Math II · G-SRT.4

Proving Triangle-Similarity Theorems, Including the Pythagorean Theorem

Similarity proves why major triangle formulas work. It turns the Pythagorean Theorem and proportional segment rules from memorized facts into consequences of shape, scale, and ratio.

Concept Geometry
Domain Similarity, Right Triangles, and Trigonometry
Read time 6 minutes

What this learning objective is really asking you to learn

This objective asks students to use similarity as a proof engine. In earlier objectives, students learned what similarity means and why AA similarity works. Now they use similarity to prove important triangle relationships. The goal is not simply to solve for missing lengths. The goal is to understand why certain length relationships must be true.

One of the central configurations is a right triangle with an altitude drawn from the right angle to the hypotenuse. This one line creates three right triangles: the original large triangle and two smaller triangles inside it. Because of AA similarity, all three triangles are similar to one another. The angles line up in a precise way. Once similarity is established, corresponding sides are proportional. Those proportions produce powerful relationships among the legs, the hypotenuse, and the pieces of the hypotenuse.

This configuration can prove the Pythagorean Theorem. The theorem says that in a right triangle with legs \(a\) and \(b\) and hypotenuse \(c\), \(a^2 + b^2 = c^2\). Many students memorize this formula early. This objective asks them to see it as a consequence of similar triangles. When the altitude to the hypotenuse is drawn, each leg becomes a geometric mean between the hypotenuse and the adjacent segment of the hypotenuse. Algebraically, if the hypotenuse is split into segments \(m\) and \(n\), and the whole hypotenuse is \(c\), then \(a^2 = cm\) and \(b^2 = cn\). Adding gives \(a^2 + b^2 = c(m + n)\). Since \(m + n = c\), the result is \(a^2 + b^2 = c^2\).

That proof is important because it links one of the most famous formulas in mathematics to similarity. The theorem is not a magic fact about squares. It emerges from the stable proportions created by right-triangle similarity.

This objective also includes proportional segment theorems more generally. If a line parallel to one side of a triangle cuts the other two sides, it creates a smaller triangle similar to the original. That similarity produces proportional side segments. These results are used in geometry, design, coordinate proof, and trigonometry.

Why students should learn this math

Students should learn this because proof is what turns mathematical facts into trustworthy tools. A formula that is memorized can be forgotten, misused, or treated as a trick. A formula that is understood through proof becomes part of a connected map. The Pythagorean Theorem is used in construction, navigation, computer graphics, physics, robotics, surveying, architecture, and coordinate geometry. Students deserve to know why such an important formula works.

Similarity proofs also show how one idea can generate many results. Once students know that certain triangles are similar, many length relationships follow. This is efficient and elegant. Instead of memorizing a separate rule for every diagram, students learn the engine: prove similarity, write proportions, derive the relationship.

In real applications, the Pythagorean Theorem supports distance. The distance formula in coordinate geometry comes from it. GPS systems, mapping, screen graphics, engineering layouts, and game environments all use distance calculations. A robot deciding how far it is from a target, a designer checking diagonal clearance, a builder squaring a corner, and a programmer calculating collision distance are all relying on the right-triangle distance relationship.

Proportional segment reasoning also matters in design and measurement. If a scaled drawing is similar to a real object, lengths can be found through proportions. If a parallel cross-section creates similar triangles, unknown widths or heights can be calculated. In optics, perspective, and camera geometry, similar triangles explain how image size depends on distance. In physics and engineering, similar triangle reasoning helps model forces, slopes, ramps, and components.

The “why” is therefore direct: similarity is not just about shapes looking alike. It is a proof system that explains major formulas and makes indirect measurement reliable.

The historical machinery: one theorem, many proofs

The Pythagorean Theorem has an unusually rich history. It was known in various forms in ancient Babylonian, Indian, Chinese, and Greek mathematics. It is associated by name with Pythagoras and the Pythagorean tradition, but the relationship itself appears across cultures because right triangles occur naturally in land measurement, construction, astronomy, and geometry.

