Math I · F-IF.2

Using Function Notation to Evaluate and Interpret Relationships

Function notation gives students a precise language for naming relationships, evaluating them, comparing them, and interpreting mathematical statements in context.

Concept Functions
Domain Interpreting Functions
Read time 10 minutes

What this learning objective is really asking you to learn

This objective is asking students to become fluent in function notation. Function notation is one of the main languages of high school mathematics. It lets us name relationships, evaluate outputs, compare functions, describe contexts, and communicate precisely.

If \(f(x) = 3x + 7\), then \(f\) is the name of the function, \(x\) is the input, and \(f(x)\) is the output. The notation \(f(4)\) means “the output of function \(f\) when the input is 4.” To evaluate it, substitute 4 for \(x\):

\[f(4) = 3(4) + 7 = 19\].

This is not a new kind of arithmetic. It is substitution with meaning. The input goes into the rule, and the output comes out.

The objective also asks students to evaluate functions on their domains. That phrase matters. A domain is the set of allowed input values. If a function represents the cost of buying tickets, the input might have to be a whole number. If a function includes division, some inputs may be forbidden because they make the denominator zero. If a function includes a square root in later courses, some inputs may be forbidden because they would require taking the square root of a negative number in the real-number system. Evaluation is not just plugging in blindly; it includes checking whether the input is allowed.

Function notation also needs interpretation in context. Suppose \(C(t)\) represents the cost in dollars of renting a bike for \(t\) hours. Then \(C(3) = 24\) means “renting the bike for 3 hours costs $24.” It does not merely mean “C of 3 equals 24.” The notation is a compressed sentence. Students need to unpack it.

Similarly, if \(h(t)\) represents the height of a ball in feet after \(t\) seconds, then \(h(2) = 15\) means “after 2 seconds, the ball is 15 feet high.” If \(h(t) = 0\), that means “the ball is on the ground at time \(t\).” If \(h(0)\) is given, that is the initial height. If \(h(5) > h(3)\), that means the ball is higher at 5 seconds than at 3 seconds, at least according to the model.

Students also need to interpret statements using variables. If \(f(a) = 10\), that means the output is 10 when the input is \(a\). If \(f(x + 2)\) appears, that means the function is being evaluated at an input two units larger than \(x\). If \(f(x) + 2\) appears, that means the output of the function is increased by 2. These are different. This distinction prepares students for transformations, composition, rates of change, and calculus.

This learning objective is therefore about more than calculation. It is about reading, writing, and thinking in the language of functions.

Why students should learn this math

Students should learn function notation because it makes relationships precise. Without notation, we are stuck using long sentences. With notation, we can say a great deal clearly and compactly. \(P(10) = 250\) can mean “the profit from selling 10 items is $250.” \(T(0) = 72\) can mean “the starting temperature is 72 degrees.” \(d(5) = 300\) can mean “after 5 hours, the distance traveled is 300 miles.”

This precision matters in real life. People constantly deal with systems where outputs depend on inputs. A ride-share fare depends on miles and time. A grade depends on assignment scores. A paycheck depends on hours worked. A bank balance depends on deposits, withdrawals, fees, and interest. A delivery time depends on distance and traffic. A medication level depends on time after dosage. Function notation gives students a clean way to name these relationships.

It also prevents confusion. Suppose a teacher says, “The function \(S(t)\) gives a student’s score after \(t\) practice sessions.” Then \(S(5)\) has a clear meaning: the score after 5 sessions. The notation carries the context. If another function \(H(t)\) represents hours studied after \(t\) days, the different function name tells us we are discussing a different relationship. Names matter.

Function notation is also essential for comparing models. Suppose \(A(x)\) and \(B(x)\) represent the costs of two phone plans for \(x\) gigabytes of data. Then \(A(4) < B(4)\) means plan A is cheaper at 4 gigabytes. Solving \(A(x) = B(x)\) means finding the data usage where the plans cost the same. Writing \(A(x) - B(x)\) creates a function that measures the difference between the plans. This is practical decision mathematics.

