Math I · A-REI.12

Graphing Linear Inequalities and Systems as Half-Plane Solution Regions

Half-plane solution regions show students how inequalities describe whole families of acceptable choices, which is the beginning of optimization and planning under limits.

Concept Algebra
Domain Reasoning with Equations and Inequalities
Read time 10 minutes

What this learning objective is really asking you to learn

This objective is about moving from a single boundary line to an entire region of possible solutions. A two-variable equation such as \(y = 2x + 3\) has a graph that is a line. A two-variable inequality such as \(y \le 2x + 3\) has a graph that is a half-plane: all the points on one side of the boundary line, plus the boundary itself if the inequality includes equality. Instead of asking, “Which points make this equation exactly true?” an inequality asks, “Which points satisfy this condition?”

A linear inequality divides the coordinate plane into two sides. The boundary line is where equality holds. For \(y \le 2x + 3\), the boundary is \(y = 2x + 3\). Points on the line make \(y\) exactly equal to \(2x + 3\). Points below the line have y-values less than the boundary value, so they satisfy the inequality. Points above the line do not. The graph of the inequality is the set of all points that make the statement true.

The phrase half-plane means one of the two infinite flat regions created by a line. A line cuts the plane into two halves. A linear inequality chooses one of those halves. If the inequality is strict, such as \(<\) or \(>\), the boundary line is dashed because points on the boundary are not included. If the inequality is inclusive, such as \(\le\) or \(\ge\), the boundary line is solid because boundary points are included.

A system of linear inequalities is a collection of conditions that must all be true at the same time. Each inequality creates its own half-plane. The solution set to the system is the overlap, or intersection, of all those half-planes. This overlapping region is called the feasible region in many applied contexts. It contains every point that satisfies every constraint.

This objective is not just about shading. Shading is the visual result. The real idea is constraint. A constraint limits what is possible. If \(x\) represents hours of one activity and \(y\) represents hours of another, inequalities can describe limits on time, money, materials, space, nutrition, speed, or safety. The solution region is the map of all options that fit the rules.

Why students should learn this math

This objective answers one of the most practical questions in mathematics: “What choices are allowed?” Many real problems do not ask for one exact answer. They ask for a set of options that satisfy several limits. You may have at most $100 to spend. You need at least 20 grams of protein. You can work no more than 15 hours. A machine can carry at most 500 pounds. A package must fit within length and width restrictions. A company must meet demand while staying under budget. These are inequality situations.

Equations are about exact balance. Inequalities are about feasibility. Real life is full of feasibility. A student planning a schedule may need enough study time, enough sleep, and enough work hours while not exceeding the hours in a week. A family planning meals may want nutrition above minimum levels while keeping cost below a maximum. A city planner may need to fit housing, roads, parks, and utilities into limited land. An engineer may need a design that is strong enough, light enough, cheap enough, and safe enough. These are systems of constraints.

The graph of a system of inequalities makes constraint visible. Instead of seeing separate rules in a list, you see the region where all rules overlap. That region can be empty, which means no option satisfies all the conditions. It can be large, meaning there are many possible choices. It can be bounded, like a polygon, or unbounded, extending forever in some direction. Its corners may represent extreme choices. Later, in linear programming, those corners become especially important because optimal solutions often occur at vertices of the feasible region.

This is why students should learn this math: it is the beginning of optimization. Optimization means choosing the best option under constraints. Businesses optimize profit under cost and production limits. Airlines optimize routes and schedules. Hospitals optimize staffing. Delivery services optimize paths. Farmers optimize crop choices under land, water, and market constraints. Engineers optimize designs. Even a student choosing how to spend a weekend is informally optimizing time, energy, money, and goals.

Graphing inequalities teaches a disciplined way to think about freedom and limits. The shaded region is freedom: all the choices still available. The boundary lines are limits: places where a condition is exactly tight. Points outside the region are not morally wrong; they simply violate at least one rule. That mindset is useful beyond math. It helps students see decision-making as a matter of constraints, tradeoffs, and viable options.

