Math I · F-BF.1.b

Combining Functions to Build Better Models

Combining functions mirrors real systems, where total cost, total distance, temperature, profit, and risk are often built from several interacting pieces.

Concept Functions
Domain Building Functions
Read time 13 minutes

What this learning objective is really asking you to learn

This learning objective is asking students to understand that many real-world models are not built from one single formula. They are built by combining smaller formulas, each of which represents one part of a situation. In earlier algebra, a student might see a function such as \(f(x) = 3x + 8\) and treat it as a complete object. That is useful, but it is only the beginning. A serious model often has several pieces. One function might represent income. Another function might represent cost. One function might represent a starting amount. Another might represent growth or decay. One function might represent a baseline. Another might represent a change above or below that baseline. F-BF.1.b is about learning how to assemble these parts into one model.

The phrase “standard functions” means function types students already recognize: constant functions, linear functions, exponential functions, and eventually quadratic, absolute-value, radical, rational, logarithmic, and trigonometric functions. In Integrated Math I, the main focus is usually linear and exponential functions, with some attention to constant functions and arithmetic or geometric patterns. The phrase “using arithmetic operations” means adding, subtracting, multiplying, or dividing functions. These operations are not just symbol games. They correspond to real actions: combining quantities, comparing quantities, scaling quantities, finding totals, finding differences, and forming ratios.

For example, suppose a small business sells shirts. Revenue might be modeled by \(R(x) = 20x\), where \(x\) is the number of shirts sold and each shirt brings in $20. Cost might be modeled by \(C(x) = 300 + 8x\), where $300 is a fixed setup cost and each shirt costs $8 to produce. Profit is not a completely new kind of mystery formula. It is the difference between revenue and cost:

\[P(x) = R(x) - C(x)\]

So

\[P(x) = 20x - (300 + 8x) = 12x - 300\].

This is a new function built from two existing functions. The operation has meaning: subtracting cost from revenue gives profit. A student who sees only \(P(x) = 12x - 300\) may miss the story. A student who understands function combination can see the machinery behind the model.

Another example comes from temperature. Imagine a cup of hot chocolate cooling in a room. The room temperature might be modeled as a constant function, such as \(A(t) = 70\), where the room stays at 70 degrees Fahrenheit. The amount by which the drink is warmer than the room might decay exponentially, perhaps \(D(t) = 100(0.85)^t\), where \(t\) is time in minutes. The actual temperature of the drink is the room temperature plus the remaining extra heat:

\[T(t) = A(t) + D(t) = 70 + 100(0.85)^t\].

The model is not just “an exponential function.” It is a constant baseline plus a decaying exponential difference. That structure is the meaning. Without the combination, the formula is just symbols. With the combination, the formula becomes a machine that says, “The drink approaches room temperature because the extra heat fades over time.”

This objective also asks students to pay attention to the input. When we write \((f + g)(x) = f(x) + g(x)\), both \(f\) and \(g\) are being evaluated at the same input \(x\). That matters. You cannot responsibly add two functions unless their inputs represent compatible situations. If \(R(x)\) uses \(x\) as shirts sold and \(C(x)\) also uses \(x\) as shirts produced, subtracting them makes sense. If one function uses \(x\) as days and another uses \(x\) as miles, then combining them without translation may produce nonsense. Function combination is powerful, but it requires careful thinking about units, domains, and meaning.

So the objective is not merely “add two formulas.” It is: identify component relationships, decide what each function represents, combine them with the operation that matches the real situation, simplify when useful, and interpret the resulting model. That is a major step from doing algebra to using algebra as a modeling language.

Why students should learn this math

Students often ask, “Why am I learning this?” For function combination, the answer is direct: because the world is built from interacting quantities, not isolated formulas. Real life rarely gives you one clean relationship. A phone bill might have a fixed monthly fee, a per-gigabyte charge, taxes, discounts, and penalties. A paycheck might include hourly wages, overtime, deductions, and bonuses. A science model might include a baseline level plus a changing amount. A car trip might combine a fixed starting distance, a speed-based distance, and a delay. A bank account might combine deposits, withdrawals, fees, and interest. In each case, a useful model is assembled from parts.

