Math I · F-LE.1.b

Recognizing Constant Rate of Change as Evidence for a Linear Model

Constant rate of change is the math behind steady speed, hourly pay, unit price, fixed monthly charges, straight-line depreciation, and many everyday predictions where each additional unit adds the same amount.

Concept Functions
Domain Linear, Quadratic, and Exponential Models
Read time 9 minutes

What this learning objective is really asking you to learn

This objective asks students to recognize when a relationship is linear because one quantity changes at a constant rate per unit interval relative to another. In plain language, every equal step in the input adds or subtracts the same amount in the output. That constant amount per input unit is the slope.

For example, suppose a parking garage charges 5 dollars per hour plus a 3 dollar entry fee. Each additional hour adds exactly 5 dollars. The cost is linear because the rate of change is constant. A rule is \(C(h) = 5h + 3\), where \(h\) is hours and \(C(h)\) is cost. The slope is 5 dollars per hour, and the vertical intercept is 3 dollars.

A constant rate of change can appear in a table. If the inputs are 0, 1, 2, 3, 4 and the outputs are 12, 19, 26, 33, 40, the output increases by 7 for every increase of 1 in the input. The rate of change is 7 per input unit. The relationship is linear. If the inputs are 0, 2, 4, 6 and the outputs are 10, 18, 26, 34, the output increases by 8 for every 2 input units, so the rate is 4 per one input unit. The relationship is still linear because the rate per unit is constant.

On a graph, constant rate of change appears as a straight line. The line's slope tells how much the output changes for each one-unit increase in input. A positive slope means the output increases. A negative slope means it decreases. A slope of zero means the output stays constant. A steeper line has a larger rate of change in magnitude, assuming the axes use the same scale and units are interpreted correctly.

In an equation written as \(y = mx + b\), the constant rate of change is \(m\). The number \(b\) is the output when the input is zero. Students often learn this as a formula, but the formula is not the heart of the idea. The heart is that a linear relationship has a predictable additive pattern: start with \(b\), then add \(m\) for each input unit.

Why students should learn this math

Students should learn constant rate of change because it is one of the most common patterns in daily life. Hourly wages, miles driven at constant speed, cost per item, water filling a tank at a steady rate, calories burned per minute at a steady pace, printing pages per minute, and monthly subscription charges all use linear thinking when the rate stays constant.

This math helps students make quick, practical decisions. If a rideshare charges a base fee plus a fixed amount per mile, the slope is the per-mile charge and the intercept is the base fee. If a job pays a fixed hourly wage, the slope is dollars per hour. If a car travels at 60 miles per hour, the slope is 60 miles per hour. If a plant grows 2 centimeters per week for a short measured period, the slope is 2 centimeters per week. These are not artificial textbook examples. They are units of real change.

Constant rate of change also supports fairness and comparison. If two phone plans have different base fees and different per-GB charges, students can compare slopes and intercepts. A lower intercept might be attractive for low usage, while a lower slope may be better for high usage. Without understanding constant rate of change, students may compare only starting prices and miss the long-term cost.

It also supports science. In physics, constant speed is a linear distance-time relationship. In chemistry, a reaction might be approximated linearly over a small interval. In environmental science, a reservoir might be draining at a roughly constant rate. In engineering, a machine may produce a constant number of units per minute. Even when the real world is not perfectly linear forever, linear models are often useful over limited domains.

Students should also learn this objective because linear thinking can be misused. People often assume a constant rate continues forever when it does not. A plant may grow roughly linearly for a few weeks but not indefinitely. A business may gain customers steadily for a quarter but later accelerate or slow down. A car may travel at constant speed on a highway but not in traffic. Recognizing constant rate of change includes recognizing the domain where the constant-rate assumption is reasonable.

Where this objective fits on the full map of mathematics

Constant rate of change is the backbone of linear functions. It connects arithmetic, algebra, graphing, geometry, statistics, and calculus. In arithmetic, students learn unit rates and proportional relationships. In algebra, those rates become slopes. In graphing, slope becomes the steepness of a line. In statistics, slope becomes the rate in a linear model fitted to data. In calculus, slope becomes the derivative, the instantaneous rate of change.

