Math II · A-SSE.1.b

Interpreting Complex Quadratic and Exponential Expressions by Treating Sub-Expressions as Single Units

This objective teaches students how to “chunk” algebra. Complicated formulas become manageable when meaningful parts are treated as units: a growth factor, a shifted input, a squared distance from a center, a monthly multiplier, or a whole expression representing demand, time, or cost.

Concept Algebra
Domain Seeing Structure in Expressions
Read time 8 minutes

What this learning objective is really asking you to learn

This objective is about grouping. Not grouping as a minor algebra trick, but grouping as a way of thinking. Complex expressions are rarely meant to be understood one symbol at a time from left to right. They are built from meaningful sub-expressions. A sub-expression might be \((x - 3)\), \((1 + r)\), \((1.04)^t\), \((p - 20)\), 12t, or an entire expression like \(500 - 10p\) inside a revenue formula. When students learn to treat these parts as single units, they gain control over expressions that otherwise look intimidating.

A simple example is \(P(1 + r)^n\). A beginning student may see four letters and several operations. A stronger student sees three units: \(P\), the initial amount; \((1 + r)\), the growth factor per period; and \(n\), the number of periods. The sub-expression \((1 + r)\) should be treated as one object because it represents the multiplier applied each time. If \(r = 0.08\), then \((1 + r)\) is 1.08, meaning 108 percent of the previous amount remains after one growth period. The expression is not just multiplying random pieces; it is describing repeated proportional growth.

Quadratics also depend heavily on meaningful sub-expressions. In \(a(x - h)^2 + k\), the sub-expression \((x - h)\) represents distance from a central input value \(h\). Squaring it makes values on either side of \(h\) behave symmetrically. Multiplying by \(a\) scales or flips the squared distance. Adding \(k\) shifts the result. If the expression models the height of a bridge arch, \(h\) may represent the horizontal center and \(k\) may represent the maximum or minimum height, depending on the sign of \(a\). The expression is easiest to interpret when \((x - h)\) is treated as a single unit.

The objective matters because advanced algebra is not mostly about more symbols. It is about more structure. Students who cannot chunk expressions often try to memorize procedures blindly. Students who can chunk expressions can see patterns. They notice that \(x^4 - 10x^2 + 25\) has the structure of a quadratic in \(x^2\). They notice that \((2x + 1)^2 - 49\) is a difference of squares. They notice that \(300(1.01)^{12t}\) applies a monthly factor for 12t months. They notice that \(-5(t - 4)^2 + 80\) says “start from the time 4, measure squared distance from it, then flip and scale.”

In real modeling, sub-expressions often represent quantities within quantities. A revenue model might be \(R(p) = p(1000 - 20p)\). The sub-expression \((1000 - 20p)\) may represent demand as a function of price. The whole expression multiplies price by demand to produce revenue. If a student expands it to \(1000p - 20p^2\), the expression becomes a standard quadratic, but the original product form explains the model better. The grouped expression says: revenue equals price times number sold. That is a meaningful chunk.

This objective is also about reducing cognitive load. Human working memory is limited. Experts in math, science, engineering, and programming do not process complex structures as disconnected pieces. They chunk. A chess expert sees patterns of pieces, not just individual squares. A musician sees chord shapes and phrases, not just notes. A mathematician sees \((x - h)^2\) as one structure, \(ab^t\) as one structure, and \((1 + r)^n\) as one structure. This objective helps students build that expert habit.

The historical machinery behind this idea

The history of algebra includes a gradual move from specific procedures to general structures. Early algebra often described steps for particular kinds of problems. Over time, symbolic notation allowed mathematicians to represent entire families of problems at once. Once expressions could be written generally, mathematicians could also begin treating parts of expressions as objects.