In science, notation is unavoidable. Physicists write position as \(s(t)\), velocity as \(v(t)\), and temperature as \(T(t)\) because those quantities depend on time. Biologists may write population as \(P(t)\). Economists may write demand as \(D(p)\), where demand depends on price. Computer scientists write functions that take inputs and return outputs. Statistics uses functions to model predictions. Calculus uses function notation constantly to describe rates of change and accumulation.

For students, function notation is a gateway to reading advanced mathematics. A student who is uncomfortable with \(f(3)\), \(f(x + h)\), or \(g(f(x))\) will struggle later, not because the ideas are impossible, but because the notation feels foreign. Learning the notation early lowers the cost of future learning.

The “why” is also about mental organization. Function notation helps students separate the relationship from the input. The function \(f\) is the whole rule. The expression \(f(3)\) is one output. This is like understanding the difference between a vending machine and one snack from the machine, or the difference between an app and one result produced by the app. That distinction is essential for mathematical maturity.

Function notation also helps students understand change. If \(f(2) = 7\) and \(f(5) = 16\), the output increased by 9 while the input increased by 3. That supports rate-of-change thinking. If \(f(x + 1) - f(x)\) appears, it describes how much the function changes when the input increases by 1. That is the beginning of difference equations and, eventually, calculus.

Students should learn this because it is one of the most useful compact languages humans have invented for describing dependence, prediction, comparison, and change.

The historical machinery: naming relationships precisely

Function notation developed because mathematicians needed a clear way to discuss relationships between changing quantities. Early mathematics often described relationships in words, tables, or geometric diagrams. As algebraic symbolism developed, mathematicians gained the ability to write general rules using variables. But they also needed a way to name the rule itself.

The notation \(f(x)\) became widely associated with Leonhard Euler in the eighteenth century. Euler’s notation helped mathematics treat a function as an object that could be named, evaluated, transformed, and studied. Instead of repeatedly saying “the expression involving x,” one could name the function \(f\) and then refer to \(f(x)\), \(f(a)\), \(f(x + h)\), or other related expressions.

This was a major step in abstraction. Naming a function separates the rule from any single calculation. For example, \(f(x) = x^2 + 1\) names the whole relationship. Then \(f(3) = 10\) is one evaluation. \(f(a) = a^2 + 1\) is a symbolic evaluation. \(f(x + h) = (x + h)^2 + 1\) is an evaluation at a shifted input. The notation makes all of these possible without inventing a new sentence every time.

As functions became central to calculus, notation became even more important. Calculus studies how functions change. Expressions such as \(f(x + h) - f(x)\) compare outputs at nearby inputs. The difference quotient \([f(x + h) - f(x)]/h\) measures average rate of change over a small interval. Without function notation, these ideas would be much harder to express compactly.

In modern mathematics, function notation extends far beyond formulas. A function may be described by a graph, a table, a recursive process, a computer algorithm, a probability distribution, or an abstract mapping between sets. The notation still works because it names the relationship and specifies the input.

In computer science, the influence is obvious. Functions or procedures take inputs, perform operations, and produce outputs. A command like \(totalCost(items)\) in a program is conceptually similar to mathematical function notation. The details differ across programming languages, but the mindset is the same: name a process, give it an input, get an output.

The historical development of function notation shows why symbols matter. Good notation does not merely save space. It makes new thinking possible. When relationships can be named, they can be combined, transformed, compared, inverted, graphed, and analyzed. F-IF.2 teaches students to use that language.

Where this fits in the big map of mathematics

F-IF.2 sits immediately after the definition of function because notation is how students begin to work with functions efficiently. Understanding what a function is and using function notation are inseparable skills. Once students know that a function assigns inputs to outputs, they need a way to name those assignments.

Backward, this objective connects to substitution. Students have substituted values into expressions before. Function evaluation is substitution with the added meaning that the expression represents a named relationship.

It connects to tables and graphs. If a table says that when \(x = 4\), \(y = 13\), then we can write \(f(4) = 13\) if the table represents function \(f\). If the point \((4, 13)\) is on the graph of \(y = f(x)\), then \(f(4) = 13\). The notation ties together formulas, tables, graphs, and verbal descriptions.

It connects to domain. Students learn that not every input is allowed. This prepares them for rational functions, square-root functions, logarithmic functions, and real-world restrictions.

