Math I · G-GPE.7

Using Coordinates to Compute Polygon Perimeters and Areas

This objective teaches students that the coordinate plane is not just a place to draw shapes. It is a measuring machine. Once a shape is located by coordinates, distances, perimeters, and areas can be computed with algebra.

Concept Geometry
Domain Expressing Geometric Properties with Equations
Read time 10 minutes

What this learning objective is really asking you to learn

This learning objective asks students to combine two ideas that often feel separate: geometry and algebra. Geometry asks about shapes, distances, areas, and spatial relationships. Algebra gives rules for calculating with numbers and variables. The coordinate plane is the bridge. When a geometric figure is placed on a coordinate grid, each point has an address. That address lets students calculate geometric measurements without guessing from the picture.

The core tool is the distance formula. If two points are \(A(x1, y1)\) and \(B(x2, y2)\), then the distance between them is

\[AB = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}\].

This formula is the Pythagorean Theorem in coordinate form. The horizontal change \(x2 - x1\) is one leg of a right triangle. The vertical change \(y2 - y1\) is the other leg. The segment between the two points is the hypotenuse. Instead of drawing a new right triangle every time, the distance formula packages that reasoning into one reliable calculation.

Once students can find the distance between two points, they can compute the perimeter of a polygon. A polygon is a closed figure made of line segments. Its perimeter is the total distance around the outside. If a triangle has vertices \(A\), \(B\), and \(C\), then its perimeter is \(AB + BC + CA\). If a quadrilateral has vertices \(A\), \(B\), \(C\), and \(D\) in order, then its perimeter is \(AB + BC + CD + DA\). The coordinate plane supplies each side length.

Area requires another layer of reasoning. For rectangles aligned with the grid, area can be found by multiplying horizontal length by vertical height. If a rectangle has corners at \((1, 2)\), \((7, 2)\), \((7, 5)\), and \((1, 5)\), its width is \(7 - 1 = 6\) units and its height is \(5 - 2 = 3\) units, so its area is 18 square units. For a rectangle that is tilted, students may use distance to find side lengths and then confirm perpendicular sides with slopes before multiplying base by height.

For triangles, the familiar formula is \(Area = 1/2 × base × height\). On a coordinate plane, the base and height may be obvious when the triangle has a horizontal or vertical side. If the base lies on \(y = 2\) from \(x = 1\) to \(x = 7\), the base is 6 units. If the opposite vertex is at \(y = 6\), the height is 4 units. The area is \(1/2 × 6 × 4 = 12\) square units. If the triangle is not conveniently aligned, students can still find area by enclosing it in a rectangle and subtracting surrounding right triangles, by choosing a different base, or by using a coordinate-area formula later often called the shoelace formula.

The objective specifically mentions triangles and rectangles because they are the basic building blocks of area. Many complicated polygons can be decomposed into triangles and rectangles. A floor plan, a garden plot, a game map, or a screen interface may look irregular at first, but a student can often split it into simpler pieces. This is not a trick; it is how measurement works. Instead of searching for a single magic formula, mathematicians break a shape into pieces whose areas are known, calculate those pieces, and combine them carefully.

Students also learn that the order of vertices matters. To compute perimeter, the points must be connected in the order around the polygon. Connecting the same points in a different order may create a different polygon, possibly even one with crossing sides. To compute area, students must understand which region is enclosed. A coordinate list is not just a collection of dots; it is a description of a boundary.

A strong student can move flexibly among several representations. They can look at a coordinate drawing, list vertices, compute distances, identify horizontal and vertical lengths, decompose a shape, and attach units to the final answer. They do not merely “plug numbers into a formula.” They understand what the formula is measuring.

Why students should learn this math

Students should learn this math because it is one of the most concrete answers to the question, “What does math have to do with real life?” Real objects occupy space. Rooms have dimensions. Roads have lengths. Screens have coordinates. Maps have scale. Land parcels have boundaries. Robots move from one coordinate to another. Video game characters occupy positions in a virtual world. Architects, engineers, surveyors, city planners, designers, and computer graphics programmers all need ways to turn location data into distances and areas.

