Math II · A-CED.1

Creating and Solving One-Variable Equations and Inequalities in Math II Models

This objective teaches students how to turn a real question into a solvable mathematical machine. Whenever a person asks, “What value makes this happen?” or “What values are allowed?” this is the math underneath.

Concept Algebra
Domain Creating Equations
Read time 11 minutes

What this learning objective is really asking you to learn

This objective asks students to do one of the most important jobs in all of mathematics: convert a situation into a precise statement about an unknown quantity. In Math I, students learned to create linear equations and inequalities, solve them, graph them, and interpret them in context. Math II keeps that same modeling habit, but the mathematical machinery becomes more powerful. The unknown quantity may now appear inside an absolute value, as part of a quadratic expression, in a denominator, or in an exponent. That is a major upgrade. It means students are no longer limited to situations where change is constant. They can model distance from a target, area and projectile motion, rate and work relationships, and growth or decay.

A one-variable equation is a statement that two expressions are equal for certain values of one unknown. A one-variable inequality is a statement that one expression is greater than, less than, at least, or at most another expression. In real situations, equations answer questions like “When does this quantity hit a target?” Inequalities answer questions like “When is this quantity acceptable?” “How many are needed?” “How much can we spend?” “What range is safe?” An equation often identifies boundary points. An inequality often identifies the allowable region on one side of those boundaries.

The phrase create equations matters. Many students think the hard part of algebra is solving after the equation is handed to them. In real life, the hard part is usually deciding what equation should exist in the first place. If a problem says a phone plan charges a fixed monthly fee plus a rate per gigabyte, the student must identify the fixed amount, the variable amount, the unknown, and the condition being asked about. If a problem says the area of a rectangle is known and one side is longer than the other, the student must represent the dimensions and build an area equation. If a situation involves repeated percentage growth, the student must choose an exponential model instead of adding the same amount again and again.

Math II expands the range of situations that can be modeled. A linear equation might represent a constant rate, such as cost per mile or pay per hour. An absolute-value equation or inequality might represent distance from a target, tolerance in manufacturing, error range in measurement, or acceptable deviation from a goal. A quadratic equation might represent area, falling objects, revenue, or any situation where two changing quantities are multiplied. A simple rational equation might represent average speed, density, work rate, concentration, or inverse variation. An exponential equation might represent compound interest, population growth, radioactive decay, medicine leaving the bloodstream, or a value repeatedly multiplied by the same factor.

This objective is not only about getting an answer. It is about building a chain of meaning. The student must decide what the variable represents, write expressions that match the situation, set up an equation or inequality, solve using legal algebraic moves, check for extraneous or impossible answers, and translate the solution back into context. The answer is not just \(x = 7\). The answer is “the package must weigh 7 pounds,” “the object reaches the ground after 7 seconds,” “the temperature must stay within 7 degrees of the target,” or “the investment reaches the goal after about 7 years.”

A strong student sees the difference between a symbolic answer and a contextual answer. The symbol is only a compressed representation. The context gives the answer its meaning, its unit, and its limitations. If \(x\) represents time, negative values may not make sense. If \(x\) represents a length, zero or negative values may be impossible. If \(x\) appears in a denominator, values that make the denominator zero must be excluded. If the original problem involves a square root or a squared equation, some algebraic solutions may be extraneous. If the solution to an inequality is a range, the student must know whether endpoints are included and whether the range makes sense in the situation.

Why students should learn this math

Students should learn this objective because equations are the language of “make this happen.” A student may not use the phrase “one-variable equation” in daily conversation, but they constantly face one-variable decisions. How many hours do I need to work to afford this? What test score do I need to average a B? How much can I spend and still stay within budget? When will a phone battery reach 20 percent? How far can a car travel before refueling? What height should a ramp be to meet a design requirement? What price gives a certain profit? These are not separate math tricks. They are all versions of the same modeling act.

The “why” becomes clearer when students see that different equation types represent different kinds of real machinery. Linear equations represent steady change. If every extra hour adds the same amount of money, a line is a good model. Absolute-value equations represent distance from a center or target. If a machine part must be within 0.02 inches of a design length, the issue is not whether the part is above or below the target. The issue is how far it is from the target. Quadratic equations represent multiplication of related quantities, curved motion, and optimization. A garden area problem, a revenue problem, or a projectile problem often becomes quadratic because the situation involves squared quantities or products of changing factors. Rational equations represent ratios, rates, and sharing. Exponential equations represent repeated multiplication, which is why they appear in finance, biology, chemistry, epidemiology, and technology.

Learning to create equations also builds intellectual independence. A student who can only solve worksheet equations is dependent on someone else to translate the world. A student who can create equations can model new situations. That skill is valuable even when the exact algebra is later handled by technology. Calculators, spreadsheets, and programming languages can solve many equations. They cannot decide for the student what variables to use, what assumptions are reasonable, what units belong in the model, what restrictions apply, and whether the final answer is sensible. Human judgment is still the central tool.

