Math II · A-CED.4

Rearranging Formulas, Including Formulas with Quadratic Terms

This objective teaches students how to take a formula built for one purpose and rewire it for another. In real work, formulas do not always arrive solved for the quantity you need.

Concept Algebra
Domain Creating Equations
Read time 9 minutes

What this learning objective is really asking you to learn

This objective asks students to become fluent in formula control. A formula is a relationship among quantities. It may be written to solve for one quantity, but a real problem may ask for a different quantity. Rearranging the formula means using algebra to isolate the quantity of interest while keeping the relationship true.

Students have already seen simpler versions of this idea. The distance formula \(d = rt\) can be rearranged as \(r = d/t\) or \(t = d/r\). The perimeter formula \(P = 2l + 2w\) can be rearranged to solve for \(l\) or \(w\). The temperature conversion formula \(F = (9/5)C + 32\) can be rearranged to solve for Celsius. These examples are sometimes called literal equations because letters stand for quantities, not just unknown numbers.

Math II raises the level by including formulas with quadratic terms. A quadratic term is a squared variable or a term involving the second power of a variable, such as \(x^2\), \(r^2\), \(t^2\), or \(v^2\). These formulas are common in geometry and physics. The area of a circle is \(A = pi r^2\). Kinetic energy is often written \(K = (1/2)mv^2\). The equation \(v^2 = v0^2 + 2a\Delta x\) connects velocity, acceleration, and displacement. Projectile height formulas often include a \(t^2\) term. Rearranging these formulas requires more care because undoing a square usually involves square roots, and square roots can introduce plus/minus cases or domain restrictions.

The objective says to use the same reasoning as in solving equations. That phrase is important. Rearranging formulas is not a separate branch of algebra. It is equation solving with letters. Whatever operation is performed on one side must be performed on the other. Addition is undone by subtraction. Multiplication is undone by division. Squaring is undone by square roots, but with attention to sign and context. A formula remains equivalent only if each step is logically valid.

To “highlight a quantity of interest” means to make the formula answer the question currently being asked. If \(A = pi r^2\) and the problem gives area but asks for radius, the formula in its current form is not convenient. Rearranged, it becomes \(r = \sqrt{A/pi}\) for a physical radius. If \(K = (1/2)mv^2\) and the problem asks for speed, then \(v = \sqrt{2K/m}\) when speed is nonnegative. If a formula contains a full quadratic expression, rearranging may require collecting terms, factoring, completing the square, or using the quadratic formula.

This objective is partly technical and partly conceptual. Technically, students must manipulate symbols accurately. Conceptually, they must understand that each rearranged version of a formula tells a different story. \(d = rt\) calculates distance from rate and time. \(r = d/t\) calculates rate from distance and time. \(t = d/r\) calculates time from distance and rate. The same relationship is being viewed through different windows.

A strong student also knows that rearranged formulas carry conditions. Division by a variable assumes that variable is not zero. Taking a square root requires the quantity under the radical to be nonnegative in the real number system. Solving for a squared variable may produce two algebraic possibilities, even when the context allows only one. A formula that makes sense for positive lengths may not make sense for negative values. Rearranging does not erase the real-world meaning of the quantities.

Why students should learn this math

Students should learn this objective because real formulas are usually not arranged for your convenience. A textbook exercise might ask exactly what the formula already computes, but life rarely does. Science, engineering, finance, medicine, construction, and technology all require people to solve formulas for whatever quantity matters at the moment.

Consider a driver who knows distance and time and wants average speed. The formula \(d = rt\) must be rearranged. Consider a scientist who knows the area of a circular sample and wants its radius. The formula \(A = pi r^2\) must be rearranged. Consider a physics student who knows kinetic energy and mass and wants speed. The formula \(K = (1/2)mv^2\) must be rearranged. Consider an engineer who knows a target volume and needs a missing dimension. The formula must be rearranged. In each case, the formula is not a static fact to memorize; it is a tool that can be turned around.

This objective also helps students understand formulas rather than merely use them. A student who can rearrange \(A = pi r^2\) sees that radius grows with the square root of area, not directly with area. Doubling the area does not double the radius. A student who rearranges an energy formula sees that speed grows with the square root of energy, not linearly with energy. That matters for real intuition. Many physical and geometric relationships are nonlinear, and rearranged formulas reveal how quantities actually depend on each other.