This structural thinking became central in modern mathematics. A polynomial could be considered not just as a calculation but as an object with roots, factors, degree, and graph behavior. A function could be considered not just as a formula but as a machine with inputs, outputs, transformations, and composition. An exponential expression could represent repeated multiplication across time. The ability to treat sub-expressions as single entities is part of this larger historical shift toward abstraction.

Science also pushed this development. Formulas in physics and engineering often contain nested structures. Kinetic energy, gravitational potential, wave equations, and growth/decay laws all require interpreting grouped parts. Finance uses compound expressions where interest rates, compounding periods, principal, and time must be separated and interpreted. Statistics uses formulas with deviations from a mean, squared deviations, standardized values, and parameters. In all these cases, the formula is readable only if the reader can chunk.

Function notation made this even more important. When a student sees \(f(x + 3)\) or \(f(2x)\), the input itself is a sub-expression. Later, inverse functions, composite functions, logarithms, trigonometry, and rational functions all depend on treating parts as units. This objective may look small, but it is a gateway to advanced algebraic thinking.

Technical execution: how to treat sub-expressions as units

The first technique is to look for parentheses, powers, repeated patterns, and meaningful operations. Parentheses often signal a unit, but not always. Sometimes the unit is hidden, such as \(x^4 - 9\), which can be seen as \((x^2)^2 - 3^2\). Sometimes the unit is contextual, such as \(500 - 10p\) in a revenue model. The question is not merely “What is inside parentheses?” The better question is “What part of this expression behaves like a single quantity?”

The second technique is to name the unit. If an expression contains \((x - 4)^2\), call \(x - 4\) the distance from 4. If an expression contains \((1.03)^t\), call it the growth multiplier after \(t\) periods. If an expression contains 12t, call it the number of months when \(t\) is in years. Naming the chunk gives it meaning and prevents mechanical manipulation from taking over too early.

Consider \(A(t) = 2000(1.015)^{12t}\). A student might read it as a mess of numbers. A structured reading says: 2000 is the starting amount. 1.015 is the monthly growth factor. 12t is the number of months in \(t\) years. The sub-expression \((1.015)^{12t}\) is the total growth multiplier over \(t\) years. The whole expression is starting amount times accumulated growth multiplier. That reading is far more useful than simply plugging in values.

Consider \(h(t) = -16(t - 2)^2 + 64\). Here \((t - 2)\) is the time difference from 2 seconds. Squaring it makes height depend on squared distance from the time 2. The coefficient -16 makes the graph open downward and controls steepness. The \(+64\) sets the maximum height at 64 when \(t = 2\). Treating \((t - 2)\) as one unit reveals the vertex immediately. Expanding to \(-16t^2 + 64t\) may be useful for some calculations, but it hides the maximum.

Consider \(R(p) = p(800 - 25p)\). The expression has two meaningful units: \(p\), the price per item, and \((800 - 25p)\), the number of items sold at that price under the model. The whole expression is price times quantity. If a student expands it to \(800p - 25p^2\), the revenue structure is still there, but it is less obvious. The unexpanded form explains the business logic.

A fourth technique is substitution with a temporary variable. If an expression is \(x^4 - 13x^2 + 36\), let \(u = x^2\). Then the expression becomes \(u^2 - 13u + 36\), which factors as \((u - 9)(u - 4)\). Substituting back gives \((x^2 - 9)(x^2 - 4)\). This is not just a trick. It is a formal version of treating a sub-expression as a single unit.

A fifth technique is to compare forms. The expression \(x^2 - 6x + 9\) can be read as a sum of terms, but it can also be read as \((x - 3)^2\). The second form treats \(x - 3\) as a unit and reveals a square, a minimum value, and symmetry around \(x = 3\). Equivalent forms are not equally informative. A central skill is choosing the form that reveals the feature you need.

Why students should learn this math

Real-life formulas are layered. A mortgage payment formula contains principal, interest rate, number of payments, and compound factors. A medicine concentration formula may contain an initial dose and a decay factor raised to a time-dependent exponent. A projectile formula may contain time since launch or time since peak. A manufacturing tolerance formula may contain deviation from a target. A profit formula may contain price, demand, cost, and production limits.