Consider a map. A point might represent a school, a bus stop, a house, or a delivery address. A coordinate system may be latitude and longitude, a local map grid, or a digital pixel coordinate system. If a planning team wants to estimate walking distance, delivery range, service area, or property boundary, the question becomes geometric. Coordinates describe where things are. Distance and area calculations describe how far apart they are and how much space they cover.

In construction, a blueprint is a coordinate-like representation. Corners, walls, beams, and fixtures have locations. A contractor needs to know the length of trim around a room, the amount of flooring needed, or the area of a triangular support panel. If the dimensions are known, these quantities can be computed before materials are purchased. Mistakes cost money. Too little material delays the job. Too much material wastes resources. Coordinate measurement helps turn a drawing into a plan.

In computer graphics and game design, every visible object is built from points, lines, polygons, and surfaces. A game engine tracks positions using coordinates. A collision system checks whether objects overlap. A rendering system uses triangles to approximate surfaces. A level designer may calculate the area of a zone, the length of a path, or the boundary of a region. The math behind these systems is not separate from school geometry; it is an extension of coordinate geometry.

In robotics, a robot may be told to move from one coordinate to another. The length of the path matters because it affects time, battery use, and collision risk. If a robot is painting a floor, mapping a room, scanning a field, or cleaning a warehouse, it must relate coordinates to physical distance and area. A path drawn on a grid becomes a set of instructions, and the distance formula becomes part of the machine's planning logic.

Students should also learn this objective because it deepens their understanding of units. A side length measured on a coordinate grid is in linear units. Area is in square units. If a coordinate grid represents meters, then perimeter is measured in meters and area is measured in square meters. Confusing these units is not a small mistake. It changes the kind of quantity being described. A fence length and a lawn area are not interchangeable.

This objective also develops mathematical independence. Many students learn formulas as isolated facts: perimeter means add sides, rectangle area means length times width, triangle area means half base times height. Coordinate geometry forces those formulas to become tools rather than slogans. Students must decide which measurements are needed, extract those measurements from coordinates, and apply the correct formula. That decision-making is the real skill.

Where this objective fits on the full map of mathematics

On the full map of mathematics, this objective sits at the meeting point of geometry, algebra, measurement, and modeling. Earlier in Math I, students learned to graph equations, interpret coordinate points, and understand functions as relationships. In the geometry arc, they learned transformations, congruence, slope criteria, and coordinate proof. Objective 046 uses that same coordinate machinery for measurement.

The connection to the Pythagorean Theorem is especially important. The distance formula is not a new theorem floating in space. It is the Pythagorean Theorem applied to a coordinate grid. Every time students compute \(\sqrt{(x2 - x1)^2 + (y2 - y1)^2}\), they are building a right triangle whose legs are the horizontal and vertical changes. This prepares them for Math II work with circles, because the equation of a circle is also built from distance. A circle is the set of all points a fixed distance from a center, and that fixed-distance idea is expressed with the same coordinate machinery.

The objective connects to algebra because students must operate with expressions, radicals, and sometimes variables. A side length may simplify to \(\sqrt{25} = 5\), or it may remain \(\sqrt{13}\). A perimeter may be an exact expression such as \(5 + \sqrt{13} + \sqrt{20}\). Students learn that exact answers can be more informative than rounded decimals, especially when a later calculation needs precision.

It connects to statistics and data visualization because coordinate systems are the language of graphs. A histogram, scatter plot, or line graph is a coordinate representation of data. Choosing scales, reading distances, and interpreting visual size all depend on understanding that graphical space represents quantitative information.

It connects to calculus in the long run. Area under a curve, arc length, optimization, and coordinate-based modeling all depend on the idea that location can be translated into measurement. Students are not doing calculus yet, but they are learning the basic move: represent a spatial object with coordinates, then compute from the representation.

The historical machinery behind coordinate measurement

For most of human history, geometry and algebra were separate languages. Ancient geometers studied figures, proportions, constructions, and areas. Algebraists studied equations and numerical relationships. The coordinate plane changed everything because it allowed geometric problems to be written as algebraic problems. This development is often associated with René Descartes and Pierre de Fermat in the seventeenth century, although coordinate-like ideas appeared in older astronomy, mapping, and surveying traditions.

The power of analytic geometry is that location becomes number. A point is no longer only a mark in space; it is an ordered pair. A line is no longer only a drawn object; it can be described by an equation. A circle, triangle, rectangle, or polygon can be stored as coordinate data. Once that happens, geometric questions can be solved by calculation.