This is the mathematics of “total effect.” If one process adds something and another process removes something, the final amount is a combination. If one quantity grows and another decays, the total may be a sum or difference of functions. If a machine produces parts at one rate and a second machine produces parts at another rate, total production is the sum of two functions. If a city wants to know net population change, it may combine births, deaths, people moving in, and people moving out. If a company wants to know profit, it combines revenue and cost. If a student wants to compare the true cost of two plans, they combine flat fees, usage charges, discounts, and extra charges.

Learning this skill also changes how students see formulas. Many students think a formula is something handed down by a textbook. But in real modeling, formulas are constructed. A modeler asks: What pieces are present? What does each piece do? How do those pieces interact? Is the total a sum? Is the useful quantity a difference? Is one piece scaling another? Is a ratio needed? Function combination trains students to build formulas instead of merely receiving them.

This matters in careers. In finance, analysts build models by combining revenue streams, expenses, interest, taxes, inflation, and risk. In engineering, total force, total energy, total cost, or total load often comes from multiple component functions. In medicine and biology, models combine baseline levels with rates of change, dosage effects, and decay processes. In computer science, functions are literally building blocks: programmers write small functions and combine them into larger systems. In data science, a prediction model may be a combination of simpler terms, each representing one influence on the outcome. In economics, supply and demand, profit and cost, utility and constraints are all expressed through relationships that combine.

But the skill is not only for technical fields. It is also for ordinary decisions. Suppose a student is choosing between two gym memberships. One plan charges $25 per month plus $5 per class. Another charges $60 per month with unlimited classes. A function model can show when each plan is cheaper. Suppose a family is planning a road trip. Total cost might include gas, hotel, food, tickets, and parking. Some costs are fixed, some depend on miles, some depend on people, and some depend on days. Combining functions makes the hidden structure visible.

The deeper reason to learn this math is that it teaches compositional thinking. Compositional thinking means understanding a complex system by breaking it into parts and then understanding how the parts combine. This is one of the most important forms of intelligence in modern life. A smartphone app is built from components. A business plan is built from components. A scientific explanation is built from components. A legal argument, a budget, a game strategy, a diet plan, a workout plan, and a transportation system are all built from parts that interact. Mathematics gives students a clean, precise way to practice that kind of thinking.

When students understand function combination, they also become less intimidated by complicated formulas. A formula like \(T(t) = 70 + 100(0.85)^t\) may look advanced. But if the student sees it as “room temperature plus extra heat that decays,” the model becomes understandable. A formula like \(P(x) = 20x - (300 + 8x)\) may look like algebra, but it is just “money in minus money out.” That is the missing “why”: the math represents the architecture of a situation.

The historical machinery: from formulas to models made of parts

The history behind this objective is really the history of mathematics becoming a language for describing change. Early mathematics was often about counting, measuring, trading, and solving specific practical problems. People needed to calculate areas, divide goods, compare prices, and track quantities. Over time, symbolic algebra developed so that relationships could be represented generally. Instead of solving only one price problem, mathematicians could write formulas that worked for whole families of problems.

The function concept grew out of the study of changing quantities. Astronomers tracked the position of planets over time. Physicists studied distance as a function of time, velocity as a function of time, and force as a function of position. Merchants and governments tracked price, tax, interest, and population. The more people studied change, the more they needed a language for relationships. A function became a way to say, “This quantity depends on that quantity.”

As mathematics became more powerful, it became clear that real relationships could often be assembled from simpler ones. A projectile’s height might combine an initial height, an initial upward velocity term, and a gravitational term. A cooling object might combine the surrounding temperature with a decaying temperature difference. A periodic signal might combine several waves. A financial model might combine principal, interest, deposits, and fees. A statistical model might combine a baseline value with the effects of several variables.

This idea is everywhere in modern mathematics. In algebra, students combine functions with arithmetic operations. In calculus, students combine functions and then study how the combined function changes. The derivative of a sum is the sum of derivatives; the derivative of a product requires the product rule; the derivative of a quotient requires the quotient rule. In linear algebra, complicated transformations can be built from simpler transformations. In Fourier analysis, complicated waves are represented as sums of simpler sine and cosine waves. In computer science, complicated programs are built by composing and combining smaller functions.

Function combination also reflects the rise of mathematical modeling in science and engineering. A model is not reality itself. It is a simplified structure that captures important features of reality. To build a model, people decide which pieces matter. Sometimes a simple model is enough. Sometimes several functions must be combined. In a climate model, for example, many processes interact: solar input, reflection, absorption, ocean circulation, atmospheric chemistry, and more. In a far simpler classroom setting, students may combine a constant function and a linear function, but the underlying modeling idea is the same: understand the parts, then build the whole.