This math also protects students from bad reasoning. Without equations, people often rely on intuition alone. Intuition is useful, but it fails when relationships are nonlinear. Exponential growth is famously hard to estimate mentally. A quantity that increases by 5 percent repeatedly does not grow by adding the same amount each time; it compounds. Quadratic relationships can also fool intuition because the output changes faster as the input grows. Doubling a side length can quadruple area. Doubling speed can more than double stopping distance in common physical models. Rational relationships can be counterintuitive because increasing one variable may decrease another. Equations make these hidden structures visible.

There is also a career reason. Creating and solving equations appears in engineering, architecture, computer science, finance, health science, construction, logistics, environmental science, manufacturing, animation, game design, and public policy. A nurse calculating dosage, an engineer designing a support, a business owner setting prices, a programmer building a simulation, and a scientist estimating decay all use the same fundamental idea: define an unknown, express relationships, solve, and check. The tools may be more advanced, but the root habit is exactly this objective.

For students who ask, “Why am I learning this?” the honest answer is not “because it will be on a test.” The better answer is: because this is how humans turn uncertainty into a decision. Equations let you take a messy question and create a structured path toward an answer. Inequalities let you describe acceptable ranges instead of single targets. Together, they form one of the main control systems of modern life.

The historical machinery behind this idea

The history of this objective is the history of algebra itself. The word algebra is connected to the Arabic term al-jabr, associated with the work of Muhammad ibn Musa al-Khwarizmi in the ninth century. His work organized procedures for solving equations in systematic ways. Long before modern notation, people solved practical problems about inheritance, land, trade, and measurement by setting up relationships among unknown quantities. The notation looked different, but the purpose was familiar: represent what is unknown and reason toward its value.

Ancient Babylonian mathematicians solved problems that we would now call quadratic, often in geometric or verbal form. They did not write \(x^2 + bx + c = 0\) the way students do today, but they reasoned about squares, rectangles, areas, and unknown lengths. Greek mathematics added geometric rigor. Islamic mathematicians preserved, extended, and organized algebraic methods. Later European mathematicians developed symbolic notation that made algebra more general and more efficient.

The development of symbolic algebra changed everything. Francois Viète helped popularize the use of letters for known and unknown quantities. René Descartes connected algebra to geometry, making it possible to see equations as curves and curves as equations. That connection is one of the major bridges in the math map. A one-variable equation can be solved symbolically, but it can also be understood as an intersection, a zero, or a target value on a graph.

Inequalities also became essential as mathematics moved into science and engineering. Real-world design rarely asks only for exact values. It asks for tolerances, limits, thresholds, and safe operating ranges. A bridge must support at least a certain load. A medicine dose must stay within a safe range. A budget must not exceed a limit. A manufactured part must be close enough to a target dimension. These are inequality ideas. Absolute value became a natural way to describe error and distance from a desired value.

Quadratic, rational, and exponential equations entered the mainstream because they model different structures in the world. Quadratics arise naturally from area and accelerated motion. Rational equations arise from ratios and inverse relationships. Exponential equations arise from repeated multiplication, including compound interest and growth/decay. As science and commerce became more quantitative, algebra had to handle more than straight lines.

This objective therefore sits inside a long historical machine. It inherits ancient practical problem solving, medieval algebraic organization, early modern symbolic notation, coordinate geometry, and modern modeling. Students are not merely learning school procedures. They are learning a compressed version of a tool humanity built over centuries to solve problems that words alone could not handle precisely.

Technical execution: how to create and solve the equation or inequality

A reliable process starts before any algebraic manipulation. First, identify the unknown and define the variable clearly. Do not just write \(x\). Write what \(x\) means: number of tickets, time in seconds, width in meters, price in dollars, percent as a decimal, or number of years. The unit is part of the variable. A naked variable without a meaning is a symbol floating in space.

Second, identify the relationship. What quantities are being compared? Is there a total, a difference, a product, a ratio, a distance from a target, or a repeated growth factor? This step determines the kind of equation. If the situation says “per” or “for each,” the model may be linear. If it says “within,” “at most this far from,” or “deviation,” absolute value may be appropriate. If area or projectile motion appears, look for quadratic structure. If there is a rate, reciprocal, or average, a rational expression may appear. If the situation uses percent growth per time period, repeated doubling, half-life, or compounding, look for exponential structure.

Third, write the equation or inequality. Translate the condition exactly. Equal to, greater than, less than, at least, and at most are not interchangeable. “At least 50” means \(\ge 50\); “less than 50” means \(< 50\); “within 3 of 20” means \(|x - 20| \le 3\). Many mistakes happen because students solve correctly after translating incorrectly.