This shift helped make modern science and engineering possible. Navigation, astronomy, mechanics, mapping, architecture, and later computer graphics all depend on coordinate systems. The same basic idea appears at many scales. A city map uses coordinates. A computer screen uses pixel coordinates. A warehouse robot uses coordinate positioning. A satellite navigation system uses coordinate models of Earth. A graph in a science report uses axes to represent measured quantities.

Coordinate area also has a long practical history. Surveyors needed to calculate land areas from boundary measurements. Architects needed to calculate floor areas from plans. Engineers needed to know cross-sectional areas and material quantities. Before computers, these calculations required careful hand methods. Today software handles much of the arithmetic, but the underlying logic is still coordinate geometry.

The technical execution: how to compute perimeter and area from coordinates

A reliable technical process begins with the vertices. List the points in order around the polygon. Label them clearly. If the polygon is \(A(1, 2)\), \(B(5, 2)\), \(C(6, 5)\), and \(D(2, 6)\), then the sides are \(AB\), \(BC\), \(CD\), and \(DA\). Do not accidentally use diagonals such as \(AC\) unless the problem asks for them.

For each side, compute the horizontal and vertical changes. For \(AB\), the change is \(5 - 1 = 4\) horizontally and \(2 - 2 = 0\) vertically, so \(AB = 4\). For \(BC\), the horizontal change is 1 and the vertical change is 3, so \(BC = \sqrt{1^2 + 3^2} = \sqrt{10}\). Continue for each side. The perimeter is the sum of the side lengths. Exact radical form is often best unless the context requires a decimal.

For rectangles, first verify that the figure is a rectangle if it is not visually obvious. Horizontal and vertical rectangles are easiest because width and height can be read from coordinate differences. Tilted rectangles may require checking perpendicular sides using slope and finding side lengths using distance. Once base and height are known, multiply them.

For triangles, choose a base and height. If one side is horizontal, its length is the difference in x-values, and the height is the vertical distance from the opposite vertex to the line containing the base. If one side is vertical, its length is the difference in y-values, and the height is the horizontal distance from the opposite vertex. If no side is horizontal or vertical, students can enclose the triangle in a rectangle and subtract the extra right triangles. Advanced students may learn the coordinate-area formula:

\[Area = 1/2 |x1y2 + x2y3 + x3y1 - y1x2 - y2x3 - y3x1|\].

This formula is useful, but students should not treat it as magic. It is another way of decomposing coordinate area.

A common mistake is rounding too early. If two side lengths are \(\sqrt{13}\) and \(\sqrt{17}\), rounding them before adding may create a small error. In pure math problems, keep exact values as long as possible. In modeling problems, decide how much accuracy the context requires.

Another common mistake is forgetting square units for area. If each grid unit represents one meter, then a perimeter answer is in meters, but an area answer is in square meters. A final answer without units is incomplete in a modeling context.

What mastery looks like

Mastery means a student can look at coordinate data and see measurement possibilities. They can compute side lengths without counting slanted segments by eye. They can explain why the distance formula works. They can find the perimeter of a polygon by adding the correct side lengths. They can find the area of triangles and rectangles using coordinate information, decomposition, or formulas. They can decide whether an answer should be exact or rounded. They can attach correct units and explain what the result means.

The deeper mastery is seeing the coordinate plane as a bridge. It turns location into calculation. That bridge is one of the main reasons algebra and geometry became the language of modern technical work.

Problem Library

Problems in the App From This Objective

144 problems across 12 archetypes in the app.

apply distance formula.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Find the distance between points 0, 0 and 3, 4.

Problem 2

Find the distance between points -2, 5 and 4, 5.

Problem 3

Find the distance between points 1, -3 and 1, 8.

Problem 4

Find the distance between points -1, 2 and 5, 10.

Problem 5

Find the distance between points 0, 0 and 5, 12.

Open in simulator
Problem 6

Find the distance between points -7, -3 and 2, -3.

Problem 7

Find the distance between points 4, -1 and 4, -9.

Problem 8

Find the distance between points 0, 0 and 1, 1.

Problem 9

Find the distance between points -2, -3 and 1, 0.