It connects to transformations. The difference between \(f(x) + k\) and \(f(x + k)\) depends on understanding function notation. One changes the output after evaluation; the other changes the input before evaluation.

It connects to function operations. Expressions like \((f + g)(x)\) and \(f(x) - g(x)\) require students to understand that functions can be evaluated and their outputs combined.

It connects to composition and inverse functions. Later, students will see \(f(g(x))\), which means use \(g(x)\) as the input to \(f\). Without fluency in basic notation, composition feels impossible. With fluency, it is just a chain of input-output processes.

It connects to average rate of change. The expression \([f(b) - f(a)]/(b - a)\) describes the average change in output per unit change in input. This is a major idea in algebra, modeling, and calculus.

It connects to statistics and modeling because named functions allow predictions. If \(M(t)\) models median home price at time \(t\), then \(M(2030)\) is a predicted output. If \(E(h)\) models exam score after \(h\) hours of studying, then \(E(6)\) has contextual meaning.

It connects to calculus, where notation becomes even more powerful: limits, derivatives, integrals, differential equations, and function transformations all use precise function notation.

The big-picture placement is this: F-IF.1 tells students what a function is; F-IF.2 teaches them how to speak the language of functions. That language then supports almost everything else in the Functions strand.

How to execute the skill technically

The basic procedure for evaluating a function from a formula is: identify the input, substitute it for the variable everywhere it appears, simplify carefully, and interpret the result if there is context.

Example:

\[f(x) = 2x^2 - 3x + 5\].

Evaluate \(f(4)\):

\[f(4) = 2(4)^2 - 3(4) + 5\]
\[= 2(16) - 12 + 5\]
\[= 32 - 12 + 5\]
\[= 25\].

So \(f(4) = 25\).

If the input is an expression, substitute the entire expression. For example, evaluate \(f(x + 1)\) for \(f(x) = 3x - 2\):

\[f(x + 1) = 3(x + 1) - 2 = 3x + 3 - 2 = 3x + 1\].

A common error is to write \(3x + 1 - 2\) or substitute only part of the expression. Parentheses protect the input.

From a table, evaluation means reading the output for a given input. If a table for \(g\) shows that input 6 has output 14, then \(g(6) = 14\). If the input is not listed, the table may not provide enough information unless a pattern or rule is given.

From a graph, evaluation means finding the y-value for a given x-value. If the graph of \(y = h(x)\) passes through \((2, 9)\), then \(h(2) = 9\). If the graph crosses the x-axis at \(x = 5\), then \(h(5) = 0\).

In context, always translate the notation into a sentence. If \(P(t)\) is population in thousands after \(t\) years, then \(P(8) = 42\) means “after 8 years, the population is 42 thousand.” If \(P(t) = 42\), that is a different statement: it asks for or describes the time when the population is 42 thousand. Students must distinguish evaluating a function from solving an equation involving a function.

Domain checking is part of the process. Suppose \(C(n) = 12n + 5\) represents the cost in dollars for buying \(n\) notebooks plus a shipping fee. \(C(4)\) is meaningful. \(C(-3)\) is not meaningful in the context because buying negative notebooks makes no sense. \(C(2.5)\) may also be invalid if notebooks must be whole items.

For division, check denominators. If \(f(x) = 10/(x - 2)\), then \(f(2)\) is undefined because it would require division by zero. The input 2 is not in the domain.

Students should also understand notation involving multiple functions. If \(f(x) = 2x + 1\) and \(g(x) = x^2\), then \(f(3) = 7\) and \(g(3) = 9\). The same input can be used in different functions and produce different outputs. The function name tells which rule to apply.

Another important distinction is \(f(x) + 3\) versus \(f(x + 3)\). If \(f(x) = 2x\), then:

\[f(x) + 3 = 2x + 3\].

But:

\[f(x + 3) = 2(x + 3) = 2x + 6\].

These are not the same. One adds 3 after doubling. The other adds 3 to the input before doubling.

Common mistakes and how to avoid them

The most common mistake is treating \(f(x)\) as multiplication. It does not mean \(f \cdot x\). It means the output of function \(f\) for input \(x\).

