Math I · S-ID.3

Interpreting Shape, Center, Spread, and Outliers in Context

This objective teaches students how to turn a data display into a story about the real world. Shape, center, spread, and outliers are not vocabulary words to memorize; they are the basic clues that tell what happened, what is typical, what is unusual, and what deserves investigation.

Concept Statistics and Probability
Domain Interpreting Categorical and Quantitative Data
Read time 9 minutes

What this learning objective is really asking you to learn

This learning objective is about reading a distribution as evidence. A distribution is the pattern formed by data values. It answers questions such as: Where are most of the values? How spread out are they? Are there clusters? Are there gaps? Is one side stretched farther than the other? Are there unusual values far away from the rest? These questions matter because real data are not random piles of numbers. They are traces of real processes.

The four central features are shape, center, spread, and outliers. Shape describes the overall form of the distribution. Center describes a typical value. Spread describes variability. Outliers are data points that stand far away from the main body of the data. This standard asks students not only to identify these features but also to interpret them in context.

Shape includes symmetry, skew, clusters, gaps, peaks, and tails. A symmetric distribution has values balanced on both sides of the center. A right-skewed distribution has a long tail stretching toward larger values. A left-skewed distribution has a long tail stretching toward smaller values. A clustered distribution may suggest subgroups. A gap may suggest a break between categories or an absence of certain values. A bimodal distribution, with two peaks, may indicate that the data combine two different populations.

Center gives a typical value. In a symmetric distribution, the mean and median are often close. In a skewed distribution, the mean is pulled toward the tail. Students should not merely calculate center; they should explain what it means. If the data are commute times, the center represents a typical commute. If the data are reaction times, the center represents typical performance. If the data are home prices, the center represents a typical market value, though the median may be more meaningful when prices are skewed.

Spread gives a sense of consistency or variation. A small spread means values are similar. A large spread means values differ widely. In context, spread may represent reliability, inequality, uncertainty, diversity, or risk. A small spread in manufacturing measurements may be good because products are consistent. A large spread in student project topics may be good because it shows variety. The same mathematical feature can have different practical meanings depending on the context.

Outliers deserve special attention. An outlier might be a measurement error, a data-entry mistake, a rare but valid event, or an important signal. If a student records a height of 650 inches, that is probably an error. If a city records a heat wave temperature far above normal, that may be a real and important extreme. If one customer spends ten times more than others, that may indicate a special buyer or a recording mistake. The math does not decide automatically; context matters.

This objective pushes students beyond naming. It is not enough to say, “The distribution is right-skewed.” A better statement is, “The distribution of home prices is right-skewed because most homes are in the lower-to-middle price range, but a small number of very expensive homes stretch the tail to the right.” The second statement connects shape to meaning.

Students also need to compare distributions. Suppose two schools have similar median commute times, but one school has a much larger spread. That might mean students at one school live at a wider range of distances. Suppose two neighborhoods have similar average rent, but one has a right-skewed distribution with luxury apartments. That affects how “average rent” should be interpreted. Suppose two athletes have similar median performance, but one has an outlier caused by injury. Interpretation depends on the story behind the point.

Why students should learn this math

Students should learn this math because data without context can mislead. A graph may look convincing, but if the viewer does not understand shape, center, spread, and outliers, they may draw the wrong conclusion. This objective teaches students how to slow down and ask better questions before accepting a claim.

In real life, distributions appear everywhere. Test scores form distributions. Waiting times form distributions. Housing prices form distributions. Body measurements, rainfall, website load times, delivery times, hospital stays, customer ratings, and athletic results all form distributions. To understand any of these, students need to read more than one number. They need to see the whole pattern.

Consider income. Income distributions are often right-skewed: many people are in lower and middle ranges, while a smaller number earn very high incomes. In such a distribution, the mean can be much higher than the median. A report that emphasizes only mean income may make the typical person appear richer than they are. A student who understands skew can see why median income is often used in public discussion.

Consider health data. Suppose a clinic compares recovery times for two treatments. Treatment A has a slightly lower median recovery time, but Treatment B has fewer extreme long recoveries. Which is better? The answer depends on the situation. Patients and doctors may care about the center, but they may also care deeply about the risk of unusually long recovery. Spread and outliers become part of the decision.

