Math II · G-GPE.1

Deriving and Interpreting the Equation of a Circle

This objective teaches students how to turn a visual object, a circle, into an equation that can be graphed, analyzed, stored, tested, and used by technology.

Concept Geometry
Domain Expressing Geometric Properties with Equations
Read time 9 minutes

What this learning objective is really asking you to learn

This objective asks students to connect geometry and algebra. Geometrically, a circle is the set of all points in a plane that are the same distance from a fixed point. The fixed point is the center. The common distance is the radius. Algebraically, that definition becomes an equation. The equation tells whether any point \((x, y)\) is on the circle.

If a circle has center \((h, k)\) and radius \(r\), then a point \((x, y)\) lies on the circle exactly when its distance from \((h, k)\) is \(r\). The distance formula says that distance is \(\sqrt{(x - h)² + (y - k)²}\). Setting that equal to \(r\) gives \(\sqrt{(x - h)² + (y - k)²} = r\). Squaring both sides gives the standard circle equation: \((x - h)² + (y - k)² = r²\).

This is the heart of the objective. The equation of a circle is the Pythagorean Theorem in coordinate form. The horizontal distance from the center to the point is \(x - h\). The vertical distance is \(y - k\). Those two distances form the legs of a right triangle. The radius is the hypotenuse. Therefore \((x - h)² + (y - k)² = r²\).

Students should be able to move in both directions. If the center is \((3, -2)\) and the radius is 5, the equation is \((x - 3)² + (y + 2)² = 25\). If the equation is \((x + 4)² + (y - 7)² = 9\), the center is \((-4, 7)\) and the radius is 3. Notice the sign pattern: \((x - h)\) means the center’s x-coordinate is \(h\). So \((x + 4)\) means \(x - (-4)\), not center 4.

The second half of the objective is completing the square. Circles are not always given in standard form. A problem may give an equation like \(x² + y² - 6x + 8y - 11 = 0\). Students need to rearrange it into standard form. Group the x terms and y terms: \((x² - 6x) + (y² + 8y) = 11\). Complete the square: \(x² - 6x + 9 = (x - 3)²\), and \(y² + 8y + 16 = (y + 4)²\). Add the same numbers to both sides: \((x - 3)² + (y + 4)² = 11 + 9 + 16 = 36\). Therefore the center is \((3, -4)\) and the radius is 6.

Why students should learn this math

Students should learn this math because it turns geometric location into a testable equation. A circle equation can describe a boundary, a range, a zone, a wheel, a signal radius, a circular path, a design constraint, a cross-section, or a target area. Once a circle becomes an equation, it can be graphed, programmed, stored in software, intersected with lines, compared with other shapes, and used in calculations.

Think about location. A delivery zone might include all addresses within five miles of a warehouse. In a flat coordinate model, that zone is a circle: all points within radius 5 of the warehouse. The boundary is the circle equation. A wireless signal may be modeled by a radius around a transmitter. A sprinkler covers a circular region. A robot sensor may detect obstacles within a circular range. A game character may have an interaction radius. In all of these cases, the circle is not just a drawing; it is a mathematical condition on points.

The equation also teaches students how technology sees geometry. Computers do not “see” a perfect circle the way a person imagines one. They store coordinates, equations, inequalities, and algorithms. To decide whether a point is on, inside, or outside a circle, a computer can compare \((x - h)² + (y - k)²\) to . If it equals , the point is on the circle. If it is less than , the point is inside. If it is greater than , the point is outside. This is used in graphics, games, mapping, robotics, and simulations.

This objective also gives a real purpose for completing the square. Many students experience completing the square as an algebra trick for quadratics. Circle equations show why the method matters. Completing the square reveals hidden structure. It turns expanded algebra into geometric information: center and radius. The algebra is not busywork; it uncovers the shape.

