real modeling is exact. Sometimes the best answer is “about 4.83,” or “between 12 and 13 months,” or “near 7.2 seconds.” In advanced work, numerical approximation is not a weakness. It is a major part of how modern mathematics, science, and engineering actually operate.

Why students should learn this math

A huge number of real-life questions are comparison questions. When will two phone plans cost the same? When will two runners be at the same distance? When will a savings account reach a target balance? When will a population model pass a certain threshold? When does the height of a thrown ball equal the height of a balcony? When does revenue equal cost? When does one investment become better than another? These are all \(f(x) = g(x)\) questions.

Students often see equations as isolated symbol puzzles, but equality is usually a meeting point. It is the point where two descriptions agree. If one function describes money earned and another describes money spent, their intersection is a break-even point. If one function describes distance traveled by one car and another describes distance traveled by another car, their intersection is a meeting point. If one function describes the amount of medicine in the body and another describes a minimum effective level, their intersection is a threshold time. If one function describes demand and another describes supply, their intersection is an equilibrium.

This is a major reason to learn the objective. It turns equation solving into a tool for comparison and decision-making. A business owner does not care about solving \(12x + 500 = 20x\) because the symbols look interesting. They care because it may tell them how many units must be sold before revenue covers startup cost. A student choosing between two subscription plans does not care about intersections as a graphing exercise. They care because the intersection shows the usage level where the cheaper plan changes.

This objective is also important because many real models are not linear. The world often grows, decays, bends, oscillates, saturates, or behaves in pieces. Exact symbolic methods work beautifully for many equations, but not all. Modern mathematics depends heavily on numerical and graphical methods because real problems do not always produce neat textbook equations. Weather models, epidemiology models, traffic simulations, machine learning systems, engineering designs, and financial models often require approximation.

Learning to solve by intersection gives students a more honest view of mathematics. It says: math is not only about getting perfect answers from perfect equations. Math is also about locating answers, estimating carefully, checking error, and interpreting results in context. A student who can approximate an intersection understands that math can still be useful when the numbers are messy.

There is another benefit: graphical solving builds intuition. If an equation has no solution, the graphs do not intersect. If it has one solution, they cross once. If it has two, three, or many solutions, the picture can reveal that. Algebraic manipulation sometimes hides the big picture. A graph shows the entire relationship at once.

The historical machinery: from exact solving to numerical thinking

For centuries, a major goal of algebra was to find exact solutions. Mathematicians developed methods for solving linear equations, quadratic equations, cubic equations, and quartic equations. The quadratic formula is one of the famous successes of symbolic algebra: every quadratic equation can be solved by a general formula. Later mathematicians discovered something surprising and humbling: there is no general formula using ordinary radicals for every fifth-degree polynomial. This did not make polynomial equations useless. It showed that exact symbolic formulas are only one part of mathematics.

At the same time, scientists and engineers needed answers to problems that did not have neat exact forms. Astronomy, navigation, mechanics, architecture, and later electricity and thermodynamics required calculation. People built tables of values, used geometric diagrams, and developed approximation methods. The rise of calculus expanded this need. Equations involving motion, change, and accumulation often had to be solved approximately.

Isaac Newton's name is often connected to a powerful approximation method now called Newton's method. The basic idea is to use local linear behavior to improve a guess for a solution. Even if students do not learn Newton's method in Integrated Math I, they are learning the beginning of the same worldview: a solution can be approached, refined, and estimated. Tables, graphs, and technology are not shortcuts around mathematics. They are part of mathematical machinery.

The invention of computers transformed this even further. Computers do not “understand” equations the way people do, but they can calculate enormous tables of values, search intervals, plot graphs, and approximate intersections quickly. Modern numerical methods support aircraft design, medical imaging, weather prediction, cryptography, animation, economics, and artificial intelligence. In many of these fields, the answer is not a beautiful exact number. It is an approximation with known accuracy.