This objective follows naturally from average rate of change. Any function can have an average rate of change over an interval, but a linear function has the same average rate of change over every interval. That is what makes it linear. If \(f(x) = 3x + 8\), the average rate of change from \(x = 0\) to \(x = 2\) is 3, from \(x = 5\) to \(x = 9\) is 3, and from \(x = -10\) to \(x = 100\) is still 3. The rate does not depend on where you measure.

This objective also prepares students for systems of equations. When two linear models are compared, their slopes and intercepts determine whether they intersect, are parallel, or are the same line. In real life, that intersection may be the break-even point between two cost plans or the time when two moving objects meet.

Later, students will study non-linear rates. Quadratic functions have changing rates of change. Exponential functions have rates that are proportional to the current amount. Trigonometric functions have rates that vary cyclically. Calculus studies changing rates with precision. But constant rate is the foundation. Students need to understand the simple case deeply before they can understand more complex change.

The historical machinery behind constant rate

Constant rate of change comes from measurement. People needed to measure how far, how fast, how much, and how costly. If a worker earns the same amount each day, total pay grows linearly. If a merchant sells cloth at a fixed price per yard, cost grows linearly. If a cart moves at a steady pace, distance grows linearly with time. These ideas existed long before modern algebra notation.

Coordinate geometry later gave constant rate a visual form. A straight line on a coordinate plane shows a relationship where the ratio of vertical change to horizontal change stays the same. The line is not merely a drawing; it is a picture of constant change. This connection between algebra and geometry made slope a central mathematical object.

The rise of science made rates even more important. Motion, force, density, pressure, speed, and flow all involve quantities changing relative to other quantities. A rate is a comparison between changes. Linear models became a first language for describing the physical world, especially when conditions are controlled or when a small interval can be approximated as straight.

Today, constant-rate thinking appears in spreadsheets, contracts, dashboards, invoices, maps, and engineering systems. The historical machinery has become ordinary life. The student who understands slope understands a hidden structure behind many adult decisions.

The technical machinery: calculating and interpreting constant rate

The rate of change between two points \((x1, y1)\) and \((x2, y2)\) is \((y2 - y1)/(x2 - x1)\). For a linear function, this value is constant for every pair of points on the line. Students should always attach units. If \(y\) is dollars and \(x\) is hours, the rate is dollars per hour. If \(y\) is miles and \(x\) is gallons, the rate is miles per gallon. Units are not decoration; they explain what the slope means.

From a table, choose two rows and compute the change in output divided by the change in input. Then check another pair to see whether the rate is the same. For example:

| Hours | 0 | 2 | 4 | 6 | |---:|---:|---:|---:|---:| | Cost | 15 | 27 | 39 | 51 |

The cost increases by 12 dollars every 2 hours, so the rate is 6 dollars per hour. Since this pattern continues through the table, a linear model is appropriate for the given data. The cost at zero hours is 15 dollars, so a rule is \(C(h) = 6h + 15\).

From a graph, pick two clear points, calculate rise over run, and read the intercept if visible. If the graph crosses the y-axis at 20 and rises 30 units for every 5 units to the right, the slope is 6. The rule is \(y = 6x + 20\) if the graph is exactly linear and the context supports it.

From words, identify fixed starting amounts and per-unit changes. “A plumber charges 80 dollars to visit and 45 dollars per hour” means the intercept is 80 and the slope is 45 dollars per hour. “A tank starts with 500 gallons and loses 12 gallons per minute” means the intercept is 500 and the slope is -12 gallons per minute. The negative sign matters because the output decreases.

From an equation, read the slope if the equation is in slope-intercept form. If it is not, rearrange or compare coefficients carefully. For \(2x + y = 14\), solving for \(y\) gives \(y = -2x + 14\), so the rate of change is -2. For \(3y = 12x + 9\), dividing by 3 gives \(y = 4x + 3\), so the rate is 4.

Linear models and the danger of overextension

Linear models are powerful because they are simple. But simplicity is not the same as universal truth. A constant-rate model may work over a particular domain and fail outside it. If a bathtub fills at 3 gallons per minute, a linear model may work until the tub is full. After that, the model breaks because the water cannot keep rising in the same way. If a student earns 15 dollars per hour, the model works for hours actually worked, not for 10,000 hours in a week. If a car depreciates by 2,000 dollars per year, the model may eventually predict a negative value, which may not make sense.