This history matters because it helps students see that combining functions is not a random algebra topic. It is one of the ways mathematics became useful for the modern world. A single relationship is useful. A system of interacting relationships is much more powerful. F-BF.1.b is an early doorway into that larger modeling tradition.

Where this fits in the big map of mathematics

In the big map of mathematics, this objective sits in the Functions branch, but it reaches into algebra, modeling, calculus, statistics, and computer science. It comes after students have learned to recognize basic function types and before they are expected to handle more advanced function operations, transformations, composition, inverse functions, and rates of change.

Backward, it connects to arithmetic. Adding, subtracting, multiplying, and dividing functions are extensions of adding, subtracting, multiplying, and dividing numbers. The difference is that a function represents a whole relationship, not just one value. When we write \((f + g)(x)\), we are adding the outputs produced by two relationships at the same input. That is arithmetic lifted from numbers to entire rules.

It also connects to expressions. Students have learned that \(3x + 5x\) can be combined because the terms refer to compatible quantities. Function combination is the same idea at a higher level. If \(f(x)\) and \(g(x)\) represent compatible outputs for the same input, then \(f(x) + g(x)\) can represent a combined output. This is structure in action.

Forward, this objective leads to transformations. A transformation such as \(f(x) + k\) is really a combination of \(f(x)\) with a constant function. A transformation such as \(kf(x)\) is multiplication of a function by a constant. A model like \(70 + 100(0.85)^t\) is both a function combination and a graph transformation: it is an exponential curve shifted upward by 70. So F-BF.1.b prepares students for F-BF.3.

It also prepares students for calculus. In calculus, students do not only study simple functions one at a time. They study sums, differences, products, quotients, and compositions. Understanding that a function can be built from other functions is essential for understanding derivative rules, integrals, differential equations, and models of motion or growth.

In computer science, a function is a reusable process. Large programs are built from smaller functions. Sometimes outputs from multiple functions are combined. A shopping-cart app, for example, may have one function for item subtotal, another for tax, another for discounts, another for shipping, and another for final cost. The algebraic idea of combining functions mirrors the programming idea of building larger systems from smaller procedures.

In statistics and data science, many models are additive. A predicted value might equal a baseline plus several adjustment terms. For example, a model predicting house price might combine square footage, location, age, number of bedrooms, interest rates, and neighborhood trends. Students are not doing that full work in Integrated Math I, but F-BF.1.b gives them the first mental structure: a model can be assembled from component functions.

The big-picture position is this: functions describe relationships; function combination builds complex relationships from simpler ones. That is a huge step in mathematical maturity.

How to execute the skill technically

The technical heart of this objective is simple to state but important to use carefully. If \(f\) and \(g\) are functions, then we can define new functions:

\[(f + g)(x) = f(x) + g(x)\]
\[(f - g)(x) = f(x) - g(x)\]
\[(fg)(x) = f(x)g(x)\]

\((f/g)(x) = f(x)/g(x)\), as long as \(g(x) \ne 0\).

The symbols are short, but the interpretation is the main point. The new function takes the same input \(x\), sends it through both component functions, and then combines the outputs.

A good modeling process has several steps.

First, define the input. What does \(x\) mean? Is it time in minutes, number of items, distance in miles, or days since an event? The input must be clear before any function can be meaningful.

Second, define the output of each component function. What does \(f(x)\) measure? What does \(g(x)\) measure? Are they in dollars, degrees, gallons, people, meters, or points? Outputs must be compatible for addition or subtraction. You can add dollars to dollars. You cannot directly add dollars to miles unless the model has a clear conversion or meaning.

Third, choose the operation. If the situation asks for a total, addition may be appropriate. If it asks for a net amount, difference may be appropriate. If one quantity scales another, multiplication may be appropriate. If the situation asks for a rate, density, unit price, or comparison, division may be appropriate.

Fourth, write the combined function. For example, if revenue is \(R(x) = 15x\) and cost is \(C(x) = 200 + 6x\), then profit is

\[P(x) = R(x) - C(x)\].

Substitute:

\[P(x) = 15x - (200 + 6x)\].