This objective is the school-level doorway into computational mathematics. Finding an intersection on a graph or in a table may seem basic, but the underlying idea is profound: to solve an equation, compare two quantities and locate where their difference becomes zero. In advanced notation, solving \(f(x) = g(x)\) is the same as solving \(h(x) = 0\), where \(h(x) = f(x) - g(x)\). That one idea links graphing, algebra, numerical methods, and computation.

Where this fits in the big map of mathematics

This objective sits directly between algebra, functions, graphing, and modeling. Algebra asks you to manipulate equations. Functions ask you to understand relationships between inputs and outputs. Graphing shows those relationships visually. Modeling uses the relationships to describe the world. Solving \(f(x) = g(x)\) by intersections connects all four.

It also prepares students for systems of equations. A system is essentially a request to find values that satisfy more than one relationship at the same time. When two graphs intersect, the intersection point satisfies both equations. In Integrated Math I, students often solve systems of linear equations. The intersection method is the visual heart of systems.

It prepares students for nonlinear work in Math II and Math III. A line and a parabola can intersect in zero, one, or two places. A line and an exponential curve may intersect once or twice depending on the functions. A polynomial and a horizontal line may intersect many times. A rational function may have gaps or asymptotes. A logarithmic equation may require domain restrictions. The intersection idea remains stable across all of these: solutions are x-values where outputs match.

It prepares students for calculus. In calculus, finding where a function equals another function is common. Area between curves depends on intersection points. Optimization often requires solving equations derived from rates of change. Differential equations compare rates and quantities. Numerical methods approximate roots. The graph/table intersection skill is an early version of a much larger practice.

It also prepares students for statistics and data science. A fitted model may be compared to a threshold. Two trend lines may be compared. A prediction may be found by locating where a model reaches a value. Error and residuals can be seen as vertical differences between functions or between a model and data. The idea that equality happens at an intersection is a small but central piece of mathematical literacy.

How to execute the skill technically

The technical process begins by identifying the two functions. In an equation like \(3x + 4 = 2^x\), one side can be named \(f(x) = 3x + 4\), and the other can be named \(g(x) = 2^x\). The solution to the equation is any x-value where \(f(x)\) and \(g(x)\) are equal.

The graphing method is straightforward in concept. Graph \(y = f(x)\) and \(y = g(x)\) on the same coordinate plane. Locate the point or points where the graphs intersect. Read the x-coordinate of each intersection. Those x-values are the solutions. The y-coordinate is the shared output, which may also have meaning in context.

The table method is equally important. Make a table with columns for \(x\), \(f(x)\), and \(g(x)\). Look for values where the outputs are equal or nearly equal. If exact equality does not appear in the table, look for where the difference \(f(x) - g(x)\) changes sign. If \(f(x) - g(x)\) is positive at one x-value and negative at a nearby x-value, then the functions crossed somewhere between, assuming the functions are continuous over that interval. This is the foundation of bracketing methods.

For example, if \(f(2) = 9\) and \(g(2) = 7\), then \(f\) is above \(g\) at \(x = 2\). If \(f(3) = 10\) and \(g(3) = 12\), then \(f\) is below \(g\) at \(x = 3\). There must be an intersection between 2 and 3 if the graphs do not jump over each other. A table with smaller steps, such as 2.1, 2.2, 2.3, and so on, can narrow the answer.

Technology makes this easier, but technology does not replace thinking. A graphing calculator or software can show intersections, but the student must choose a reasonable window, label axes, understand scale, and interpret the result. A bad graphing window can hide an intersection. A table with steps that are too large can miss a crossing. A rounded answer can be misleading if the context requires a whole number or a safe margin.

Another useful method is to rewrite the equation as \(f(x) - g(x) = 0\). Then graph \(y = f(x) - g(x)\) and find where it crosses the x-axis. This is the same problem in a different form. The x-intercepts of the difference function are exactly the x-values where the original functions are equal. This form becomes extremely useful later in mathematics because many solving methods are root-finding methods: they find where a function equals zero.

Students should also learn to report approximate answers responsibly. Saying x ≈ 4.7 is different from saying \(x = 4.7\). The approximation symbol tells the reader that the answer has been estimated or rounded. In a context, the sentence should say what the approximation means. “The two plans cost the same at about 4.7 months” may need an interpretation: if billing occurs monthly, compare month 4 and month 5 rather than pretending 4.7 months is a billable cycle.