This is why domain and context are part of mastery. Recognizing constant rate of change does not mean blindly extending a line forever. It means using a linear model where the constant-rate assumption is reasonable. The graph of a line extends infinitely in both directions as a mathematical object, but the real-world situation may not.

Common mistakes and how to avoid them

A common mistake is confusing slope with y-intercept. The slope is how much the output changes per input unit. The intercept is the output when the input is zero. In a taxi model, the base fee and the per-mile fee are different features. Mixing them leads to wrong comparisons.

Another mistake is ignoring units. A slope of 5 means little by itself. Five dollars per hour, five miles per gallon, five points per game, and five gallons per minute are completely different meanings. Students should train themselves to say the units every time.

A third mistake is using unequal input intervals incorrectly. If a table jumps from 1 to 2 to 5 to 10, students cannot just compare output differences directly. They must divide by the input change to see whether the rate per unit is constant.

A fourth mistake is assuming any nearly straight data set is perfectly linear. Real data may have noise. A scatter plot may suggest a linear association even if the points do not fall exactly on a line. In later statistics standards, students learn to fit linear models and study residuals. Here, the focus is exact or clearly described constant rate, but students should know that real data can be approximate.

How students know they have mastered this objective

Students have mastered this objective when they can identify a linear relationship from any representation and explain the constant rate with units. They can write a model like \(y = mx + b\), interpret \(m\) and \(b\), and use the model to answer questions within a reasonable domain.

They should also be able to compare a constant-rate situation with a percent-rate situation. “Adds 20 dollars each week” is linear. “Increases by 20 percent each week” is exponential. “Loses 5 gallons each minute” is linear. “Loses 5 percent each minute” is exponential. Those distinctions are the practical heart of the standard.

The deeper sign of mastery is that students see slope as a measurement of steady change. It is not just a number beside \(x\). It is the machinery of a straight-line model.

Problem Library

Problems in the App From This Objective

144 problems across 12 archetypes in the app.

compute output change per input change.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Find the constant rate of change for the table with points 0, 5; 2, 11; 4, 17.

Problem 2

Find the constant rate of change for the table with points 1, 20; 3, 12; 5, 4.

Problem 3

Find the constant rate of change for the table with points 0, 7; 5, 7; 10, 7.

Problem 4

Find the constant rate of change for the table with points 1, 3; 3, 9; 5, 15.

Problem 5

Find the constant rate of change for the table with points 0, 10; 2, 6; 4, 2.

Problem 6

Find the constant rate of change for the table with points 1, 100; 4, 100; 7, 100.

Problem 7

Find the constant rate of change for the table with points 0, 0; 2, 1; 4, 2.

Problem 8

Find the constant rate of change for the table with points 0, 3; 3, 2; 6, 1.

Problem 9

Find the constant rate of change for the table with points 10, 50; 15, 75; 20, 100.

Problem 10

Find the constant rate of change for the table with points 10, 100; 12, 80; 14, 60.

Problem 11

Find the constant rate of change for the table with points -2, 1; 0, 5; 2, 9.

Open in simulator
Problem 12

Find the constant rate of change for the table with points 0, -1; 1, -3; 2, -5.

compare slopes across intervals.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Verify whether the table 0, 2; 3, 11; 7, 23 has a constant rate of change.

Problem 14

Verify whether the table 1, 4; 2, 9; 4, 21 has a constant rate of change.

Problem 15

Verify whether the table 0, 18; 4, 10; 10, -2 has a constant rate of change.

Problem 16

Verify whether the table 1, 5; 3, 11; 6, 20 has a constant rate of change.

Problem 17

Verify whether the table 0, 10; 2, 6; 5, 0 has a constant rate of change.

Problem 18

Verify whether the table 0, 1; 2, 7; 5, 19 has a constant rate of change.

Problem 19

Verify whether the table 1, 20; 3, 12; 6, 3 has a constant rate of change.

Problem 20

Verify whether the table 0, 7; 3, 7; 8, 7 has a constant rate of change.

Problem 21

Verify whether the table 0, 0; 2, 4; 5, 1 has a constant rate of change.

Problem 22

Verify whether the table 0, 0; 2, 3; 6, 9 has a constant rate of change.

Open in simulator
Problem 23

Verify whether the table 0, 0; 3, 2; 5, 5 has a constant rate of change.