Another common mistake is substituting without parentheses. If \(f(x) = x^2\) and the input is \(x + 1\), then \(f(x + 1) = (x + 1)^2\), not \(x^2 + 1\).

A third mistake is confusing \(f(3) = 10\) with \(f(x) = 3\). The first gives an output for a specific input. The second describes a condition on outputs and may require solving for input values.

A fourth mistake is ignoring context. If \(t\) represents time after a race begins, then negative values may not be meaningful. If \(n\) represents number of people, fractional values may not make sense.

A fifth mistake is assuming every function uses \(x\). Function notation can use any input variable. \(T(t)\), \(C(n)\), \(P(r)\), and \(A(s)\) all use the same idea.

What students should be able to say

A student who understands this objective should be able to say: “Function notation names a relationship and shows the input. To evaluate a function, I substitute the input into the rule, table, or graph, while checking that the input is in the domain. I can interpret statements like \(f(3) = 12\) in context, and I know the difference between changing an input, changing an output, evaluating a function, and solving an equation involving a function.”

Problem Library

Problems in the App From This Objective

147 problems across 12 archetypes in the app.

substitute input and simplify.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Evaluate f(x)=3x+2 at x=4.

Problem 2

Evaluate g(x)=x^2-5 at x=-3.

Problem 3

Evaluate h(x)=|x-6| at x=2.

Problem 4

Evaluate f(x)=5x-7 at x=-2.

Problem 5

Evaluate f(x)=2x^2+3x-1 at x=3.

Problem 6

Evaluate f(x)=|x+5| at x=-8.

Problem 7

Evaluate f(x)=4x+10 at x=1/2.

Problem 8

Evaluate f(x)=x^3-2x at x=-1.

Open in simulator
Problem 9

Evaluate f(x)=(x+6)/3 at x=0.

Problem 10

Evaluate f(x)=2|x-10| at x=4.

Problem 11

Evaluate f(x)=-x^2+5x at x=-2.

Problem 12

Evaluate f(x)=-6x+9 at x=0.

locate input and read output.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Use the table f=4, x=1; f=7, x=2; f=10, x=3 to evaluate f(2).

Problem 14

Use the table f=5, x=-1; f=2, x=0; f=9, x=4 to evaluate f(4).

Problem 15

Use the table f=8, x=1; f=8, x=2; f=1, x=5 to evaluate f(3).

Problem 16

Use the table f=12, x=5; f=15, x=6; f=18, x=7 to evaluate f(5).

Problem 17

Use the table f=1, x=-2; f=0, x=-1; f=-1, x=0 to evaluate f(-1).

Problem 18

Use the table f=100, x=10; f=0, x=0; f=100, x=-10 to evaluate f(0).

Problem 19

Use the table f=1, x=1; f=9, x=3; f=25, x=5 to evaluate f(2).

Problem 20

Use the table f=25, x=-5; f=9, x=-3; f=1, x=-1 to evaluate f(-2).

Problem 21

Use the table f=50, x=100 to evaluate f(100).

Problem 22

Use the table f=50, x=100 to evaluate f(1).

Open in simulator
Problem 23

Use the table f=9, x=-3; f=1, x=-1; f=0, x=0; f=1, x=1; f=9, x=3 to evaluate f(-3).

Problem 24

Use the table f=9, x=-3; f=1, x=-1; f=0, x=0; f=1, x=1; f=9, x=3 to evaluate f(2).

read y-value for a given x-value.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Use the graph description the graph contains point (3,8) to evaluate f(3).

Problem 26

Use the graph description at x=-2, the y-value is 5 to evaluate f(-2).

Problem 27

Use the graph description closed endpoint at (4,1) and open point at (4,6) to evaluate f(4).

Problem 28

Use the graph description the graph passes through (7, -3) to evaluate f(7).

Problem 29

Use the graph description a point on the graph is (-1, 0) to evaluate f(-1).

Problem 30

Use the graph description when x=0, y=10 to evaluate f(0).

Problem 31

Use the graph description there is an open circle at (2, 5) and a closed circle at (2, -1) to evaluate f(2).