Consider school data. A class average can hide important structure. A class might have one cluster of students who understand the material and another cluster who are lost. The mean may sit between the clusters and describe almost nobody. In that case, shape is the key feature. A teacher who sees a bimodal distribution might respond differently than a teacher who sees a symmetric distribution centered near mastery.

This objective also helps students become careful citizens. Public arguments often use data selectively. A politician, company, influencer, or news headline can choose statistics that support a desired message. By learning to interpret distribution features, students become harder to manipulate. They can ask: What is the distribution shape? Are there outliers? Which center was used? How much variation exists? Does the statistic match the claim?

The “why” is especially strong here because this skill applies beyond math class. It applies to reading the world. Students do not need to become professional statisticians to benefit. They need enough statistical literacy to question averages, understand variation, and recognize when unusual values change the story.

The historical machinery behind this idea

For much of human history, people collected data for practical reasons: taxes, land, births, deaths, harvests, trade, and astronomy. But large lists of values were difficult to interpret. As scientific measurement expanded, researchers needed ways to summarize patterns. Graphs, averages, and measures of variation became tools for compressing information.

The development of statistical graphics was a major step. Tables are precise, but graphs reveal shape. A histogram can show skew. A dot plot can show clusters. A box plot can show median, spread, and possible outliers. These displays let people see patterns that would be hidden in a list of numbers.

The idea of outliers has a complicated history because unusual values can be either errors or discoveries. In measurement science, outliers might come from faulty instruments or recording mistakes. In astronomy, medicine, finance, and quality control, unusual values might also reveal new phenomena or serious risks. The mature habit is not to delete outliers automatically, but to investigate them.

The machinery of this objective is partly numerical and partly interpretive. A distribution is built from data values. A graph reveals the shape. Statistics summarize center and spread. Context explains why the pattern might exist. The student must move through all these layers. The goal is not just to describe the data but to understand the situation that produced the data.

This is why statistics is different from many earlier topics in math. In algebra, a problem often has a clean symbolic answer. In statistics, the same numerical pattern can have different meanings in different contexts. A large spread may indicate bad quality control in manufacturing, healthy variety in student interests, or unequal access in social data. The technical feature is the same; the interpretation depends on the story.

Technical execution: how to do the math

When interpreting a distribution, students should begin with the graph. Is the data display a dot plot, histogram, or box plot? What variable is being measured? What are the units? What does each axis or number line represent? Before naming shape, students should understand what the values mean.

Next, students should describe shape. Is the distribution roughly symmetric, skewed left, skewed right, uniform, clustered, or bimodal? Are there gaps? Are there tails? Do most values gather in one interval? Students should avoid forcing every distribution into one simple label. Real data can be messy. A useful description is better than a memorized label.

Then students should discuss center. Depending on the distribution, the mean or median may be more helpful. If the distribution is symmetric, the mean can be a useful center. If the distribution is skewed or has outliers, the median may better represent the typical value. A good interpretation names the statistic and translates it into context.

Then students should discuss spread. If using a box plot or skewed data, the IQR is often helpful. If using symmetric data without major outliers, standard deviation may be useful. Students can also describe spread informally: “Most values are between 20 and 30 minutes,” or “The data are spread from about 5 to 80.” At this level, informal spread descriptions are valuable when they are clear and tied to context.

Finally, students should identify possible outliers and explain their possible effect. An outlier can pull the mean, increase the standard deviation, stretch the range, or suggest a special case. Students should say whether an outlier seems to change the conclusion. For example, if one unusually high value pulls the mean above the median, the median may be a better typical value.

A complete interpretation usually has the form: “The distribution of [variable] is [shape], with a typical value around [center]. The values vary by about [spread]. There is/are [outlier description], which may [effect]. In context, this suggests [meaning].” That sentence frame helps students connect computation to explanation.

For example, suppose a histogram of delivery times is right-skewed. Most deliveries occur between 20 and 40 minutes, but a few take over 90 minutes. A weak interpretation says, “It is right-skewed.” A strong interpretation says, “Most customers receive delivery in under 40 minutes, but a small number experience very long waits. Those long waits pull the mean upward, so the median may better describe the usual customer experience. The outliers are important because they may indicate traffic problems, staffing shortages, or incorrect addresses.”