Formula rearrangement is also central to problem solving under constraints. Suppose a design must fit within a maximum area. Suppose a package must have a certain volume. Suppose a projectile must clear a height. Suppose a budget formula must be solved for a maximum allowable rate. The quantity of interest changes depending on the decision. Algebra lets the same relationship serve different questions.

There is a deeper learning reason as well. Rearranging formulas builds reversible thinking. Many students learn procedures in one direction only: plug in numbers, compute, finish. But mathematics often asks you to reverse a process. If the output is known, what input produced it? If the area is known, what length produced it? If the final amount is known, what rate or time produced it? This reversible thinking prepares students for inverse functions, logarithms, trigonometry, calculus, and scientific modeling.

In modern life, software can rearrange formulas symbolically in many cases. But relying on software without understanding is dangerous. A tool may return multiple branches, restrictions, or forms that need interpretation. A human must know which branch fits the context, which units apply, and whether the result is reasonable. This objective gives students the judgment needed to use technology intelligently rather than passively.

The historical machinery behind this idea

The ability to rearrange formulas depends on the development of symbolic algebra. For much of mathematical history, relationships were written in words or geometric diagrams. Problems were solved case by case. The introduction of symbolic notation made formulas portable and flexible. Letters could represent known quantities, unknown quantities, or varying quantities. Once relationships could be written symbolically, they could be transformed systematically.

Francois Viète played an important role in the development of literal notation, using letters to represent general quantities. This was a major step toward modern algebra. Instead of solving one numerical problem at a time, mathematicians could write general relationships and manipulate them. Descartes and later mathematicians strengthened the connection between symbolic equations and geometric curves. Physics then pushed formula manipulation even further, because natural laws often relate several quantities at once.

The scientific revolution made formula rearrangement essential. Newton's laws, formulas for motion, formulas for force, formulas for energy, and formulas for gravitation all involve multiple variables. A scientist may need to solve for force, mass, acceleration, time, velocity, radius, or distance depending on what is known and what is unknown. The formula is a compact expression of a relationship, not a one-way recipe.

Quadratic terms have an especially old history. Ancient mathematicians studied areas of squares and rectangles, which naturally involve squared lengths. Babylonian and Greek mathematics used geometric reasoning that corresponds to rearranging and solving quadratic relationships. Later algebra turned those geometric relationships into symbolic procedures.

This objective therefore reflects a historical shift from arithmetic calculation to symbolic control. Arithmetic answers a question with numbers. Algebra lets you reshape the question itself. Formula rearrangement is one of the clearest examples of that power.

Technical execution: how to rearrange formulas well

The first step is to identify the target variable. Circle it mentally. Every algebraic move should serve the goal of isolating that variable. Students often get lost because they begin moving symbols without a plan. The plan is simple: undo what is being done to the target variable, in a legal order.

For formulas with addition and subtraction, isolate the term containing the target variable. For example, in \(F = (9/5)C + 32\), subtract 32 first: \(F - 32 = (9/5)C\). Then multiply by \(5/9\): \(C = (5/9)(F - 32)\). The order reverses the operations applied to \(C\).

For formulas with multiplication or division, undo the multiplier or divisor. In \(A = bh\), solving for \(h\) gives \(h = A/b\), assuming \(b \ne 0\). In \(d = rt\), solving for \(t\) gives \(t = d/r\), assuming \(r \ne 0\). The assumption matters. A rate of zero changes the meaning of the original situation.

For formulas with variables in more than one term, collect the target terms. Suppose \(P = 2l + 2w\) and the target is \(w\). Subtract 2l: \(P - 2l = 2w\). Divide by 2: \(w = (P - 2l)/2\). If the target appears in multiple places, factoring may be necessary. For example, \(A = P + Prt\) can be solved for \(P\) by factoring: \(A = P(1 + rt)\), so \(P = A/(1 + rt)\), assuming \(1 + rt \ne 0\).

For formulas with squares, isolate the squared expression before taking square roots. In \(A = pi r^2\), divide by \(pi\): \(A/pi = r^2\). Then take square roots: \(r = ±\sqrt{A/pi}\) algebraically. In a physical circle-radius context, radius is nonnegative, so \(r = \sqrt{A/pi}\). The context chooses the meaningful branch.

In formulas like \(K = (1/2)mv^2\), solve for speed by multiplying by 2, dividing by mass, and taking the square root: \(2K/m = v^2\), so \(v = \sqrt{2K/m}\) if speed is nonnegative. If \(v\) represents velocity with direction, positive and negative values may both have meaning in a one-dimensional model. This distinction is important: speed is nonnegative; velocity can be signed.