Chunking lets students understand such formulas without drowning in details. A student who sees \(1.08^{t}\) as “the total growth multiplier after \(t\) years” can reason about investments. A student who sees \((x - h)^2\) as “squared distance from a center” can understand parabolas, circles, variance, and optimization. A student who sees \(p(1000 - 20p)\) as “price times demand” can understand revenue. The real-life value is not only computation. It is interpretation.

This also helps students become skeptical readers of quantitative claims. If someone says an investment grows by 8 percent annually, the expression should have a factor like 1.08, not 8. If a model uses 12t in an exponent, the reader should ask whether time is measured in months or years. If a quadratic expression is presented in factored form, the reader should ask what the zeros mean. These are adult numeracy skills.

Where this fits in the big map of mathematics

This objective supports nearly every major algebra move in Math II and Math III. Completing the square requires treating \((x - h)\) as a unit. Factoring special patterns requires seeing expressions as squares or products. Function transformations require reading \(f(x + k)\), \(f(kx)\), \(kf(x)\), and \(f(x) + k\) as structured modifications. Exponential modeling requires interpreting bases and exponents as grouped units. Logarithms later require solving for exponents inside exponential structures.

The big map idea is that mathematics builds complex objects from simpler ones. Numbers form expressions. Expressions form equations and functions. Functions form models. Models are compared, transformed, inverted, and analyzed. A student who can identify sub-expressions is learning to see the architecture of mathematics.

Common student traps and how to avoid them

One trap is expanding everything automatically. Expansion can be useful, but it often destroys visible meaning. Before expanding, ask what the current form reveals.

A second trap is treating parentheses as decoration. Parentheses often protect a meaningful unit. In \((1 + r)^n\), the whole growth factor is raised to the exponent. Removing or misreading parentheses changes the model.

A third trap is confusing the meaning of a shifted input. In \((x - 5)^2\), the important center is \(x = 5\), not \(x = -5\). The expression equals zero when the inside is zero.

A fourth trap is ignoring units inside exponents. If \(t\) is in years but the base is monthly, the exponent may need 12t. If the base is annual, using 12t would be wrong. Units decide whether the structure makes sense.

Problem Library

Problems in the App From This Objective

156 problems across 12 archetypes in the app.

treat `(x-h)` as one quantity.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Interpret the squared binomial in vertex form f(x)=(x-4)^2+7.

Problem 2

Interpret the squared binomial in vertex form g(t)=-3(t+2)^2+5.

Open in simulator
Problem 3

Interpret the squared binomial in vertex form h(n)=0.5(n-10)^2-1.

Problem 4

Interpret the squared binomial in vertex form A(s)=2(s+6)^2.

Problem 5

Interpret the squared binomial in vertex form f(y)=(y-1)^2.

Problem 6

Interpret the squared binomial in vertex form g(z)=4(z+7)^2+10.

Problem 7

Interpret the squared binomial in vertex form h(p)=-(p-0.5)^2-2.

Problem 8

Interpret the squared binomial in vertex form k(q)=0.25q^2.

Problem 9

Interpret the squared binomial in vertex form m(r)=(r+1.5)^2+3.5.

Problem 10

Interpret the squared binomial in vertex form n(u)=-2(u-8)^2.

Problem 11

Interpret the squared binomial in vertex form p(v)=(1/3)(v+12)^2-4.

Problem 12

Interpret the squared binomial in vertex form q(m)=(m-2.5)^2.

connect sub-expression to vertical change from vertex.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Interpret the scaled squared-distance term in f(x)=3(x-2)^2+1.

Open in simulator
Problem 14

Interpret the scaled squared-distance term in g(x)=-2(x+5)^2+8.

Problem 15

Interpret the scaled squared-distance term in h(t)=0.25(t-4)^2-6.