Students should also learn this because it connects math topics that often feel separate. The Pythagorean Theorem from geometry becomes the distance formula in coordinate geometry. The distance formula becomes the equation of a circle. Completing the square from algebra becomes a way to identify geometric features. Graphing becomes the visual interpretation of an equation. This objective is a clear example of the big picture: algebra and geometry are two languages for the same relationships.

The historical machinery behind circle equations

Classical geometry studied circles long before coordinate equations existed. Ancient mathematicians knew circles through constructions, chords, tangents, arcs, sectors, and angle relationships. A circle was a geometric object defined by center and radius. It could be drawn with a compass, studied with theorems, and used in astronomy and architecture.

The major historical shift came with analytic geometry, associated especially with René Descartes and Pierre de Fermat in the seventeenth century. Analytic geometry introduced the idea that curves could be represented by equations and equations could be represented by curves. This was revolutionary. It allowed geometric problems to be solved with algebra and algebraic relationships to be visualized as geometry.

The circle equation is one of the cleanest examples of analytic geometry. The geometric definition is ancient: all points at a fixed distance from a center. The algebraic expression uses coordinates and the Pythagorean Theorem. The result is a curve described by an equation. This bridge eventually led to conic sections, calculus, physics, engineering, computer graphics, and modern mathematical modeling.

Completing the square also has historical depth. Algebra developed methods for solving quadratic equations long before modern symbolic notation. Completing the square is a geometric and algebraic idea: transform an expression into a perfect square plus or minus a remainder. In the circle equation, it reorganizes x and y terms into squared distance components. The method reveals that an expanded equation may be hiding a simple geometric shape.

This objective therefore sits at an important historical crossroads. It takes the ancient circle and places it into the coordinate plane. It takes a geometric definition and writes it as algebra. It takes an algebraic equation and reads it back as a shape. That back-and-forth is one of the great engines of modern mathematics.

The technical machinery: deriving the standard form

Start with the definition of a circle: all points \((x, y)\) that are distance \(r\) from center \((h, k)\). The horizontal change from center to point is \(x - h\). The vertical change is \(y - k\). These form the legs of a right triangle. By the Pythagorean Theorem, the squared distance is \((x - h)² + (y - k)²\). Since the distance is radius \(r\), the equation is \((x - h)² + (y - k)² = r²\).

For a circle centered at the origin, the equation simplifies to \(x² + y² = r²\). If the radius is 10, the equation is \(x² + y² = 100\). A point like \((6, 8)\) lies on the circle because \(6² + 8² = 36 + 64 = 100\). A point like \((3, 4)\) lies inside because \(3² + 4² = 25\), which is less than 100. A point like \((10, 10)\) lies outside because \(100 + 100 = 200\), which is greater than 100.

For a shifted center, the same distance logic applies. If center is \((2, -5)\) and radius is 7, the equation is \((x - 2)² + (y + 5)² = 49\). The graph is the circle centered at \((2, -5)\) extending 7 units in every direction. Its leftmost point is \((-5, -5)\), rightmost point is \((9, -5)\), top point is \((2, 2)\), and bottom point is \((2, -12)\).

Students should understand that the equation describes every point on the circle at once. It is not a recipe for finding one y-value for each x-value like many function equations. A circle is usually not a function of x because most x-values inside the circle correspond to two y-values, one above the center and one below.

The technical machinery: completing the square

Completing the square rewrites quadratic expressions in a form that reveals center and radius. A circle equation often starts expanded: \(x² + y² + Dx + Ey + F = 0\). To rewrite it, move the constant to the other side, group x terms and y terms, complete each square, and simplify.

Example: \(x² + y² + 10x - 4y - 20 = 0\). Move the constant: \(x² + 10x + y² - 4y = 20\). Complete the x-square. Half of 10 is 5, and \(5² = 25\). Complete the y-square. Half of -4 is -2, and \((-2)² = 4\). Add both to the left, and therefore also to the right: \(x² + 10x + 25 + y² - 4y + 4 = 20 + 25 + 4\). Rewrite: \((x + 5)² + (y - 2)² = 49\). So the center is \((-5, 2)\) and the radius is 7.