A worked example: comparing two payment plans

Suppose Plan A charges a $30 setup fee plus $12 per month. Plan B charges no setup fee but $18 per month. Let \(m\) be the number of months and \(C\) be total cost.

Plan A: \(f(m) = 30 + 12m\) Plan B: \(g(m) = 18m\)

To find when they cost the same, solve \(30 + 12m = 18m\). Graphically, this means graph both lines and find their intersection. Algebraically, subtract 12m from both sides:

\[30 = 6m\]

So \(m = 5\). The graphs intersect at \((5, 90)\) because both plans cost $90 after 5 months. Before 5 months, Plan B is cheaper because the setup fee for Plan A has not yet paid off. After 5 months, Plan A is cheaper because its monthly cost is lower.

The intersection is not just an answer. It is a decision point. It tells the customer that the better plan depends on how long they expect to keep the service.

A worked example: approximate intersection

Suppose a small plant is 8 cm tall and grows 1.5 cm per week, so its height is modeled by \(f(t) = 8 + 1.5t\). Another plant is 5 cm tall but grows by 12 percent each week, so its height is modeled by \(g(t) = 5(1.12)^t\). When are the plants the same height?

The equation is \(8 + 1.5t = 5(1.12)^t\). This is not a simple linear equation because one side is linear and the other is exponential. A graph or table is appropriate.

Make a table:

| \(t\) | \(8 + 1.5t\) | \(5(1.12)^t\) | |---:|---:|---:| | 0 | 8.00 | 5.00 | | 10 | 23.00 | 15.53 | | 20 | 38.00 | 48.23 |

At \(t = 10\), the linear plant is taller. At \(t = 20\), the exponential plant is taller. So the intersection is between 10 and 20 weeks. A more detailed table or graph narrows it. The point is not just the number; it is the story. Linear growth wins early, but exponential growth eventually catches up and passes it.

Common mistakes and how to avoid them

One common mistake is giving the intersection point when the question asks for the x-value. If the equation is \(f(x) = g(x)\), the solution is the input value, not the whole ordered pair. The whole point can be useful, but the x-coordinate answers the equation.

Another mistake is trusting a graph without checking scale. If the axes are too compressed, two graphs may appear to intersect when they actually do not, or an important intersection may be off-screen. Students should learn to zoom, adjust windows, and confirm with a table or substitution.

A third mistake is assuming every equation has one solution. Some graphs never intersect. Some intersect once. Some intersect multiple times. Some overlap entirely. The graph gives information about the number of solutions, not just their approximate location.

A fourth mistake is ignoring context. If an intersection occurs at \(x = -3\), but x represents time after a purchase, the mathematical solution may not be viable. If an answer is \(x = 6.4\) people, the context requires interpretation. Approximate solving must always end with a real sentence.

What students should be able to say

A student who has mastered this objective should be able to say: “Solving \(f(x) = g(x)\) means finding the input values where two functions have the same output. On a graph, those are the x-coordinates of intersection points. In a table, they are places where the output values match or where the difference changes sign. I can use technology to approximate the solution, but I still need to choose a good window, check my result, and explain what the answer means in context.”

That is powerful. It turns equations from symbol puzzles into meeting points between competing or cooperating models.

Problem Library

Problems in the App From This Objective

150 problems across 12 archetypes in the app.

solve `f(x)=g(x)` algebraically.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Find the exact intersection of y = 2x + 1 and y = -x + 7.

Problem 2

Find the exact intersection of y = 3x - 4 and y = x + 2.

Problem 3

Find the exact intersection of y = -2x + 8 and y = x - 1.

Problem 4

Find the exact intersection of y = 2x + 5 and y = -3x.

Problem 5

Find the exact intersection of y = x + 10 and y = -2x + 1.

Problem 6

Find the exact intersection of y = 5x - 2 and y = 2x + 4.