Problem 16

Interpret the scaled squared-distance term in p(n)=-(n-1)^2+10.

Problem 17

Interpret the scaled squared-distance term in f(y)=5(y-10)^2-3.

Problem 18

Interpret the scaled squared-distance term in g(z)=-4(z+1)^2+7.

Problem 19

Interpret the scaled squared-distance term in h(k)=0.5k^2+2.

Problem 20

Interpret the scaled squared-distance term in p(m)=-0.75(m+3)^2-1.

Problem 21

Interpret the scaled squared-distance term in q(x)=(x-7)^2+5.

Problem 22

Interpret the scaled squared-distance term in r(s)=-(s+6)^2-9.

Problem 23

Interpret the scaled squared-distance term in u(v)=10(v-1.5)^2.

Problem 24

Interpret the scaled squared-distance term in w(x)=0.1(x+0.5)^2+100.

connect factors to dimensions or zero conditions.
15 problems Warmup Practice Mixed Review Assessment
Problem 25

Interpret the factored quadratic A=(x+2)(x+7) in context rectangle area.

Problem 26

Interpret the factored quadratic R=p(50-p) in context revenue.

Problem 27

Interpret the factored quadratic h=-5(t-1)(t-9) in context height above ground.

Problem 28

Interpret the factored quadratic P=(q-3)(q-12) in context profit relative to zero.

Problem 29

Interpret the factored quadratic A=(w-3)(w+5) in context rectangle area.

Problem 30

Interpret the factored quadratic P=(x-5)(x-20) in context company's profit.

Problem 31

Interpret the factored quadratic h=-16t(t-4) in context height of a ball.

Problem 32

Interpret the factored quadratic Area=(x-1)(x-6) in context garden area.

Problem 33

Interpret the factored quadratic Revenue=(s-10)(s-80) in context product sales revenue.

Problem 34

Interpret the factored quadratic N=(t+1)(t-5) in context population change over time.

Problem 35

Interpret the factored quadratic A=(L+3)(L-2) in context area of a modified shape.

Problem 36

Interpret the factored quadratic Profit=(items-100)(items-500) in context company's quarterly profit.

Problem 37

Interpret the factored quadratic d=(x-2)(x-8) in context depth of a submarine relative to a reference point.

Open in simulator
Problem 38

Interpret the factored quadratic V=x(x-5) in context volume of a specific container with fixed height.

Problem 39

Interpret the factored quadratic V=(t-3)(t-7) in context value of an asset over time.

treat discriminant as solution-type indicator.
15 problems Warmup Practice Mixed Review Assessment
Problem 40

Interpret the discriminant for x^2-6x+9=0.

Problem 41

Interpret the discriminant for x^2-5x+4=0.

Problem 42

Interpret the discriminant for x^2-2x+5=0.

Problem 43

Interpret the discriminant for 2x^2-4x-1=0.

Problem 44

Interpret the discriminant for x^2+4x+4=0.

Problem 45

Interpret the discriminant for x^2+7x+10=0.

Problem 46

Interpret the discriminant for x^2+x+1=0.

Problem 47

Interpret the discriminant for x^2+3x+1=0.

Problem 48

Interpret the discriminant for 4x^2-12x+9=0.

Problem 49

Interpret the discriminant for 3x^2-10x+3=0.

Problem 50

Interpret the discriminant for 3x^2-x+1=0.

Problem 51

Interpret the discriminant for x^2-6x+2=0.

Problem 52

Interpret the discriminant for x^2-10x+25=0.

Problem 53

Interpret the discriminant for 2x^2+5x-3=0.

Problem 54

Interpret the discriminant for 5x^2-2x+1=0.

Open in simulator
treat `b^t` as repeated multiplication.
15 problems Warmup Practice Mixed Review Assessment
Problem 55

Interpret the growth factor over multiple intervals in P(t)=100(1.1)^3.