Fourth, solve using methods appropriate to the structure. Linear equations usually require inverse operations and combining like terms. Absolute-value equations often split into two cases because a distance can occur on either side of a target. For example, \(|x - 10| = 3\) gives \(x - 10 = 3\) or \(x - 10 = -3\), so \(x = 13\) or \(x = 7\). Absolute-value inequalities require careful interpretation: \(|x - 10| \le 3\) means the distance from 10 is no more than 3, so \(7 \le x \le 13\); \(|x - 10| > 3\) means outside that interval.

Quadratic equations can be solved by factoring, square roots, completing the square, or the quadratic formula. The chosen method should match the form. If the equation is already factored, use the zero product property. If it looks like \((x - 4)^2 = 25\), take square roots. If it is not factorable nicely, completing the square or the quadratic formula may be better. The important idea is that solving is not one button. It is method selection based on structure.

Simple rational equations often require multiplying by a common denominator to clear fractions, but students must record restrictions first. If the equation contains \(1/(x - 2)\), then \(x = 2\) cannot be a solution because it makes the original expression undefined. Clearing denominators can create candidate solutions that must be checked. This is not optional. A solution is only valid if it works in the original problem.

Exponential equations may be solved in Math II by recognizing common bases, using tables or graphs, or applying technology when logarithms are not yet the focus. For example, \(2^x = 32\) can be solved by recognizing \(32 = 2^5\), so \(x = 5\). A compound-interest equation may require estimating when a value passes a threshold. Later, logarithms will give a more general symbolic method.

Fifth, check the solution in the original context. Substitute into the original equation when possible. Check units. Check domain restrictions. Check whether the answer is reasonable. If a model about time gives \(t = -4\), that may be algebraically possible but physically meaningless. If a length comes out negative, reject it in a geometry context. If an inequality solution includes values that violate the story, trim the solution to the viable domain.

Where this fits in the big map of mathematics

In the full map of high-school mathematics, this objective is a hub. It touches algebra because students manipulate symbols. It touches functions because the equations often come from linear, quadratic, rational, or exponential relationships. It touches graphing because solving can be interpreted as finding where a function reaches a value or crosses another function. It touches geometry because many equations arise from length, area, volume, and distance. It touches statistics and science because models are built from observed relationships. It touches number systems because some equations have no rational solution, no real solution, or solutions that require new kinds of numbers.

This objective also prepares students for later Math II and Math III work. Completing the square, the quadratic formula, linear-quadratic systems, inverse functions, rational exponents, trigonometry, logarithms, and polynomial equations all depend on the same foundation: create a mathematical statement and solve it honestly. Students who master this objective are much better prepared for advanced modeling because they understand equations as meaning-making tools rather than as isolated exercises.

Common student traps and how to avoid them

One common trap is solving before understanding. Students see numbers and immediately start manipulating them. The better habit is to pause and define the variable, units, relationship, and question. Algebraic speed is worthless if the equation is wrong.

A second trap is ignoring restrictions. Rational equations can have excluded values. Square-root or squared equations can create extraneous solutions. Real-world contexts can eliminate negative values. Every solution must survive the original equation and the story.

A third trap is confusing equations and inequalities. An equation finds values that make something exactly true. An inequality finds a range of values that make a condition acceptable. In real modeling, inequalities are often more realistic because the world usually has tolerances and limits rather than perfect targets.

A fourth trap is treating all models as linear. Math II expands the toolkit because not every situation changes by equal differences. Area, repeated growth, rates, and distance from a target require different structures. Choosing the wrong model type can lead to a beautifully solved wrong problem.

Problem Library

Problems in the App From This Objective

198 problems across 15 archetypes in the app.

model fixed/rate relationships and solve.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Create and solve a linear equation for context A gym charges 20 dollars plus 5 dollars per visit. Total cost is 65 dollars.

Problem 2

Create and solve a linear equation for context A taxi costs 4 dollars plus 2 dollars per mile. Total is 30 dollars.

Problem 3

Create and solve a linear equation for context A phone plan has 15 dollar fee plus 0.10 dollars per text. Total is 27 dollars.

Problem 4

Create and solve a linear equation for context A plumber charges a 50 dollar service fee plus 75 dollars per hour. The total bill was 275 dollars.

Problem 5

Create and solve a linear equation for context A car rental company charges a 30 dollar flat fee plus 0.25 dollars per mile. The total cost was 80 dollars.

Problem 6

Create and solve a linear equation for context A babysitter charges a 10 dollar base fee plus 12 dollars per hour. If the total earned was 58 dollars.

Problem 7

Create and solve a linear equation for context An internet provider charges a 40 dollar installation fee plus 60 dollars per month. If the total bill was 220 dollars.

Open in simulator
Problem 8

Create and solve a linear equation for context A T-shirt printing service charges a 25 dollar design fee plus 8 dollars per shirt. The total cost was 105 dollars.