Where this objective fits on the full map of mathematics

S-ID.3 sits in the center of descriptive statistics. Objective 050 taught students to represent one-variable data. Objective 051 taught them to compare center and spread. Objective 052 teaches them to interpret the full distribution. This is the moment when statistics becomes storytelling with evidence.

It connects to functions because students are again reading visual features. In functions, they interpret intercepts, increasing intervals, and rates of change. In statistics, they interpret shape, center, spread, and outliers. Both require translating mathematical features into real-world meaning.

It connects to modeling because a distribution can reveal whether a model is reasonable. If data have a roughly symmetric mound shape, one kind of model may be useful. If data are skewed, another kind may be needed. If data have two clusters, there may be two groups mixed together. Later, students will study residuals, correlation, causation, and inference. All of those rely on the habit of reading patterns carefully.

It connects to probability because spread and outliers are early ways of thinking about uncertainty. Values vary. Some values are typical; some are rare. Probability later gives tools for predicting how often different kinds of values occur. But students first need the descriptive language of distribution.

In the full map, this objective teaches a powerful idea: variation is information. Students often want data to be neat, but real data are rarely perfect. The shape, the spread, and the unusual values are not annoyances. They are clues.

Common misconceptions and productive corrections

One misconception is that outliers are always mistakes. They are not. Some are errors, but others are real events that deserve attention. Students should investigate outliers, not delete them automatically.

Another misconception is that center tells the whole story. It does not. A distribution with a typical value of 50 can be tightly packed around 50 or spread from 0 to 100. The meaning is very different. A third misconception is that shape words are just vocabulary. Shape words are useful only when they help explain the real situation.

A fourth misconception is that a graph has one correct interpretation. In statistics, interpretations can have nuance. A good interpretation should be supported by the data, acknowledge variation, and stay tied to context.

Mastery check

A student has mastered this objective when they can look at a data display, describe its shape, center, spread, and outliers, and explain what those features mean in the original situation. They can say how an outlier affects the mean or spread. They can choose language carefully, avoid overclaiming, and treat data as evidence rather than decoration.

Problem Library

Problems in the App From This Objective

144 problems across 12 archetypes in the app.

identify symmetric, skewed, uniform, clustered, or bimodal shape.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Describe the shape of a dot plot with counts 1=1, 2=2, 3=4, 4=2, 5=1.

Problem 2

Describe the shape of a dot plot with counts 1=4, 2=3, 3=1, 8=1.

Problem 3

Describe the shape of a dot plot with counts 2=2, 4=2, 6=2, 8=2.

Problem 4

Describe the shape of a dot plot with counts 1=3, 2=1, 7=1, 8=3.

Problem 5

Describe the shape of a dot plot with counts 1=1, 2=2, 3=4, 4=5.

Problem 6

Describe the shape of a dot plot with counts 1=1, 2=3, 3=5, 4=3, 5=1.

Problem 7

Describe the shape of a dot plot with counts 1=5, 2=3, 3=2, 4=1.

Problem 8

Describe the shape of a dot plot with counts 1=2, 2=2, 3=2, 4=2, 5=2.

Problem 9

Describe the shape of a dot plot with counts 1=4, 2=1, 3=2, 4=1, 5=4.

Problem 10

Describe the shape of a dot plot with counts 1=1, 2=2, 3=3, 4=5, 5=6.

Problem 11

Describe the shape of a dot plot with counts 1=5, 2=4, 3=3, 4=2, 5=1.

Open in simulator
Problem 12

Describe the shape of a dot plot with counts 1=4, 2=1, 3=1, 4=1, 5=4.

identify skew, symmetry, peaks, and gaps.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Describe the shape of a histogram with bin counts 0-9=2, 10-19=5, 20-29=2.

Problem 14

Describe the shape of a histogram with bin counts 0-9=6, 10-19=3, 20-29=1.

Problem 15

Describe the shape of a histogram with bin counts 0-9=1, 10-19=2, 20-29=6.

Open in simulator
Problem 16

Describe the shape of a histogram with bin counts 0-9=4, 10-19=1, 20-29=4.

Problem 17

Describe the shape of a histogram with bin counts 0-9=3, 10-19=3, 20-29=3.

Problem 18

Describe the shape of a histogram with bin counts 0-9=8, 10-19=4, 20-29=2, 30-39=1.