Problem 56

Interpret the growth factor over multiple intervals in A(t)=500(0.8)^4.

Problem 57

Interpret the growth factor over multiple intervals in N(t)=20(2)^5.

Problem 58

Interpret the growth factor over multiple intervals in M(t)=64(0.5)^3.

Problem 59

Interpret the growth factor over multiple intervals in Y = 75(1.05)^2.

Problem 60

Interpret the growth factor over multiple intervals in f(x) = 1000(0.9)^3.

Problem 61

Interpret the growth factor over multiple intervals in C(x) = 15(2)^4.

Problem 62

Interpret the growth factor over multiple intervals in P = 128(0.5)^5.

Problem 63

Interpret the growth factor over multiple intervals in G(t) = 1.5(1.2)^3.

Problem 64

Interpret the growth factor over multiple intervals in H(x) = 300(0.75)^2.

Problem 65

Interpret the growth factor over multiple intervals in K = 5000(2)^6.

Problem 66

Interpret the growth factor over multiple intervals in L(t) = 256(0.5)^4.

Problem 67

Interpret the growth factor over multiple intervals in R(s) = 40(1.3)^2.

Problem 68

Interpret the growth factor over multiple intervals in S = 250(0.6)^3.

Open in simulator
Problem 69

Interpret the growth factor over multiple intervals in Q(z) = 12(1.15)^4.

treat baseline/asymptote as meaningful.
15 problems Warmup Practice Mixed Review Assessment
Problem 70

Interpret the vertical shift or baseline in exponential model T(t)=60(0.8)^t+20 for context cooling object temperature.

Problem 71

Interpret the vertical shift or baseline in exponential model M(t)=30(0.5)^t+5 for context medicine level with residual baseline.

Problem 72

Interpret the vertical shift or baseline in exponential model P(t)=100(1.2)^t+50 for context population with existing base group.

Problem 73

Interpret the vertical shift or baseline in exponential model D(t)=12(0.7)^t-3 for context distance relative to a reference point.

Problem 74

Interpret the vertical shift or baseline in exponential model A(t)=5000(1.05)^t+1000 for context investment portfolio with a fixed initial deposit.

Problem 75

Interpret the vertical shift or baseline in exponential model L(t)=100(0.9)^t+10 for context pollution level decreasing towards a minimum safe level.

Problem 76

Interpret the vertical shift or baseline in exponential model C(t)=20(0.75)^t+5 for context drug concentration in blood with a continuous low-level infusion.

Problem 77

Interpret the vertical shift or baseline in exponential model V(t)=10000(0.8)^t+500 for context asset value depreciating to a salvage value.

Problem 78

Interpret the vertical shift or baseline in exponential model T(t)=-50(0.95)^t+70 for context substance heating up in a warm environment.

Problem 79

Interpret the vertical shift or baseline in exponential model B(t)=200(1.1)^t+50 for context bacterial population with a persistent non-growing strain.

Problem 80

Interpret the vertical shift or baseline in exponential model R(t)=1000(1.02)^t+200 for context product revenue with a fixed monthly subscription income.

Open in simulator
Problem 81

Interpret the vertical shift or baseline in exponential model I(x)=50(0.6)^x+5 for context light intensity passing through a medium with a constant background glow.

Problem 82

Interpret the vertical shift or baseline in exponential model P(t)=200(0.85)^t+100 for context pressure in a closed system decaying to an equilibrium pressure.

Problem 83

Interpret the vertical shift or baseline in exponential model H(t)=10(0.7)^t+2 for context height of a bouncing ball relative to a raised platform.

Problem 84

Interpret the vertical shift or baseline in exponential model R(t)=1000(0.5)^t+10 for context radioactivity level with a constant background radiation.

connect `(1+r)^t` or `(1-r)^t` to repeated percent change.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Interpret grouped percent-change expression 800(1+0.06)^t.

Problem 86

Interpret grouped percent-change expression 1200(1-0.15)^t.