Problem 32

Use the graph description at x=-5, there's an open point at y=2 and a closed point at y=7 to evaluate f(-5).

Problem 33

Use the graph description the function has a value of 9 when x is 6 to evaluate f(6).

Problem 34

Use the graph description the y-coordinate is -4 when the x-coordinate is -8 to evaluate f(-8).

Problem 35

Use the graph description at x=0, there's an open point at (0, -3) and a closed point at (0, 4) to evaluate f(0).

Problem 36

Use the graph description the graph contains the point (100, 25) to evaluate f(100).

Open in simulator
translate notation into an input-output sentence.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Interpret the notation C(5)=35 in the context C(n) is cost in dollars for n tickets.

Problem 38

Interpret the notation h(3)=18 in the context h(t) is plant height in cm after t weeks.

Open in simulator
Problem 39

Interpret the notation T(14)=72 in the context T(d) is temperature on day d.

Problem 40

Interpret the notation D(2)=120 in the context D(t) is distance in miles traveled after t hours.

Problem 41

Interpret the notation P(10)=5000 in the context P(y) is population in people after y years.

Problem 42

Interpret the notation F(300)=10 in the context F(m) is fuel consumed in gallons for m miles driven.

Problem 43

Interpret the notation B(45)=350 in the context B(t) is oven temperature in degrees Fahrenheit after t minutes.

Problem 44

Interpret the notation R(7)=2.5 in the context R(d) is total rainfall in inches after d days.

Problem 45

Interpret the notation S(3)=85 in the context S(h) is exam score in percentage after h hours of study.

Problem 46

Interpret the notation W(8)=15 in the context W(h) is water level in feet after h hours.

Problem 47

Interpret the notation C(100)=500 in the context C(u) is cost in dollars to produce u units.

Problem 48

Interpret the notation L(5)=75 in the context L(t) is battery charge remaining in percent after t hours.

solve `f(x)=c` or read inverse question from representation.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Find the input value(s) for which f(x)=2x+3 has output 11.

Problem 50

Find the input value(s) for which g(x)=x^2 has output 9.

Problem 51

Find the input value(s) for which h(x)=|x-2| has output 5.

Problem 52

Find the input value(s) for which p(x)=x^2+4 has output 1.

Open in simulator
Problem 53

Find the input value(s) for which f(x)=3x-5 has output 7.

Problem 54

Find the input value(s) for which g(x)=-x+10 has output 2.

Problem 55

Find the input value(s) for which h(x)=x^2-1 has output 8.

Problem 56

Find the input value(s) for which k(x)=(x+1)^2 has output 4.

Problem 57

Find the input value(s) for which m(x)=|x| has output 6.

Problem 58

Find the input value(s) for which n(x)=|x+3| has output 1.

Problem 59

Find the input value(s) for which q(x)=x^2+5 has output 2.

Problem 60

Find the input value(s) for which r(x)=|x-1| has output -4.

substitute expressions like `x+h` or `2a`.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Evaluate f(x)=3x+2 at the algebraic input x+h.

Problem 62

Evaluate g(x)=x^2 at the algebraic input a+1.

Problem 63

Evaluate p(x)=2x-5 at the algebraic input 4t.

Problem 64

Evaluate f(x)=5x-3 at the algebraic input y-2.

Problem 65

Evaluate h(x)=x^2+1 at the algebraic input k-3.

Open in simulator
Problem 66

Evaluate f(x)=x^2-4x at the algebraic input t+1.

Problem 67

Evaluate g(x)=2x^2+x at the algebraic input m+h.

Problem 68

Evaluate f(x)=-x+7 at the algebraic input 2z+1.

Problem 69

Evaluate q(x)=3x^2-2x+1 at the algebraic input w-1.

Problem 70

Evaluate f(x)=1/2 x+4 at the algebraic input 2k-6.

Problem 71

Evaluate r(x)=(x+1)^2 at the algebraic input y-1.

Problem 72

Evaluate s(x)=x^3 at the algebraic input a+2.

choose the correct rule based on input domain.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Evaluate the piecewise function f(x)=x+2 for x<0; f(x)=3x for x>=0 at x=-4.