Simplify:

\[P(x) = 9x - 200\].

Fifth, interpret the result. The coefficient 9 means each additional item increases profit by $9 after variable cost. The -200 means the business starts $200 below zero because of fixed costs. The break-even point occurs when \(P(x) = 0\), so \(9x - 200 = 0\), which gives \(x = 200/9\), or about 22.22. Since shirts are whole items, the business needs to sell at least 23 shirts to make a positive profit.

Sixth, check the domain. If \(x\) is number of shirts, then negative values make no sense. Fractional shirts may not make sense either, depending on the context. A model may be algebraically defined for all real numbers but realistically meaningful only for whole numbers greater than or equal to zero.

Consider another example. A gym plan has a monthly membership fee of $40 and charges $3 per class. Let the fixed fee be \(F(c) = 40\) and the class cost be \(G(c) = 3c\), where \(c\) is the number of classes. The total monthly cost is

\[T(c) = F(c) + G(c) = 40 + 3c\].

This may seem simple, but it shows the logic. A constant function plus a linear function creates a linear total-cost model. If another plan has \(H(c) = 70\), then comparing plans means solving \(40 + 3c = 70\). The combined model supports decision-making.

In exponential contexts, suppose a population has a base count of tagged animals that remains known and a separate untagged population estimate that grows. If \(B(t) = 500\) and \(U(t) = 300(1.04)^t\), total estimated population is \(P(t) = B(t) + U(t)\). Again, a constant function combines with an exponential function.

The key technical questions are always: What does each function represent? Are the inputs aligned? Are the outputs compatible? Which arithmetic operation matches the situation? What does the combined function mean?

Common mistakes and how to avoid them

One common mistake is combining formulas without checking the meaning of the variables. If one formula uses \(t\) for hours and another uses \(t\) for days, adding them directly is probably wrong. Convert units or redefine the input first.

Another mistake is forgetting parentheses. In the profit example, \(P(x) = 20x - (300 + 8x)\) is not the same as \(20x - 300 + 8x\). Subtracting a whole cost function means subtracting every part of the cost.

A third mistake is simplifying correctly but losing interpretation. \(20x - (300 + 8x)\) simplifies to \(12x - 300\), but the original expression shows the story more clearly. Students should learn both forms: the unsimplified model reveals structure, while the simplified model makes calculation easier.

A fourth mistake is ignoring domain restrictions. A quotient function is not defined where the denominator is zero. A real-world model may also have restrictions because of time, capacity, whole-number quantities, or physical limits.

A fifth mistake is treating function notation as multiplication. \((f + g)(x)\) does not mean \((f + g) times x\). It means the function formed by adding \(f\) and \(g\), evaluated at \(x\).

What students should be able to say

A student who understands this objective should be able to say: “A complicated model can be built from simpler functions. I can add, subtract, multiply, or divide functions when the operation matches the context. I need to make sure the input means the same thing for each function and that the outputs have compatible units. The combined function is not just a formula; it represents how the parts of a situation work together.”

Problem Library

Problems in the App From This Objective

144 problems across 12 archetypes in the app.

form `(f+g)(x)` and interpret.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Given f(x)=3x+10 and g(x)=2x+5, form and interpret (f+g)(x) for two separate costs for x items.

Problem 2

Given f(t)=60t and g(t)=45t, form and interpret (f+g)(t) for distances traveled by two vehicles.

Problem 3

Given f(n)=8n and g(n)=12n+20, form and interpret (f+g)(n) for two parts of an order cost.

Problem 4

Given f(s)=5s+100 and g(s)=3s+50, form and interpret (f+g)(s) for two separate sales figures for s days.

Problem 5

Given f(h)=h^2 and g(h)=4h, form and interpret (f+g)(h) for areas of two geometric figures based on dimension h.

Problem 6

Given f(m)=0.5m and g(m)=20, form and interpret (f+g)(m) for variable material cost and fixed shipping cost for m items.

Problem 7

Given f(t)=t^3+2t and g(t)=t^2+5, form and interpret (f+g)(t) for volumes of liquid flowing into a tank from two pipes over time t.

Problem 8

Given f(d)=100-2d and g(d)=50-d, form and interpret (f+g)(d) for remaining distances for two people in a race after d minutes.

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Problem 9

Given f(x)=x^2+3x and g(x)=2x^2+x, form and interpret (f+g)(x) for production rates of two different products as a function of labor x.