The historical machinery: constraints, linear programming, and decision mathematics

The idea of inequalities is old because comparison is old. People have always needed to know whether one quantity is greater than another, whether supplies are enough, whether taxes exceed income, or whether land measurements fit a plan. But the systematic use of inequalities as geometric regions became especially powerful with coordinate geometry and later with optimization theory.

Once algebraic relationships could be graphed on coordinate axes, inequalities became regions. A line no longer had to represent only equality; it could represent a boundary between acceptable and unacceptable values. This geometric view opened the door to solving practical planning problems visually and later computationally.

In the twentieth century, systems of linear inequalities became central in a field called linear programming. Despite the word “programming,” this originally meant planning or scheduling, not writing computer code. Linear programming studies how to maximize or minimize a linear objective, such as profit or cost, subject to linear constraints. During and after World War II, these methods became important for logistics, resource allocation, transportation, and operations research. George Dantzig's simplex method became one of the most famous algorithms for solving such problems.

The classroom act of shading half-planes is a small version of this big historical development. When a student graphs inequalities and finds the overlapping feasible region, they are doing the visual foundation of linear programming. They are learning how equations become boundaries, inequalities become allowable regions, and systems become intersections of constraints.

This is also part of the history of mathematical modeling. Exact equations are often too rigid to describe decision-making. Real problems usually involve ranges: at least this much, no more than that much, between these values, within this tolerance. Inequalities are how mathematics represents those ranges. Without inequalities, algebra would be missing the language of limits, safety, and feasibility.

Where this fits in the big map of mathematics

This objective connects algebra, geometry, modeling, and optimization. Algebra supplies the inequalities. Geometry supplies the half-planes and intersections. Modeling supplies the real-world meaning. Optimization, which comes later, asks which point in the solution region is best according to some goal.

It also builds directly on the idea from Article 006: a graph is a solution set. For an equation, the solution set might be a line. For an inequality, the solution set is a region. If students understand that every point on a line can be tested in an equation, they can also understand that every point in a shaded region can be tested in an inequality. The graph is not decoration. It is the set of all solutions.

This objective also prepares students for systems of equations and inequalities. A system requires simultaneous truth. In a system of equations, the solution might be where lines intersect. In a system of inequalities, the solution is where regions overlap. That idea later generalizes into higher dimensions. In three variables, a linear inequality describes a half-space. A system of inequalities can create a three-dimensional feasible solid. In many variables, the same idea becomes a high-dimensional feasible region. That is the world of modern optimization, data science, economics, and machine learning.

It also connects to geometry through polygons. A system of linear inequalities can form a polygonal region. The boundary lines create sides; intersections of boundary lines create vertices. In linear programming, those vertices often matter because the maximum or minimum of a linear objective over a bounded polygon occurs at a vertex. Students do not need to master the full theory yet, but they should see that shading inequalities is not isolated. It leads toward powerful decision mathematics.

In statistics and data science, inequalities define categories and decision boundaries. A model might classify outcomes depending on which side of a line a data point falls. In computer graphics, inequalities can define visible regions, clipping windows, and collision boundaries. In engineering, inequalities express safe operating ranges. In finance, they express risk limits and budget constraints. The humble shaded half-plane has a long reach.

How to execute the skill technically

The technical process starts by identifying the boundary line. Replace the inequality symbol with an equals sign. For \(y < -3x + 2\), the boundary line is \(y = -3x + 2\). Graph that line using slope-intercept form, intercepts, or a table.

Next, decide whether the boundary is included. If the inequality is \(<\) or \(>\), use a dashed line because points on the boundary do not satisfy the strict inequality. If the inequality is \(\le\) or \(\ge\), use a solid line because points on the boundary are included.

Then choose which side to shade. One method is to use the inequality's direction when it is solved for y. If \(y < -3x + 2\), shade below the line because y-values less than the boundary are below it. If \(y > -3x + 2\), shade above the line. But students should not rely only on visual rules because not every inequality is already solved for y. A reliable method is to test a point not on the boundary, often \((0, 0)\) if it is not on the line. Substitute the point into the original inequality. If the point makes the inequality true, shade the side containing that point. If it makes the inequality false, shade the other side.