Problem 9

Create and solve a linear equation for context A pizza place charges a 5 dollar delivery fee plus 15 dollars per pizza. If the total was 50 dollars.

Problem 10

Create and solve a linear equation for context An electrician charges a 60 dollar call-out fee plus 80 dollars per hour. The total bill was 300 dollars.

Problem 11

Create and solve a linear equation for context A gardening service charges a 15 dollar equipment fee plus 35 dollars per hour. The total bill was 120 dollars.

Problem 12

Create and solve a linear equation for context A book club has a 10 dollar annual membership fee plus 7 dollars per book. If a member spent 45 dollars in total.

represent thresholds and interpret solution sets.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Create and solve a linear inequality for context A budget is at most 50 dollars with 8 dollar entry fee and 6 dollars per ride.

Problem 14

Create and solve a linear inequality for context A truck can carry at most 1200 pounds after 150 pounds of equipment and boxes of 35 pounds.

Problem 15

Create and solve a linear inequality for context A fundraiser needs at least 500 dollars after 80 already raised and 12 per ticket.

Problem 16

Create and solve a linear inequality for context A concert budget is at most 150 dollars for a 25 dollar ticket and 15 dollars per merchandise item.

Problem 17

Create and solve a linear inequality for context A salesperson needs to earn at least 800 dollars this week with a 200 dollar base salary and 50 dollars commission per sale.

Problem 18

Create and solve a linear inequality for context An elevator has a maximum capacity of 1800 pounds. The operator weighs 160 pounds, and each passenger averages 150 pounds.

Problem 19

Create and solve a linear inequality for context A factory must produce a minimum of 300 units per day. They already produced 75 units, and each machine produces 25 units per hour.

Problem 20

Create and solve a linear inequality for context A driver wants to travel at most 400 miles. They already drove 120 miles and plan to drive at an average speed of 60 mph.

Problem 21

Create and solve a linear inequality for context A baker needs at least 25 cups of flour for a large order. They have 7 cups already, and each bag contains 3 cups.

Problem 22

Create and solve a linear inequality for context A phone plan allows a maximum of 10 GB of data. 2 GB has already been used, and each app download uses 0.5 GB.

Open in simulator
Problem 23

Create and solve a linear inequality for context A student needs a minimum average score of 85 on five tests. Their first four scores are 78, 92, 80, and 88.

Problem 24

Create and solve a linear inequality for context The sum of two siblings' ages is at most 30. The older sibling is 4 years older than the younger sibling.

interpret absolute value as distance and split cases.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Create and solve an absolute-value equation for context A measurement is 3 units from target 20.

Problem 26

Create and solve an absolute-value equation for context A temperature is 5 degrees from 72.

Problem 27

Create and solve an absolute-value equation for context A score differs from 85 by 4 points.

Open in simulator
Problem 28

Create and solve an absolute-value equation for context A weight is 2 pounds from 150.

Problem 29

Create and solve an absolute-value equation for context A time is 10 minutes from 60.

Problem 30

Create and solve an absolute-value equation for context A height is 6 inches from 70.

Problem 31

Create and solve an absolute-value equation for context A speed is 7 mph from 55.

Problem 32

Create and solve an absolute-value equation for context A price is $1.50 from $25.00.

Problem 33

Create and solve an absolute-value equation for context A volume is 0.5 liters from 10 liters.

Problem 34

Create and solve an absolute-value equation for context A length is 8 cm from 100 cm.

Problem 35

Create and solve an absolute-value equation for context A population differs from 5000 by 200.

Problem 36

Create and solve an absolute-value equation for context A voltage is 0.2 volts from 120 volts.

distinguish within versus outside distance.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Create and solve an absolute-value inequality for context A part must be within 0.2 cm of 10 cm.

Problem 38

Create and solve an absolute-value inequality for context Temperature must be more than 4 degrees away from 32.

Problem 39

Create and solve an absolute-value inequality for context A score is acceptable if within 6 points of 80.

Problem 40

Create and solve an absolute-value inequality for context The ideal weight for a package is 5 kg, with a tolerance of 0.5 kg.

Problem 41

Create and solve an absolute-value inequality for context A machine is out of calibration if its reading is more than 0.1 units away from 15.

Problem 42

Create and solve an absolute-value inequality for context The height of a bookshelf must be within 2 inches of 60 inches.

Problem 43

Create and solve an absolute-value inequality for context A satellite is considered off-course if its distance from the target is greater than 100 km from 5000 km.

Problem 44

Create and solve an absolute-value inequality for context The price of a stock is stable if it stays within $1.50 of $75.

Problem 45

Create and solve an absolute-value inequality for context An event is considered late or early if its start time is more than 5 minutes away from the scheduled time (0 minutes deviation).