Problem 74

Evaluate the piecewise function f(x)=x+2 for x<0; f(x)=3x for x>=0 at x=2.

Problem 75

Evaluate the piecewise function g(x)=5 for x<=1; g(x)=x^2 for x>1 at x=1.

Problem 76

Evaluate the piecewise function g(x)=5 for x<=1; g(x)=x^2 for x>1 at x=3.

Open in simulator
Problem 77

Evaluate the piecewise function h(x)=2x-1 for x<5; h(x)=x+4 for x>=5 at x=4.

Problem 78

Evaluate the piecewise function h(x)=2x-1 for x<5; h(x)=x+4 for x>=5 at x=5.

Problem 79

Evaluate the piecewise function h(x)=2x-1 for x<5; h(x)=x+4 for x>=5 at x=7.

Problem 80

Evaluate the piecewise function k(t)=t^2 for t<-1; k(t)=t+3 for -1<=t<2; k(t)=2t for t>=2 at t=-2.

Problem 81

Evaluate the piecewise function k(t)=t^2 for t<-1; k(t)=t+3 for -1<=t<2; k(t)=2t for t>=2 at t=-1.

Problem 82

Evaluate the piecewise function k(t)=t^2 for t<-1; k(t)=t+3 for -1<=t<2; k(t)=2t for t>=2 at t=2.

Problem 83

Evaluate the piecewise function k(t)=t^2 for t<-1; k(t)=t+3 for -1<=t<2; k(t)=2t for t>=2 at t=0.

Problem 84

Evaluate the piecewise function m(y)=y^2+1 for y<=-3; m(y)=y-5 for y>-3 at y=-3.

apply domain restrictions.
15 problems Warmup Practice Mixed Review Assessment
Problem 85

Before evaluating f(x)=sqrt(x-2) at x=5, determine whether the input is in the domain.

Problem 86

Before evaluating f(x)=sqrt(x-2) at x=1, determine whether the input is in the domain.

Problem 87

Before evaluating g(x)=1/(x-4) at x=4, determine whether the input is in the domain.

Problem 88

Before evaluating C(n)=8n for integer ticket counts 0 to 10 at n=3.5, determine whether the input is in the domain.

Problem 89

Before evaluating f(x)=sqrt(x+3) at x=-2, determine whether the input is in the domain.

Problem 90

Before evaluating f(x)=sqrt(x+3) at x=-5, determine whether the input is in the domain.

Problem 91

Before evaluating g(x)=sqrt(9-x^2) at x=0, determine whether the input is in the domain.

Problem 92

Before evaluating g(x)=sqrt(9-x^2) at x=4, determine whether the input is in the domain.

Problem 93

Before evaluating h(x)=1/(x+5) at x=0, determine whether the input is in the domain.

Problem 94

Before evaluating h(x)=1/(x+5) at x=-5, determine whether the input is in the domain.

Problem 95

Before evaluating k(x)=x/(x^2-4) at x=1, determine whether the input is in the domain.

Open in simulator
Problem 96

Before evaluating k(x)=x/(x^2-4) at x=2, determine whether the input is in the domain.

Problem 97

Before evaluating M(t)=100t for t representing whole hours worked, 0 to 8 at t=5, determine whether the input is in the domain.

Problem 98

Before evaluating M(t)=100t for t representing whole hours worked, 0 to 8 at t=9, determine whether the input is in the domain.

Problem 99

Before evaluating P(c)=5c for c representing number of people, must be a positive integer at c=0.5, determine whether the input is in the domain.

identify units of input and output.
12 problems Warmup Practice Mixed Review Assessment
Problem 100

Interpret the units in C(4)=28 for C(n) is total cost in dollars for n tickets.

Problem 101

Interpret the units in d(3)=180 for d(t) is distance in miles after t hours.

Problem 102

Interpret the units in P(2026)=12000 for P(y) is population in year y.

Problem 103

Interpret the units in T(5)=70 for T(h) is temperature in degrees Fahrenheit after h hours.

Open in simulator
Problem 104

Interpret the units in V(10)=500 for V(m) is volume of water in liters after m minutes.

Problem 105

Interpret the units in C(100)=2500 for C(x) is total cost in dollars to produce x items.