For example, graph \(2x + y \le 6\). The boundary is \(2x + y = 6\), or \(y = -2x + 6\), and the line is solid. Test \((0, 0)\): \(2(0) + 0 \le 6\), so \(0 \le 6\), which is true. Shade the side containing the origin.

For a system, repeat this process for each inequality. The solution is the overlap of the shaded regions. A point is a solution only if it satisfies every inequality in the system. If it satisfies one but not another, it is not a solution to the system.

It is important to graph carefully. Boundary lines should be accurate. Shading should be clear. Intersections should be estimated or calculated if needed. If the solution region is used for a real-world problem, axis labels and units matter. If \(x\) and \(y\) represent quantities that cannot be negative, then constraints like \(x \ge 0\) and \(y \ge 0\) may need to be included even if the word problem does not state them loudly.

Students should also learn to interpret regions. A boundary line often represents a constraint being exactly met. Points inside the feasible region represent choices with slack or room left over. Points outside violate at least one condition. A corner point represents a combination where two or more constraints are tight at the same time.

A worked example: a simple budget and time system

Suppose a student is choosing between two kinds of tutoring sessions. Algebra sessions cost $20 each and geometry sessions cost $30 each. The student can spend at most $180 and wants at least 2 sessions of each type. Let \(x\) be the number of algebra sessions and \(y\) be the number of geometry sessions.

The budget constraint is \(20x + 30y \le 180\). Dividing by 10 gives \(2x + 3y \le 18\). The minimum session constraints are \(x \ge 2\) and \(y \ge 2\).

The graph of \(2x + 3y \le 18\) is the half-plane at or below the line \(2x + 3y = 18\). The graph of \(x \ge 2\) is the region to the right of the vertical line \(x = 2\). The graph of \(y \ge 2\) is the region above the horizontal line \(y = 2\). The feasible region is the overlap.

A point such as \((3, 3)\) means 3 algebra sessions and 3 geometry sessions. Check the budget: \(20(3) + 30(3) = 60 + 90 = 150\), which is within $180. It also satisfies the minimums. So \((3, 3)\) is viable. A point such as \((1, 5)\) may fit the budget but violates the requirement of at least 2 algebra sessions. A point such as \((6, 3)\) violates the budget because \(120 + 90 = 210\).

The graph is a decision map. It does not choose for the student, but it shows every combination that meets the rules.

Common mistakes and how to avoid them

A common mistake is shading the wrong side of the boundary. Testing a point fixes this. Another common mistake is using a dashed line for \(\le\) or \(\ge\), or a solid line for \(<\) or \(>\). Remember that equality included means solid; equality excluded means dashed.

Students also sometimes forget that a system requires all inequalities to be true. The solution is not all shaded areas combined; it is only the overlap. If two inequalities shade opposite regions with no overlap, the system has no solution.

Another common mistake is ignoring real-world restrictions. If \(x\) means number of items, \(x\) cannot be negative. If \(x\) and \(y\) represent whole objects, fractional points may lie in the mathematical region but may not be viable in context. The graph may show a continuous region, but the real solution set may be only lattice points with whole-number coordinates.

Finally, students sometimes treat shading as a mechanical art task. The deeper skill is logical. Every point in the shaded region should make the inequality true. Every point outside should fail at least one condition. The graph is a truth map.

What students should be able to say

A student who has mastered this objective should be able to say: “A linear inequality in two variables graphs as a half-plane. The boundary line comes from replacing the inequality with equality. A solid boundary means the line is included; a dashed boundary means it is not. I can test a point to decide which side to shade. For a system, the solution is the overlap of all the half-planes. In a real situation, the shaded region represents all viable choices under the constraints.”

That is the beginning of serious decision mathematics. It teaches students that math is not only about finding one answer. Sometimes it is about mapping all possible answers that obey the rules.

Problem Library

Problems in the App From This Objective

144 problems across 12 archetypes in the app.

boundary line, solid/dashed, shade.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Graph the inequality y <= 2x + 1. Describe the boundary and shading.

Problem 2

Graph the inequality y > -x + 4. Describe the boundary and shading.

Open in simulator
Problem 3

Graph the inequality y < 3. Describe the boundary and shading.