Problem 46

Create and solve an absolute-value inequality for context The volume of a liquid in a container must be within 10 mL of 250 mL.

Open in simulator
Problem 47

Create and solve an absolute-value inequality for context A plank is unusable if its width deviates by more than 0.05 inches from 8 inches.

Problem 48

Create and solve an absolute-value inequality for context A chemical reaction requires a mass of reactant to be within 0.01 grams of 1.5 grams.

set up product relationship and solve by factoring or formula.
15 problems Warmup Practice Mixed Review Assessment
Problem 49

Create and solve a quadratic equation from area context A rectangle has length x+5, width x, and area 84.

Problem 50

Create and solve a quadratic equation from area context A rectangle has dimensions x+3 and x+1 with area 48.

Problem 51

Create and solve a quadratic equation from area context A triangle has base x and height x+4 with area 30.

Problem 52

Create and solve a quadratic equation from area context A rectangle has width x, length x+2, and area 35.

Problem 53

Create and solve a quadratic equation from area context A rectangle has length x, width x-3, and area 54.

Problem 54

Create and solve a quadratic equation from area context A rectangle has width x, length 2x, and area 72.

Open in simulator
Problem 55

Create and solve a quadratic equation from area context A rectangle has length x, width x/3, and area 75.

Problem 56

Create and solve a quadratic equation from area context A triangle has height x, base x+5, and area 42.

Problem 57

Create and solve a quadratic equation from area context A triangle has base x, height x-2, and area 24.

Problem 58

Create and solve a quadratic equation from area context A rectangle has dimensions x-2 and x+4 with area 55.

Problem 59

Create and solve a quadratic equation from area context A rectangle has dimensions 2x-1 and x+2 with area 42.

Problem 60

Create and solve a quadratic equation from area context A square has a side length of x+3 and an area of 100.

Problem 61

Create and solve a quadratic equation from area context A square has a side length of 2x-1 and an area of 49.

Problem 62

Create and solve a quadratic equation from area context A triangle has base x+1 and height x-3 with area 16.

Problem 63

Create and solve a quadratic equation from area context A rectangle has dimensions x+6 and x-1 with area 30.

identify height equation and solve for time or height condition.
15 problems Warmup Practice Mixed Review Assessment
Problem 64

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+64t. Find when height is 0 after launch.

Open in simulator
Problem 65

Create and solve a quadratic equation from motion context Height h(t)=-5t^2+20t+1. Find when it returns to height 1.

Problem 66

Create and solve a quadratic equation from motion context Height h(t)=-t^2+6t+7. Find when it hits ground.

Problem 67

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+80t. Find when it hits the ground after launch.

Problem 68

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+48t+160. Find when it hits the ground.

Problem 69

Create and solve a quadratic equation from motion context Height h(t)=-4.9t^2+19.6t+24.5. Find when it hits the ground.

Problem 70

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+96t+10. Find when it returns to height 10 feet after launch.

Problem 71

Create and solve a quadratic equation from motion context Height h(t)=-5t^2+30t+20. Find when it returns to height 20 meters after launch.

Problem 72

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+112t. Find when it hits the ground after launch.

Problem 73

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+80t+20. Find when it returns to its initial height.

Problem 74

Create and solve a quadratic equation from motion context Height h(t)=-4.9t^2+9.8t+39.2. Find when it hits the ground.

Problem 75

Create and solve a quadratic equation from motion context Height h(t)=-2t^2+10t+12. Find when it hits the ground.

Problem 76

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+128t+32. Find when it reaches 32 feet again after launch.

Problem 77

Create and solve a quadratic equation from motion context Height h(t)=-16t^2+160t+384. Find when it hits the ground.

Problem 78

Create and solve a quadratic equation from motion context Height h(t)=-4.9t^2+29.4t+10. Find when it returns to a height of 10 meters after launch.

solve boundary equation and test intervals.
15 problems Warmup Practice Mixed Review Assessment
Problem 79

Create and solve a quadratic inequality from context Profit P(x)=x^2-5x+6 is positive.

Problem 80

Create and solve a quadratic inequality from context Height h(t)=-t^2+6t is at least 8.

Problem 81

Create and solve a quadratic inequality from context Area x(x+4) is less than 12 for positive x.

Problem 82

Create and solve a quadratic inequality from context A company's profit P(x) = -x^2 + 10x - 21 is negative.

Problem 83

Create and solve a quadratic inequality from context A ball's height h(t) = -t^2 + 8t is less than 12 for t>=0.

Problem 84

Create and solve a quadratic inequality from context The area of a rectangle with sides x and x+5 is at most 14 for positive x.

Problem 85

Create and solve a quadratic inequality from context The product of two consecutive integers, x and x+1, is at least 6.

Problem 86

Create and solve a quadratic inequality from context A company's revenue R(x) = 10x and cost C(x) = x^2 + 16. When is revenue greater than cost?.

