Math II · N-CN.9

Knowing the Fundamental Theorem of Algebra and Verifying It for Quadratics

The Fundamental Theorem of Algebra gives students the full root-count map: polynomial equations have all their roots when complex numbers are allowed.

Concept Number and Quantity
Domain The Complex Number System
Read time 8 minutes

What this learning objective is really asking you to learn

This objective asks students to know one of the biggest organizing facts in algebra: the Fundamental Theorem of Algebra. In student-friendly language, the theorem says that every nonconstant polynomial has at least one complex root. A related classroom version says that a polynomial of degree \(n\) has exactly \(n\) complex roots when roots are counted with multiplicity.

For Math II, the focus is not proving the theorem in full. The full proof is far beyond a standard high-school algebra course. The focus is understanding what the theorem means and verifying it for quadratic polynomials. A quadratic has degree 2, so the theorem says it should have two complex roots when repeated roots are counted.

This matches what students already know. A quadratic can have two real roots, one repeated real root, or two nonreal complex roots. For example, \(x^2 - 5x + 6 = 0\) has two real roots: 2 and 3. The equation \(x^2 - 4x + 4 = 0\) has one visible root, 2, but it is a repeated root because the polynomial factors as \((x - 2)^2\). Counting multiplicity, there are two roots: 2 and 2. The equation \(x^2 + 4 = 0\) has two complex roots: 2i and -2i.

So the quadratic case verifies the pattern. Degree 2 means two roots, but the roots may be real, repeated, or complex. The discriminant tells which case occurs. Positive discriminant gives two real roots. Zero discriminant gives one repeated real root. Negative discriminant gives two nonreal complex conjugate roots.

The objective is also asking students to connect roots and factors. If \(r\) is a root of a polynomial, then \((x - r)\) is a factor. A quadratic with roots r1 and r2 can be written as \(a(x - r1)(x - r2)\) for some nonzero leading coefficient \(a\). Complex numbers make this factorization complete.

This is a big conceptual upgrade. Students are not merely solving individual equations. They are learning the root-count architecture of polynomial algebra.

Why students should learn this math

Students should learn the Fundamental Theorem of Algebra because it gives the big map of polynomial equations. Without it, roots may feel unpredictable. Sometimes a polynomial factors, sometimes it does not. Sometimes a graph crosses the x-axis, sometimes it does not. Sometimes the quadratic formula gives real answers, sometimes it gives complex answers. The theorem says there is order underneath: complex numbers provide enough room for polynomial roots to exist completely.

This theorem also helps students understand why complex numbers matter. Complex numbers are not a strange side invention used only for a few awkward quadratics. They are the number system in which polynomial equations have their full root structure. The theorem is one of the strongest reasons complex numbers are central in algebra.

For quadratics, the theorem gives a satisfying conclusion to the course arc. Students learned factoring, completing the square, the quadratic formula, discriminants, graph interpretation, and complex numbers. The Fundamental Theorem of Algebra ties those pieces together. A quadratic graph may have zero, one, or two real x-intercepts, but algebraically the degree-2 polynomial has two complex roots counted with multiplicity.

This matters in later mathematics and science because roots control behavior. Polynomial roots reveal where expressions are zero. In applied settings, zeros can represent equilibrium, break-even points, resonance conditions, stability thresholds, time of impact, or system states. In advanced mathematics, roots and factors are used to analyze functions, solve equations, decompose systems, and understand transformations.

The theorem also teaches a philosophical lesson about mathematical completion. Earlier number systems leave gaps. Complex numbers close a major algebraic gap. This does not mean complex numbers solve every possible problem in mathematics, but for polynomial roots, they provide a complete setting. That is a powerful idea for students: a number system can be judged by what kinds of equations it can solve.

The “why” is that the theorem gives students a root-count guarantee. It turns polynomial solving from a collection of cases into a coherent system.

The historical machinery: why this theorem mattered

The Fundamental Theorem of Algebra developed over centuries as mathematicians studied polynomial equations. Solving linear and quadratic equations was known in ancient forms. Cubic and quartic equations were solved later by algebraic formulas. But the general behavior of polynomial roots remained a deep question.