Problem 24

Verify whether the table 0, 10; 2, 14; 5, 20; 7, 24 has a constant rate of change.

recognize straight-line behavior and slope.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Find the constant rate of change of the line passing through graph points 0, 1; 4, 9.

Problem 26

Find the constant rate of change of the line passing through graph points -2, 6; 2, -2.

Problem 27

Find the constant rate of change of the line passing through graph points -3, 5; 5, 5.

Open in simulator
Problem 28

Find the constant rate of change of the line passing through graph points 1, 2; 3, 8.

Problem 29

Find the constant rate of change of the line passing through graph points 0, 5; 5, 0.

Problem 30

Find the constant rate of change of the line passing through graph points 1, 3; 7, 3.

Problem 31

Find the constant rate of change of the line passing through graph points -1, -1; 1, 3.

Problem 32

Find the constant rate of change of the line passing through graph points -5, 10; 5, 0.

Problem 33

Find the constant rate of change of the line passing through graph points -4, -7; 0, -3.

Problem 34

Find the constant rate of change of the line passing through graph points 1, 7; 3, 1.

Problem 35

Find the constant rate of change of the line passing through graph points -2, -4; 6, -4.

Problem 36

Find the constant rate of change of the line passing through graph points 10, 20; 15, 30.

recognize same change per unit input.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Identify the constant rate of change in the context: A car travels 180 miles in 3 hours at a constant speed.

Problem 38

Identify the constant rate of change in the context: A faucet adds 12 gallons in 4 minutes at a constant rate.

Problem 39

Identify the constant rate of change in the context: A balance decreases by 45 dollars over 5 weeks at a constant rate.

Open in simulator
Problem 40

Identify the constant rate of change in the context: A cyclist covers 50 kilometers in 2 hours at a constant speed.

Problem 41

Identify the constant rate of change in the context: A water tank drains 100 liters in 20 minutes at a constant rate.

Problem 42

Identify the constant rate of change in the context: A savings account balance increases by 15 dollars in 3 months at a constant rate.

Problem 43

Identify the constant rate of change in the context: A plant grows 15 centimeters in 5 weeks at a constant rate.

Problem 44

Identify the constant rate of change in the context: The temperature drops 18 degrees Celsius in 3 hours at a constant rate.

Problem 45

Identify the constant rate of change in the context: A train travels 300 miles in 6 hours at a constant speed.

Problem 46

Identify the constant rate of change in the context: A pump fills a pool with 500 gallons in 10 minutes at a constant rate.

Problem 47

Identify the constant rate of change in the context: A debt increases by 60 dollars over 4 months at a constant rate.

Problem 48

Identify the constant rate of change in the context: A file downloads 200 megabytes in 40 seconds at a constant rate.

build `f(x)=mx+b`.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Write a linear model with constant rate 4 and initial value 9.

Problem 50

Write a linear model with constant rate -3 and initial value 20.

Problem 51

Write a linear model with constant rate 1/2 and initial value 6.

Problem 52

Write a linear model with constant rate 5 and initial value 10.

Problem 53

Write a linear model with constant rate -2 and initial value -7.

Problem 54

Write a linear model with constant rate 0 and initial value 15.

Problem 55

Write a linear model with constant rate -3/4 and initial value 8.

Problem 56

Write a linear model with constant rate 2.5 and initial value -5.

Problem 57

Write a linear model with constant rate 7 and initial value 0.

Open in simulator
Problem 58

Write a linear model with constant rate 1/3 and initial value -0.4.

Problem 59

Write a linear model with constant rate -1.5 and initial value 3.2.

Problem 60

Write a linear model with constant rate 100 and initial value 1.

attach units and direction to slope.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Interpret the constant rate of change 18 dollars per hour in the context money earned after hours worked.

Problem 62

Interpret the constant rate of change -0.08 miles per minute in the context distance from home after minutes walking toward home.

Problem 63

Interpret the constant rate of change 2 points per game in the context team points after games played.

Problem 64

Interpret the constant rate of change -3 liters per minute in the context water level in a pool after minutes of draining.

Problem 65

Interpret the constant rate of change 2.50 dollars per mile in the context cost of a taxi ride after miles traveled.

Problem 66

Interpret the constant rate of change -1.5 pages per minute in the context number of remaining pages in a book after minutes of reading.