Problem 19

Describe the shape of a histogram with bin counts 0-9=1, 10-19=2, 20-29=5, 30-39=9.

Problem 20

Describe the shape of a histogram with bin counts 0-9=5, 10-19=2, 20-29=6, 30-39=3.

Problem 21

Describe the shape of a histogram with bin counts 0-9=4, 10-19=1, 20-29=1, 30-39=4.

Problem 22

Describe the shape of a histogram with bin counts 0-9=7, 10-19=5, 20-29=3, 30-39=1.

Problem 23

Describe the shape of a histogram with bin counts 0-9=1, 10-19=3, 20-29=5, 30-39=7.

Problem 24

Describe the shape of a histogram with bin counts 0-9=3, 10-19=6, 20-29=6, 30-39=3.

locate unusual values relative to the distribution.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Identify outliers from display summary dot plot values cluster from 10 to 14 with a single value at 30.

Problem 26

Identify outliers from display summary histogram has most values from 40-59 and one bar at 90-99.

Open in simulator
Problem 27

Identify outliers from display summary box plot has a marked point at 3 below the lower whisker.

Problem 28

Identify outliers from display summary data values 5,6,7,8,9 with no separated points.

Problem 29

Identify outliers from display summary dot plot values cluster from 50 to 55 with a single value at 20.

Problem 30

Identify outliers from display summary histogram has most values from 10-29 and one bar at 0-9.

Problem 31

Identify outliers from display summary box plot has a marked point at 75 above the upper whisker.

Problem 32

Identify outliers from display summary data values 10, 12, 11, 13, 100.

Problem 33

Identify outliers from display summary data values 2, 50, 51, 53, 52.

Problem 34

Identify outliers from display summary dot plot values are evenly distributed from 1 to 10.

Problem 35

Identify outliers from display summary histogram shows a bell-shaped distribution from 0-100 with no separated bins.

Problem 36

Identify outliers from display summary box plot shows whiskers extending to the minimum and maximum data points with no marked outliers.

explain what the unusual value may mean.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Interpret outlier a commute time of 95 minutes when most are 20-35 minutes in context student commute times.

Problem 38

Interpret outlier a plant height of 2 cm when most are 18-25 cm in context plant growth experiment.

Open in simulator
Problem 39

Interpret outlier a score of 100 when most scores are 60-75 in context quiz scores.

Problem 40

Interpret outlier a temperature of 10°F when most are 45-60°F in context daily temperatures in April.

Problem 41

Interpret outlier a price of $500 for a used textbook when most are $50-70 in context used textbook prices for a specific course.

Problem 42

Interpret outlier 1 sale on a day when most sales are 20-30 units in context daily sales of a popular product.

Problem 43

Interpret outlier a pumpkin weighing 500 lbs when most are 10-20 lbs in context pumpkins grown in a garden.

Problem 44

Interpret outlier a reaction time of 5 seconds when most are 0.2-0.5 seconds in context reaction times in a psychology experiment.

Problem 45

Interpret outlier 50 defects in a batch when most batches have 2-5 defects in context defects found in product batches.

Problem 46

Interpret outlier an annual income of $5,000,000 when most are $80,000-$150,000 in context annual incomes for software engineers.

Problem 47

Interpret outlier a novel with 10 pages when most are 250-400 pages in context number of pages in published novels.

Problem 48

Interpret outlier a soccer team scoring 15 goals in a match when most are 0-3 goals in context goals scored per game by a professional soccer team.

describe differences in skew, clusters, and gaps.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Compare distribution shapes for groups roughly symmetric around 50 and right-skewed with several high values.

Problem 50

Compare distribution shapes for groups one cluster near 10 and two clusters near 5 and 15.

Problem 51

Compare distribution shapes for groups uniform from 1 to 6 and clustered tightly around 3.

Problem 52

Compare distribution shapes for groups left-skewed with a tail towards lower values and symmetric around its mean.

Problem 53

Compare distribution shapes for groups bimodal with peaks at 20 and 80 and unimodal with a single peak at 50.

Problem 54

Compare distribution shapes for groups has a significant gap between 30 and 40 and shows no clear gaps in its range.

Problem 55

Compare distribution shapes for groups uniform across the range 0 to 100 and right-skewed with most data at lower values.