Open in simulator
Problem 7

Find the exact intersection of y = -x + 3 and y = 2x - 6.

Problem 8

Find the exact intersection of y = -3x + 1 and y = x - 7.

Problem 9

Find the exact intersection of y = 4x + 10 and y = x + 1.

Problem 10

Find the exact intersection of y = -2x - 5 and y = x + 4.

Problem 11

Find the exact intersection of y = 6x - 1 and y = 3x + 5.

Problem 12

Find the exact intersection of y = -x + 12 and y = 3x.

read approximate coordinates.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

From the graph description two lines cross slightly right of x = 2 and near y = 5, estimate the intersection point.

Problem 14

From the graph description a line and curve cross between x = 3 and x = 4 at about y = 10, estimate the intersection point.

Problem 15

From the graph description two graphs meet near the grid point x = -1, y = 4, estimate the intersection point.

Problem 16

From the graph description two lines intersect near x = 1 and y = 3, estimate the intersection point.

Problem 17

From the graph description a parabola and a line cross near x = -2 and y = 6, estimate the intersection point.

Problem 18

From the graph description two curves meet near x = -4 and y = -1, estimate the intersection point.

Problem 19

From the graph description a line and a circle intersect near x = 5 and y = -2, estimate the intersection point.

Problem 20

From the graph description two graphs cross between x = -1 and x = 0, and between y = 1 and y = 2, estimate the intersection point.

Problem 21

From the graph description two functions intersect very close to the origin (0,0), estimate the intersection point.

Problem 22

From the graph description a curve and a line cross on the x-axis at x = 3, estimate the intersection point.

Open in simulator
Problem 23

From the graph description two graphs meet on the y-axis at y = -5, estimate the intersection point.

Problem 24

From the graph description two parabolas intersect near x = 1 and y = 1, estimate the intersection point.

locate where output values match or cross.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Use the table f=2, g=8, x=0; f=4, g=6, x=1; f=6, g=4, x=2 to estimate where f(x) = g(x).

Problem 26

Use the table f=5, g=1, x=0; f=4, g=3, x=1; f=3, g=5, x=2 to estimate where f(x) = g(x).

Problem 27

Use the table f=3, g=7, x=0; f=5, g=5, x=1; f=7, g=3, x=2 to estimate where f(x) = g(x).

Open in simulator
Problem 28

Use the table f=10, g=2, x=1; f=8, g=5, x=2; f=6, g=9, x=3 to estimate where f(x) = g(x).

Problem 29

Use the table f=1, g=7, x=0; f=3, g=6, x=1; f=5, g=5, x=2 to estimate where f(x) = g(x).

Problem 30

Use the table f=2, g=8, x=5; f=7, g=5, x=6; f=10, g=3, x=7 to estimate where f(x) = g(x).

Problem 31

Use the table f=4, g=4, x=-1; f=6, g=2, x=0; f=8, g=0, x=1 to estimate where f(x) = g(x).

Problem 32

Use the table f=1, g=8, x=0; f=3, g=6, x=1; f=5, g=4, x=2; f=7, g=2, x=3 to estimate where f(x) = g(x).

Problem 33

Use the table f=10, g=2, x=0; f=8, g=4, x=1; f=6, g=6, x=2; f=4, g=8, x=3 to estimate where f(x) = g(x).

Problem 34

Use the table f=1, g=6, x=-3; f=3, g=4, x=-2; f=5, g=2, x=-1 to estimate where f(x) = g(x).

Problem 35

Use the table f=8, g=8, x=-4; f=6, g=10, x=-3; f=4, g=12, x=-2 to estimate where f(x) = g(x).

Problem 36

Use the table f=100, g=70, x=10; f=90, g=85, x=11; f=80, g=95, x=12 to estimate where f(x) = g(x).

explain break-even/equal-output meaning.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Interpret the intersection (4,50) for the context two phone plans where x is months and y is total cost in dollars.

Open in simulator
Problem 38

Interpret the intersection (3,120) for the context two runners where x is hours and y is distance in miles.

Problem 39

Interpret the intersection (10,500) for the context revenue and cost where x is items and y is dollars.