Problem 106

Interpret the units in H(2)=64 for H(t) is height of a ball in feet after t seconds.

Problem 107

Interpret the units in R(50)=1000 for R(q) is total revenue in dollars from selling q units.

Problem 108

Interpret the units in B(3)=800 for B(d) is number of bacteria after d days.

Problem 109

Interpret the units in F(200)=10 for F(m) is fuel consumed in gallons after driving m miles.

Problem 110

Interpret the units in W(3)=15 for W(s) is weight in pounds of s identical objects.

Problem 111

Interpret the units in S(4)=60 for S(t) is speed in miles per hour after t hours.

evaluate and compare outputs.
12 problems Warmup Practice Mixed Review Assessment
Problem 112

Compare f(3) and f(5) using f(x)=2x+1.

Problem 113

Compare f(1) and f(3) using table: f(1)=8, f(2)=6, f(3)=6.

Open in simulator
Problem 114

Compare g(-4) and g(3) using g(x)=x^2.

Problem 115

Compare h(2) and h(7) using h(x)=5-x.

Problem 116

Compare k(-2) and k(4) using k(x)=|x-1|.

Problem 117

Compare p(-1) and p(2) using p(x)=x^3.

Problem 118

Compare q(0) and q(5) using q(x)=sqrt(x+4).

Problem 119

Compare f(1) and f(3) using f(x)=-3x+10.

Problem 120

Compare g(2) and g(4) using g(x)=1/x.

Problem 121

Compare m(0) and m(2) using table: m(0)=10, m(1)=5, m(2)=10, m(3)=15.

Problem 122

Compare r(-1) and r(1) using r(t)=t^2-5.

Problem 123

Compare s(3) and s(0) using s(y)=2^y.

distinguish evaluating, solving, and expression input.
12 problems Warmup Practice Mixed Review Assessment
Problem 124

Explain the meaning of the notation f(3) for a function f.

Problem 125

Explain the meaning of the notation f(x)=7 for a function f.

Problem 126

Explain the meaning of the notation f(a+h) for a function f.

Problem 127

Explain the meaning of the notation f(3)=10 for a function f.

Problem 128

Explain the meaning of the notation f(a) for a function f.

Problem 129

Explain the meaning of the notation f(-2) for a function f.

Problem 130

Explain the meaning of the notation f(2x) for a function f.

Problem 131

Explain the meaning of the notation f(x)=y for a function f.

Problem 132

Explain the meaning of the notation f(a)=b for a function f.

Problem 133

Explain the meaning of the notation f(0) for a function f.

Problem 134

Explain the meaning of the notation f(x-1) for a function f.

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Problem 135

Explain the meaning of the notation f(t)=5 for a function f.

preserve parentheses and operation order.
12 problems Warmup Practice Mixed Review Assessment
Problem 136

Find and correct the substitution error in For f(x)=x^2, f(-3)=-3^2=-9.

Problem 137

Find and correct the substitution error in For f(x)=2x+5, f(x+1)=2x+1+5.

Problem 138

Find and correct the substitution error in For g(x)=3-x, g(4)=3-4=1.

Problem 139

Find and correct the substitution error in For f(x)=x^3, f(-2)=-2^3=-8.

Problem 140

Find and correct the substitution error in For h(x)=3(x-1), h(x+2)=3x+2-1.

Problem 141

Find and correct the substitution error in For g(x)=5x-7, g(3)=5*3-7=10-7=3.

Problem 142

Find and correct the substitution error in For f(x)=2+3x, f(4)=2+3*4=5*4=20.

Problem 143

Find and correct the substitution error in For h(x)=5-(x+2), h(x)=5-x+2=7-x.

Problem 144

Find and correct the substitution error in For f(x)=(x+1)^2, f(x)=x^2+1^2=x^2+1.

Problem 145

Find and correct the substitution error in For f(x)=12/x, f(3)=12/3=3.

Problem 146

Find and correct the substitution error in For g(x)=-4x, g(-2)=-4*-2=-8.

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Problem 147

Find and correct the substitution error in For f(x)=3x^2, f(2)=(3*2)^2=6^2=36.