Mathematicians gradually realized that complex numbers were necessary for a complete theory. A polynomial might not have all its roots in the real numbers, but when complex numbers were allowed, the root structure became complete. Carl Friedrich Gauss gave important proofs of the Fundamental Theorem of Algebra, though the history includes several mathematicians and refinements over time.

The theorem's name can be confusing. It is called “fundamental” because it is foundational for algebra, but its proof usually requires tools from analysis or topology, not just elementary algebra. High-school students are not expected to prove it fully. They are expected to understand its meaning and verify it in accessible cases, especially quadratics.

The historical importance is enormous. The theorem says that complex numbers are algebraically closed with respect to polynomial equations. In simpler terms, if you build a polynomial equation using complex numbers, its roots can be found within the complex number system. You do not need to invent an even larger number system just to solve polynomials. That is a remarkable closure property.

For students, the quadratic case is the visible entry point. The quadratic formula always produces roots if complex square roots are allowed. That small case reflects the larger theorem.

Where this fits in the big map of mathematics

This objective sits at the end of the Math II complex-number block. Objective 114 introduced \(i\). Objective 115 taught complex arithmetic. Objective 116 used complex numbers to solve quadratics. Objective 117 extended polynomial identities to complex factors. Objective 118 states the theorem that explains why this all matters.

It connects to polynomial degree. The degree of a polynomial predicts the number of complex roots when multiplicity is counted. A quadratic has degree 2. A cubic has degree 3. A fourth-degree polynomial has degree 4. Students should not yet expect to solve all higher-degree polynomials, but they can understand the root-count principle.

It connects to graphing. A real polynomial's graph shows real roots as x-intercepts. But the graph does not show nonreal complex roots as ordinary x-intercepts. The theorem reminds students that the graph is only part of the root story.

It connects to factoring. If all roots are known, a polynomial can be expressed as a product of linear factors over the complex numbers. This is a central algebraic idea.

It connects to advanced algebra and calculus. Roots and factors are used in polynomial division, rational functions, limits, derivatives, integrals, and differential equations. The theorem supports a huge amount of later structure.

The big-map role is unification. Polynomial roots, complex numbers, degree, factors, and graph behavior become part of one system.

How to execute the skill technically

For quadratics, verification means showing that a degree-2 polynomial has two roots when counted correctly.

Case 1: two distinct real roots.

\[x^2 - 5x + 6 = 0\]

Factor:

\[(x - 2)(x - 3) = 0\].

The roots are 2 and 3. There are two roots.

Case 2: one repeated real root.

\[x^2 - 6x + 9 = 0\]

Factor:

\[(x - 3)^2 = 0\].

The root is 3, but it occurs twice. Counting multiplicity, the roots are 3 and 3. There are two roots.

Case 3: two nonreal complex roots.

\[x^2 + 4 = 0\]

Then

\[x^2 = -4\]

so

\[x = ±2i\].

The roots are 2i and -2i. There are two roots.

Students can also use the discriminant. For \(ax^2 + bx + c = 0\), the discriminant \(D = b^2 - 4ac\) determines the type of roots. But in all three cases, the quadratic formula produces two roots counted with multiplicity:

\[x = (-b ± \sqrt{D}) / (2a)\].

If \(D > 0\), the two roots are real and different. If \(D = 0\), the plus and minus versions are the same, creating a repeated root. If \(D < 0\), the square root is imaginary, creating two complex conjugates.

A worked example: verify the theorem for \(2x^2 + 4x + 10 = 0\).

The discriminant is

\[D = 4^2 - 4(2)(10) = 16 - 80 = -64\].

The roots are

\[x = (-4 ± \sqrt{-64}) / 4 = (-4 ± 8i) / 4 = -1 ± 2i\].

The polynomial has degree 2 and two complex roots: \(-1 + 2i\) and \(-1 - 2i\). This verifies the theorem for this quadratic.