Open in simulator
Problem 56

Compare distribution shapes for groups perfectly symmetric around 10 and bimodal with peaks at 5 and 15.

Problem 57

Compare distribution shapes for groups highly concentrated around 75 and widely spread from 10 to 90.

Problem 58

Compare distribution shapes for groups left-skewed, with its tail extending to lower values and right-skewed, with its tail extending to higher values.

Problem 59

Compare distribution shapes for groups shows three distinct clusters and has one prominent cluster.

Problem 60

Compare distribution shapes for groups uniform from 0 to 20 and right-skewed with a gap between 5 and 10.

use median/mean language with units.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Compare centers of two distributions in context using group A median 42 minutes, group B median 35 minutes.

Problem 62

Compare centers of two distributions in context using class A mean 81 points, class B mean 84 points.

Problem 63

Compare centers of two distributions in context using store A median price 18 dollars, store B median price 18 dollars.

Problem 64

Compare centers of two distributions in context using Team X mean 15 goals, Team Y mean 12 goals.

Open in simulator
Problem 65

Compare centers of two distributions in context using Company A median salary $65,000, Company B median salary $70,000.

Problem 66

Compare centers of two distributions in context using Plant A median height 25 cm, Plant B median height 28 cm.

Problem 67

Compare centers of two distributions in context using Morning shift mean 8 customers, Afternoon shift mean 10 customers.

Problem 68

Compare centers of two distributions in context using Brand P median battery life 12 hours, Brand Q median battery life 11 hours.

Problem 69

Compare centers of two distributions in context using City North mean temperature 55 degrees, City South mean temperature 60 degrees.

Problem 70

Compare centers of two distributions in context using Group 1 median reaction time 0.25 seconds, Group 2 median reaction time 0.28 seconds.

Problem 71

Compare centers of two distributions in context using Server Alpha mean download speed 90 Mbps, Server Beta mean download speed 85 Mbps.

Problem 72

Compare centers of two distributions in context using Restaurant X median wait time 15 minutes, Restaurant Y median wait time 15 minutes.

use range/IQR/visual spread accurately.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Compare spreads of two distributions in context using group A IQR 4 seconds, group B IQR 12 seconds.

Problem 74

Compare spreads of two distributions in context using class A range 20 points, class B range 20 points.

Problem 75

Compare spreads of two distributions in context using machine A values tightly clustered, machine B values spread across the full display.

Problem 76

Compare spreads of two distributions in context using City X standard deviation 5 degrees, City Y standard deviation 10 degrees.

Problem 77

Compare spreads of two distributions in context using morning class range 5 years, evening class range 8 years.

Problem 78

Compare spreads of two distributions in context using drug A IQR 150 ms, drug B IQR 150 ms.

Open in simulator
Problem 79

Compare spreads of two distributions in context using forest A tree heights are very consistent, forest B tree heights vary widely.

Problem 80

Compare spreads of two distributions in context using brand P standard deviation 0.5 hours, brand Q standard deviation 1.2 hours.

Problem 81

Compare spreads of two distributions in context using region 1 range 10 inches, region 2 range 4 inches.

Problem 82

Compare spreads of two distributions in context using section A IQR 10 points, section B IQR 6 points.

Problem 83

Compare spreads of two distributions in context using batch X weights are spread evenly across 10 grams, batch Y weights are also spread evenly across 10 grams.

Problem 84

Compare spreads of two distributions in context using server A standard deviation 0.2 seconds, server B standard deviation 0.2 seconds.

avoid overclaiming when groups overlap.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Interpret overlap between distributions described by two box plots have similar IQRs and heavily overlapping boxes.

Problem 86

Interpret overlap between distributions described by two dot plots have little overlap, with group B mostly higher.

Open in simulator
Problem 87

Interpret overlap between distributions described by histograms overlap in the middle but one group has a longer high tail.

Problem 88

Interpret overlap between distributions described by two density curves have similar central peaks but one is significantly wider.

Problem 89

Interpret overlap between distributions described by the entire range of values for group P is contained within the interquartile range of group Q.

Problem 90

Interpret overlap between distributions described by two frequency tables show that 80% of values for group A are lower than the median of group B, but there's still a 20% overlap.

Problem 91

Interpret overlap between distributions described by two box plots show that the upper whisker of group X extends above the median of group Y, while Y's lower whisker extends below X's median.