Problem 10

Find the distance between points 0, 6 and 8, 6.

Problem 11

Find the distance between points -5, 0 and -5, 7.

Problem 12

Find the distance between points -10, -5 and 2, 0.

sum side lengths from distances.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Compute the perimeter of triangle with vertices 0, 0; 3, 0; 0, 4.

Problem 14

Compute the perimeter of triangle with vertices 1, 1; 5, 1; 1, 4.

Problem 15

Compute the perimeter of triangle with vertices -2, 0; 4, 0; 1, 4.

Problem 16

Compute the perimeter of triangle with vertices 0, 0; -3, 0; 0, -4.

Problem 17

Compute the perimeter of triangle with vertices 0, 0; 8, 0; 4, 3.

Open in simulator
Problem 18

Compute the perimeter of triangle with vertices 0, 0; 7, 0; 3, 4.

Problem 19

Compute the perimeter of triangle with vertices 1, 2; 4, 2; 1, 6.

Problem 20

Compute the perimeter of triangle with vertices 1, 1; 5, 4; 9, 1.

Problem 21

Compute the perimeter of triangle with vertices -1, -1; 3, 2; 0, 4.

Problem 22

Compute the perimeter of triangle with vertices 0, 0; 5, 0; 2, 3.

Problem 23

Compute the perimeter of triangle with vertices 0, 0; 6, 0; 0, 3.

Problem 24

Compute the perimeter of triangle with vertices -2, -3; 1, 1; 4, -1.

determine side lengths and sum.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Compute the perimeter of rectangle with vertices 0, 0; 6, 0; 6, 4; 0, 4.

Problem 26

Compute the perimeter of rectangle with vertices 1, 1; 4, 5; 8, 2; 5, -2.

Problem 27

Compute the perimeter of rectangle with vertices -3, -1; 2, -1; 2, 2; -3, 2.

Problem 28

Compute the perimeter of rectangle with vertices 1, 1; 5, 1; 5, 3; 1, 3.

Problem 29

Compute the perimeter of rectangle with vertices 0, 0; 7, 0; 7, 3; 0, 3.

Problem 30

Compute the perimeter of rectangle with vertices -2, -2; 3, -2; 3, 1; -2, 1.

Problem 31

Compute the perimeter of rectangle with vertices 0, 0; 3, 4; -1, 7; -4, 3.

Problem 32

Compute the perimeter of rectangle with vertices 0, 0; 4, 2; 3, 4; -1, 2.

Problem 33

Compute the perimeter of rectangle with vertices 10, 5; 15, 5; 15, 8; 10, 8.

Open in simulator
Problem 34

Compute the perimeter of rectangle with vertices -5, 0; -1, 0; -1, 6; -5, 6.

Problem 35

Compute the perimeter of rectangle with vertices 0, 0; 3, 1; 1, 7; -2, 6.

Problem 36

Compute the perimeter of rectangle with vertices 100, 200; 110, 200; 110, 205; 100, 205.

find base and height from coordinate differences.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Compute the area of the axis-aligned rectangle with vertices 0, 0; 6, 0; 6, 4; 0, 4.

Problem 38

Compute the area of the axis-aligned rectangle with vertices -3, -2; 2, -2; 2, 5; -3, 5.

Problem 39

Compute the area of the axis-aligned rectangle with vertices 1, 1; 8, 1; 8, 3; 1, 3.

Problem 40

Compute the area of the axis-aligned rectangle with vertices 2, 3; 7, 3; 7, 8; 2, 8.

Problem 41

Compute the area of the axis-aligned rectangle with vertices -1, 0; 4, 0; 4, 6; -1, 6.

Problem 42

Compute the area of the axis-aligned rectangle with vertices -5, -7; -1, -7; -1, -3; -5, -3.

Problem 43

Compute the area of the axis-aligned rectangle with vertices 10, 15; 20, 15; 20, 25; 10, 25.

Problem 44

Compute the area of the axis-aligned rectangle with vertices 0, 5; 3, 5; 3, 9; 0, 9.

Open in simulator
Problem 45

Compute the area of the axis-aligned rectangle with vertices -4, -6; 0, -6; 0, 0; -4, 0.

Problem 46

Compute the area of the axis-aligned rectangle with vertices -7, 2; -2, 2; -2, 10; -7, 10.