Multiplicity: the counting idea students usually miss

The most common confusion with the Fundamental Theorem of Algebra is multiplicity. A student sees \(x^2 - 6x + 9 = 0\), factors it as \((x - 3)^2 = 0\), and says, “There is only one answer, so the theorem is wrong.” The theorem is not wrong. The root 3 occurs twice because the factor \((x - 3)\) appears twice.

Multiplicity matters because roots are not only a list of distinct numbers; they also describe factor structure. The polynomial \((x - 3)^2\) has degree 2 because it has two linear factors, even though those factors are identical. Graphically, this is why the parabola touches the x-axis at \(x = 3\) instead of crossing through it. The repeated root changes the graph behavior.

For a quadratic, there are always two roots counted with multiplicity:

  • two different real roots, such as 2 and 5;
  • one repeated real root, such as 3 and 3;
  • two nonreal complex conjugates, such as \(-1 + 2i\) and \(-1 - 2i\).

This is the simplest way for students to understand the theorem without needing a full proof.

Why the theorem is a map, not a procedure

The Fundamental Theorem of Algebra does not tell students an easy method for finding every root. It tells them what kind of result to expect. That difference is important. A map does not walk for you, but it tells you what territory exists. The theorem tells students that if they are working over the complex numbers, a degree \(n\) polynomial has \(n\) roots counted with multiplicity.

That expectation helps students check their work. If a quadratic has only one listed root, ask whether it is repeated. If a cubic has one real root, expect two more roots, possibly complex. If a fourth-degree polynomial factors into two quadratics, each quadratic contributes two roots over the complex numbers. The theorem gives structure before technique.

Common misconceptions and how to avoid them

One misconception is thinking the theorem says every polynomial has real roots. It does not. It says complex roots.

Another mistake is forgetting multiplicity. The equation \((x - 4)^2 = 0\) has one distinct root, but it counts twice.

A third mistake is expecting complex roots to show up as x-intercepts. Real roots show as x-intercepts on a real graph. Nonreal roots do not.

A fourth mistake is thinking the theorem provides a simple formula for all roots. It does not. It guarantees existence and count, but finding roots can still be hard.

A fifth mistake is separating the theorem from factoring. Roots and linear factors are linked. If \(r\) is a root, then \((x - r)\) is a factor.

The big takeaway

The Fundamental Theorem of Algebra gives the big root-count map: a degree \(n\) polynomial has \(n\) complex roots when multiplicity is counted. For quadratics, students can verify this directly using factoring, the quadratic formula, and complex numbers. The theorem explains why complex numbers matter: they complete the root structure of polynomial algebra.

Problem Library

Problems in the App From This Objective

174 problems across 12 archetypes in the app.

apply Fundamental Theorem of Algebra to degree 2.
15 problems Warmup Practice Mixed Review Assessment
Problem 1

State how many complex roots quadratic x^2-5x+6 has counting multiplicity.

Problem 2

State how many complex roots quadratic x^2-4x+4 has counting multiplicity.

Problem 3

State how many complex roots quadratic x^2+9 has counting multiplicity.

Open in simulator
Problem 4

State how many complex roots quadratic 2x^2+3x+7 has counting multiplicity.

Problem 5

State how many complex roots quadratic x^2 - x - 2 has counting multiplicity.

Problem 6

State how many complex roots quadratic x^2 + 6x + 9 has counting multiplicity.

Problem 7

State how many complex roots quadratic x^2 + 4 has counting multiplicity.

Problem 8

State how many complex roots quadratic x^2 - 7x + 10 has counting multiplicity.

Problem 9

State how many complex roots quadratic 4x^2 - 4x + 1 has counting multiplicity.

Problem 10

State how many complex roots quadratic x^2 - 2x + 5 has counting multiplicity.

Problem 11

State how many complex roots quadratic x^2 - 16 has counting multiplicity.

Problem 12

State how many complex roots quadratic x^2 has counting multiplicity.

Problem 13

State how many complex roots quadratic x^2 + x + 1 has counting multiplicity.

Problem 14

State how many complex roots quadratic 3x^2 + 5x - 2 has counting multiplicity.