Problem 40

Interpret the intersection (2,75) for the context two competing companies' stock prices where x is years and y is price in dollars.

Problem 41

Interpret the intersection (5,200) for the context the amount of water in two different swimming pools where x is hours and y is gallons.

Problem 42

Interpret the intersection (1.5,30) for the context the speed of two cyclists where x is hours and y is miles per hour.

Problem 43

Interpret the intersection (8,1000) for the context the population of two small towns where x is years and y is number of people.

Problem 44

Interpret the intersection (6,150) for the context the amount of money in two savings accounts where x is months and y is dollars.

Problem 45

Interpret the intersection (2.5,40) for the context the height of two different plants where x is weeks and y is centimeters.

Problem 46

Interpret the intersection (12,600) for the context the number of units produced by two factories where x is days and y is units.

Problem 47

Interpret the intersection (0.5,25) for the context the remaining fuel in two cars where x is hours and y is gallons.

Problem 48

Interpret the intersection (7,350) for the context the sales figures for two different products where x is weeks and y is total sales in dollars.

identify one or two solution points.
15 problems Warmup Practice Mixed Review Assessment
Problem 49

Find the intersections of the linear function y = x + 2 and quadratic function y = x^2 - 2.

Problem 50

Find the intersections of the linear function y = 4 and quadratic function y = x^2.

Open in simulator
Problem 51

Find the intersections of the linear function y = 2x + 1 and quadratic function y = x^2 + 1.

Problem 52

Find the intersections of the linear function y = x and quadratic function y = x^2.

Problem 53

Find the intersections of the linear function y = -x and quadratic function y = x^2.

Problem 54

Find the intersections of the linear function y = 3x - 2 and quadratic function y = x^2.

Problem 55

Find the intersections of the linear function y = -3x - 2 and quadratic function y = x^2.

Problem 56

Find the intersections of the linear function y = 1 and quadratic function y = x^2.

Problem 57

Find the intersections of the linear function y = 2x + 3 and quadratic function y = x^2 + 3.

Problem 58

Find the intersections of the linear function y = -2x - 1 and quadratic function y = x^2 - 1.

Problem 59

Find the intersections of the linear function y = -2x + 8 and quadratic function y = x^2 + 5.

Problem 60

Find the intersections of the linear function y = 8x - 6 and quadratic function y = 2x^2.

Problem 61

Find the intersections of the linear function y = x + 1 and quadratic function y = 2x^2.

Problem 62

Find the intersections of the linear function y = -5x and quadratic function y = -x^2.

Problem 63

Find the intersections of the linear function y = 5x + 6 and quadratic function y = -x^2.

approximate crossing point.
15 problems Warmup Practice Mixed Review Assessment
Problem 64

Use the table comparing linear f and exponential g to approximate their intersection.

Problem 65

Use the table comparing linear p and exponential q to approximate their intersection.

Problem 66

Use the table comparing linear r and exponential s to approximate their intersection.

Problem 67

Use the table comparing linear A and exponential B to approximate their intersection.

Problem 68

Use the table comparing linear C and exponential D to approximate their intersection.

Problem 69

Use the table comparing linear E and exponential F to approximate their intersection.

Problem 70

Use the table comparing linear G and exponential H to approximate their intersection.

Problem 71

Use the table comparing linear I and exponential J to approximate their intersection.

Open in simulator
Problem 72

Use the table comparing linear K and exponential L to approximate their intersection.

Problem 73

Use the table comparing linear M and exponential N to approximate their intersection.

Problem 74

Use the table comparing linear O and exponential P to approximate their intersection.

Problem 75

Use the table comparing linear Q and exponential R to approximate their intersection.

Problem 76

Use the table comparing linear S and exponential T to approximate their intersection.

Problem 77

Use the table comparing linear U and exponential V to approximate their intersection.

Problem 78

Use the table comparing linear X and exponential Y to approximate their intersection.

count intersections and reason about none/one/multiple.
12 problems Warmup Practice Mixed Review Assessment
Problem 79

From the graph behavior two nonparallel lines cross once, decide how many solutions f(x) = g(x) has.