Some formulas contain quadratic expressions that are not simple squares. For example, a height model might be \(h = -16t^2 + 64t + 5\). Solving for \(t\) when \(h\) is known may require rearranging into standard quadratic form: \(-16t^2 + 64t + 5 - h = 0\). Then use factoring, completing the square, or the quadratic formula. The formula cannot always be rearranged into a single simple expression without choosing branches.

Students should also keep units in mind. Units can guide rearrangement and catch mistakes. If solving for time, the final unit should be seconds, minutes, hours, or years. If the expression has units of area when the target is length, something has gone wrong. Dimensional reasoning is one of the best error-checking tools in applied math.

Finally, students should interpret the rearranged formula. Do not stop at \(r = \sqrt{A/pi}\). Say what it means: the radius of a circle is determined by taking the square root of the area divided by pi. That tells us radius grows more slowly than area. Do not stop at \(P = A/(1 + rt)\). Say that the initial principal is the final amount divided by the growth factor. Interpretation turns algebra into understanding.

Where this fits in the big map of mathematics

This objective is a direct bridge between equation solving and functions. Rearranging a formula changes which variable is treated as the output. That is closely related to inverse functions, where students ask what input produces a given output. It also connects to modeling because real formulas often come from geometry, physics, finance, and data.

It prepares students for completing the square and the quadratic formula. The derivation of the quadratic formula is essentially a formula-rearrangement problem: start with \(ax^2 + bx + c = 0\) and isolate \(x\). Students who are comfortable moving symbols while preserving equivalence will understand the derivation much more deeply.

It also prepares students for science. Many science courses assume students can rearrange formulas. Students who cannot isolate variables often struggle even when they understand the science concept. Algebra becomes the bottleneck. Mastering this objective removes that bottleneck.

Common student traps and how to avoid them

One trap is moving only one part of a term. For example, in \(A = pi r^2\), students may incorrectly divide by \(r^2\) when the goal is to solve for \(r\). The target variable should stay in the equation while other operations are undone.

A second trap is forgetting plus/minus after taking square roots. Algebraically, \(v^2 = 25\) gives \(v = 5\) or \(v = -5\). The context may eliminate one, but students should know why.

A third trap is dividing by an expression that could be zero without noting the restriction. If a formula rearrangement divides by \(b\), \(m\), \(r\), or \(1 + rt\), the rearranged formula assumes that expression is not zero.

A fourth trap is not distributing or factoring correctly. When the target variable appears in more than one term, factoring is often the key move. Students should look for common factors involving the target variable.

Problem Library

Problems in the App From This Objective

147 problems across 12 archetypes in the app.

use inverse operations with symbols.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Isolate variable x in linear literal equation y=mx+b.

Problem 2

Isolate variable l in linear literal equation P=2l+2w.

Problem 3

Isolate variable F in linear literal equation C=F-32.

Problem 4

Isolate variable h in linear literal equation A=bh.

Problem 5

Isolate variable m in linear literal equation y=mx+b.

Problem 6

Isolate variable w in linear literal equation P=2l+2w.

Problem 7

Isolate variable x in linear literal equation ax+by=c.

Problem 8

Isolate variable b in linear literal equation A=(1/2)bh.

Problem 9

Isolate variable w in linear literal equation V=lwh.

Problem 10

Isolate variable P in linear literal equation I=Prt.

Open in simulator
Problem 11

Isolate variable C in linear literal equation F=(9/5)C+32.

Problem 12

Isolate variable t in linear literal equation d=rt.

distribute or factor strategically.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Isolate variable l in formula with parentheses P=2(l+w).

Problem 14

Isolate variable n in formula with parentheses C=r(n+5).

Problem 15

Isolate variable b1 in formula with parentheses A=1/2h(b1+b2).

Problem 16

Isolate variable C in formula with parentheses F=9/5(C+40)-40.

Problem 17

Isolate variable x in formula with parentheses V=3(x-y).

Problem 18

Isolate variable a in formula with parentheses M=(a+b)/c.

Problem 19

Isolate variable k in formula with parentheses T=5-2(k+m).

Problem 20

Isolate variable p in formula with parentheses Y=10+4(p-q).

Open in simulator
Problem 21

Isolate variable e in formula with parentheses D=2/3(e+f).