Problem 87

Create and solve a quadratic inequality from context The area of a square with side length (x-1) is at most 9, given x-1>0.

Open in simulator
Problem 88

Create and solve a quadratic inequality from context A projectile's height h(t) = -16t^2 + 64t. When is the projectile above the ground?.

Problem 89

Create and solve a quadratic inequality from context The product of two numbers, one is x and the other is (x-5), is negative.

Problem 90

Create and solve a quadratic inequality from context The cost C(x) = 2x^2 - 12x + 20 is at most 10.

Problem 91

Create and solve a quadratic inequality from context The area of a rectangle with length (x+3) and width (x-2) is greater than 14, given x-2>0.

Problem 92

Create and solve a quadratic inequality from context The square of a number x is less than 16.

Problem 93

Create and solve a quadratic inequality from context The expression 2x^2 + 7x - 4 is non-negative.

clear denominators and check restrictions.
15 problems Warmup Practice Mixed Review Assessment
Problem 94

Create and solve a rational equation from rate context A trip of 120 miles takes 3 hours. Find speed.

Problem 95

Create and solve a rational equation from rate context A worker completes 1 job in x hours, and rate is 1/6 job per hour.

Problem 96

Create and solve a rational equation from rate context Average cost 12 dollars for x items with total cost 96 dollars.

Problem 97

Create and solve a rational equation from rate context A car travels 240 miles in 't' hours at a speed of 60 mph. Find 't'.

Problem 98

Create and solve a rational equation from rate context A machine processes 500 units in 'h' hours. Its processing rate is 125 units per hour. Find 'h'.

Problem 99

Create and solve a rational equation from rate context The total cost for 'n' books is $105, and each book costs $15. Find 'n'.

Problem 100

Create and solve a rational equation from rate context A substance has a mass of 72 grams and a density of 8 g/cm³. Find its volume 'v'.

Problem 101

Create and solve a rational equation from rate context A pipe fills a 300-liter tank in 'm' minutes. The flow rate is 50 liters per minute. Find 'm'.

Problem 102

Create and solve a rational equation from rate context A 200 ml solution contains 'x' grams of salt. The concentration is 0.05 g/ml. Find 'x'.

Problem 103

Create and solve a rational equation from rate context A car travels 'd' miles in 4 hours at a speed of 55 mph. Find 'd'.

Problem 104

Create and solve a rational equation from rate context A worker completes 3 jobs in 12 hours. Find the rate 'r' in jobs per hour.

Problem 105

Create and solve a rational equation from rate context It takes 'x' hours to paint 3 walls. The painting rate is 1/2 wall per hour. Find 'x'.

Problem 106

Create and solve a rational equation from rate context A total of $180 was spent on 'y' shirts. Each shirt cost $20. Find 'y'.

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Problem 107

Create and solve a rational equation from rate context A train travels at 70 mph for 't' hours, covering 350 miles. Find 't'.

Problem 108

Create and solve a rational equation from rate context A printer prints 'p' pages in 30 minutes at a rate of 5 pages per minute. Find 'p'.

identify restricted values and test intervals.
15 problems Warmup Practice Mixed Review Assessment
Problem 109

Create and solve a rational inequality from constraint Average cost 100/x must be at most 20 for x>0.

Problem 110

Create and solve a rational inequality from constraint Speed 60/t must be greater than 30 for t>0.

Problem 111

Create and solve a rational inequality from constraint Density 24/V is at least 6 for V>0.

Problem 112

Create and solve a rational inequality from constraint Production rate 120/h must be less than 40 for h>0.

Problem 113

Create and solve a rational inequality from constraint Current 50/R is at most 10 for R>0.

Problem 114

Create and solve a rational inequality from constraint Efficiency 90/w must be greater than 15 for w>0.

Problem 115

Create and solve a rational inequality from constraint Concentration 75/m is at least 25 for m>0.

Problem 116

Create and solve a rational inequality from constraint Time taken 180/s must be at most 6 for s>0.

Problem 117

Create and solve a rational inequality from constraint Flow rate 200/t must be less than 50 for t>0.

Problem 118

Create and solve a rational inequality from constraint Pressure 300/A is at least 100 for A>0.

Problem 119

Create and solve a rational inequality from constraint Work done 400/d must be greater than 80 for d>0.

Problem 120

Create and solve a rational inequality from constraint Resistance 150/L is at most 30 for L>0.

Problem 121

Create and solve a rational inequality from constraint Temperature change 210/k must be less than 70 for k>0.

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Problem 122

Create and solve a rational inequality from constraint Volume 250/h is at least 50 for h>0.