Problem 80

From the graph behavior two parallel lines never meet, decide how many solutions f(x) = g(x) has.

Problem 81

From the graph behavior a parabola crosses a line at two points, decide how many solutions f(x) = g(x) has.

Problem 82

From the graph behavior a line is tangent to a parabola, decide how many solutions f(x) = g(x) has.

Open in simulator
Problem 83

From the graph behavior two parabolas open away from each other and do not intersect, decide how many solutions f(x) = g(x) has.

Problem 84

From the graph behavior two parabolas are tangent at a single point, decide how many solutions f(x) = g(x) has.

Problem 85

From the graph behavior two parabolas intersect at two distinct points, decide how many solutions f(x) = g(x) has.

Problem 86

From the graph behavior a line passes through a circle at two points, decide how many solutions f(x) = g(x) has.

Problem 87

From the graph behavior a line is tangent to a circle, decide how many solutions f(x) = g(x) has.

Problem 88

From the graph behavior a line does not intersect a circle, decide how many solutions f(x) = g(x) has.

Problem 89

From the graph behavior two lines coincide perfectly, decide how many solutions f(x) = g(x) has.

Problem 90

From the graph behavior a cubic function crosses a line at three distinct points, decide how many solutions f(x) = g(x) has.

evaluate graph/table/equation usefulness.
12 problems Warmup Practice Mixed Review Assessment
Problem 91

Choose whether a graph, table, or equation is best for finding an exact intersection of two simple linear equations, and explain.

Problem 92

Choose whether a graph, table, or equation is best for estimating where two messy curves cross visually, and explain.

Problem 93

Choose whether a graph, table, or equation is best for narrowing an intersection when values are provided at decimal inputs, and explain.

Problem 94

Choose whether a graph, table, or equation is best for calculating the exact output of a function for a specific input, and explain.

Problem 95

Choose whether a graph, table, or equation is best for determining the exact x-intercepts of a quadratic function, and explain.

Problem 96

Choose whether a graph, table, or equation is best for finding the exact slope of a line given its equation in standard form, and explain.

Problem 97

Choose whether a graph, table, or equation is best for visualizing the overall behavior and shape of a complex polynomial function, and explain.

Problem 98

Choose whether a graph, table, or equation is best for estimating the maximum height reached by a projectile described by a parabolic function, and explain.

Problem 99

Choose whether a graph, table, or equation is best for identifying the intervals where a function is increasing or decreasing, and explain.

Problem 100

Choose whether a graph, table, or equation is best for comparing the values of two different functions at a series of discrete integer inputs, and explain.

Open in simulator
Problem 101

Choose whether a graph, table, or equation is best for finding the exact output of a function for an input that is explicitly listed, and explain.

Problem 102

Choose whether a graph, table, or equation is best for identifying a pattern in a sequence of numbers generated by a function at integer inputs, and explain.

bracket solution and refine interval.
12 problems Warmup Practice Mixed Review Assessment
Problem 103

Use successive approximation from the table f minus g=-2, x=1.0; f minus g=-0.5, x=1.5; f minus g=0.8, x=2.0; f minus g=2.1, x=2.5 to narrow the solution interval for f(x)=g(x).

Open in simulator
Problem 104

Use successive approximation from the table f minus g=1.2, x=3.0; f minus g=0.4, x=3.2; f minus g=-0.1, x=3.4; f minus g=-0.7, x=3.6 to narrow the solution interval for f(x)=g(x).

Problem 105

Use successive approximation from the table f minus g=3.0, x=0.0; f minus g=1.1, x=0.5; f minus g=-0.2, x=1.0; f minus g=-1.4, x=1.5 to narrow the solution interval for f(x)=g(x).

Problem 106

Use successive approximation from the table f minus g=-1.5, x=4.0; f minus g=-0.8, x=4.1; f minus g=0.3, x=4.2; f minus g=1.1, x=4.3 to narrow the solution interval for f(x)=g(x).