Problem 10

Given f(h)=20h and g(h)=15h+5, form and interpret (f+g)(h) for fuel consumption of two cars over h hours.

Problem 11

Given f(w)=w^2+2w and g(w)=3w^2-w, form and interpret (f+g)(w) for growth in height of two plant species over w weeks.

Problem 12

Given f(p)=0.1p and g(p)=0.05p+50, form and interpret (f+g)(p) for two sources of commission based on total sales p.

form `(f-g)(x)` and interpret sign.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Given R(x)=15x and C(x)=5x+40, form and interpret (f-g)(x) for revenue and cost.

Problem 14

Given A(t)=100-4t and B(t)=60+2t, form and interpret (f-g)(t) for amounts in two tanks.

Problem 15

Given d_1(t)=70t and d_2(t)=55t+30, form and interpret (f-g)(t) for two travel distances.

Problem 16

Given T_room(h)=75-0.5h and T_outside(h)=60+2h, form and interpret (f-g)(h) for indoor and outdoor temperatures.

Problem 17

Given P_cityA(y)=100000+500y and P_cityB(y)=80000+700y, form and interpret (f-g)(y) for populations of two cities.

Problem 18

Given A_savings(m)=5000-100m and A_checking(m)=1200-50m, form and interpret (f-g)(m) for balances in two bank accounts.

Problem 19

Given L_res1(d)=250-5d and L_res2(d)=200-3d, form and interpret (f-g)(d) for water levels in two reservoirs.

Problem 20

Given P_machine1(h)=100h and P_machine2(h)=80h+50, form and interpret (f-g)(h) for items produced by two machines.

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Problem 21

Given F_car(m)=15-0.05m and F_truck(m)=20-0.1m, form and interpret (f-g)(m) for fuel remaining in two vehicles.

Problem 22

Given D_personA(t)=10000-500t and D_personB(t)=8000-300t, form and interpret (f-g)(t) for debt amounts of two people.

Problem 23

Given A_square(s)=s^2 and A_rectangle(s)=s(s-2), form and interpret (f-g)(s) for areas of two shapes.

Problem 24

Given S(w)=5000+100w and R(w)=500+20w, form and interpret (f-g)(w) for total sales and total returns.

write `k f(x)` and interpret effect.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Given f(x)=4x+3, write 5f(x) and interpret the scaled model.

Problem 26

Given d(t)=60t, write 2f(t) and interpret the scaled model.

Problem 27

Given C(n)=8n+10, write 3f(n) and interpret the scaled model.

Problem 28

Given A(h)=15h, write 4f(h) and interpret the scaled model.

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Problem 29

Given g(x)=x^2-2x+1, write 10f(x) and interpret the scaled model.

Problem 30

Given P(p)=100-2p, write 6f(p) and interpret the scaled model.

Problem 31

Given h(y)=(1/2)y+7, write 2f(y) and interpret the scaled model.

Problem 32

Given V(r)=5r^2-2r, write 3f(r) and interpret the scaled model.

Problem 33

Given R(t)=3t^2+5t-1, write 7f(t) and interpret the scaled model.

Problem 34

Given E(m)=9m, write 8f(m) and interpret the scaled model.

Problem 35

Given T(k)=2k-5, write 4f(k) and interpret the scaled model.

Problem 36

Given W(w)=0.5w+10, write 5f(w) and interpret the scaled model.

interpret product of quantities.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Given p(x)=10-x and q(x)=5x, form the product function and interpret it for price times quantity revenue.

Problem 38

Given l(x)=x+3 and w(x)=2x, form the product function and interpret it for rectangle area.

Problem 39

Given r(t)=20t and h(t)=3, form the product function and interpret it for rectangular region with changing length and fixed height.

Problem 40

Given c(x)=2x+5 and n(x)=100-x, form the product function and interpret it for total cost of production.

Problem 41

Given r(t)=t^2+1 and T(t)=2t, form the product function and interpret it for distance traveled.

Problem 42

Given l(x)=3x and h(x)=x-1, form the product function and interpret it for area of a parallelogram.

Problem 43

Given P(s)=1000-5s and A(s)=s+10, form the product function and interpret it for total population.

Problem 44

Given v(t)=5t+10 and m(t)=2t, form the product function and interpret it for momentum of an object.