Problem 4

Graph the inequality y >= x - 2. Describe the boundary and shading.

Problem 5

Graph the inequality y < -2x. Describe the boundary and shading.

Problem 6

Graph the inequality y > 1/2 x + 3. Describe the boundary and shading.

Problem 7

Graph the inequality y <= -x - 1. Describe the boundary and shading.

Problem 8

Graph the inequality y >= 0. Describe the boundary and shading.

Problem 9

Graph the inequality y < -4. Describe the boundary and shading.

Problem 10

Graph the inequality y <= -1/3 x + 2. Describe the boundary and shading.

Problem 11

Graph the inequality y > x. Describe the boundary and shading.

Problem 12

Graph the inequality y >= -5. Describe the boundary and shading.

find intercepts or rearrange.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Graph the standard-form inequality 2x + y <= 6. Describe intercepts or rearranged form and shading.

Problem 14

Graph the standard-form inequality 3x - y > 9. Describe intercepts or rearranged form and shading.

Problem 15

Graph the standard-form inequality x + 2y >= 8. Describe intercepts or rearranged form and shading.

Open in simulator
Problem 16

Graph the standard-form inequality x + y < 5. Describe intercepts or rearranged form and shading.

Problem 17

Graph the standard-form inequality 2x - y < 4. Describe intercepts or rearranged form and shading.

Problem 18

Graph the standard-form inequality 4x + 2y >= 10. Describe intercepts or rearranged form and shading.

Problem 19

Graph the standard-form inequality x - 3y <= 6. Describe intercepts or rearranged form and shading.

Problem 20

Graph the standard-form inequality 3x + 5y > 15. Describe intercepts or rearranged form and shading.

Problem 21

Graph the standard-form inequality 5x - y >= 10. Describe intercepts or rearranged form and shading.

Problem 22

Graph the standard-form inequality x + 3y <= -6. Describe intercepts or rearranged form and shading.

Problem 23

Graph the standard-form inequality 2x - y > -2. Describe intercepts or rearranged form and shading.

Problem 24

Graph the standard-form inequality x <= 4. Describe intercepts or rearranged form and shading.

substitute test point.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Use a test point to decide which side to shade for y > 2x + 1.

Problem 26

Use a test point to decide which side to shade for x + y <= 5.

Problem 27

Use a test point to decide which side to shade for y < -x - 2.

Problem 28

Use a test point to decide which side to shade for y >= x.

Problem 29

Use a test point to decide which side to shade for y < 3x - 2.

Problem 30

Use a test point to decide which side to shade for 2x - y > 4.

Problem 31

Use a test point to decide which side to shade for x + 2y <= 6.

Problem 32

Use a test point to decide which side to shade for y > -x + 3.

Problem 33

Use a test point to decide which side to shade for 3x - 2y < 0.

Problem 34

Use a test point to decide which side to shade for y <= -x.

Open in simulator
Problem 35

Use a test point to decide which side to shade for x - y >= 0.

Problem 36

Use a test point to decide which side to shade for y + 4x > -1.

overlap solution regions.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Graph the system y >= x + 1, y <= 5. Describe the overlapping solution region.

Problem 38

Graph the system x + y <= 6, x >= 0, y >= 0. Describe the overlapping solution region.

Problem 39

Graph the system y < 2x, y >= -1. Describe the overlapping solution region.

Problem 40

Graph the system y > -x + 2, x > 0. Describe the overlapping solution region.

Open in simulator
Problem 41

Graph the system y <= x, y >= -x, y <= 3. Describe the overlapping solution region.

Problem 42

Graph the system y < 2x + 1, y > 2x - 3. Describe the overlapping solution region.

Problem 43

Graph the system x >= 1, x <= 4, y >= 0, y <= 2. Describe the overlapping solution region.

Problem 44

Graph the system x + y >= 4, y <= -x + 8. Describe the overlapping solution region.

Problem 45

Graph the system y >= x - 2, y <= -x + 6, x >= 0. Describe the overlapping solution region.

Problem 46

Graph the system y > x, y < x + 3. Describe the overlapping solution region.