Problem 87

Interpret grouped percent-change expression P(1+r)^5.

Problem 88

Interpret grouped percent-change expression A(1-r)^n.

Problem 89

Interpret grouped percent-change expression 500(1+0.03)^4.

Problem 90

Interpret grouped percent-change expression 2500(1-0.20)^3.

Problem 91

Interpret grouped percent-change expression X(1+0.01)^y.

Problem 92

Interpret grouped percent-change expression M(1-0.05)^k.

Problem 93

Interpret grouped percent-change expression 100(1+x)^10.

Open in simulator
Problem 94

Interpret grouped percent-change expression 750(1-y)^2.

Problem 95

Interpret grouped percent-change expression B(1+z)^6.

Problem 96

Interpret grouped percent-change expression Q(1-w)^p.

identify which part represents base amount, change, or condition.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Match sub-expression 80-p in R=p(80-p) to its contextual quantity: p is price and 80-p is quantity demanded.

Problem 98

Match sub-expression t-2 in h(t)=-16(t-2)^2+64 to its contextual quantity: height t seconds after launch.

Problem 99

Match sub-expression x+6 in A=x(x+6) to its contextual quantity: rectangle with width x and length x+6.

Problem 100

Match sub-expression 1.04 in P=500(1.04)^t to its contextual quantity: account grows 4% each year.

Problem 101

Match sub-expression b^2 - 4ac in x = (-b + sqrt(b^2 - 4ac)) / 2a to its contextual quantity: quadratic formula for ax^2 + bx + c = 0.

Problem 102

Match sub-expression 1 + r/n in A = P(1 + r/n)^(nt) to its contextual quantity: compound interest formula where r is annual interest rate and n is number of times compounded per year.

Problem 103

Match sub-expression m in y = mx + b to its contextual quantity: linear equation in slope-intercept form.

Open in simulator
Problem 104

Match sub-expression r^2 in A = pi * r^2 to its contextual quantity: area of a circle with radius r.

Problem 105

Match sub-expression (x2-x1)^2 in d = sqrt((x2-x1)^2 + (y2-y1)^2) to its contextual quantity: distance between two points (x1, y1) and (x2, y2).

Problem 106

Match sub-expression a^2 in c^2 = a^2 + b^2 to its contextual quantity: Pythagorean theorem for a right triangle with legs a and b, and hypotenuse c.

Problem 107

Match sub-expression pi * r^2 in V = pi * r^2 * h to its contextual quantity: volume of a cylinder with radius r and height h.

Problem 108

Match sub-expression m1 * m2 in F = G * (m1 * m2) / r^2 to its contextual quantity: Newton's law of universal gravitation where F is force, G is gravitational constant, m1 and m2 are masses, and r is distance.

factor, complete square, or regroup.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Rewrite x^2+6x+5 to reveal zeros.

Problem 110

Rewrite x^2-8x+10 to reveal vertex.

Open in simulator
Problem 111

Rewrite 3(2)^t(2)^4 to reveal initial coefficient times one exponential.

Problem 112

Rewrite x^2-9 to reveal difference-of-squares factors.

Problem 113

Rewrite x^2-5x+6 to reveal zeros.

Problem 114

Rewrite x^2+4x+1 to reveal vertex.

Problem 115

Rewrite 5(3)^x(3)^2 to reveal initial coefficient times one exponential.

Problem 116

Rewrite 4x^2-25 to reveal difference-of-squares factors.

Problem 117

Rewrite x^3+2x^2-3x to reveal factors.

Problem 118

Rewrite (2x)^3 to reveal product of powers.

Problem 119

Rewrite log(x^4) to reveal coefficient times log(x).

Problem 120

Rewrite sqrt(x^7) to reveal x to a rational power.

explain which form exposes zeros, vertex, or growth rate.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Compare what forms x^2-6x+8 and (x-2)(x-4) reveal about the same expression.