There are hundreds of proofs of the Pythagorean Theorem. Some use rearranged areas. Some use algebra. Some use similar triangles. This variety is part of what makes the theorem important. It sits at a crossroads of geometry, algebra, area, proportion, and distance.

The similarity proof is especially valuable in high school because it connects the theorem to the broader similarity unit. It shows that the formula is not isolated. A right triangle contains smaller similar right triangles when the altitude is drawn to the hypotenuse. Those internal copies explain why the side squares add the way they do.

Historically, proportional reasoning was central to Greek geometry. Before algebraic symbolism became dominant, ratios and geometric relationships were the language of proof. Similar triangles were a powerful way to express relationships among lengths. Modern algebra lets us write the proof compactly, but the geometric idea is ancient: same shape creates proportional lengths.

In modern mathematics and science, the Pythagorean Theorem becomes the foundation for Euclidean distance. In two dimensions, distance between points comes from a right triangle. In three dimensions, the theorem extends to \(d^2 = x^2 + y^2 + z^2\). In higher dimensions, it becomes part of vector length and linear algebra. The same relationship supports statistics, machine learning, physics, and computer graphics.

Where this fits in the big map of mathematics

This objective is one of the key bridges between geometry proof and later technical mathematics. It connects similarity to the Pythagorean Theorem, and the Pythagorean Theorem connects to coordinate distance. Coordinate distance connects to circles, conics, vectors, analytic geometry, and eventually calculus and linear algebra.

It also prepares students for trigonometry. In right triangles, side ratios are stable because of similarity. The Pythagorean identity \(sin^2(theta) + cos^2(theta) = 1\) later emerges from the Pythagorean Theorem on the unit circle. That means the theorem appears again inside trigonometric functions.

Similarity proofs also support geometric modeling. When an object is scaled, all lengths scale by the same factor. Areas scale by the square of that factor. Volumes scale by the cube. This objective reinforces the length-proportion part of that larger scaling map.

In proof development, Objective 108 helps students move from observing diagrams to deriving relationships. A diagram may suggest that segments are proportional, but proof explains why. This matters because diagrams can mislead; proof gives certainty.

How to execute the skill technically

A common proof process begins with a right triangle \(ABC\), where ∠C is the right angle. Draw altitude \(CD\) from \(C\) to hypotenuse \(AB\), meeting \(AB\) at \(D\). This creates triangles \(ACD\), \(BCD\), and \(ABC\).

To prove similarity, use AA. Each small triangle has a right angle at \(D\), and each shares an acute angle with the original triangle. Therefore ACD ~ ABC and BCD ~ ABC, and the two small triangles are also similar to each other.

Once similarity is established, write proportions carefully. If \(AB = c\), \(AD = m\), \(DB = n\), \(AC = b\), and \(BC = a\), then from similarity we get relationships such as \(a^2 = cn\) and \(b^2 = cm\), depending on labeling. Adding these relationships gives the Pythagorean Theorem.

Students should not memorize only the final algebra. They should understand the sequence: draw altitude, prove similar triangles, write proportions, derive equations, combine equations.

For proportional segment theorems, if a line parallel to one side of a triangle cuts the other two sides, the smaller triangle is similar to the larger triangle by AA because corresponding angles are equal. Then side ratios give proportional segments. This is the same proof engine in another diagram.

Common misconceptions and productive corrections

One misconception is thinking the Pythagorean Theorem applies to every triangle. It applies to right triangles only. If there is no right angle, the relationship changes; later students meet the Law of Cosines.

Another misconception is writing proportions from similar triangles without matching corresponding sides. The proof depends on correct correspondence.

A third misconception is believing a proof is just a formal requirement after the useful formula. In fact, the proof explains where the formula comes from and why it can be trusted.

A fourth misconception is assuming the altitude to the hypotenuse is just an extra line. It is the line that creates the similar triangles that make the proof work.