Problem 107

Use successive approximation from the table f minus g=2.0, x=5.0; f minus g=0.7, x=5.1; f minus g=-0.2, x=5.2; f minus g=-1.0, x=5.3 to narrow the solution interval for f(x)=g(x).

Problem 108

Use successive approximation from the table f minus g=-0.5, x=0.1; f minus g=0.1, x=0.2; f minus g=0.8, x=0.3; f minus g=1.5, x=0.4 to narrow the solution interval for f(x)=g(x).

Problem 109

Use successive approximation from the table f minus g=3.0, x=10.0; f minus g=2.0, x=10.1; f minus g=1.0, x=10.2; f minus g=-0.5, x=10.3 to narrow the solution interval for f(x)=g(x).

Problem 110

Use successive approximation from the table f minus g=-0.12, x=7.0; f minus g=-0.05, x=7.05; f minus g=0.03, x=7.1; f minus g=0.1, x=7.15 to narrow the solution interval for f(x)=g(x).

Problem 111

Use successive approximation from the table f minus g=15, x=-2.0; f minus g=5, x=-1.0; f minus g=-3, x=0.0; f minus g=-10, x=1.0 to narrow the solution interval for f(x)=g(x).

Problem 112

Use successive approximation from the table f minus g=-50.0, x=100.0; f minus g=-10.0, x=105.0; f minus g=20.0, x=110.0; f minus g=60.0, x=115.0 to narrow the solution interval for f(x)=g(x).

Problem 113

Use successive approximation from the table f minus g=0.8, x=-3.0; f minus g=0.3, x=-2.9; f minus g=-0.1, x=-2.8; f minus g=-0.5, x=-2.7 to narrow the solution interval for f(x)=g(x).

Problem 114

Use successive approximation from the table f minus g=-0.9, x=6.0; f minus g=-0.3, x=6.1; f minus g=0.2, x=6.2; f minus g=0.7, x=6.3 to narrow the solution interval for f(x)=g(x).

set competing models equal and interpret.
12 problems Warmup Practice Mixed Review Assessment
Problem 115

Solve the break-even problem: Plan A costs 20 dollars plus 5 dollars per month. Plan B costs 8 dollars plus 8 dollars per month.

Problem 116

Solve the break-even problem: Company revenue is 15x and cost is 60 + 5x.

Problem 117

Solve the break-even problem: Runner A has 10 miles head start and runs 6 mph; Runner B runs 8 mph.

Problem 118

Solve the break-even problem: Cell phone plan X costs 30 dollars plus 0.10 dollars per minute. Cell phone plan Y costs 10 dollars plus 0.20 dollars per minute.

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Problem 119

Solve the break-even problem: Car rental company A charges 50 dollars plus 0.25 dollars per mile. Company B charges 30 dollars plus 0.35 dollars per mile.

Problem 120

Solve the break-even problem: Plumber P charges a 75 dollar service fee plus 40 dollars per hour. Plumber Q charges a 50 dollar service fee plus 50 dollars per hour.

Problem 121

Solve the break-even problem: Investment fund A starts with 500 dollars and grows by 50 dollars per month. Fund B starts with 200 dollars and grows by 80 dollars per month.

Problem 122

Solve the break-even problem: Production line 1 has a setup cost of 1000 dollars and produces items at 5 dollars each. Production line 2 has a setup cost of 400 dollars and produces items at 8 dollars each.

Problem 123

Solve the break-even problem: Delivery service X charges 10 dollars plus 2 dollars per pound. Service Y charges 4 dollars plus 3 dollars per pound.

Problem 124

Solve the break-even problem: Savings account A starts with 100 dollars and adds 20 dollars weekly. Account B starts with 40 dollars and adds 30 dollars weekly.

Problem 125

Solve the break-even problem: Gym membership Gold costs 60 dollars plus 15 dollars per month. Membership Platinum costs 20 dollars plus 25 dollars per month.

Problem 126

Solve the break-even problem: Tank A starts with 50 gallons and fills at 10 gallons per minute. Tank B starts with 20 gallons and fills at 13 gallons per minute.

interpret calculator/table/intersection result.
12 problems Warmup Practice Mixed Review Assessment
Problem 127

Technology reports intersection output Intersect: x = 2.667, y = 15.333. Interpret the solution for two cost models where x is months and y is dollars.