Problem 22

Isolate variable j in formula with parentheses G=5(h-j).

Problem 23

Isolate variable L in formula with parentheses K=2/3(L-10)+5.

Problem 24

Isolate variable U in formula with parentheses R=S(T+U-V).

clear fractions and state restrictions.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Isolate variable t that appears in a denominator in formula r=d/t.

Problem 26

Isolate variable V that appears in a denominator in formula D=m/V.

Problem 27

Isolate variable x that appears in a denominator in formula A=k/x.

Problem 28

Isolate variable t that appears in a denominator in formula v=(p+n)/t.

Problem 29

Isolate variable R that appears in a denominator in formula I=V/R.

Problem 30

Isolate variable t that appears in a denominator in formula P=W/t.

Open in simulator
Problem 31

Isolate variable x that appears in a denominator in formula y=5/x.

Problem 32

Isolate variable d that appears in a denominator in formula F=(m*a)/d.

Problem 33

Isolate variable D that appears in a denominator in formula A=(B-C)/D.

Problem 34

Isolate variable M that appears in a denominator in formula K=L/M.

Problem 35

Isolate variable f that appears in a denominator in formula lambda=c/f.

Problem 36

Isolate variable t that appears in a denominator in formula v=s/t.

take square roots and choose meaningful branch.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Isolate the squared variable s in formula A=s^2, choosing the branch that fits side length.

Problem 38

Isolate the squared variable c in formula c^2=a^2+b^2, choosing the branch that fits hypotenuse length.

Problem 39

Isolate the squared variable v in formula v^2=2ad, choosing the branch that fits speed.

Problem 40

Isolate the squared variable r in formula r^2=A/pi, choosing the branch that fits circle radius.

Problem 41

Isolate the squared variable d in formula d^2=(x2-x1)^2+(y2-y1)^2, choosing the branch that fits distance.

Problem 42

Isolate the squared variable r in formula SA=4*pi*r^2, choosing the branch that fits sphere radius.

Problem 43

Isolate the squared variable r in formula V=pi*r^2*h, choosing the branch that fits cylinder radius.

Problem 44

Isolate the squared variable v in formula KE=(1/2)*m*v^2, choosing the branch that fits object speed.

Problem 45

Isolate the squared variable r in formula (x-h)^2+(y-k)^2=r^2, choosing the branch that fits circle radius.

Problem 46

Isolate the squared variable r in formula A=(1/2)*pi*r^2, choosing the branch that fits semicircle radius.

Problem 47

Isolate the squared variable I in formula P=I^2*R, choosing the branch that fits current magnitude.

Open in simulator
Problem 48

Isolate the squared variable v in formula F=m*v^2/r, choosing the branch that fits object speed.

complete inverse operations around squared binomial or expression.
15 problems Warmup Practice Mixed Review Assessment
Problem 49

Isolate x inside the quadratic expression in y=a(x-h)^2+k.

Open in simulator
Problem 50

Isolate x inside the quadratic expression in d=(x-3)^2+5.

Problem 51

Isolate r inside the quadratic expression in A=pi(r-2)^2.

Problem 52

Isolate t inside the quadratic expression in H=-16(t-1)^2+64.

Problem 53

Isolate x inside the quadratic expression in y=(x+4)^2-1.

Problem 54

Isolate q inside the quadratic expression in P=-(q-5)^2+10.

Problem 55

Isolate z inside the quadratic expression in V=2(z+1)^2+3.

Problem 56

Isolate m inside the quadratic expression in C=(1/4)(m-2)^2-5.

Problem 57

Isolate w inside the quadratic expression in E=3(w+7)^2.

Problem 58

Isolate k inside the quadratic expression in F=-5(k-10)^2.

Problem 59

Isolate s inside the quadratic expression in G=-2(s+6)^2-8.

Problem 60

Isolate t inside the quadratic expression in L=100(t-0.5)^2.

Problem 61

Isolate w inside the quadratic expression in Area=(w+3)^2.

Problem 62

Isolate x inside the quadratic expression in N=-0.5(x-1.5)^2+20.

Problem 63

Isolate y inside the quadratic expression in K=4(y-2)^2+7.

collect and factor target variable.
12 problems Warmup Practice Mixed Review Assessment
Problem 64

Isolate l in formula A=lw+lh, where l appears in more than one term.

Problem 65

Isolate l in formula P=2l+2w+lx, where l appears in more than one term.