Problem 47

Graph the system x >= 0, y >= 0, 2x + 3y <= 12. Describe the overlapping solution region.

Problem 48

Graph the system y >= -2x + 4, y >= x - 1. Describe the overlapping solution region.

test all inequalities.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Determine whether (2,3) lies in the solution region for y >= x, x + y <= 6.

Problem 50

Determine whether (4,1) lies in the solution region for y >= x, x + y <= 6.

Open in simulator
Problem 51

Determine whether (0,5) lies in the solution region for y < 5, x >= 0.

Problem 52

Determine whether (1,1) lies in the solution region for y > x - 1, x + y < 3.

Problem 53

Determine whether (1,0) lies in the solution region for x > 3, y <= x.

Problem 54

Determine whether (2,5) lies in the solution region for y >= x, x + y <= 6.

Problem 55

Determine whether (3,3) lies in the solution region for y >= x, x + y <= 6.

Problem 56

Determine whether (2,4) lies in the solution region for x + y < 6, x > 1.

Problem 57

Determine whether (5,-2) lies in the solution region for y < -1.

Problem 58

Determine whether (0,0) lies in the solution region for x > 1.

Problem 59

Determine whether (-1,-3) lies in the solution region for y <= x, x + y >= -5.

Problem 60

Determine whether (-2,-2) lies in the solution region for y > x, x + y < -4.

recover boundary and shading direction.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Write inequalities for the graphed region described as on or below solid line y = 2x + 3 and above dashed line y = -1.

Problem 62

Write inequalities for the graphed region described as right of solid vertical line x = 0 and below dashed line y = x + 4.

Problem 63

Write inequalities for the graphed region described as inside the first quadrant below solid line x + y = 10.

Problem 64

Write inequalities for the graphed region described as above solid line y = x - 2 and to the left of dashed vertical line x = 5.

Problem 65

Write inequalities for the graphed region described as below dashed line y = -x + 1 and above solid line y = 2x - 3.

Problem 66

Write inequalities for the graphed region described as inside the first quadrant below solid line y = -x + 5.

Problem 67

Write inequalities for the graphed region described as to the right of dashed line x = -3 and on or above solid line y = -2x + 1.

Open in simulator
Problem 68

Write inequalities for the graphed region described as between solid line y = 1 and dashed line y = 4.

Problem 69

Write inequalities for the graphed region described as between dashed line x = -2 and solid line x = 3.

Problem 70

Write inequalities for the graphed region described as in the second quadrant above solid line y = x + 1.

Problem 71

Write inequalities for the graphed region described as below dashed line y = -x and above dashed line y = 2.

Problem 72

Write inequalities for the graphed region described as on or above solid line y = 3x - 4 and on or to the left of solid line x = 2.

translate constraints and include nonnegative restrictions.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Model the feasible region for Make x small posters and y large posters. Small takes 2 minutes, large takes 5 minutes, and there are at most 40 minutes. At least 8 posters are needed. with linear inequalities.

Problem 74

Model the feasible region for Buy x apples at 1 dollar and y oranges at 2 dollars with at most 20 dollars and at most 15 fruits total. with linear inequalities.

Problem 75

Model the feasible region for A fundraiser sells x adult meals and y student meals. Adult meals take 3 minutes, student meals take 2 minutes, total prep time is at most 60 minutes, and at least 20 meals must be sold. with linear inequalities.

Problem 76

Model the feasible region for A factory produces x widgets and y gadgets. Each widget requires 1 unit of material A and 2 units of material B. Each gadget requires 3 units of material A and 1 unit of material B. There are at most 30 units of material A and 20 units of material B available. with linear inequalities.

Problem 77

Model the feasible region for You want to consume x servings of cereal and y servings of yogurt. Each serving of cereal has 150 calories and 5g of protein. Each serving of yogurt has 100 calories and 10g of protein. You need at least 30g of protein and want to consume at most 700 calories. with linear inequalities.

Problem 78

Model the feasible region for An investor puts x dollars into stocks and y dollars into bonds. Stocks yield 8% and bonds yield 5%. The investor wants to earn at least 60 dollars in interest and invest no more than 1500 dollars in total. with linear inequalities.