Problem 128

Technology reports intersection output Intersection 1: (-1.24, 3.91), Intersection 2: (4.08, 9.15). Interpret the solution for two function graphs.

Problem 129

Technology reports intersection output x = 10.5, y = 220. Interpret the solution for revenue equals cost.

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Problem 130

Technology reports intersection output Intersection: Quantity = 150, Price = 25.75. Interpret the solution for supply and demand curves where Quantity is units and Price is dollars.

Problem 131

Technology reports intersection output Intersection: t = 1.5, h = 30. Interpret the solution for the height of two projectiles over time, where t is seconds and h is meters.

Problem 132

Technology reports intersection output Intersection: Year = 2025, Population = 125000. Interpret the solution for two population models where Year is the year and Population is the number of individuals.

Problem 133

Technology reports intersection output Intersection: Time = 3.2 hours, Distance = 160 miles. Interpret the solution for two vehicles' distance traveled over time, where Time is hours and Distance is miles.

Problem 134

Technology reports intersection output Intersection: t = 5.8 min, conc = 0.45 M. Interpret the solution for the concentration of two reactants over time, where t is minutes and conc is molarity.

Problem 135

Technology reports intersection output Intersection: Years = 7.5, Value = 12500. Interpret the solution for two investment options where Years is the time in years and Value is the dollar amount.

Problem 136

Technology reports intersection output Intersection: Time = 45 seconds, Temp = 72.3 F. Interpret the solution for the temperature of two objects over time, where Time is seconds and Temp is Fahrenheit.

Problem 137

Technology reports intersection output Intersection: Units = 500, Cost = 15000. Interpret the solution for two production cost models where Units is the number of items and Cost is dollars.

Problem 138

Technology reports intersection output Intersection: Side = 8.2 cm, Area = 67.24 sq cm. Interpret the solution for the area of two shapes based on a common side length, where Side is centimeters and Area is square centimeters.

support estimate using nearby graph/table values.
12 problems Warmup Practice Mixed Review Assessment
Problem 139

Explain why the approximate solution x is about 2 is reasonable using at x=1.9, f-g=-0.2; at x=2.1, f-g=0.3.

Problem 140

Explain why the approximate solution intersection near (3,7) is reasonable using the two graphed curves cross just to the right of x=3 and near y=7.

Problem 141

Explain why the approximate solution x is between 4 and 5 is reasonable using the table shows f<g at x=4 and f>g at x=5.

Problem 142

Explain why the approximate solution x is approximately -1 is reasonable using f(-1.1) = 0.1 and f(-0.9) = -0.05.

Problem 143

Explain why the approximate solution the root is about x=0.5 is reasonable using the graph of h(x) crosses the x-axis slightly to the right of x=0.

Problem 144

Explain why the approximate solution the solution is between 0 and 1 is reasonable using the table shows y=4 at x=0 and y=-2 at x=1.

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Problem 145

Explain why the approximate solution y is close to 10 is reasonable using at y=9.9, A(y)-B(y) is positive; at y=10.1, A(y)-B(y) is negative.

Problem 146

Explain why the approximate solution the intersection is near (-2, 5) is reasonable using the two lines intersect in the second quadrant, visibly close to x=-2 and y=5.

Problem 147

Explain why the approximate solution x is roughly 7.5 is reasonable using table values show f(7) = 12, g(7) = 15 and f(8) = 16, g(8) = 14.

Problem 148

Explain why the approximate solution the critical point is around x=3 is reasonable using the derivative f'(2.9) is negative and f'(3.1) is positive.

Problem 149

Explain why the approximate solution the curves are tangent near x=1 is reasonable using the graph shows the two functions touching but not crossing at x=1.

Problem 150

Explain why the approximate solution f(x) = 0.5 when x is about 1.5 is reasonable using the table shows f(1.4) = 0.48 and f(1.6) = 0.53.