The method works because a perfect square has the pattern \(x² + 2ax + a² = (x + a)²\). The middle coefficient tells you twice the number inside the square. So for \(x² + 10x\), the number is 5; for \(y² - 4y\), the number is -2.

Sometimes the right side after completing the square is positive, zero, or negative. If it is positive, the graph is a circle with radius equal to the square root of that number. If it is zero, the graph is a single point: a circle of radius zero. If it is negative, there is no real circle because squared distances cannot add to a negative number. This is another example of algebra revealing geometry.

Real-world and technical execution

Circle equations are used whenever distance from a center matters. Suppose a cell tower is at coordinate \((4, -1)\) and has a service radius of 12 miles. The boundary of its idealized coverage area is \((x - 4)² + (y + 1)² = 144\). A location \((10, 7)\) is within range if \((10 - 4)² + (7 + 1)² = 36 + 64 = 100\), which is less than 144.

In robotics, a robot with arm reach \(r\) from a pivot point can reach points inside or on a circle. In game design, a character might interact with objects within radius \(r\); the software can test squared distances without even taking square roots. In manufacturing, circular tolerances can describe allowed variation around a target point. In navigation, circular exclusion zones can represent hazards, protected areas, or range limits.

Circle equations also prepare students for line-circle intersections. A path modeled by a line may cross, miss, or touch a circular region. Algebra can solve this by substituting the line equation into the circle equation. If the resulting quadratic has two solutions, the line crosses the circle twice. If it has one solution, the line is tangent. If it has no real solutions, it misses. This connects directly back to circle tangents and forward to analytic geometry.

Common mistakes and how to fix them

A common mistake is reading the center signs incorrectly. In \((x - 3)² + (y + 2)² = 25\), the center is \((3, -2)\), not \((-3, 2)\). The fix is to match the form \((x - h)² + (y - k)² = r²\).

Another mistake is treating as the radius. If the equation is \((x - 1)² + (y - 4)² = 36\), the radius is 6, not 36. The right side is radius squared.

A third mistake is completing the square on one side without doing the same to the other. Whatever number is added to create a perfect square must also be added to the other side of the equation.

A fourth mistake is forgetting to group x terms and y terms separately. Completing the square works on one variable at a time. Students should organize the equation before manipulating it.

A fifth mistake is assuming every equation with and is a circle. For a circle in this standard form, the coefficients of and must match, and there should be no \(xy\) term. Otherwise the graph may be another conic or a transformed version beyond this course’s focus.

Where this fits into the big map of math

This objective is one of the cleanest examples of the algebra-geometry bridge. A circle begins as a visual object. The Pythagorean Theorem turns distance into an equation. Completing the square turns an expanded equation back into a visual object. The student moves between diagram, formula, graph, and interpretation.

It also prepares students for conic sections. Circles are the simplest conic. Parabolas, ellipses, and hyperbolas also have geometric definitions and algebraic equations. Later, students will see that completing the square helps analyze more general conic equations.

The objective also connects to functions and inequalities. The circle boundary is an equation. The disk inside the circle is an inequality: \((x - h)² + (y - k)² \le r²\). The outside region is \((x - h)² + (y - k)² > r²\). This is useful for modeling zones, constraints, and feasible regions.

In the full map of mathematics, circle equations support trigonometry, vectors, complex numbers, physics, engineering, graphics, and calculus. The unit circle, central to trigonometry, is simply \(x² + y² = 1\). Circular motion, waves, rotations, and periodic functions all connect back to this structure.

Mastery of this objective means a student can see a circle as both a shape and a relationship among coordinates. They can derive the equation, not just remember it. They can decode an equation, not just graph it mechanically. That is the real goal: understanding how algebra can describe space.

Problem Library

Problems in the App From This Objective

183 problems across 15 archetypes in the app.

use `(x-h)^2+(y-k)^2=r^2`.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Write the equation of a circle with center (0,0) and radius 5.