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Problem 45

Given b(x)=x+1 and h(x)=2x, form the product function and interpret it for area of a triangle.

Problem 46

Given P(t)=1000+10t and R(t)=0.05, form the product function and interpret it for annual interest earned.

Problem 47

Given F(d)=d^2 and D(d)=d+5, form the product function and interpret it for work done by a force.

Problem 48

Given w(x)=x^2 and l(x)=x+2, form the product function and interpret it for area of the base of a rectangular prism.

form quotient and state restrictions.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Given C(n)=120+6n and n, form the quotient function and state restrictions for average cost per item.

Problem 50

Given d(t)=180t and t, form the quotient function and state restrictions for average speed.

Problem 51

Given m(V)=50V and V, form the quotient function and state restrictions for density as mass per volume.

Problem 52

Given C(x) = 500 + 25x and x, form the quotient function and state restrictions for average cost per unit.

Problem 53

Given d(t) = 0.5gt^2 and t, form the quotient function and state restrictions for average velocity.

Problem 54

Given m(V) = 100 + 2V and V, form the quotient function and state restrictions for average density.

Problem 55

Given S(x) = 5x and V(x) = 100 + x, form the quotient function and state restrictions for concentration of a solution.

Problem 56

Given P(q) = 100q - 0.5q^2 and q, form the quotient function and state restrictions for average profit per item.

Problem 57

Given W(h) = 20h and h, form the quotient function and state restrictions for average work rate.

Problem 58

Given C(A) = 1000 + 5A and A, form the quotient function and state restrictions for cost per square foot.

Problem 59

Given T(s) = 80s + 50 and s, form the quotient function and state restrictions for average score per student.

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Problem 60

Given R(c) = 25c - 0.1c^2 and c, form the quotient function and state restrictions for average revenue per customer.

perform arithmetic on outputs for a given input.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Evaluate the combined function expression (f+g)(3) at 3, using f(x)=2x+1, g(x)=x^2.

Problem 62

Evaluate the combined function expression (f-g)(2) at 2, using f(x)=5x, g(x)=x+4.

Problem 63

Evaluate the combined function expression (fg)(4) at 4, using f(x)=x+1, g(x)=3x.

Problem 64

Evaluate the combined function expression (f+g)(2) at 2, using f(x)=3x-2, g(x)=x^2+1.

Problem 65

Evaluate the combined function expression (f-g)(-1) at -1, using f(x)=x^2, g(x)=2x+5.

Problem 66

Evaluate the combined function expression (fg)(0) at 0, using f(x)=x+5, g(x)=x-3.

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Problem 67

Evaluate the combined function expression (f/g)(1) at 1, using f(x)=4x+6, g(x)=x+1.

Problem 68

Evaluate the combined function expression (f+g)(4) at 4, using f(x)=10x, g(x)=x^2-4.

Problem 69

Evaluate the combined function expression (f-g)(5) at 5, using f(x)=x^2+3x, g(x)=x-7.

Problem 70

Evaluate the combined function expression (fg)(-2) at -2, using f(x)=2x-1, g(x)=-x+3.

Problem 71

Evaluate the combined function expression (f/g)(-3) at -3, using f(x)=6x+12, g(x)=x-1.

Problem 72

Evaluate the combined function expression (f+g)(3) at 3, using f(x)=x^2-1, g(x)=2x.

combine corresponding table values.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Use the table values f=7, g=5, x=2 to evaluate (f+g)(2).

Problem 74

Use the table values f=10, g=4, x=3 to evaluate (f-g)(3).

Problem 75

Use the table values f=6, g=8, x=4 to evaluate (fg)(4).

Problem 76

Use the table values f=20, g=4, x=5 to evaluate (f/g)(5).

Problem 77

Use the table values f=15, g=3, x=1 to evaluate (f+g)(1).

Problem 78

Use the table values f=12, g=7, x=6 to evaluate (f-g)(6).

Problem 79

Use the table values f=9, g=2, x=7 to evaluate (fg)(7).

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Problem 80

Use the table values f=24, g=6, x=8 to evaluate (f/g)(8).

Problem 81

Use the table values f=11, g=13, x=9 to evaluate (f+g)(9).

Problem 82

Use the table values f=5, g=10, x=10 to evaluate (f-g)(10).

Problem 83

Use the table values f=10, g=12, x=11 to evaluate (fg)(11).