Problem 67

Interpret the constant rate of change 0.5 inches per day in the context plant height after days.

Problem 68

Interpret the constant rate of change -0.2 degrees Celsius per minute in the context temperature of a cooling object after minutes.

Problem 69

Interpret the constant rate of change -0.05 gallons per mile in the context amount of fuel in a car after miles driven.

Problem 70

Interpret the constant rate of change 150 people per year in the context population of a town after years.

Problem 71

Interpret the constant rate of change 12.75 dollars per unit in the context total sales revenue after units sold.

Problem 72

Interpret the constant rate of change -200 feet per minute in the context altitude of a descending airplane after minutes.

Open in simulator
extend or interpolate linearly.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Use constant rate to find the missing value in points (0,4), (2,10), (5,?).

Problem 74

Use constant rate to find the missing value in points (1,15), (3,9), (?,0).

Problem 75

Use constant rate to find the missing value in points (0,8), (4,8), (9,?).

Problem 76

Use constant rate to find the missing value in points (1,5), (3,11), (7,?).

Problem 77

Use constant rate to find the missing value in points (10,50), (12,40), (15,?).

Problem 78

Use constant rate to find the missing value in points (2,7), (4,13), (?,22).

Problem 79

Use constant rate to find the missing value in points (5,30), (7,20), (?,5).

Problem 80

Use constant rate to find the missing value in points (3,10), (8,10), (12,?).

Problem 81

Use constant rate to find the missing value in points (1,2), (3,5), (7,?).

Problem 82

Use constant rate to find the missing value in points (0,10), (2,7), (?,1).

Problem 83

Use constant rate to find the missing value in points (-2,1), (0,7), (3,?).

Problem 84

Use constant rate to find the missing value in points (1,-5), (3,-11), (?,-20).

Open in simulator
judge constant-rate assumption.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Decide whether A worker earns 16 dollars for each hour worked plus no bonus. should be modeled linearly.

Open in simulator
Problem 86

Decide whether A bacteria culture doubles every hour. should be modeled linearly.

Problem 87

Decide whether A taxi fare has a 4 dollar start fee plus 2 dollars per mile. should be modeled linearly.

Problem 88

Decide whether A car travels at a constant speed of 60 miles per hour. should be modeled linearly.

Problem 89

Decide whether An investment earns 5% interest compounded annually. should be modeled linearly.

Problem 90

Decide whether The cost of apples is 1.50 dollars per pound. should be modeled linearly.

Problem 91

Decide whether The area of a square as its side length increases. should be modeled linearly.

Problem 92

Decide whether A car consumes gasoline at a rate of 0.05 gallons per mile. should be modeled linearly.

Problem 93

Decide whether A town's population increases by 2% each year. should be modeled linearly.

Problem 94

Decide whether Rent for an apartment increases by 50 dollars every year. should be modeled linearly.

Problem 95

Decide whether A radioactive substance decays by half every 10 years. should be modeled linearly.

Problem 96

Decide whether A water tank is filled at a constant rate of 10 liters per minute. should be modeled linearly.

compute and interpret slopes from different representations.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Compare the constant rates in f(x)=5x+2 and table points (0,1),(2,7).

Problem 98

Compare the constant rates in graph through (1,8) and (4,2) and g(x)=-3x+10.

Problem 99

Compare the constant rates in a tank fills 20 gallons in 4 minutes and h(x)=6x+1.

Problem 100

Compare the constant rates in y = 10 - 2x and A car travels 150 miles in 3 hours.

Problem 101

Compare the constant rates in table points (-1, 5), (1, 9) and graph passing through (0,0) and (3,-6).

Problem 102

Compare the constant rates in A plant grows 12 cm in 6 weeks. and f(x) = 2x - 5.

Problem 103

Compare the constant rates in graph with points (0, 10) and (5, 0) and table points (1, 3), (3, 7).

Problem 104

Compare the constant rates in g(x) = 0.5x + 3 and A faucet drips 1 liter in 2 hours.

Problem 105

Compare the constant rates in table points (0, 100), (10, 0) and h(x) = -5x + 20.

Problem 106

Compare the constant rates in A runner covers 10 miles in 1 hour. and graph through (-2, -5) and (0, 5).