Problem 2

Write the equation of a circle with center (3,-2) and radius 4.

Problem 3

Write the equation of a circle with center (-1,6) and radius sqrt(7).

Problem 4

Write the equation of a circle with center (1/2,-3) and radius 2.

Problem 5

Write the equation of a circle with center (2,5) and radius 3.

Problem 6

Write the equation of a circle with center (-4,-1) and radius 6.

Problem 7

Write the equation of a circle with center (0,7) and radius 1.

Problem 8

Write the equation of a circle with center (8,0) and radius 10.

Problem 9

Write the equation of a circle with center (1/3,-5) and radius 2.

Problem 10

Write the equation of a circle with center (-6,3/4) and radius 5.

Problem 11

Write the equation of a circle with center (5,-3) and radius sqrt(11).

Problem 12

Write the equation of a circle with center (-1/2,-3/2) and radius 7.

Open in simulator
read signs and square-root radius.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Identify the center and radius of circle (x-3)^2+(y+2)^2=16.

Problem 14

Identify the center and radius of circle x^2+y^2=25.

Problem 15

Identify the center and radius of circle (x+1)^2+(y-6)^2=7.

Problem 16

Identify the center and radius of circle (x-1/2)^2+(y+3)^2=4.

Problem 17

Identify the center and radius of circle (x+5)^2+y^2=36.

Problem 18

Identify the center and radius of circle x^2+(y+7)^2=49.

Problem 19

Identify the center and radius of circle (x-4)^2+(y-5)^2=10.

Problem 20

Identify the center and radius of circle (x+2)^2+(y+8)^2=1.

Problem 21

Identify the center and radius of circle (x-1/3)^2+(y+1/2)^2=9.

Problem 22

Identify the center and radius of circle (x+4)^2+(y-1)^2=13.

Problem 23

Identify the center and radius of circle x^2+y^2=2.

Problem 24

Identify the center and radius of circle (x-10)^2+(y+12)^2=100.

Open in simulator
set distance from center to variable point equal to radius.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Derive the circle equation from distance formula for center (0,0) and radius 5.

Problem 26

Derive the circle equation from distance formula for center (3,-2) and radius 4.

Problem 27

Derive the circle equation from distance formula for center (-1,6) and radius sqrt(7).

Problem 28

Derive the circle equation from distance formula for center (h,k) and radius r.

Problem 29

Derive the circle equation from distance formula for center (1,1) and radius 3.

Problem 30

Derive the circle equation from distance formula for center (-5,-8) and radius 10.

Problem 31

Derive the circle equation from distance formula for center (0,-4) and radius 6.

Problem 32

Derive the circle equation from distance formula for center (7,0) and radius sqrt(11).

Problem 33

Derive the circle equation from distance formula for center (-2,3) and radius 1/2.

Problem 34

Derive the circle equation from distance formula for center (5,-5) and radius sqrt(2).

Open in simulator
Problem 35

Derive the circle equation from distance formula for center (0,0) and radius 1.

Problem 36

Derive the circle equation from distance formula for center (10,-1) and radius 7.

group x/y terms and complete both squares.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Complete the square to convert circle equation x^2+y^2-6x+4y-3=0 to standard form.

Problem 38

Complete the square to convert circle equation x^2+y^2+2x-12y+30=0 to standard form.

Problem 39

Complete the square to convert circle equation x^2+y^2-8x-10y+16=0 to standard form.

Problem 40

Complete the square to convert circle equation x^2+y^2+4x+6y+9=0 to standard form.

Problem 41

Complete the square to convert circle equation x^2+y^2+10x-2y+10=0 to standard form.

Problem 42

Complete the square to convert circle equation x^2+y^2-4x+8y-11=0 to standard form.

Problem 43

Complete the square to convert circle equation x^2+y^2+6x-7=0 to standard form.