A concrete example

Suppose a right triangle has hypotenuse 25, and the altitude to the hypotenuse splits it into segments 9 and 16. The leg adjacent to the 9 segment satisfies \(leg^2 = 25 \cdot 9 = 225\), so that leg is 15. The other leg satisfies \(leg^2 = 25 \cdot 16 = 400\), so that leg is 20. Then \(15^2 + 20^2 = 225 + 400 = 625 = 25^2\). This example is not a coincidence; it is the similarity machinery working.

Problem Library

Problems in the App From This Objective

171 problems across 12 archetypes in the app.

show parallel line creates proportional segments.
15 problems Warmup Practice Mixed Review Assessment
Problem 1

Prove the side-splitter theorem in DE parallel BC in triangle ABC.

Problem 2

Prove the side-splitter theorem in segment MN parallel QR in triangle PQR.

Problem 3

Prove the side-splitter theorem in line parallel to one side intersects the other two sides.

Problem 4

Prove the side-splitter theorem in proof completion with parallel segment.

Problem 5

Prove the side-splitter theorem in Triangle XYZ with segment AB parallel to YZ, where A is on XY and B is on XZ.

Problem 6

Prove the side-splitter theorem in In triangle LMN, segment ST is parallel to MN, intersecting LM at S and LN at T.

Problem 7

Prove the side-splitter theorem in A segment parallel to the base of a triangle, connecting the other two sides.

Problem 8

Prove the side-splitter theorem in Triangle DEF with segment GH parallel to EF, G on DE, H on DF.

Problem 9

Prove the side-splitter theorem in A line segment drawn within a triangle, parallel to one of its sides.

Problem 10

Prove the side-splitter theorem in Segment UV parallel to QR in triangle PQR, with U on PQ and V on PR.

Problem 11

Prove the side-splitter theorem in Triangle ABC with a segment DE parallel to BC, D on AB, E on AC.

Problem 12

Prove the side-splitter theorem in A transversal line segment parallel to one side of a triangle, cutting the other two sides.

Open in simulator
Problem 13

Prove the side-splitter theorem in The geometric configuration for the side-splitter theorem.

Problem 14

Prove the side-splitter theorem in Triangle GHI with segment JK parallel to HI, J on GH, K on GI.

Problem 15

Prove the side-splitter theorem in A line segment inside a triangle, parallel to its base.

set up proportions from parallel segment.
12 problems Warmup Practice Mixed Review Assessment
Problem 16

Use the side-splitter theorem to find the missing segment from DE parallel BC, AD=4, DB=6, AE=x, EC=9.

Problem 17

Use the side-splitter theorem to find the missing segment from MN parallel QR, PM=5, MQ=10, PN=4, NR=x.

Problem 18

Use the side-splitter theorem to find the missing segment from split sides are 3 and 9 on one side, 2 and x on the other.

Problem 19

Use the side-splitter theorem to find the missing segment from AD/DB=2/3 and AE=8, EC=x.

Problem 20

Use the side-splitter theorem to find the missing segment from DE parallel BC, AD=6, DB=x, AE=8, EC=12.

Problem 21

Use the side-splitter theorem to find the missing segment from A line parallel to one side of a triangle divides the other two sides into segments. One side is split into x and 5, the other into 6 and 15.

Problem 22

Use the side-splitter theorem to find the missing segment from In triangle PQR, MN is parallel to QR. PM=7, MQ=x, PN=3, NR=9.

Problem 23

Use the side-splitter theorem to find the missing segment from A segment parallel to the base of a triangle cuts the sides into lengths 10 and 4 on one side, and x and 2 on the other.

Problem 24

Use the side-splitter theorem to find the missing segment from Given a triangle with a line parallel to one side, the segments on one side are 12 and 8, and on the other side are 9 and x.

Problem 25

Use the side-splitter theorem to find the missing segment from The ratio of segments on one side of a triangle is 5/2. If the corresponding segments on the other side are y and 10, find y.