Problem 15

State how many complex roots quadratic 5x^2 - 2x + 1 has counting multiplicity.

evaluate polynomial at proposed roots.
15 problems Warmup Practice Mixed Review Assessment
Problem 16

Verify proposed root 2 of quadratic x^2-5x+6 by substitution.

Problem 17

Verify proposed root 3i of quadratic x^2+9 by substitution.

Problem 18

Verify proposed root 1+2i of quadratic x^2-2x+5 by substitution.

Open in simulator
Problem 19

Verify proposed root 4 of quadratic x^2-4x+8 by substitution.

Problem 20

Verify proposed root -1 of quadratic x^2+2x+1 by substitution.

Problem 21

Verify proposed root 5 of quadratic x^2-10x+25 by substitution.

Problem 22

Verify proposed root 1 of quadratic x^2+x+1 by substitution.

Problem 23

Verify proposed root 2i of quadratic x^2+4 by substitution.

Problem 24

Verify proposed root -2i of quadratic x^2+4 by substitution.

Problem 25

Verify proposed root i of quadratic x^2-1 by substitution.

Problem 26

Verify proposed root 1-2i of quadratic x^2-2x+5 by substitution.

Problem 27

Verify proposed root 1 of quadratic 2x^2-3x+1 by substitution.

Problem 28

Verify proposed root 2 of quadratic 3x^2-5x+1 by substitution.

Problem 29

Verify proposed root 1+i of quadratic x^2+x+1 by substitution.

Problem 30

Verify proposed root -3 of quadratic x^2+6x+9 by substitution.

multiply factors and compare polynomial.
15 problems Warmup Practice Mixed Review Assessment
Problem 31

Verify factorization from roots 2, 3 for quadratic x^2-5x+6.

Problem 32

Verify factorization from roots 1+2i, 1-2i for quadratic x^2-2x+5.

Problem 33

Verify factorization from roots -4, -4 for quadratic x^2+8x+16.

Open in simulator
Problem 34

Verify factorization from roots i, -i for quadratic 2x^2+2.

Problem 35

Verify factorization from roots -1, 5 for quadratic 3x^2-12x-15.

Problem 36

Verify factorization from roots 3, 3 for quadratic -2x^2+12x-18.

Problem 37

Verify factorization from roots 2+i, 2-i for quadratic 4x^2-16x+20.

Problem 38

Verify factorization from roots 0, 7 for quadratic x^2-7x.

Problem 39

Verify factorization from roots 0, -6 for quadratic -5x^2-30x.

Problem 40

Verify factorization from roots 1/2, -3 for quadratic x^2+5/2x-3/2.

Problem 41

Verify factorization from roots 1/3, 2/3 for quadratic 9x^2-9x+2.

Problem 42

Verify factorization from roots 1+sqrt(2), 1-sqrt(2) for quadratic x^2-2x-1.

Problem 43

Verify factorization from roots 3+sqrt(5), 3-sqrt(5) for quadratic -x^2+6x-4.

Problem 44

Verify factorization from roots 3i, -3i for quadratic x^2+9.

Problem 45

Verify factorization from roots -2, -5 for quadratic x^2+7x+10.

connect squared factor to multiplicity 2.
15 problems Warmup Practice Mixed Review Assessment
Problem 46

Identify multiplicity of repeated root in (x-3)^2.

Problem 47

Identify multiplicity of repeated root in 2(x+5)^2.

Problem 48

Identify multiplicity of repeated root in (x-i)^2.

Problem 49

Identify multiplicity of repeated root in (x-4)(x+1).

Problem 50

Identify multiplicity of repeated root in (x+7)^2.

Problem 51

Identify multiplicity of repeated root in -3(x-1)^2.

Problem 52

Identify multiplicity of repeated root in (x - 1/2)^2.

Problem 53

Identify multiplicity of repeated root in (x + 2.5)^2.

Problem 54

Identify multiplicity of repeated root in (x - sqrt(2))^2.

Problem 55

Identify multiplicity of repeated root in (x - (1+i))^2.

Problem 56

Identify multiplicity of repeated root in (2x - 4)^2.