Problem 47

Compute the area of the axis-aligned rectangle with vertices 1, 2; 3, 2; 3, 5; 1, 5.

Problem 48

Compute the area of the axis-aligned rectangle with vertices -10, -20; -5, -20; -5, -10; -10, -10.

identify perpendicular base-height pair.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Compute the area of triangle with coordinate base-height information base from (0,0) to (6,0), third vertex (2,4).

Problem 50

Compute the area of triangle with coordinate base-height information base from (-2,1) to (4,1), third vertex (0,6).

Problem 51

Compute the area of triangle with coordinate base-height information base from (3,-1) to (3,5), third vertex (-1,2).

Problem 52

Compute the area of triangle with coordinate base-height information base from (1,1) to (7,1), third vertex (3,4).

Problem 53

Compute the area of triangle with coordinate base-height information base from (-5,-2) to (1,-2), third vertex (-2,2).

Problem 54

Compute the area of triangle with coordinate base-height information base from (2,-3) to (2,5), third vertex (6,1).

Problem 55

Compute the area of triangle with coordinate base-height information base from (0,0) to (8,0), third vertex (4,3).

Open in simulator
Problem 56

Compute the area of triangle with coordinate base-height information base from (-1,0) to (-1,4), third vertex (3,2).

Problem 57

Compute the area of triangle with coordinate base-height information base from (0,5) to (5,5), third vertex (2,1).

Problem 58

Compute the area of triangle with coordinate base-height information base from (4,0) to (4,7), third vertex (1,3).

Problem 59

Compute the area of triangle with coordinate base-height information base from (0,0) to (4,0), third vertex (2,5).

Problem 60

Compute the area of triangle with coordinate base-height information base from (0,0) to (0,8), third vertex (3,4).

identify legs and use `1/2 bh`.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Compute the area of a right triangle with vertices 0, 0; 5, 0; 0, 6.

Problem 62

Compute the area of a right triangle with vertices 1, 2; 1, 8; 4, 2.

Problem 63

Compute the area of a right triangle with vertices 0, 0; 3, 4; 7, 1.

Problem 64

Compute the area of a right triangle with vertices 0, 0; -4, 0; 0, -7.

Problem 65

Compute the area of a right triangle with vertices 2, 3; 2, 9; 7, 3.

Problem 66

Compute the area of a right triangle with vertices -1, -1; -1, -5; -6, -1.

Problem 67

Compute the area of a right triangle with vertices 0, 0; 3, 4; 4, -3.

Problem 68

Compute the area of a right triangle with vertices 1, 1; 6, 13; -11, 6.

Problem 69

Compute the area of a right triangle with vertices 10, 20; 10, 35; 40, 20.

Problem 70

Compute the area of a right triangle with vertices 0, 0; 3, 0; 0, 5.

Problem 71

Compute the area of a right triangle with vertices 0, 0; 6, 8; -8, 6.

Open in simulator
Problem 72

Compute the area of a right triangle with vertices 2, 2; 7, 14; -10, 7.

partition coordinate figure and add/subtract areas.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Compute the area of polygon L-shape made from a 6 by 5 rectangle with a 2 by 3 corner removed by decomposing it.

Problem 74

Compute the area of polygon pentagon split into a 4 by 3 rectangle and a triangle with base 4 height 2 by decomposing it.

Problem 75

Compute the area of polygon concave polygon split into rectangles of areas 15 and 8 by decomposing it.

Problem 76

Compute the area of polygon rectangle 10 by 8 with a 3 by 3 square removed from a corner by decomposing it.

Problem 77

Compute the area of polygon rectangle 7 by 6 with a triangle of base 4 and height 3 removed from one side by decomposing it.

Problem 78

Compute the area of polygon T-shaped polygon formed by an 8 by 2 rectangle and a 2 by 6 rectangle by decomposing it.

Open in simulator
Problem 79

Compute the area of polygon house-like shape composed of a 5 by 4 rectangle and a triangle with base 5 and height 3 on top by decomposing it.

Problem 80

Compute the area of polygon U-shaped polygon with outer dimensions 10 by 8 and an inner 6 by 4 rectangular cutout by decomposing it.

Problem 81

Compute the area of polygon cross-shaped polygon formed by a 7 by 3 central rectangle and two 2 by 3 rectangles attached to its sides by decomposing it.