Problem 26

Use the side-splitter theorem to find the missing segment from In triangle ABC, DE is parallel to BC. AD=15, DB=x, AE=10, EC=6.

Open in simulator
Problem 27

Use the side-splitter theorem to find the missing segment from For triangle PQR, MN is parallel to QR. PM=x, MQ=14, PN=3, NR=21.

compare segment ratios.
12 problems Warmup Practice Mixed Review Assessment
Problem 28

Use the converse of the side-splitter theorem to prove lines parallel from AD/DB=4/6 and AE/EC=6/9.

Problem 29

Use the converse of the side-splitter theorem to prove lines parallel from PM/MQ=5/10 and PN/NR=4/8.

Problem 30

Use the converse of the side-splitter theorem to prove lines parallel from split ratios 3/9 and 2/6.

Problem 31

Use the converse of the side-splitter theorem to prove lines parallel from ratios 2/5 and 3/7.

Open in simulator
Problem 32

Use the converse of the side-splitter theorem to prove lines parallel from FG/GH=7/14 and FI/IJ=3/6.

Problem 33

Use the converse of the side-splitter theorem to prove lines parallel from KL/LM=8/12 and KN/NO=10/15.

Problem 34

Use the converse of the side-splitter theorem to prove lines parallel from PX/XQ=9/3 and PY/YR=12/4.

Problem 35

Use the converse of the side-splitter theorem to prove lines parallel from ST/TU=15/5 and SV/VW=21/7.

Problem 36

Use the converse of the side-splitter theorem to prove lines parallel from AB/BC=5/8 and AD/DE=6/9.

Problem 37

Use the converse of the side-splitter theorem to prove lines parallel from PQ/QR=4/7 and PS/ST=5/8.

Problem 38

Use the converse of the side-splitter theorem to prove lines parallel from WX/XY=10/4 and WZ/ZA=12/5.

Problem 39

Use the converse of the side-splitter theorem to prove lines parallel from MN/NP=6/10 and MO/OQ=7/11.

connect angle bisector to opposite-side segment ratio.
15 problems Warmup Practice Mixed Review Assessment
Problem 40

Prove the angle bisector theorem for angle bisector AD in triangle ABC meets BC at D.

Problem 41

Prove the angle bisector theorem for angle bisector from A divides side BC.

Problem 42

Prove the angle bisector theorem for AD bisects angle A with D on BC.

Problem 43

Prove the angle bisector theorem for triangle with internal angle bisector.

Problem 44

Prove the angle bisector theorem for Triangle PQR with PS bisecting angle P, where S is on QR.

Open in simulator
Problem 45

Prove the angle bisector theorem for In ΔABC, the bisector of ∠A is AD, with D on BC.

Problem 46

Prove the angle bisector theorem for The angle bisector BE of triangle ABC, with E on AC.

Problem 47

Prove the angle bisector theorem for Angle bisector XY in triangle WXZ, where Y is on WZ.

Problem 48

Prove the angle bisector theorem for Given triangle DEF with angle bisector DG, D on EF.

Problem 49

Prove the angle bisector theorem for In ΔLMN, the angle bisector of ∠M is MO, O on LN.

Problem 50

Prove the angle bisector theorem for Triangle RST with angle bisector SU, U on RT.

Problem 51

Prove the angle bisector theorem for The segment bisecting an angle of a triangle, dividing the opposite side.

Problem 52

Prove the angle bisector theorem for A triangle ABC with an internal angle bisector AD.

Problem 53

Prove the angle bisector theorem for In ΔXYZ, YW is the bisector of ∠Y, with W on XZ.

Problem 54

Prove the angle bisector theorem for The line segment from vertex A bisecting angle A in triangle ABC, meeting BC at D.

set adjacent side ratio equal to divided side ratio.
12 problems Warmup Practice Mixed Review Assessment
Problem 55

Use the angle bisector theorem to find a missing segment from AB=6, AC=9, BD=4, DC=x.