Problem 44

Complete the square to convert circle equation x^2+y^2-14y+40=0 to standard form.

Problem 45

Complete the square to convert circle equation x^2+y^2-2x-6y-15=0 to standard form.

Problem 46

Complete the square to convert circle equation x^2+y^2+12x+10y+50=0 to standard form.

Problem 47

Complete the square to convert circle equation x^2+y^2+8x+2y+1=0 to standard form.

Problem 48

Complete the square to convert circle equation x^2+y^2-10x+4y+20=0 to standard form.

Open in simulator
interpret transformed equation.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Identify center and radius after completing the square for x^2+y^2-6x+4y-3=0.

Problem 50

Identify center and radius after completing the square for x^2+y^2+2x-12y+30=0.

Problem 51

Identify center and radius after completing the square for x^2+y^2-8x-10y+16=0.

Problem 52

Identify center and radius after completing the square for x^2+y^2+4x+6y+9=0.

Problem 53

Identify center and radius after completing the square for x^2+y^2-2x-4y-4=0.

Problem 54

Identify center and radius after completing the square for x^2+y^2+10x-8y+5=0.

Problem 55

Identify center and radius after completing the square for x^2+y^2-14x+2y+40=0.

Problem 56

Identify center and radius after completing the square for x^2+y^2+6x+10y+18=0.

Open in simulator
Problem 57

Identify center and radius after completing the square for x^2+y^2-12x+6y+40=0.

Problem 58

Identify center and radius after completing the square for x^2+y^2+8x-2y-8=0.

Problem 59

Identify center and radius after completing the square for x^2+y^2-4x+12y+24=0.

Problem 60

Identify center and radius after completing the square for x^2+y^2+2x-10y+1=0.

check equal x/y squared coefficients and positive radius squared.
15 problems Warmup Practice Mixed Review Assessment
Problem 61

Determine whether general quadratic equation x^2+y^2-6x+4y-3=0 represents a real circle.

Problem 62

Determine whether general quadratic equation x^2+y^2+2x-12y+38=0 represents a real circle.

Problem 63

Determine whether general quadratic equation x^2+y^2+4x+6y+20=0 represents a real circle.

Problem 64

Determine whether general quadratic equation x^2+2y^2-4x+8y=0 represents a real circle.

Problem 65

Determine whether general quadratic equation x^2+y^2-8x+2y-8=0 represents a real circle.

Problem 66

Determine whether general quadratic equation x^2+y^2+10x-4y+29=0 represents a real circle.

Problem 67

Determine whether general quadratic equation x^2+y^2-6x-8y+30=0 represents a real circle.

Problem 68

Determine whether general quadratic equation 3x^2+2y^2-6x+4y-1=0 represents a real circle.

Open in simulator
Problem 69

Determine whether general quadratic equation 2x^2+2y^2+12x-8y-10=0 represents a real circle.

Problem 70

Determine whether general quadratic equation 3x^2+3y^2-18x+6y+30=0 represents a real circle.

Problem 71

Determine whether general quadratic equation 4x^2+4y^2+8x+16y+24=0 represents a real circle.

Problem 72

Determine whether general quadratic equation x^2-4x+6y+1=0 represents a real circle.

Problem 73

Determine whether general quadratic equation x^2+y^2+10x+12y-20=0 represents a real circle.

Problem 74

Determine whether general quadratic equation x^2+y^2-2x-4y+5=0 represents a real circle.

Problem 75

Determine whether general quadratic equation x^2+y^2+2x+2y+3=0 represents a real circle.

find midpoint and radius from distance.
12 problems Warmup Practice Mixed Review Assessment
Problem 76

Write the circle equation with diameter endpoints (0,0) and (6,8).

Problem 77

Write the circle equation with diameter endpoints (-2,5) and (4,5).

Problem 78

Write the circle equation with diameter endpoints (1,-3) and (1,7).

Problem 79

Write the circle equation with diameter endpoints (-4,-1) and (2,3).