Problem 122

Compare what forms x^2+4x+1 and (x+2)^2-3 reveal about the same expression.

Problem 123

Compare what forms 5(1.2)^t and 6(1.2)^(t-1) reveal about the same expression.

Problem 124

Compare what forms -2(x-3)^2+7 and -2x^2+12x-11 reveal about the same expression.

Problem 125

Compare what forms y = 3x + 5 and y - 2 = 3(x + 1) reveal about the same expression.

Problem 126

Compare what forms 2x^2 + 10x + 12 and 2(x+2)(x+3) reveal about the same expression.

Problem 127

Compare what forms 3(x+1)^2 - 5 and 3x^2 + 6x - 2 reveal about the same expression.

Problem 128

Compare what forms 100 * (0.5)^t and 100 * (2)^(-t) reveal about the same expression.

Problem 129

Compare what forms (x^2 - 9) / (x - 3) and x + 3 reveal about the same expression.

Problem 130

Compare what forms x^3 - 4x and x(x-2)(x+2) reveal about the same expression.

Problem 131

Compare what forms 2x + 3y = 6 and y = (-2/3)x + 2 reveal about the same expression.

Problem 132

Compare what forms P(1 + 0.05)^t and P(1.05)^t reveal about the same expression.

Open in simulator
parse nested operations and units.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Identify the operation applied to sub-expression x-2 in 3(x-2)^2+5.

Problem 134

Identify the operation applied to sub-expression 1.04 in 100(1.04)^t.

Problem 135

Identify the operation applied to sub-expression 60-p in p(60-p).

Problem 136

Identify the operation applied to sub-expression t-3 in -16(t-3)^2+80.

Problem 137

Identify the operation applied to sub-expression y+7 in (y+7)/4 - 1.

Problem 138

Identify the operation applied to sub-expression x+1 in 5 * sqrt(x+1).

Problem 139

Identify the operation applied to sub-expression 2x-3 in |2x-3| + 10.

Problem 140

Identify the operation applied to sub-expression x-5 in 2^(x-5) - 3.

Problem 141

Identify the operation applied to sub-expression x^2 in 7 * log(x^2).

Problem 142

Identify the operation applied to sub-expression x+4 in 1 / (x+4)^3.

Problem 143

Identify the operation applied to sub-expression 2x+1 in (2x+1)/3 + 5.

Open in simulator
Problem 144

Identify the operation applied to sub-expression x-1 in 4 * (x-1)^(-2).

detect wrong target of square, exponent, or multiplier.
12 problems Warmup Practice Mixed Review Assessment
Problem 145

Correct the grouping interpretation error: Only the x is squared. for expression 3(x-2)^2.

Problem 146

Correct the grouping interpretation error: 100 and 1.05 are both raised to t. for expression 100(1.05)^t.

Problem 147

Correct the grouping interpretation error: The negative sign is inside the square. for expression -(x+4)^2+9.

Problem 148

Correct the grouping interpretation error: The expression means 30p-p. for expression p(30-p).

Problem 149

Correct the grouping interpretation error: The expression means -5 squared. for expression (-5)^2.

Problem 150

Correct the grouping interpretation error: Only x is cubed. for expression (2x)^3.

Problem 151

Correct the grouping interpretation error: The expression means 1 divided by x, plus 1. for expression 1/(x+1).

Problem 152

Correct the grouping interpretation error: The expression means the square root of x, plus y. for expression sqrt(x+y).

Problem 153

Correct the grouping interpretation error: Only b is divided by c. for expression (a+b)/c.

Open in simulator
Problem 154

Correct the grouping interpretation error: The expression means 1 divided by 2, then multiplied by x. for expression 1 / (2x).

Problem 155

Correct the grouping interpretation error: The negative sign is squared along with x-3. for expression -(x-3)^2.

Problem 156

Correct the grouping interpretation error: The expression means -x-y. for expression -(x-y).