Open in simulator
Problem 107

Compare the constant rates in f(x) = -x + 7 and A temperature drops 15 degrees in 3 hours.

Problem 108

Compare the constant rates in graph passing through (2, 1) and (4, 7) and table points (0, 0), (5, 10).

cite changing slopes.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Explain why the table 0, 1; 1, 3; 2, 7; 3, 13 is not linear.

Problem 110

Explain why the table 0, 2; 2, 8; 4, 32; 6, 128 is not linear.

Problem 111

Explain why the table 1, 5; 3, 10; 6, 13 is not linear.

Problem 112

Explain why the table 0, 0; 1, 1; 2, 4; 3, 9 is not linear.

Problem 113

Explain why the table -1, 1; 0, 0; 1, 1; 2, 4 is not linear.

Problem 114

Explain why the table 0, 1; 1, 2; 2, 4; 3, 8 is not linear.

Problem 115

Explain why the table 1, 10; 2, 8; 3, 6; 4, 4.5 is not linear.

Problem 116

Explain why the table 0, 0; 2, 4; 4, 16; 6, 36 is not linear.

Problem 117

Explain why the table -2, 4; -1, 1; 0, 0; 1, 1 is not linear.

Problem 118

Explain why the table 0, 5; 1, 7; 3, 11; 6, 20 is not linear.

Open in simulator
Problem 119

Explain why the table 0, 100; 1, 50; 2, 25; 3, 12.5 is not linear.

Problem 120

Explain why the table -3, 9; -1, 1; 1, 1; 3, 9 is not linear.

solve using constant rate.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

For the linear model f(x)=4x+7, find the x-value when the output reaches 31.

Problem 122

For the linear model f(x)=-5x+50, find the x-value when the output reaches 20.

Problem 123

For the linear model f(x)=2.5x+10, find the x-value when the output reaches 35.

Problem 124

For the linear model f(x)=3x-5, find the x-value when the output reaches 10.

Problem 125

For the linear model f(x)=-2x+15, find the x-value when the output reaches 5.

Problem 126

For the linear model f(x)=0.5x+12, find the x-value when the output reaches 15.

Problem 127

For the linear model f(x)=10x-20, find the x-value when the output reaches 30.

Problem 128

For the linear model f(x)=-x+8, find the x-value when the output reaches 12.

Problem 129

For the linear model f(x)=6x+1, find the x-value when the output reaches -11.

Open in simulator
Problem 130

For the linear model f(x)=1.5x-3, find the x-value when the output reaches 6.

Problem 131

For the linear model f(x)=7x+10, find the x-value when the output reaches 31.

Problem 132

For the linear model f(x)=-4x-2, find the x-value when the output reaches 10.

detect wrong slope, wrong units, or wrong initial value.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Correct the proposed linear model f(x)=12x+5 for starts at 12 and increases by 5 each week.

Problem 134

Correct the proposed linear model f(x)=3x+40 for starts at 40 and decreases by 3 each day.

Problem 135

Correct the proposed linear model C(t)=6t+8 for cost is 8 dollars per ticket plus a 6 dollar fee.

Problem 136

Correct the proposed linear model D(t)=100t+60 for A car starts at 100 miles from home and drives away at 60 miles per hour.

Problem 137

Correct the proposed linear model V(m)=25m+500 for A tank holds 500 liters of water and drains at a rate of 25 liters per minute.

Problem 138

Correct the proposed linear model C(m)=15m+15 for A subscription costs $15 per month plus a one-time activation fee of $20.

Problem 139

Correct the proposed linear model H(w)=5w+2 for A plant is 5 cm tall and grows 2 cm per week.

Problem 140

Correct the proposed linear model A(d)=10d+200 for You have $200 and spend $10 each day.

Open in simulator
Problem 141

Correct the proposed linear model C(m)=3m+2.50 for A taxi charges a flat fee of $3 plus $2.50 per mile.

Problem 142

Correct the proposed linear model N(m)=50m+50 for A company starts with 1000 customers and gains 50 customers per month.

Problem 143

Correct the proposed linear model A(m)=20m+800 for A balloon is at an altitude of 800 feet and descends at 20 feet per minute.

Problem 144

Correct the proposed linear model C(i)=500i+15 for The cost of producing items is $500 for setup plus $15 per item.