Problem 80

Write the circle equation with diameter endpoints (0,0) and (2,0).

Problem 81

Write the circle equation with diameter endpoints (-1,-1) and (1,1).

Problem 82

Write the circle equation with diameter endpoints (3,0) and (-1,4).

Problem 83

Write the circle equation with diameter endpoints (-5,2) and (1,-4).

Problem 84

Write the circle equation with diameter endpoints (0,-3) and (0,3).

Problem 85

Write the circle equation with diameter endpoints (2,7) and (8,1).

Open in simulator
Problem 86

Write the circle equation with diameter endpoints (-3,-2) and (5,4).

Problem 87

Write the circle equation with diameter endpoints (10,-1) and (4,-1).

compute radius using distance formula.
12 problems Warmup Practice Mixed Review Assessment
Problem 88

Write the circle equation with center (2,1) passing through point (5,5).

Problem 89

Write the circle equation with center (-1,3) passing through point (2,7).

Problem 90

Write the circle equation with center (0,0) passing through point (3,-4).

Problem 91

Write the circle equation with center (4,-2) passing through point (6,1).

Problem 92

Write the circle equation with center (1,1) passing through point (4,5).

Problem 93

Write the circle equation with center (-2,-3) passing through point (1,1).

Open in simulator
Problem 94

Write the circle equation with center (0,5) passing through point (3,1).

Problem 95

Write the circle equation with center (-3,0) passing through point (1,3).

Problem 96

Write the circle equation with center (0,0) passing through point (1,2).

Problem 97

Write the circle equation with center (5,-1) passing through point (2,3).

Problem 98

Write the circle equation with center (-4,2) passing through point (-1,-2).

Problem 99

Write the circle equation with center (1,2) passing through point (4,2).

compare squared distance to radius squared.
12 problems Warmup Practice Mixed Review Assessment
Problem 100

Classify point (3,4) relative to circle x^2+y^2=25.

Open in simulator
Problem 101

Classify point (1,2) relative to circle x^2+y^2=25.

Problem 102

Classify point (6,0) relative to circle x^2+y^2=25.

Problem 103

Classify point (5,-2) relative to circle (x-2)^2+(y+2)^2=9.

Problem 104

Classify point (5,3) relative to circle (x-1)^2+(y-3)^2=16.

Problem 105

Classify point (1,3) relative to circle (x-1)^2+(y-3)^2=16.

Problem 106

Classify point (6,3) relative to circle (x-1)^2+(y-3)^2=16.

Problem 107

Classify point (7,-1) relative to circle (x+3)^2+(y+1)^2=100.

Problem 108

Classify point (-2,-1) relative to circle (x+3)^2+(y+1)^2=100.

Problem 109

Classify point (8,-1) relative to circle (x+3)^2+(y+1)^2=100.

Problem 110

Classify point (2,3) relative to circle x^2+y^2=13.

Problem 111

Classify point (0,0) relative to circle (x-4)^2+(y+5)^2=20.

plot center and radius points.
12 problems Warmup Practice Mixed Review Assessment
Problem 112

Describe how to graph circle (x-3)^2+(y+2)^2=16.

Problem 113

Describe how to graph circle x^2+y^2=25.

Problem 114

Describe how to graph circle (x+1)^2+(y-6)^2=7.

Problem 115

Describe how to graph circle x^2+y^2-6x+4y-3=0.

Problem 116

Describe how to graph circle (x+5)^2+(y-1)^2=9.

Problem 117

Describe how to graph circle (x+2)^2+(y+4)^2=11.

Open in simulator
Problem 118

Describe how to graph circle (x-7)^2+(y-3)^2=49.

Problem 119

Describe how to graph circle (x-8)^2+y^2=1.

Problem 120

Describe how to graph circle x^2+y^2+10x-2y-10=0.

Problem 121

Describe how to graph circle x^2+y^2-4x+8y-5=0.