Problem 123

Create and solve a rational inequality from constraint Power output 360/r must be greater than 90 for r>0.

use common bases, tables, or technology-supported logs preview.
15 problems Warmup Practice Mixed Review Assessment
Problem 124

Create and solve an exponential equation from context A population starts at 100 and doubles each hour. When is it 800?.

Problem 125

Create and solve an exponential equation from context A medicine amount starts at 64 mg and halves each hour. When is it 8 mg?.

Problem 126

Create and solve an exponential equation from context An account starts at 500 and grows by factor 1.1 each year. When does model reach 605?.

Problem 127

Create and solve an exponential equation from context A bacterial colony starts with 50 cells and triples every hour. When does it reach 450 cells?.

Problem 128

Create and solve an exponential equation from context An investment of $200 quadruples every year. When does it reach $3200?.

Problem 129

Create and solve an exponential equation from context A substance starts at 128 grams and halves every hour. When is it 16 grams?.

Problem 130

Create and solve an exponential equation from context A radioactive material starts with 256 units and quarters every day. When is it 4 units?.

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Problem 131

Create and solve an exponential equation from context A plant starts at 10 cm and grows by a factor of 1.5 each week. When does it reach 22.5 cm?.

Problem 132

Create and solve an exponential equation from context A car's value starts at $20,000 and decreases by a factor of 0.8 each year. When is its value $12,800?.

Problem 133

Create and solve an exponential equation from context A rumor starts with 3 people and the number of people who know it triples each day. When do 243 people know the rumor?.

Problem 134

Create and solve an exponential equation from context A digital file starts at 1024 MB and is compressed to half its size each minute. When is its size 128 MB?.

Problem 135

Create and solve an exponential equation from context An investment of $1000 doubles each year. When does it reach $4000?.

Problem 136

Create and solve an exponential equation from context A chemical reaction starts with 250 units of a compound, and its concentration halves every minute. When does it reach 62.5 units?.

Problem 137

Create and solve an exponential equation from context A savings account starts with $200 and grows by a factor of 1.2 each year. When does it reach $288?.

Problem 138

Create and solve an exponential equation from context A machine's efficiency starts at 100 and decreases by a factor of 0.9 each month. When does its efficiency drop to 81?.

choose linear, absolute-value, quadratic, rational, or exponential model.
12 problems Warmup Practice Mixed Review Assessment
Problem 139

Choose the equation type that matches context same amount added each month.

Problem 140

Choose the equation type that matches context distance from a target value is at most 3.

Problem 141

Choose the equation type that matches context area formed by product of two expressions involving x.

Problem 142

Choose the equation type that matches context time equals distance divided by speed with variable in denominator.

Problem 143

Choose the equation type that matches context quantity is multiplied by 1.08 each year.

Problem 144

Choose the equation type that matches context initial fee of $20 plus $5 per hour.

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Problem 145

Choose the equation type that matches context the temperature deviates from 70 degrees by at most 5 degrees.

Problem 146

Choose the equation type that matches context the product of a number and two more than the number.

Problem 147

Choose the equation type that matches context average cost per item when total cost is fixed and number of items varies.

Problem 148

Choose the equation type that matches context value halves every 5 years.

Problem 149

Choose the equation type that matches context subtracting 3 from a quantity repeatedly.

Problem 150

Choose the equation type that matches context the difference between a variable and 10 is exactly 2.

reject extraneous, negative, fractional, or off-domain answers where inappropriate.
12 problems Warmup Practice Mixed Review Assessment
Problem 151

Interpret solution candidates x=5 and x=-9 for model context rectangle side length x.

Problem 152

Interpret solution candidates t=12.5 for model context number of tickets t.

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Problem 153

Interpret solution candidates t=0 and t=4 for model context time after launch, and the question asks when it lands after launch.

Problem 154

Interpret solution candidates x=3 for model context rational equation with original denominator x-3.

Problem 155

Interpret solution candidates a=15 and a=-3 for model context age of a person a.

Problem 156

Interpret solution candidates n=7.5 for model context number of whole items n.

Problem 157

Interpret solution candidates t=2 and t=-1 for model context time in seconds after an event started.

Problem 158

Interpret solution candidates x=2 and x=-1 for model context solution to sqrt(x+2)=x.

Problem 159

Interpret solution candidates L=0 and L=10 for model context length of a rope L.

Problem 160

Interpret solution candidates s=28.5 for model context number of students s in a class.

Problem 161

Interpret solution candidates d=-5 and d=100 for model context distance d traveled.

Problem 162

Interpret solution candidates y=1 for model context rational equation with original denominator y-1.

translate geometric relationships to equations or inequalities.
12 problems Warmup Practice Mixed Review Assessment
Problem 163

Create a one-variable model from diagram description rectangle length x+4 and width x with area 45.

Problem 164

Create a one-variable model from diagram description right triangle legs x and 12 with hypotenuse 13.

Problem 165

Create a one-variable model from diagram description two similar rectangles have side ratio x/6=10/15.