Problem 57

Identify multiplicity of repeated root in (3x + 9)^2.

Open in simulator
Problem 58

Identify multiplicity of repeated root in (x+6)(x-2).

Problem 59

Identify multiplicity of repeated root in -5(x + 3/4)^2.

Problem 60

Identify multiplicity of repeated root in (x + 2i)^2.

classify roots and multiplicity.
15 problems Warmup Practice Mixed Review Assessment
Problem 61

Use discriminant 16 to classify roots while preserving total count.

Problem 62

Use discriminant 0 to classify roots while preserving total count.

Problem 63

Use discriminant -25 to classify roots while preserving total count.

Problem 64

Use discriminant 5 to classify roots while preserving total count.

Problem 65

Use discriminant 1 to classify roots while preserving total count.

Problem 66

Use discriminant 4 to classify roots while preserving total count.

Open in simulator
Problem 67

Use discriminant 9 to classify roots while preserving total count.

Problem 68

Use discriminant 36 to classify roots while preserving total count.

Problem 69

Use discriminant 2 to classify roots while preserving total count.

Problem 70

Use discriminant 3 to classify roots while preserving total count.

Problem 71

Use discriminant 6 to classify roots while preserving total count.

Problem 72

Use discriminant 7 to classify roots while preserving total count.

Problem 73

Use discriminant -1 to classify roots while preserving total count.

Problem 74

Use discriminant -4 to classify roots while preserving total count.

Problem 75

Use discriminant -9 to classify roots while preserving total count.

use conjugate root relationship.
15 problems Warmup Practice Mixed Review Assessment
Problem 76

Find the missing root of a real-coefficient quadratic when one root is 3+4i.

Problem 77

Find the missing root of a real-coefficient quadratic when one root is -2-5i.

Problem 78

Find the missing root of a real-coefficient quadratic when one root is 7i.

Problem 79

Find the missing root of a real-coefficient quadratic when one root is 6.

Problem 80

Find the missing root of a real-coefficient quadratic when one root is 5-2i.

Problem 81

Find the missing root of a real-coefficient quadratic when one root is -1+3i.

Problem 82

Find the missing root of a real-coefficient quadratic when one root is -4-i.

Problem 83

Find the missing root of a real-coefficient quadratic when one root is 1+i.

Problem 84

Find the missing root of a real-coefficient quadratic when one root is -9i.

Problem 85

Find the missing root of a real-coefficient quadratic when one root is i/2.

Problem 86

Find the missing root of a real-coefficient quadratic when one root is -10.

Problem 87

Find the missing root of a real-coefficient quadratic when one root is 0.

Open in simulator
Problem 88

Find the missing root of a real-coefficient quadratic when one root is 1/3.

Problem 89

Find the missing root of a real-coefficient quadratic when one root is 100+200i.

Problem 90

Find the missing root of a real-coefficient quadratic when one root is 2-6i.

multiply linear factors.
15 problems Warmup Practice Mixed Review Assessment
Problem 91

Build a quadratic from roots 2, 5.

Problem 92

Build a quadratic from roots -3, -3.

Problem 93

Build a quadratic from roots 1+2i, 1-2i.

Problem 94

Build a quadratic from roots 3i, -3i.

Problem 95

Build a quadratic from roots 1, -2.

Problem 96

Build a quadratic from roots 0, 4.

Problem 97

Build a quadratic from roots -1, -5.

Problem 98

Build a quadratic from roots 1/2, 3/2.

Problem 99

Build a quadratic from roots -1/3, 2/3.

Problem 100

Build a quadratic from roots sqrt(2), -sqrt(2).

Problem 101

Build a quadratic from roots 1+sqrt(3), 1-sqrt(3).

Problem 102

Build a quadratic from roots 2+i, 2-i.

Problem 103

Build a quadratic from roots i, -i.

Problem 104

Build a quadratic from roots sqrt(5), sqrt(5).

Problem 105

Build a quadratic from roots -1+i, -1-i.