Problem 122

Describe how to graph circle x^2+y^2+6x+2y-1=0.

Problem 123

Describe how to graph circle x^2+(y-9)^2=81.

substitute point or use radius/center relationship.
12 problems Warmup Practice Mixed Review Assessment
Problem 124

Find the missing parameter in circle equation (x-2)^2+(y-1)^2=r^2 using condition point (5,5) lies on the circle.

Problem 125

Find the missing parameter in circle equation (x-h)^2+(y+2)^2=9 using condition center has x-coordinate 4.

Problem 126

Find the missing parameter in circle equation x^2+y^2=k using condition point (3,4) lies on the circle.

Problem 127

Find the missing parameter in circle equation (x-1)^2+(y-a)^2=16 using condition center is (1,-3).

Open in simulator
Problem 128

Find the missing parameter in circle equation (x+3)^2+(y-k)^2=25 using condition center has y-coordinate 7.

Problem 129

Find the missing parameter in circle equation x^2+y^2=R using condition point (6,8) lies on the circle.

Problem 130

Find the missing parameter in circle equation (x-h)^2+(y-5)^2=4 using condition center is (-2,5).

Problem 131

Find the missing parameter in circle equation (x+1)^2+(y-2)^2=r^2 using condition point (3,5) lies on the circle.

Problem 132

Find the missing parameter in circle equation (x-4)^2+(y+b)^2=81 using condition center has y-coordinate 6.

Problem 133

Find the missing parameter in circle equation (x-1)^2+(y+1)^2=c using condition radius is 7.

Problem 134

Find the missing parameter in circle equation (x+a)^2+(y-3)^2=100 using condition center is (5,3).

Problem 135

Find the missing parameter in circle equation (x-3)^2+(y+4)^2=m using condition point (0,0) lies on the circle.

connect center, radius, and boundary to situation.
12 problems Warmup Practice Mixed Review Assessment
Problem 136

Interpret circle equation (x-2)^2+(y-3)^2=25 in context coverage map in miles.

Problem 137

Interpret circle equation x^2+y^2=100 in context distance constraint from origin.

Problem 138

Interpret circle equation (x+4)^2+(y-1)^2=36 in context sprinkler reach in feet.

Problem 139

Interpret circle equation (x-10)^2+(y+2)^2=16 in context design boundary.

Problem 140

Interpret circle equation (x-5)^2+(y-8)^2=49 in context radio signal range in kilometers.

Problem 141

Interpret circle equation (x+1)^2+(y+6)^2=81 in context earthquake epicenter in grid units.

Problem 142

Interpret circle equation x^2+(y-7)^2=144 in context radar detection zone in nautical miles.

Problem 143

Interpret circle equation (x+3)^2+y^2=64 in context drone flight perimeter in meters.

Problem 144

Interpret circle equation (x-0.5)^2+(y-1.5)^2=2.25 in context microscopic field of view in micrometers.

Problem 145

Interpret circle equation (x-12)^2+(y+5)^2=1 in context target area in centimeters.

Open in simulator
Problem 146

Interpret circle equation (x+7)^2+(y-9)^2=225 in context cell tower signal range in miles.

Problem 147

Interpret circle equation (x-6)^2+(y+11)^2=196 in context oil spill containment zone in feet.

identify relative position and size.
12 problems Warmup Practice Mixed Review Assessment
Problem 148

Compare circles x^2+y^2=25 and (x-3)^2+y^2=4 by center and radius.

Problem 149

Compare circles (x-1)^2+(y-1)^2=9 and (x-8)^2+(y-1)^2=4 by center and radius.

Problem 150

Compare circles x^2+y^2=16 and (x-8)^2+y^2=16 by center and radius.

Problem 151

Compare circles (x+1)^2+y^2=9 and (x-1)^2+y^2=9 by center and radius.

Problem 152

Compare circles x^2+y^2=9 and x^2+y^2=16 by center and radius.