Problem 166

Create a one-variable model from diagram description perimeter of rectangle with sides x and x+3 is 30.

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Problem 167

Create a one-variable model from diagram description triangle with base x and height x+5 has area 20.

Problem 168

Create a one-variable model from diagram description triangle with sides x, x+1, and x+2 has perimeter 18.

Problem 169

Create a one-variable model from diagram description angles of a triangle are x, 2x, and 3x degrees.

Problem 170

Create a one-variable model from diagram description circle with radius x has circumference 31.4.

Problem 171

Create a one-variable model from diagram description square with side length x-3 has area 49.

Problem 172

Create a one-variable model from diagram description trapezoid with parallel bases x and x+2 and height 5 has area 30.

Problem 173

Create a one-variable model from diagram description two complementary angles are x and 2x-15 degrees.

Problem 174

Create a one-variable model from diagram description cube with side length x+1 has volume 64.

identify missing constraints, wrong operation, or wrong function type.
12 problems Warmup Practice Mixed Review Assessment
Problem 175

Compare possible one-variable models x+(x+5)=84 and x(x+5)=84 for situation rectangle with sides x and x+5 has area 84.

Problem 176

Compare possible one-variable models |x-20|<=3 and x-20<=3 for situation a value stays within 3 units of 20.

Problem 177

Compare possible one-variable models 50+2t and 50(2)^t for situation quantity doubles each period from 50.

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Problem 178

Compare possible one-variable models 1000 + 0.05t and 1000(1.05)^t for situation An investment of $1000 earns 5% interest annually for 't' years.

Problem 179

Compare possible one-variable models 4s = 48 and s^2 = 48 for situation A square has a perimeter of 48. What is the side length 's'?.

Problem 180

Compare possible one-variable models c = 1.5w and c = 1.5/w for situation The cost 'c' of apples is directly proportional to their weight 'w' in pounds, with a constant of proportionality of $1.50 per pound.

Problem 181

Compare possible one-variable models x + (x+1) + (x+2) = 45 and x * (x+1) * (x+2) = 45 for situation The sum of three consecutive integers is 45. Let 'x' be the first integer.

Problem 182

Compare possible one-variable models m + 5m = 35 and m + (m+5) = 35 for situation John is 5 years older than Mary. Their combined age is 35. Let Mary's age be 'm'.

Problem 183

Compare possible one-variable models b * h = 24 and (1/2) * b * h = 24 for situation A triangle has a base of 'b' and a height of 'h'. Its area is 24.

Problem 184

Compare possible one-variable models p - 0.20 = 80 and p - 0.20p = 80 for situation A price 'p' is reduced by 20%. The new price is $80.

Problem 185

Compare possible one-variable models s + 3 = 180 and s * 3 = 180 for situation A car travels at a speed 's' for 3 hours, covering a distance of 180 miles.

Problem 186

Compare possible one-variable models 2 * pi * r * 10 = 100pi and pi * r^2 * 10 = 100pi for situation A cylinder has a radius 'r' and a height of 10. Its volume is 100pi.

catch model-choice, algebra, and contextual-validity errors.
12 problems Warmup Practice Mixed Review Assessment
Problem 187

Diagnose the setup or solving error in modeled equation work For rectangle area, student writes 2x+2(x+4)=45.

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Problem 188

Diagnose the setup or solving error in modeled equation work Student solves |x-10|=4 and reports only x=14.

Problem 189

Diagnose the setup or solving error in modeled equation work Student clears denominator x-2, solves x=2, and accepts it.

Problem 190

Diagnose the setup or solving error in modeled equation work Student models 8% growth as A=100+0.08t.

Problem 191

Diagnose the setup or solving error in modeled equation work Student solves x^2 - 3x - 10 = 0 using the quadratic formula and writes x = (-3 ± sqrt((-3)^2 - 4(1)(-10))) / (2*1).

Problem 192

Diagnose the setup or solving error in modeled equation work Student simplifies (x+3)^2 as x^2+9.

Problem 193

Diagnose the setup or solving error in modeled equation work Student solves 3(x+2)=15 by writing 3x+2=15.

Problem 194

Diagnose the setup or solving error in modeled equation work Student solves x^2=25 and reports only x=5.

Problem 195

Diagnose the setup or solving error in modeled equation work Student solves -2x > 6 by dividing by -2 and writes x > -3.

Problem 196

Diagnose the setup or solving error in modeled equation work Student calculates the slope between (1, 2) and (3, 8) as (8-2)/(1-3).

Problem 197

Diagnose the setup or solving error in modeled equation work For a right triangle with legs 3 and 4, student calculates the hypotenuse as 3^2 + 4^2 = c.

Problem 198

Diagnose the setup or solving error in modeled equation work Student simplifies log(x+y) as log(x)+log(y).