Problem 56

Use the angle bisector theorem to find a missing segment from AB=10, AC=15, BD=x, DC=9.

Problem 57

Use the angle bisector theorem to find a missing segment from AB=8, AC=12, BD=2y, DC=9.

Problem 58

Use the angle bisector theorem to find a missing segment from AB=5, AC=7, BD=10, DC=x.

Problem 59

Use the angle bisector theorem to find a missing segment from AB=12, AC=18, BD=x, DC=6.

Problem 60

Use the angle bisector theorem to find a missing segment from AB=7, AC=14, BD=3, DC=x.

Problem 61

Use the angle bisector theorem to find a missing segment from AB=9, AC=12, BD=x, DC=8.

Problem 62

Use the angle bisector theorem to find a missing segment from AB=10, AC=8, BD=5, DC=x.

Problem 63

Use the angle bisector theorem to find a missing segment from AB=15, AC=20, BD=x, DC=12.

Open in simulator
Problem 64

Use the angle bisector theorem to find a missing segment from AB=12, AC=15, BD=4, DC=x.

Problem 65

Use the angle bisector theorem to find a missing segment from AB=6, AC=10, BD=x, DC=15.

Problem 66

Use the angle bisector theorem to find a missing segment from AB=14, AC=21, BD=6, DC=x.

identify three similar right triangles.
15 problems Warmup Practice Mixed Review Assessment
Problem 67

Prove altitude-to-hypotenuse similarity relationships for right triangle ABC with altitude CD to hypotenuse AB.

Problem 68

Prove altitude-to-hypotenuse similarity relationships for right triangle with altitude to hypotenuse.

Problem 69

Prove altitude-to-hypotenuse similarity relationships for triangle ABC right at C, altitude to AB.

Problem 70

Prove altitude-to-hypotenuse similarity relationships for altitude from right angle to hypotenuse.

Problem 71

Prove altitude-to-hypotenuse similarity relationships for triangle PQR, right-angled at Q, with altitude QS to hypotenuse PR.

Problem 72

Prove altitude-to-hypotenuse similarity relationships for a right triangle XYZ with the altitude from the right angle Y to the hypotenuse XZ, meeting at point W.

Open in simulator
Problem 73

Prove altitude-to-hypotenuse similarity relationships for right triangle DEF, where angle E is the right angle, and EG is the altitude to hypotenuse DF.

Problem 74

Prove altitude-to-hypotenuse similarity relationships for a right-angled triangle MNO, with the right angle at N, and NP is the altitude to the hypotenuse MO.

Problem 75

Prove altitude-to-hypotenuse similarity relationships for triangle JKL, right-angled at K, with altitude KM to JL.

Problem 76

Prove altitude-to-hypotenuse similarity relationships for a right triangle STU, with the right angle at T, and altitude TV to the hypotenuse SU.

Problem 77

Prove altitude-to-hypotenuse similarity relationships for right triangle RST, with right angle at S, and altitude SU to hypotenuse RT.

Problem 78

Prove altitude-to-hypotenuse similarity relationships for triangle VWX, with the right angle at W, and altitude WY to hypotenuse VX.

Problem 79

Prove altitude-to-hypotenuse similarity relationships for a right triangle with vertices P, Q, R, where angle Q is the right angle, and the altitude from Q meets PR at S.

Problem 80

Prove altitude-to-hypotenuse similarity relationships for a right triangle GHI, with the right angle at H, and HJ is the altitude to the hypotenuse GI.

Problem 81

Prove altitude-to-hypotenuse similarity relationships for triangle LMN, right-angled at M, with altitude MP to LN.

set proportions among similar right triangles.
15 problems Warmup Practice Mixed Review Assessment
Problem 82

Use right-triangle similarity to find a missing length from hypotenuse segments 4 and 9; altitude h.

Problem 83

Use right-triangle similarity to find a missing length from hypotenuse 25, leg projection 9; corresponding leg x.