Open in simulator
Problem 66

Isolate x in formula y=mx+bx, where x appears in more than one term.

Problem 67

Isolate r in formula C=pr+qr+s, where r appears in more than one term.

Problem 68

Isolate P in formula A=P+Prt, where P appears in more than one term.

Problem 69

Isolate x in formula y=ax+bx+c, where x appears in more than one term.

Problem 70

Isolate a in formula Z=ab+ac+d, where a appears in more than one term.

Problem 71

Isolate m in formula K=mn-mp, where m appears in more than one term.

Problem 72

Isolate x in formula R=xy+xz+w, where x appears in more than one term.

Problem 73

Isolate t in formula D=at+bt-c, where t appears in more than one term.

Problem 74

Isolate q in formula E=qvB+qvE, where q appears in more than one term.

Problem 75

Isolate h in formula G=h(x+y)-hz, where h appears in more than one term.

solve for coefficient, rate, or constant.
12 problems Warmup Practice Mixed Review Assessment
Problem 76

Rearrange y=mx+b to highlight parameter m.

Problem 77

Rearrange A=pi r^2 to highlight parameter pi.

Problem 78

Rearrange P=P0(1+r)^t to highlight parameter r.

Problem 79

Rearrange y=a(x-h)^2+k to highlight parameter a.

Problem 80

Rearrange y=mx+b to highlight parameter b.

Problem 81

Rearrange A=1/2(a+b)h to highlight parameter h.

Problem 82

Rearrange V=1/3 pi r^2 h to highlight parameter h.

Problem 83

Rearrange I=PRT to highlight parameter P.

Problem 84

Rearrange F=ma to highlight parameter m.

Problem 85

Rearrange V=IR to highlight parameter R.

Problem 86

Rearrange KE=1/2 mv^2 to highlight parameter m.

Problem 87

Rearrange d=rt to highlight parameter r.

Open in simulator
solve symbolically first, then substitute.
12 problems Warmup Practice Mixed Review Assessment
Problem 88

First rearrange d=rt to solve for t, then evaluate it using d=180, r=45.

Problem 89

First rearrange A=bh/2 to solve for h, then evaluate it using A=36, b=9.

Problem 90

First rearrange C=2pi r to solve for r, then evaluate it using C=18pi.

Problem 91

First rearrange P=2l+2w to solve for w, then evaluate it using P=50, l=17.

Problem 92

First rearrange F=ma to solve for a, then evaluate it using F=100, m=20.

Problem 93

First rearrange V=IR to solve for I, then evaluate it using V=12, R=3.

Problem 94

First rearrange A=P(1+rt) to solve for r, then evaluate it using A=1100, P=1000, t=2.

Problem 95

First rearrange V=lwh to solve for h, then evaluate it using V=60, l=5, w=3.

Problem 96

First rearrange y=mx+b to solve for x, then evaluate it using y=15, m=3, b=6.

Problem 97

First rearrange A=pi r^2 to solve for r, then evaluate it using A=100pi.

Problem 98

First rearrange K=1/2 mv^2 to solve for m, then evaluate it using K=100, v=5.

Open in simulator
Problem 99

First rearrange P=I^2 R to solve for R, then evaluate it using P=75, I=5.

recognize algebraically equivalent forms.
12 problems Warmup Practice Mixed Review Assessment
Problem 100

Decide whether rearrangements l=(P-2w)/2 and l=P/2-w are equivalent for solving l from P=2l+2w.

Problem 101

Decide whether rearrangements b=2A/h and b=A/(2h) are equivalent for solving b from A=bh/2.

Problem 102

Decide whether rearrangements x=(y-b)/m and x=y/m-b are equivalent for solving x from y=mx+b.

Problem 103

Decide whether rearrangements w=V/(lh) and w=(V/l)/h are equivalent for solving w from V=lwh.

Problem 104

Decide whether rearrangements r = C/(2pi) and r = C/2/pi are equivalent for solving r from C = 2pir.

Problem 105

Decide whether rearrangements C = 5(F - 32)/9 and C = 5F/9 - 32 are equivalent for solving C from F = (9/5)C + 32.

Problem 106

Decide whether rearrangements h = 2A/(a+b) and h = 2A/a + 2A/b are equivalent for solving h from A = (a+b)h/2.

Problem 107

Decide whether rearrangements l = P/2 - w and l = P - 2w are equivalent for solving l from P = 2(l+w).