Problem 82

Compute the area of polygon arrowhead shape composed of an 8 by 3 rectangle and two triangles, each with base 3 and height 2, attached to its ends by decomposing it.

Problem 83

Compute the area of polygon large 12 by 10 rectangle with a 5 by 4 rectangular cutout by decomposing it.

Problem 84

Compute the area of polygon polygon formed by a 6 by 4 rectangle and a triangle with base 6 and height 3 attached to one side by decomposing it.

calculate area from ordered vertices.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Use the coordinate area formula on ordered vertices 0, 0; 4, 0; 0, 3.

Problem 86

Use the coordinate area formula on ordered vertices 0, 0; 5, 0; 5, 2; 0, 2.

Problem 87

Use the coordinate area formula on ordered vertices 1, 1; 4, 1; 2, 5.

Problem 88

Use the coordinate area formula on ordered vertices 0, 0; 0, 5; 3, 0.

Problem 89

Use the coordinate area formula on ordered vertices 1, 1; 5, 1; 5, 3; 1, 3.

Problem 90

Use the coordinate area formula on ordered vertices -1, -1; 3, -1; 1, 4.

Problem 91

Use the coordinate area formula on ordered vertices 0, 0; 6, 0; 4, 4; 2, 4.

Problem 92

Use the coordinate area formula on ordered vertices 2, 2; 5, 2; 3, 6.

Problem 93

Use the coordinate area formula on ordered vertices -2, -2; 3, -2; 3, 1; -2, 1.

Problem 94

Use the coordinate area formula on ordered vertices 0, 0; 7, 0; 2, 3.

Problem 95

Use the coordinate area formula on ordered vertices 0, 0; 4, 0; 3, 2; 1, 2.

Problem 96

Use the coordinate area formula on ordered vertices 10, 10; 20, 10; 15, 30.

Open in simulator
use distance or coordinate differences to solve.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Find the missing coordinate in axis-aligned rectangle with vertices (0,0), (x,0), (x,3), (0,3) given perimeter 18.

Open in simulator
Problem 98

Find the missing coordinate in horizontal segment from (2,1) to (x,1) used as one side of an equilateral-looking perimeter calculation with side length 5 given perimeter 15.

Problem 99

Find the missing coordinate in right triangle with legs from (0,0) to (a,0) and (0,4), perimeter 12 with hypotenuse 5 given perimeter 12.

Problem 100

Find the missing coordinate in axis-aligned rectangle with vertices (1,0), (1,y), (5,y), (5,0) given perimeter 20.

Problem 101

Find the missing coordinate in square with one vertex at (2,2) and an adjacent vertex at (x,2) given perimeter 24.

Problem 102

Find the missing coordinate in isosceles triangle with vertices (0,0), (x,0), and (x/2, 4) given perimeter 16.

Problem 103

Find the missing coordinate in right triangle with vertices (0,0), (5,0), and (0,y) given perimeter 30.

Problem 104

Find the missing coordinate in axis-aligned rectangle with vertices (x,1), (7,1), (7,4), (x,4) given perimeter 22.

Problem 105

Find the missing coordinate in rhombus with vertices (0,0), (x,0), (x+3,4), (3,4) given perimeter 20.

Problem 106

Find the missing coordinate in axis-aligned rectangle with vertices (0,0), (x,0), (x, x+2), (0, x+2) given perimeter 40.

Problem 107

Find the missing coordinate in right triangle with vertices (0,0), (x,0), and (0,8), where the hypotenuse is 10 given perimeter 24.

Problem 108

Find the missing coordinate in equilateral triangle with one side defined by vertices (1,1) and (x,1) given perimeter 18.

use base-height relationships.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Find the missing coordinate in rectangle with vertices (0,0), (x,0), (x,4), (0,4) given area 28.

Problem 110

Find the missing coordinate in triangle with base from (0,0) to (10,0) and third vertex (3,h) given area 25.

Problem 111

Find the missing coordinate in axis-aligned rectangle from x=-2 to x=3 and y=1 to y=k given area 20.

Problem 112

Find the missing coordinate in rectangle with vertices (1,1), (x,1), (x,5), (1,5) given area 36.