Problem 84

Use right-triangle similarity to find a missing length from hypotenuse 16, leg projection 4; corresponding leg x.

Problem 85

Use right-triangle similarity to find a missing length from hypotenuse segments 5 and 20; altitude h.

Problem 86

Use right-triangle similarity to find a missing length from hypotenuse segments 2 and 8; altitude h.

Open in simulator
Problem 87

Use right-triangle similarity to find a missing length from hypotenuse segments 1 and 25; altitude h.

Problem 88

Use right-triangle similarity to find a missing length from hypotenuse segments 4 and 16; altitude h.

Problem 89

Use right-triangle similarity to find a missing length from hypotenuse segments 6 and 24; altitude h.

Problem 90

Use right-triangle similarity to find a missing length from hypotenuse segments 7 and 28; altitude h.

Problem 91

Use right-triangle similarity to find a missing length from hypotenuse 18, leg projection 2; corresponding leg x.

Problem 92

Use right-triangle similarity to find a missing length from hypotenuse 20, leg projection 5; corresponding leg x.

Problem 93

Use right-triangle similarity to find a missing length from hypotenuse 27, leg projection 3; corresponding leg x.

Problem 94

Use right-triangle similarity to find a missing length from hypotenuse 36, leg projection 4; corresponding leg x.

Problem 95

Use right-triangle similarity to find a missing length from hypotenuse 52, leg projection 13; corresponding leg x.

Problem 96

Use right-triangle similarity to find a missing length from hypotenuse 32, leg projection 8; corresponding leg x.

derive leg-square relationships and sum.
15 problems Warmup Practice Mixed Review Assessment
Problem 97

Prove the Pythagorean Theorem using similarity in right triangle with altitude to hypotenuse splitting it into segments x and y.

Problem 98

Prove the Pythagorean Theorem using similarity in right triangle ABC with altitude to hypotenuse.

Problem 99

Prove the Pythagorean Theorem using similarity in right triangle with hypotenuse c and legs a,b.

Problem 100

Prove the Pythagorean Theorem using similarity in similar smaller right triangles inside a right triangle.

Problem 101

Prove the Pythagorean Theorem using similarity in A right triangle where an altitude is drawn from the right angle to the hypotenuse.

Problem 102

Prove the Pythagorean Theorem using similarity in A right triangle with vertices P, Q, R, where Q is the right angle, and an altitude QS is drawn to the hypotenuse PR.

Problem 103

Prove the Pythagorean Theorem using similarity in A right triangle with legs 'l1' and 'l2', and hypotenuse 'h', with an altitude 'alt' to 'h'.

Open in simulator
Problem 104

Prove the Pythagorean Theorem using similarity in A right triangle whose hypotenuse is divided into segments 'm' and 'n' by the altitude from the right angle.

Problem 105

Prove the Pythagorean Theorem using similarity in A right triangle with sides a, b, c (c being the hypotenuse), and an altitude h to c.

Problem 106

Prove the Pythagorean Theorem using similarity in A right-angled triangle with the altitude drawn to its longest side.

Problem 107

Prove the Pythagorean Theorem using similarity in A right triangle divided into three similar triangles by an altitude to the hypotenuse.

Problem 108

Prove the Pythagorean Theorem using similarity in A right triangle where the altitude from the right angle vertex creates two smaller right triangles.

Problem 109

Prove the Pythagorean Theorem using similarity in A right triangle with legs 'x' and 'y', and hypotenuse 'z'. An altitude is dropped from the right angle to 'z'.

Problem 110

Prove the Pythagorean Theorem using similarity in A right triangle where the altitude to the hypotenuse divides the hypotenuse into two parts, say 'p' and 'q'.

Problem 111

Prove the Pythagorean Theorem using similarity in A right triangle with its hypotenuse as the base, and an altitude drawn from the right angle vertex to this base.

connect similar-triangle theorem to length calculation.
15 problems Warmup Practice Mixed Review Assessment
Problem 112

Use the Pythagorean Theorem after similarity reasoning for right triangle legs 9 and 12 after proving the triangle is right.