Problem 84

Use the table values f=30, g=5, x=12 to evaluate (f/g)(12).

identify common input restrictions and quotient exclusions.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Find the domain restriction for the combined function (f+g)(x) given f: x >= 0, g: x <= 10.

Problem 86

Find the domain restriction for the combined function (f/g)(x) where g(x)=x-3 given f: all real numbers, g: all real numbers.

Problem 87

Find the domain restriction for the combined function (fg)(x) given f: x > 2, g: x < 8.

Problem 88

Find the domain restriction for the combined function (f-g)(x) given f: x >= -2, g: x < 7.

Problem 89

Find the domain restriction for the combined function (fg)(x) given f: x <= 5, g: all real numbers.

Problem 90

Find the domain restriction for the combined function (f/g)(x) where g(x)=x-5 given f: x > 0, g: all real numbers.

Problem 91

Find the domain restriction for the combined function (f+g)(x) given f: x >= 1, g: x >= 5.

Problem 92

Find the domain restriction for the combined function (fg)(x) given f: x > -3, g: x <= 4.

Problem 93

Find the domain restriction for the combined function (f/g)(x) where g(x)=(x-1)(x+4) given f: x >= 0, g: all real numbers.

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Problem 94

Find the domain restriction for the combined function (f+g)(x) given f: x!= 0, g: x > -5.

Problem 95

Find the domain restriction for the combined function (f/g)(x) where g(x)=x+1 given f: x >= 2, g: all real numbers.

Problem 96

Find the domain restriction for the combined function (fg)(x) given f: x <= 0, g: x >= -5.

subtract competing rates or amounts.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Build a net-change model from inflow I(t)=12t and outflow O(t)=5t for water entering and leaving a tank.

Open in simulator
Problem 98

Build a net-change model from inflow R(x)=20x and outflow C(x)=8x+50 for income and expenses.

Problem 99

Build a net-change model from inflow G(t)=100+6t and outflow L(t)=20+2t for growth and loss totals.

Problem 100

Build a net-change model from inflow A(t)=50+3t and outflow B(t)=10+t for population increase and decrease.

Problem 101

Build a net-change model from inflow P(x)=150x and outflow Q(x)=75x+200 for revenue and production costs.

Problem 102

Build a net-change model from inflow S(h)=2000 and outflow D(h)=50h for initial stock and daily consumption.

Problem 103

Build a net-change model from inflow F(t)=10t^2 and outflow G(t)=3t^2 for material added and removed from a pile.

Problem 104

Build a net-change model from inflow I(m)=500-10m and outflow O(m)=200-5m for incoming and outgoing messages.

Problem 105

Build a net-change model from inflow R(q)=100q+50 and outflow C(q)=40q+20 for sales revenue and operating expenses.

Problem 106

Build a net-change model from inflow A(d)=1000 and outflow B(d)=150 for fixed deposit and fixed withdrawal.

Problem 107

Build a net-change model from inflow E(x)=x^2+5x and outflow L(x)=2x for energy generated and energy lost.

Problem 108

Build a net-change model from inflow V(t)=300+15t and outflow W(t)=5t+10 for volume added and volume removed from a container.

decide add/subtract/multiply/divide.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Choose the function operation that matches total cost from two separate fees f(x) and g(x): add, subtract, multiply, or divide.

Problem 110

Choose the function operation that matches profit from revenue R(x) and cost C(x): add, subtract, multiply, or divide.

Problem 111

Choose the function operation that matches area from length l(x) and width w(x): add, subtract, multiply, or divide.

Problem 112

Choose the function operation that matches cost per item from total cost C(n) and number of items n: add, subtract, multiply, or divide.

Problem 113

Choose the function operation that matches total population from two cities P1(t) and P2(t): add, subtract, multiply, or divide.

Problem 114

Choose the function operation that matches combined weight of two objects W1(x) and W2(x): add, subtract, multiply, or divide.

Problem 115

Choose the function operation that matches remaining balance in an account from initial balance B(t) and withdrawal amount W(t): add, subtract, multiply, or divide.

Open in simulator
Problem 116

Choose the function operation that matches net change in altitude from initial A_initial(t) and final A_final(t): add, subtract, multiply, or divide.

Problem 117

Choose the function operation that matches total distance covered from speed S(t) and time t: add, subtract, multiply, or divide.