Open in simulator
Problem 113

Find the missing coordinate in triangle with vertices (0,0), (0,8), (x,3) given area 20.

Problem 114

Find the missing coordinate in rectangle with vertices (-3,-2), (5,-2), (5,y), (-3,y) given area 40.

Problem 115

Find the missing coordinate in right triangle with vertices (0,0), (x,0), (0,6) given area 18.

Problem 116

Find the missing coordinate in parallelogram with vertices (1,0), (7,0), (9,h), (3,h) given area 42.

Problem 117

Find the missing coordinate in triangle with vertices (2,1), (8,1), (5,k) given area 15.

Problem 118

Find the missing coordinate in rectangle with vertices (2,1), (x,1), (x,6), (2,6) given area 30.

Problem 119

Find the missing coordinate in trapezoid with vertices (0,0), (6,0), (4,y), (1,y) given area 27.

Problem 120

Find the missing coordinate in square with vertices (0,0), (x,0), (x,x), (0,x) given area 81.

compute and interpret measurements.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Compare the area or perimeter of coordinate figures rectangle 6 by 4 and rectangle 8 by 3.

Problem 122

Compare the area or perimeter of coordinate figures triangle with base 10 height 4 and rectangle 5 by 4.

Problem 123

Compare the area or perimeter of coordinate figures square side 5 and rectangle 4 by 6.

Problem 124

Compare the area or perimeter of coordinate figures rectangle 7 by 3 and square side 4.

Open in simulator
Problem 125

Compare the area or perimeter of coordinate figures rectangle 9 by 1 and rectangle 8 by 2.

Problem 126

Compare the area or perimeter of coordinate figures right triangle with base 6 height 8 and rectangle 4 by 6.

Problem 127

Compare the area or perimeter of coordinate figures square side 6 and square side 3.

Problem 128

Compare the area or perimeter of coordinate figures rectangle 5 by 8 and triangle with base 10 height 6.

Problem 129

Compare the area or perimeter of coordinate figures rectangle 10 by 2 and rectangle 7 by 4.

Problem 130

Compare the area or perimeter of coordinate figures square side 7 and triangle with base 14 height 6.

Problem 131

Compare the area or perimeter of coordinate figures rectangle 12 by 2 and rectangle 6 by 4.

Problem 132

Compare the area or perimeter of coordinate figures triangle with base 12 height 8 and square side 6.

catch distance formula, base-height, or vertex-order mistakes.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Diagnose the coordinate measurement error in Area of triangle with base 8 and height 5 is computed as 40.

Problem 134

Diagnose the coordinate measurement error in Distance from (0,0) to (6,8) is computed as 14.

Problem 135

Diagnose the coordinate measurement error in A histogram-like polygon area calculation subtracts a rectangle that is actually inside the shape.

Open in simulator
Problem 136

Diagnose the coordinate measurement error in Shoelace formula gives -18 and the area is reported as -9.

Problem 137

Diagnose the coordinate measurement error in The slope of the line passing through (1,2) and (3,6) is computed as (3-1)/(6-2) = 2/4 = 0.5.

Problem 138

Diagnose the coordinate measurement error in The midpoint of the segment connecting (2,4) and (8,10) is computed as (2+8, 4+10) = (10,14).

Problem 139

Diagnose the coordinate measurement error in The area of a circle with radius 5 is computed as 2 * pi * 5 = 10pi.

Problem 140

Diagnose the coordinate measurement error in The perimeter of a rectangle with length 7 and width 3 is computed as 7 * 3 = 21.

Problem 141

Diagnose the coordinate measurement error in The volume of a rectangular prism with length 4, width 3, and height 5 is computed as 4 * 3 = 12.

Problem 142

Diagnose the coordinate measurement error in The hypotenuse of a right triangle with legs 3 and 4 is computed as 3^2 + 4^2 = 9 + 16 = 25.

Problem 143

Diagnose the coordinate measurement error in The distance between (1,2) and (4,6) is computed as sqrt((4+1)^2 + (6+2)^2) = sqrt(5^2 + 8^2) = sqrt(25 + 64) = sqrt(89).

Problem 144

Diagnose the coordinate measurement error in The area of a trapezoid with bases 6 and 10 and height 4 is computed as (6+10) * 4 = 16 * 4 = 64.