Problem 92

Interpret overlap between distributions described by histograms for two datasets show similar means, but one is clearly negatively skewed while the other is positively skewed.

Problem 93

Interpret overlap between distributions described by two dot plots show that group R's maximum value is equal to group S's minimum value, with no other overlap.

Problem 94

Interpret overlap between distributions described by the 95% confidence intervals for the means of two populations heavily overlap.

Problem 95

Interpret overlap between distributions described by two distributions have different modes but their interquartile ranges are nearly identical and heavily overlap.

Problem 96

Interpret overlap between distributions described by a scatter plot shows two clusters of points, one with a tighter spread and higher values, and another with a wider spread and lower values, but their boundaries touch.

connect shape, center, spread, and outliers to claim.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Choose the contextual conclusion supported by display evidence team A median score is higher and IQR is smaller than team B.

Problem 98

Choose the contextual conclusion supported by display evidence two commute histograms have similar centers but group B has a longer right tail.

Problem 99

Choose the contextual conclusion supported by display evidence a plant-height dot plot has one very low value separated from the rest.

Problem 100

Choose the contextual conclusion supported by display evidence City A's average household size is 2.5 people with a standard deviation of 0.5, while City B's average is 2.6 people with a standard deviation of 1.2.

Problem 101

Choose the contextual conclusion supported by display evidence A dot plot of student heights shows a cluster around 160 cm and another around 175 cm, with a gap in between.

Problem 102

Choose the contextual conclusion supported by display evidence The distribution of daily sales for a small business is heavily skewed right, with a median much lower than the mean.

Problem 103

Choose the contextual conclusion supported by display evidence A box plot of test scores for a class shows the upper quartile at 85, the median at 70, and the lower quartile at 60.

Problem 104

Choose the contextual conclusion supported by display evidence The distribution of commute times for employees at Company X is symmetric and unimodal, centered around 30 minutes.

Problem 105

Choose the contextual conclusion supported by display evidence Two groups of patients received different treatments; the recovery time histogram for group A is much narrower than for group B, though both are centered around 7 days.

Problem 106

Choose the contextual conclusion supported by display evidence A scatter plot of monthly rainfall over 10 years shows one year with exceptionally high rainfall, far above the typical range.

Open in simulator
Problem 107

Choose the contextual conclusion supported by display evidence The median age of participants in a marathon is 35 years with an IQR of 10 years, while a 5k race has a median age of 28 years with an IQR of 5 years.

Problem 108

Choose the contextual conclusion supported by display evidence A histogram of the number of siblings reported by students shows a peak at 1 and then quickly decreases, with a long tail to the right.

critique incomplete data interpretation.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Identify what claim Group A is better because its median is higher, but its spread is much larger. ignores about spread or outliers.

Problem 110

Identify what claim The average is representative even though there is a very high outlier. ignores about spread or outliers.

Problem 111

Identify what claim The two groups are the same because their means are equal, but one has twice the IQR. ignores about spread or outliers.

Problem 112

Identify what claim All students in group B scored higher because group B has the higher median, but the box plots overlap. ignores about spread or outliers.

Problem 113

Identify what claim The average score in Class X is 80, so most students scored around 80, even though the standard deviation is 20. ignores about spread or outliers.

Problem 114

Identify what claim The median income in Town A is $60,000, which means everyone is doing well, despite the range being $10,000 to $500,000. ignores about spread or outliers.

Problem 115

Identify what claim The median house price in this neighborhood is $300,000, so all houses are similarly priced, even with a few mansions selling for millions. ignores about spread or outliers.

Problem 116

Identify what claim Both companies have an average employee tenure of 5 years, so their employee retention is identical, but Company A's distribution is skewed right with many long-term employees and Company B's is symmetric. ignores about spread or outliers.

Problem 117

Identify what claim Team A scored higher on average than Team B, so Team A is definitely better, even though their score distributions largely overlap. ignores about spread or outliers.

Problem 118

Identify what claim The IQR for both datasets is 10, so their spreads are identical, but Dataset X has extreme values much further from the median than Dataset Y. ignores about spread or outliers.

Problem 119

Identify what claim The average age of customers is 35, so our target audience is middle-aged, even though the ages are mostly 20s and 50s. ignores about spread or outliers.