Problem 153

Compare circles (x-1)^2+(y-1)^2=1 and (x-1.5)^2+(y-1)^2=4 by center and radius.

Problem 154

Compare circles x^2+y^2=25 and (x-4)^2+y^2=9 by center and radius.

Problem 155

Compare circles (x+5)^2+(y-2)^2=4 and (x-5)^2+(y-2)^2=9 by center and radius.

Problem 156

Compare circles (x-3)^2+(y+1)^2=16 and (x-3)^2+(y+1)^2=16 by center and radius.

Problem 157

Compare circles x^2+y^2=36 and (x-2)^2+y^2=16 by center and radius.

Problem 158

Compare circles (x-1)^2+(y-1)^2=4 and (x-6)^2+(y-1)^2=9 by center and radius.

Open in simulator
Problem 159

Compare circles (x-5)^2+(y-5)^2=4 and (x-6)^2+(y-5)^2=25 by center and radius.

transform equation before answering graph/point question.
12 problems Warmup Practice Mixed Review Assessment
Problem 160

Use completing the square to answer the circle problem Find center of x^2+y^2-6x+4y-3=0.

Problem 161

Use completing the square to answer the circle problem Find radius of x^2+y^2+2x-12y+30=0.

Problem 162

Use completing the square to answer the circle problem Classify point (4,5) for x^2+y^2-8x-10y+16=0.

Problem 163

Use completing the square to answer the circle problem Graph x^2+y^2+4x+6y+9=0.

Problem 164

Use completing the square to answer the circle problem Find center of x^2+y^2+10x-8y+1=0.

Problem 165

Use completing the square to answer the circle problem Find radius of x^2+y^2-4x-6y-12=0.

Open in simulator
Problem 166

Use completing the square to answer the circle problem Classify point (1,2) for x^2+y^2-2x-4y-4=0.

Problem 167

Use completing the square to answer the circle problem Graph x^2+y^2-8x+2y+13=0.

Problem 168

Use completing the square to answer the circle problem Find center of x^2+y^2+x-3y-1/4=0.

Problem 169

Use completing the square to answer the circle problem Find radius of x^2+y^2+6x-2y-7=0.

Problem 170

Use completing the square to answer the circle problem Classify point (0,0) for x^2+y^2-6x-8y+20=0.

Problem 171

Use completing the square to answer the circle problem Graph x^2+y^2-10x-4y+20=0.

catch sign, radius, grouping, and square-completion mistakes.
12 problems Warmup Practice Mixed Review Assessment
Problem 172

Correct the circle-equation error: A student says (x-3)^2+(y+2)^2=16 has center (-3,2).

Problem 173

Correct the circle-equation error: A student says radius is 16 when r^2=16.

Problem 174

Correct the circle-equation error: A student completes x^2-6x as (x-3)^2 without adding 9 to both sides.

Problem 175

Correct the circle-equation error: A student treats x^2+2y^2=25 as a circle.

Problem 176

Correct the circle-equation error: A student says (x+1)^2 + y^2 = 4 has center (1,0).

Problem 177

Correct the circle-equation error: A student says the radius of (x-2)^2 + (y+3)^2 = 12 is 12.

Open in simulator
Problem 178

Correct the circle-equation error: A student writes the equation for a circle with radius 6 as (x-h)^2 + (y-k)^2 = 6.

Problem 179

Correct the circle-equation error: A student completes y^2+10y as (y+5)^2 by adding 5 to both sides.

Problem 180

Correct the circle-equation error: A student claims x^2+y^2+6x-2y+1=0 has center (6,-2).

Problem 181

Correct the circle-equation error: A student says the radius of 3x^2+3y^2=75 is 75.

Problem 182

Correct the circle-equation error: A student writes the equation for a circle centered at (-4, 0) with radius 1 as (x-4)^2 + y^2 = 1.

Problem 183

Correct the circle-equation error: A student says the radius of x^2+y^2=9 is -3.