Problem 113

Use the Pythagorean Theorem after similarity reasoning for right triangle hypotenuse 13 and one leg 5.

Problem 114

Use the Pythagorean Theorem after similarity reasoning for similarity proves a ladder, wall, and ground make a right triangle with legs 6 and 8.

Problem 115

Use the Pythagorean Theorem after similarity reasoning for right triangle with leg 7 and hypotenuse 25.

Open in simulator
Problem 116

Use the Pythagorean Theorem after similarity reasoning for a triangle proven right by similarity with legs 8 and 15.

Problem 117

Use the Pythagorean Theorem after similarity reasoning for a right triangle identified through similarity with hypotenuse 17 and one leg 8.

Problem 118

Use the Pythagorean Theorem after similarity reasoning for a right triangle formed by a pole, its shadow, and the sun's ray, with legs 12 and 16 after similarity reasoning.

Problem 119

Use the Pythagorean Theorem after similarity reasoning for a right triangle confirmed by similarity with legs 10 and 24.

Problem 120

Use the Pythagorean Theorem after similarity reasoning for a right triangle whose status is established by similarity, with hypotenuse 26 and one leg 10.

Problem 121

Use the Pythagorean Theorem after similarity reasoning for a right triangle with legs 9 and 40, after similarity confirms the right angle.

Problem 122

Use the Pythagorean Theorem after similarity reasoning for a right triangle with hypotenuse 41 and one leg 9, where similarity reasoning proves it's a right triangle.

Problem 123

Use the Pythagorean Theorem after similarity reasoning for a right triangle with legs 1.5 and 2, confirmed by similarity.

Problem 124

Use the Pythagorean Theorem after similarity reasoning for a right triangle with hypotenuse 6.5 and one leg 2.5, whose right angle is established by similarity.

Problem 125

Use the Pythagorean Theorem after similarity reasoning for a right triangle with legs 5 and 10, after similarity confirms the right angle.

Problem 126

Use the Pythagorean Theorem after similarity reasoning for a right triangle with hypotenuse 10 and one leg 4, where similarity reasoning proves it's a right triangle.

organize similarity statements, proportions, and conclusions.
15 problems Warmup Practice Mixed Review Assessment
Problem 127

Complete the triangle-similarity theorem proof: DE parallel BC in triangle ABC gives triangle ADE similar to ABC.

Problem 128

Complete the triangle-similarity theorem proof: AD bisects angle A and auxiliary similarity is established.

Problem 129

Complete the triangle-similarity theorem proof: Altitude to hypotenuse creates three similar triangles.

Open in simulator
Problem 130

Complete the triangle-similarity theorem proof: Right-triangle similarity gives a^2=cx and b^2=cy.

Problem 131

Complete the triangle-similarity theorem proof: Vertical angles and alternate interior angles establish triangle ABE similar to CDE.

Problem 132

Complete the triangle-similarity theorem proof: An altitude to the hypotenuse of a right triangle divides it into two smaller triangles similar to the original and to each other.

Problem 133

Complete the triangle-similarity theorem proof: Two triangles have two pairs of proportional sides and the included angles are congruent.

Problem 134

Complete the triangle-similarity theorem proof: All three pairs of corresponding sides of two triangles are proportional.

Problem 135

Complete the triangle-similarity theorem proof: A line parallel to one side of a triangle intersects the other two sides, forming a smaller similar triangle.

Problem 136

Complete the triangle-similarity theorem proof: Intersecting chords AB and CD inside a circle form similar triangles APC and DPB.

Problem 137

Complete the triangle-similarity theorem proof: Two secants PAB and PCD from an external point P to a circle form similar triangles PAD and PCB.

Problem 138

Complete the triangle-similarity theorem proof: A secant PAB and a tangent PT from an external point P to a circle form similar triangles PAT and PTB.

Problem 139

Complete the triangle-similarity theorem proof: The ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.