Problem 108

Decide whether rearrangements m = E/c^2 and m = E/c/c are equivalent for solving m from E = mc^2.

Open in simulator
Problem 109

Decide whether rearrangements C = P - S and C = S - P are equivalent for solving C from S = P - C.

Problem 110

Decide whether rearrangements f = (do*di)/(do+di) and f = 1/(1/do + 1/di) are equivalent for solving f from 1/f = 1/do + 1/di.

Problem 111

Decide whether rearrangements P = A/(1 + rt) and P = A/1 + A/rt are equivalent for solving P from A = P(1 + rt).

identify zero denominators and square-root domain limits.
12 problems Warmup Practice Mixed Review Assessment
Problem 112

State the restrictions needed when rearranging r=d/t for t.

Problem 113

State the restrictions needed when rearranging A=1/2h(b1+b2) for h.

Open in simulator
Problem 114

State the restrictions needed when rearranging y=a(x-h)^2+k for x.

Problem 115

State the restrictions needed when rearranging V=m/D for D.

Problem 116

State the restrictions needed when rearranging F=ma for a.

Problem 117

State the restrictions needed when rearranging P=V^2/R for R.

Problem 118

State the restrictions needed when rearranging I=V/(R1+R2) for R1.

Problem 119

State the restrictions needed when rearranging c=sqrt(a^2+b^2) for a.

Problem 120

State the restrictions needed when rearranging t=2pi*sqrt(L/g) for L.

Problem 121

State the restrictions needed when rearranging v=sqrt(2GM/r) for r.

Problem 122

State the restrictions needed when rearranging ax^2+bx+c=0 for x.

Problem 123

State the restrictions needed when rearranging 1/f=1/do+1/di for f.

explain what the rearranged expression computes.
12 problems Warmup Practice Mixed Review Assessment
Problem 124

Explain what isolated formula l=A/w tells you in the context: A rectangle has area A and width w.

Problem 125

Explain what isolated formula t=d/r tells you in the context: A trip covers distance d at speed r.

Problem 126

Explain what isolated formula r=C/(2pi) tells you in the context: A circle has circumference C.

Problem 127

Explain what isolated formula m=(y-b)/x tells you in the context: A linear model y=mx+b is solved for m.

Open in simulator
Problem 128

Explain what isolated formula m=DV tells you in the context: An object has density D and volume V.

Problem 129

Explain what isolated formula m=F/a tells you in the context: An object has force F and acceleration a.

Problem 130

Explain what isolated formula r=I/(Pt) tells you in the context: An investment earns simple interest I over time t with principal P.

Problem 131

Explain what isolated formula h=V/(pi*r^2) tells you in the context: A cylinder has volume V and radius r.

Problem 132

Explain what isolated formula w=(P-2l)/2 tells you in the context: A rectangle has perimeter P and length l.

Problem 133

Explain what isolated formula C=(5/9)(F-32) tells you in the context: Temperature is given in Fahrenheit F.

Problem 134

Explain what isolated formula t=W/r tells you in the context: Work W is done at a rate r.

Problem 135

Explain what isolated formula F=PA tells you in the context: Pressure P is exerted over an area A.

catch sign, factoring, square-root, and denominator mistakes.
12 problems Warmup Practice Mixed Review Assessment
Problem 136

Find and correct the error in this rearrangement: P=2l+2w, so l=P-2w/2.

Problem 137

Find and correct the error in this rearrangement: A=bh/2, so b=A/(2h).

Problem 138

Find and correct the error in this rearrangement: y=mx+b, so x=y-b/m.

Problem 139

Find and correct the error in this rearrangement: A=s^2, so s=±A.

Problem 140

Find and correct the error in this rearrangement: V = IR, so I = V - R.

Problem 141

Find and correct the error in this rearrangement: Density = Mass/Volume, so Mass = Density / Volume.

Open in simulator
Problem 142

Find and correct the error in this rearrangement: x - 7 = y, so x = y - 7.

Problem 143

Find and correct the error in this rearrangement: -2x = 10, so x = 10 - 2.

Problem 144

Find and correct the error in this rearrangement: x/5 = y, so x = y/5.

Problem 145

Find and correct the error in this rearrangement: A = πr^2, so r = A/π.

Problem 146

Find and correct the error in this rearrangement: 1/R_total = 1/R1 + 1/R2, so R_total = R1 + R2.

Problem 147

Find and correct the error in this rearrangement: y = 4(x + 3), so x = y/4 + 3.