Open in simulator
compare degree, roots, and multiplicity.
12 problems Warmup Practice Mixed Review Assessment
Problem 106

Determine whether claimed root list 2 only, multiplicity not stated satisfies FTA for polynomial quadratic x^2-4x+4.

Problem 107

Determine whether claimed root list 3i and -3i satisfies FTA for polynomial quadratic x^2+9.

Problem 108

Determine whether claimed root list 2, 3, 4 satisfies FTA for polynomial quadratic x^2-5x+6.

Problem 109

Determine whether claimed root list 1+2i only satisfies FTA for polynomial quadratic x^2-2x+5.

Open in simulator
Problem 110

Determine whether claimed root list 5 satisfies FTA for polynomial linear x-5.

Problem 111

Determine whether claimed root list 1 and -1 satisfies FTA for polynomial cubic x^3-x^2-x+1.

Problem 112

Determine whether claimed root list 0, i, and -i satisfies FTA for polynomial cubic x^3+x.

Problem 113

Determine whether claimed root list 2, -2, and 2i satisfies FTA for polynomial quartic x^4-16.

Problem 114

Determine whether claimed root list -3 with multiplicity 2 satisfies FTA for polynomial quadratic x^2+6x+9.

Problem 115

Determine whether claimed root list 1, 2, 3, 4 satisfies FTA for polynomial cubic x^3-6x^2+11x-6.

Problem 116

Determine whether claimed root list 1 with multiplicity 4 satisfies FTA for polynomial quartic (x-1)^4.

Problem 117

Determine whether claimed root list 1 only satisfies FTA for polynomial quadratic x^2-1.

distinguish real visible zeros from nonreal roots.
15 problems Warmup Practice Mixed Review Assessment
Problem 118

Interpret graph x-intercepts versus complex roots for parabola crosses the x-axis at x=2 and x=5.

Problem 119

Interpret graph x-intercepts versus complex roots for parabola touches the x-axis at x=3.

Problem 120

Interpret graph x-intercepts versus complex roots for parabola does not cross the x-axis.

Problem 121

Interpret graph x-intercepts versus complex roots for parabola crosses once and opens upward.

Problem 122

Interpret graph x-intercepts versus complex roots for parabola crosses the x-axis at x=-1 and x=4.

Problem 123

Interpret graph x-intercepts versus complex roots for the quadratic graph intersects the x-axis at x=0 and x=7.

Problem 124

Interpret graph x-intercepts versus complex roots for the graph of the quadratic equation is tangent to the x-axis at x=-5.

Problem 125

Interpret graph x-intercepts versus complex roots for the parabola touches the x-axis exactly at x=1/2.

Problem 126

Interpret graph x-intercepts versus complex roots for the parabola opens upward and its vertex is above the x-axis.

Problem 127

Interpret graph x-intercepts versus complex roots for the parabola opens downward and its vertex is below the x-axis.

Problem 128

Interpret graph x-intercepts versus complex roots for the quadratic function has x-intercepts at x=-3 and x=6.

Open in simulator
Problem 129

Interpret graph x-intercepts versus complex roots for the graph touches the x-axis at x=0.

Problem 130

Interpret graph x-intercepts versus complex roots for the quadratic's graph never intersects the x-axis.

Problem 131

Interpret graph x-intercepts versus complex roots for the quadratic has two distinct x-intercepts.

Problem 132

Interpret graph x-intercepts versus complex roots for the quadratic has no x-intercepts.

solve or factor and count multiplicity.
15 problems Warmup Practice Mixed Review Assessment
Problem 133

Verify quadratic x^2-6x+9 has exactly two roots over complex numbers.

Problem 134

Verify quadratic x^2+4 has exactly two roots over complex numbers.

Problem 135

Verify quadratic x^2-5x+6 has exactly two roots over complex numbers.

Problem 136

Verify quadratic 2x^2+8 has exactly two roots over complex numbers.

Problem 137

Verify quadratic x^2 - x - 2 has exactly two roots over complex numbers.

Problem 138

Verify quadratic 3x^2 + 5x + 2 has exactly two roots over complex numbers.

Problem 139

Verify quadratic x^2 - 2x + 1 has exactly two roots over complex numbers.