Open in simulator
Problem 120

Identify what claim The median test scores for both classes are 75, so their performance is identical, but Class A has scores from 30 to 100, while Class B has scores from 60 to 90. ignores about spread or outliers.

reason about outliers, center, and spread.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Explain how changing data value replace a high outlier 100 with 20 in data centered near 18 affects distribution interpretation.

Problem 122

Explain how changing data value add a new value near the existing median affects distribution interpretation.

Problem 123

Explain how changing data value remove the only low outlier from a data set affects distribution interpretation.

Problem 124

Explain how changing data value change one middle value to an extreme high value affects distribution interpretation.

Problem 125

Explain how changing data value add a new value significantly higher than all existing data points affects distribution interpretation.

Problem 126

Explain how changing data value remove a value close to the mean from a nearly symmetric distribution affects distribution interpretation.

Open in simulator
Problem 127

Explain how changing data value replace a low outlier 5 with 15 in data centered near 20 affects distribution interpretation.

Problem 128

Explain how changing data value add several new values that are all significantly lower than the existing data affects distribution interpretation.

Problem 129

Explain how changing data value change a value from the upper quartile to the lower quartile affects distribution interpretation.

Problem 130

Explain how changing data value remove the maximum value from a right-skewed distribution affects distribution interpretation.

Problem 131

Explain how changing data value add a new value that is higher than the current maximum but not an extreme outlier affects distribution interpretation.

Problem 132

Explain how changing data value change one middle value to an extreme low value affects distribution interpretation.

include shape, center, spread, outliers, and context.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Write a full comparative distribution summary from group A is symmetric with median 50 and IQR 8; group B is right-skewed with median 45 and IQR 20 plus a high outlier in context scores.

Problem 134

Write a full comparative distribution summary from two dot plots have similar centers near 12, but group A is tightly clustered and group B is spread from 5 to 20 in context plant heights in cm.

Problem 135

Write a full comparative distribution summary from group A has a left-skewed histogram centered near 30; group B is symmetric centered near 30 with smaller range in context wait times in minutes.

Problem 136

Write a full comparative distribution summary from Group X is roughly symmetric with a mean of 75 and standard deviation of 5; Group Y is slightly left-skewed with a mean of 82 and standard deviation of 6 in context test scores.

Problem 137

Write a full comparative distribution summary from Dataset 1 has a median of 25 and an IQR of 4, with no outliers; Dataset 2 has a median of 26 and an IQR of 15, with a low outlier at 10 in context daily temperatures in Celsius.

Problem 138

Write a full comparative distribution summary from The distribution of salaries for Company A is right-skewed with a median of $50,000 and an IQR of $15,000; Company B's salaries are also right-skewed but with a median of $65,000 and an IQR of $10,000 in context annual salaries.

Problem 139

Write a full comparative distribution summary from The number of calls per hour for Operator P is symmetric around a mean of 15 with a range of 10; Operator Q's calls are bimodal with peaks at 10 and 20, and a range of 15 in context number of customer calls.

Problem 140

Write a full comparative distribution summary from The ages of participants in Program A are strongly right-skewed with a median of 40 and an IQR of 15; Program B's participants' ages are strongly left-skewed with a median of 42 and an IQR of 12 in context participant ages.

Open in simulator
Problem 141

Write a full comparative distribution summary from The distribution of arrival times for Bus Route 1 is uniform between 8:00 AM and 8:30 AM; Bus Route 2's arrival times are symmetric around 8:15 AM with most arrivals between 8:10 AM and 8:20 AM in context bus arrival times.

Problem 142

Write a full comparative distribution summary from The weights of apples from Orchard P are symmetric with a mean of 150g and standard deviation of 10g; apples from Orchard Q are also symmetric with a mean of 180g and standard deviation of 12g in context apple weights in grams.

Problem 143

Write a full comparative distribution summary from The number of defects per batch for Machine A is symmetric with a median of 3 and an IQR of 2; Machine B's defects are slightly right-skewed with a median of 4, an IQR of 5, and several high outliers in context number of defects.

Problem 144

Write a full comparative distribution summary from The reaction times for Task 1 are bimodal with peaks at 200ms and 400ms, and a range of 300ms; Task 2's reaction times are also bimodal with peaks at 250ms and 350ms, and a range of 200ms in context reaction times in milliseconds.