Problem 140

Complete the triangle-similarity theorem proof: A segment connecting the midpoints of two sides of a triangle is parallel to the third side and half its length.

Problem 141

Complete the triangle-similarity theorem proof: Two triangles are similar by AA criterion, allowing for calculation of unknown side lengths.

classify side-splitter, angle bisector, right-triangle similarity, or Pythagorean proof.
15 problems Warmup Practice Mixed Review Assessment
Problem 142

Choose the similarity theorem needed for parallel segment cuts two sides of a triangle.

Problem 143

Choose the similarity theorem needed for angle bisector divides the opposite side.

Problem 144

Choose the similarity theorem needed for altitude from right angle to hypotenuse.

Problem 145

Choose the similarity theorem needed for prove a^2+b^2=c^2 from similar right triangles.

Problem 146

Choose the similarity theorem needed for three parallel lines cut by two transversals.

Problem 147

Choose the similarity theorem needed for a segment connecting the midpoints of two sides of a triangle.

Problem 148

Choose the similarity theorem needed for an altitude drawn to the hypotenuse of a right triangle.

Problem 149

Choose the similarity theorem needed for a leg of a right triangle and its projection onto the hypotenuse.

Problem 150

Choose the similarity theorem needed for two triangles with two corresponding angles congruent.

Problem 151

Choose the similarity theorem needed for two triangles with two corresponding sides proportional and the included angles congruent.

Problem 152

Choose the similarity theorem needed for two triangles with all three corresponding sides proportional.

Problem 153

Choose the similarity theorem needed for an exterior angle bisector of a triangle.

Problem 154

Choose the similarity theorem needed for a line dividing two sides of a triangle proportionally.

Open in simulator
Problem 155

Choose the similarity theorem needed for two triangles with vertical angles and parallel bases.

Problem 156

Choose the similarity theorem needed for two right triangles sharing an acute angle.

catch wrong proportion, wrong correspondence, or theorem misuse.
15 problems Warmup Practice Mixed Review Assessment
Problem 157

Correct the similarity-theorem error: A student uses side-splitter theorem with no parallel segment.

Open in simulator
Problem 158

Correct the similarity-theorem error: A student sets AB/BD=AC/DC for an angle bisector problem.

Problem 159

Correct the similarity-theorem error: A student uses altitude geometric mean h=(p+q)/2.

Problem 160

Correct the similarity-theorem error: A student mismatches corresponding sides in similar triangles.

Problem 161

Correct the similarity-theorem error: A student claims two triangles are similar by AA similarity after showing only one pair of angles congruent.

Problem 162

Correct the similarity-theorem error: A student attempts to use SAS similarity but the given angle is not between the two proportional sides.

Problem 163

Correct the similarity-theorem error: A student concludes SSS similarity after finding only two pairs of corresponding sides are proportional.

Problem 164

Correct the similarity-theorem error: A student applies the Triangle Proportionality Theorem without confirming the segment is parallel to the third side.

Problem 165

Correct the similarity-theorem error: A student sets up a proportion for similar triangles as side1_T1/side2_T1 = side1_T2/side2_T2.

Problem 166

Correct the similarity-theorem error: A student uses the leg rule in a right triangle as leg^2 = hypotenuse * (non-adjacent segment).

Problem 167

Correct the similarity-theorem error: A student assumes that if two triangles are similar, their corresponding sides must be equal in length.

Problem 168

Correct the similarity-theorem error: A student uses the converse of the Triangle Proportionality Theorem to conclude segments are proportional because lines are parallel.

Problem 169

Correct the similarity-theorem error: A student claims two triangles are similar because they share a common angle, without any other conditions.

Problem 170

Correct the similarity-theorem error: A student calculates the ratio of the areas of two similar triangles by finding the ratio of their perimeters.

Problem 171

Correct the similarity-theorem error: A student attempts to prove similarity using the Angle-Side-Angle (ASA) congruence theorem.