Problem 79

Model the feasible region for A truck can carry x small boxes and y large boxes. Each small box weighs 10 kg and has a volume of 0.5 cubic meters. Each large box weighs 25 kg and has a volume of 1 cubic meter. The truck has a maximum weight capacity of 500 kg and a maximum volume capacity of 20 cubic meters. with linear inequalities.

Problem 80

Model the feasible region for A workshop produces x assembled units and y packaged units. Assembling a unit takes 3 hours and packaging a unit takes 1 hour. There are at most 120 total labor hours available. At least 30 units must be produced in total. with linear inequalities.

Problem 81

Model the feasible region for A chemist wants to mix x liters of solution A and y liters of solution B. Solution A contains 20% acid and solution B contains 50% acid. The total volume of the mixture must be at least 10 liters, and the total amount of acid must be at least 3 liters. with linear inequalities.

Problem 82

Model the feasible region for A company plans to run x radio ads and y TV ads. Each radio ad costs 50 dollars and reaches 1000 people. Each TV ad costs 200 dollars and reaches 5000 people. The company has a budget of at most 2000 dollars and wants to reach at least 30000 people. with linear inequalities.

Open in simulator
Problem 83

Model the feasible region for A farmer plants x acres of corn and y acres of soybeans. Corn requires 2 hours of labor per acre and 3 units of fertilizer per acre. Soybeans require 1 hour of labor per acre and 2 units of fertilizer per acre. The farmer has at most 100 hours of labor and at most 150 units of fertilizer. with linear inequalities.

Problem 84

Model the feasible region for An event planner needs to set up x small tables and y large tables. Each small table seats 4 people and requires 1 square meter of space. Each large table seats 8 people and requires 2 square meters of space. The venue has a maximum of 50 square meters of space and needs to seat at least 100 people. with linear inequalities.

connect graph features to context limits.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Interpret the graph feature the boundary 3x + 2y = 30 of a feasible region for x and y are items using a 30 dollar budget.

Problem 86

Interpret the graph feature the vertex (4,6) of a feasible region for production of x small and y large items.

Problem 87

Interpret the graph feature the x-axis boundary y = 0 of a feasible region for buying x notebooks and y pens.

Problem 88

Interpret the graph feature the boundary x + y = 100 of a feasible region for x and y are hours worked by two employees, with a total of 100 hours available.

Problem 89

Interpret the graph feature the boundary 5x + 10y = 50 of a feasible region for x and y are units of two ingredients, needing a minimum of 50 grams of nutrient.

Open in simulator
Problem 90

Interpret the graph feature the vertex (10, 5) of a feasible region for manufacturing x chairs and y tables.

Problem 91

Interpret the graph feature the y-axis boundary x = 0 of a feasible region for allocating x hours to task A and y hours to task B.

Problem 92

Interpret the graph feature the boundary x = 20 of a feasible region for number of x students and y teachers, with a maximum of 20 students.

Problem 93

Interpret the graph feature the boundary y = 5 of a feasible region for number of x red cars and y blue cars, with at least 5 blue cars.

Problem 94

Interpret the graph feature the vertex (2, 8) of a feasible region for producing x batches of cookies and y batches of brownies, limited by flour and sugar.

Problem 95

Interpret the graph feature the boundary 1.50x + 2.00y = 15 of a feasible region for buying x apples and y oranges with a 15 dollar budget.

Problem 96

Interpret the graph feature the x-axis boundary y = 0 of a feasible region for mixing x liters of chemical A and y liters of chemical B.

interpret strict versus inclusive inequality.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Should the boundary for y <= 3x + 1 be solid or dashed? Explain.

Problem 98

Should the boundary for x + y > 8 be solid or dashed? Explain.

Problem 99

Should the boundary for y < -2 be solid or dashed? Explain.

Problem 100

Should the boundary for y >= 5x - 2 be solid or dashed? Explain.

Problem 101

Should the boundary for 2x - 3y <= 6 be solid or dashed? Explain.

Problem 102

Should the boundary for x > 5 be solid or dashed? Explain.

Problem 103

Should the boundary for y < x - 1 be solid or dashed? Explain.