Problem 118

Choose the function operation that matches total calories from number of servings N and calories per serving C(N): add, subtract, multiply, or divide.

Problem 119

Choose the function operation that matches average score from total points P(n) and number of students n: add, subtract, multiply, or divide.

Problem 120

Choose the function operation that matches fuel efficiency from total distance D(g) and total gallons used g: add, subtract, multiply, or divide.

explain how components affect output.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Compare the combined model H(x)=f(x)+g(x) with f(x)=100 and g(x)=5x to its component functions fixed base plus growing amount. Explain how the components affect output.

Problem 122

Compare the combined model P(x)=R(x)-C(x) with R(x)=20x and C(x)=8x+50 to its component functions revenue and cost. Explain how the components affect output.

Problem 123

Compare the combined model A(x)=(x+3)(2x) to its component functions length x+3 and width 2x. Explain how the components affect output.

Open in simulator
Problem 124

Compare the combined model H(t) = D(t) + S with D(t) = 60t and S = 20 to its component functions distance traveled and starting position. Explain how the components affect output.

Problem 125

Compare the combined model Net(p) = Gross(p) * (1 - 0.15) with Gross(p) = 100p to its component functions gross amount and discount factor. Explain how the components affect output.

Problem 126

Compare the combined model Area(r) = pi * r^2 to its component functions pi and radius squared. Explain how the components affect output.

Problem 127

Compare the combined model AvgCost(q) = TotalCost(q) / q with TotalCost(q) = 500 + 10q to its component functions total cost and quantity. Explain how the components affect output.

Problem 128

Compare the combined model Amount(t) = Principal * (1 + Rate)^t with Principal = 1000 and Rate = 0.03 to its component functions principal amount, growth factor, time. Explain how the components affect output.

Problem 129

Compare the combined model Balance(w) = Income(w) - Expenses(w) with Income(w) = 500w and Expenses(w) = 300w + 100 to its component functions total income and total expenses. Explain how the components affect output.

Problem 130

Compare the combined model RemainingFuel(d) = InitialFuel - ConsumptionRate * d with InitialFuel = 100 and ConsumptionRate = 5 to its component functions initial fuel and fuel consumed. Explain how the components affect output.

Problem 131

Compare the combined model Density(m, v) = m / v with m = 100 and v = 2x to its component functions mass and volume. Explain how the components affect output.

Problem 132

Compare the combined model Profit(x) = (Price - CostPerUnit) * x - FixedCost with Price = 15, CostPerUnit = 5, FixedCost = 200 to its component functions per-unit profit, number of units, fixed cost. Explain how the components affect output.

detect incorrect operation, grouping, or variable use.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Find and fix the error in the combined function expression For f(x)=2x+1 and g(x)=x-3, (f+g)(x)=2x+1+x-3x.

Problem 134

Find and fix the error in the combined function expression For f(x)=x+4 and g(x)=2x, (fg)(x)=x+4(2x).

Problem 135

Find and fix the error in the combined function expression For f/g with g(x)=x-5, domain is all real numbers.

Problem 136

Find and fix the error in the combined function expression For f(x)=x^2 and g(x)=x+1, (f-g)(x)=x^2-x+1.

Problem 137

Find and fix the error in the combined function expression For f(x)=x-2 and g(x)=x+3, (fg)(x)=x-2x+3.

Open in simulator
Problem 138

Find and fix the error in the combined function expression For f(x)=3x+2 and g(x)=x-1, (f+g)(x)=3x+2+x+1.

Problem 139

Find and fix the error in the combined function expression For f(x)=x^2 and g(x)=2x, (f-g)(x)=x^2+2x.

Problem 140

Find and fix the error in the combined function expression For f/g with g(x)=x^2-4, domain is all real numbers.

Problem 141

Find and fix the error in the combined function expression For f(x)=x+1 and g(x)=x-1, (f/g)(x)=x+1/x-1.

Problem 142

Find and fix the error in the combined function expression For f(x)=2x^2+x and g(x)=x-5, (f+g)(x)=2x^2+x-5.

Problem 143

Find and fix the error in the combined function expression For f(x)=x^2 and g(x)=3, (f-g)(x)=x^2-3x.

Problem 144

Find and fix the error in the combined function expression For f/g with g(x)=x^2+x-6, domain is all real numbers.