Problem 140

Verify quadratic 4x^2 - 4x + 1 has exactly two roots over complex numbers.

Problem 141

Verify quadratic x^2 + 1 has exactly two roots over complex numbers.

Open in simulator
Problem 142

Verify quadratic x^2 + 2x + 2 has exactly two roots over complex numbers.

Problem 143

Verify quadratic x^2 - 4x + 5 has exactly two roots over complex numbers.

Problem 144

Verify quadratic x^2 - 4x + 2 has exactly two roots over complex numbers.

Problem 145

Verify quadratic -x^2 + 2x - 1 has exactly two roots over complex numbers.

Problem 146

Verify quadratic 3x^2 + 12 has exactly two roots over complex numbers.

Problem 147

Verify quadratic 2x^2 + 2x + 1 has exactly two roots over complex numbers.

connect negative discriminants to imaginary roots.
15 problems Warmup Practice Mixed Review Assessment
Problem 148

Explain why complex numbers make quadratic a quadratic with negative discriminant solvable.

Problem 149

Explain why complex numbers make quadratic x^2+1=0 solvable.

Problem 150

Explain why complex numbers make quadratic any real-coefficient quadratic solvable.

Open in simulator
Problem 151

Explain why complex numbers make quadratic x^2 + 4 = 0 solvable.

Problem 152

Explain why complex numbers make quadratic a quadratic with no real roots solvable.

Problem 153

Explain why complex numbers make quadratic a quadratic where the discriminant is negative solvable.

Problem 154

Explain why complex numbers make quadratic x^2 - 2x + 5 = 0 solvable.

Problem 155

Explain why complex numbers make quadratic any quadratic equation solvable.

Problem 156

Explain why complex numbers make quadratic a quadratic whose graph does not intersect the x-axis solvable.

Problem 157

Explain why complex numbers make quadratic a quadratic whose discriminant is a negative real number solvable.

Problem 158

Explain why complex numbers make quadratic a quadratic that would otherwise have no solution in real numbers solvable.

Problem 159

Explain why complex numbers make quadratic 2x^2 + x + 1 = 0 solvable.

Problem 160

Explain why complex numbers make quadratic a quadratic whose discriminant makes the quadratic formula problematic over real numbers solvable.

Problem 161

Explain why complex numbers make quadratic a quadratic with non-real solutions solvable.

Problem 162

Explain why complex numbers make quadratic a quadratic that historically posed a problem for real numbers solvable.

catch missing multiplicity, ignoring complex roots, or graph-only reasoning.
12 problems Warmup Practice Mixed Review Assessment
Problem 163

Correct the FTA or root-counting error in x^2+9=0 has no roots.

Problem 164

Correct the FTA or root-counting error in (x-4)^2=0 has one root, so the quadratic has only one root counting multiplicity.

Problem 165

Correct the FTA or root-counting error in A quadratic with negative discriminant violates the Fundamental Theorem of Algebra.

Problem 166

Correct the FTA or root-counting error in A graph with no x-intercepts means the quadratic has no roots at all.

Problem 167

Correct the FTA or root-counting error in The equation x^2 + 25 = 0 has no real solutions, so it has no solutions.

Open in simulator
Problem 168

Correct the FTA or root-counting error in The polynomial (x+2)^2 = 0 is degree 2 but only has one root.

Problem 169

Correct the FTA or root-counting error in A polynomial of degree 3 can have at most 1 root if its graph only crosses the x-axis once.

Problem 170

Correct the FTA or root-counting error in The quadratic x^2 - 4x + 13 = 0 has no real roots, so it has no roots.

Problem 171

Correct the FTA or root-counting error in The equation (x-1)^3 = 0 has only one root.

Problem 172

Correct the FTA or root-counting error in The polynomial x^4 - 1 = 0 has only two real roots, so it has only two roots in total.

Problem 173

Correct the FTA or root-counting error in A polynomial of degree N can have fewer than N roots if some are not real.

Problem 174

Correct the FTA or root-counting error in If a cubic polynomial's graph crosses the x-axis only once, it only has one root.