Problem 104

Should the boundary for y >= 7 be solid or dashed? Explain.

Problem 105

Should the boundary for x <= 0 be solid or dashed? Explain.

Problem 106

Should the boundary for y > -x + 4 be solid or dashed? Explain.

Open in simulator
Problem 107

Should the boundary for 3x + y < 10 be solid or dashed? Explain.

Problem 108

Should the boundary for y <= x be solid or dashed? Explain.

write equation of boundary and choose inequality direction.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Convert the boundary and shaded side into an inequality: solid line y = -x + 6, shaded below.

Problem 110

Convert the boundary and shaded side into an inequality: dashed vertical line x = 3, shaded right.

Problem 111

Convert the boundary and shaded side into an inequality: solid horizontal line y = -2, shaded above.

Problem 112

Convert the boundary and shaded side into an inequality: solid line y = 2x - 1, shaded above.

Problem 113

Convert the boundary and shaded side into an inequality: dashed line y = (1/2)x + 3, shaded below.

Problem 114

Convert the boundary and shaded side into an inequality: dashed line y = -3x + 4, shaded above.

Problem 115

Convert the boundary and shaded side into an inequality: solid vertical line x = -5, shaded left.

Problem 116

Convert the boundary and shaded side into an inequality: solid vertical line x = 0, shaded right.

Problem 117

Convert the boundary and shaded side into an inequality: dashed vertical line x = 1, shaded left.

Open in simulator
Problem 118

Convert the boundary and shaded side into an inequality: dashed horizontal line y = 4, shaded above.

Problem 119

Convert the boundary and shaded side into an inequality: dashed horizontal line y = -1, shaded below.

Problem 120

Convert the boundary and shaded side into an inequality: solid horizontal line y = 5, shaded below.

combine multiple half-planes.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Describe the solution region of the three-constraint system x >= 0, y >= 0, x + y <= 6.

Problem 122

Describe the solution region of the three-constraint system y >= 1, y <= 4, x > 0.

Problem 123

Describe the solution region of the three-constraint system y >= x + 2, y <= x - 1, x >= 0.

Problem 124

Describe the solution region of the three-constraint system x >= 0, y >= 0, 2x + y <= 8.

Open in simulator
Problem 125

Describe the solution region of the three-constraint system x >= 0, y >= 0, x + y >= 5.

Problem 126

Describe the solution region of the three-constraint system x >= -1, x <= 2, y >= 0.

Problem 127

Describe the solution region of the three-constraint system x >= 3, x <= 1, y >= 0.

Problem 128

Describe the solution region of the three-constraint system x >= 1, y >= 1, x + y <= 6.

Problem 129

Describe the solution region of the three-constraint system y >= x, x >= 0, y >= 3.

Problem 130

Describe the solution region of the three-constraint system y >= x + 1, y <= x + 4, x >= -2.

Problem 131

Describe the solution region of the three-constraint system x - y >= 2, x - y <= 0, x >= 0.

Problem 132

Describe the solution region of the three-constraint system x <= 0, y >= 0, x + y >= -3.

connect inequality symbol to graph inclusion.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Explain whether the boundary point (2,5) is included for y <= 2x + 1.

Problem 134

Explain whether the boundary point (3,3) is included for y < x.

Problem 135

Explain whether the boundary point (0,4) is included for x >= 0 and y <= 4.

Problem 136

Explain whether the boundary point (1,2) is included for y > -x + 3.

Problem 137

Explain whether the boundary point (5,-2) is included for x >= 5.

Open in simulator
Problem 138

Explain whether the boundary point (3,0) is included for 2x + 3y < 6.

Problem 139

Explain whether the boundary point (-4,4) is included for y <= -x.

Problem 140

Explain whether the boundary point (5,5) is included for y >= x and y < 5.

Problem 141

Explain whether the boundary point (1,-1) is included for x + y >= 0 and x <= 3.

Problem 142

Explain whether the boundary point (2,2) is included for y > x - 1 and x + y <= 4.

Problem 143

Explain whether the boundary point (7,7) is included for y - x < 0.

Problem 144

Explain whether the boundary point (0,5) is included for x < 0 and y > 0.