Math II · S-CP.5

Explaining Conditional Probability and Independence in Everyday Language

Students need probability language they can use outside worksheets: evidence changes risk unless the events are independent.

Concept Statistics and Probability
Domain Conditional Probability and the Rules of Probability
Read time 7 minutes

What this learning objective is really asking you to learn

This objective asks students to translate probability notation into ordinary language and ordinary situations into probability language. It is not enough to calculate \(P(A | B)\) or test whether \(P(A \cap B) = P(A)P(B)\). Students must be able to say what those expressions mean in a human sentence. Conditional probability and independence are not just formulas; they are ways of reasoning about information.

Conditional probability means probability after a condition is known. The expression \(P(A | B)\) means “the probability of A given B.” The event after the vertical bar is the condition. It tells us the group or situation we are looking inside. For example, \(P(pass | studied)\) means “the probability a student passes given that the student studied.” It does not mean the probability a student studied given that the student passed. Those are different questions.

Independence means one event does not change the probability of another. If A and B are independent, then knowing B occurred does not change the probability of A. In notation,

\[P(A | B) = P(A)\]

when \(P(B) \ne 0\). This is the everyday-language heart of independence. The event B gives no probability information about event A.

For example, if a fair coin is flipped and a fair die is rolled, knowing the coin landed heads does not change the probability that the die shows 6. Those events are independent. But knowing a card is a face card changes the probability that it is a king. Those events are not independent.

This objective is asking students to become probability translators. They should be able to move between notation, tables, Venn diagrams, and words. They should be able to say, “Among the students who studied, 80% passed,” or “Knowing the student studied changes the probability of passing, so these events are not independent.” This is the kind of probability literacy people actually use in life.

Why students should learn this math

Students should learn this because most probability claims in real life are not presented as clean formulas. They appear as sentences: “People who exercise are less likely to develop this condition,” “Customers who use the feature are more likely to renew,” “Students who complete the review do better on the test,” “A positive test means a higher chance of disease,” “Rain increases the chance of traffic delays.” To understand or challenge those claims, students need to translate them into conditional probability.

This matters because everyday language is often vague. “More likely” than what? Among which group? Compared with which baseline? Conditional probability forces the denominator to be clear. If someone says “30% of people with symptom X have condition Y,” that is \(P(condition Y | symptom X)\). If someone says “80% of people with condition Y have symptom X,” that is \(P(symptom X | condition Y)\). These are not the same. Confusing them can lead to bad medical, legal, financial, and personal decisions.

Independence is equally important. People often assume events are independent when they are not. If a factory produces several defective parts in a row, the next part may not be independent if the same machine setting is causing the defect. If several students in the same class miss the same problem, their errors may not be independent because they may have received the same confusing instruction. If two apps fail during the same outage, the failures are not independent. Hidden common causes create dependence.

People also assume dependence when events are independent. A fair coin does not become “due” for tails after several heads. A fair die does not remember past rolls. This misconception causes poor gambling decisions and mistaken predictions. Independence is a claim about probability structure, not about emotional expectation.

The “why” is that conditional probability and independence are the grammar of evidence. They help students ask: What information do we have? What group are we focusing on? Does this information change the probability? Is the change meaningful? Is it causal, or merely associated? This is the kind of reasoning students need to evaluate claims in news, health, business, education, and technology.

The historical machinery: probability becomes a language of evidence

Probability began with games of chance, but it became far more important when people used it to reason about uncertain evidence. In gambling, independence is often built into the model: one fair die roll does not affect the next. But in medicine, law, science, and statistics, the key question is usually conditional: how should new information change what we believe?

Conditional probability is the foundation of Bayesian reasoning, medical testing, risk modeling, and many statistical methods. The notation may look modern and compact, but the underlying question is ancient: given what we know now, what should we expect?

Independence became formal because mathematicians needed a precise way to say that one event provides no information about another. Ordinary language like “unrelated” or “does not affect” is too vague. The probability definition gives a test: if conditioning on B leaves the probability of A unchanged, then A and B are independent.

This historical development matters for students because it shows that probability is not just about games. It is a disciplined language for evidence. Conditional probability tells how probabilities update. Independence tells when they do not.

Where this fits in the big map of mathematics

This objective follows the formal introduction of conditional probability and independence. Objectives 123 and 124 introduced the equations and tests. Objective 125 showed how two-way tables organize the data. Objective 126 asks students to interpret all of that in everyday language.

It connects to statistics because data interpretation requires language. A student may compute a conditional percentage correctly but still fail if they describe it backward. For example, \(P(A | B)\) and \(P(B | A)\) often have different meanings and different values. Translation is part of mastery.

It connects to modeling because probability statements represent real situations. The events must be defined clearly. The sample space must be known. The condition must be identified.

It connects to decision-making because conditional probabilities often guide action. A doctor, teacher, coach, product manager, or public official rarely needs a formula alone. They need a sentence that can support a decision.

It connects forward to the general multiplication rule and Addition Rule. Those rules are easier to remember when students understand the event language behind them.

The big-map role is interpretation. Probability formulas become useful only when students can explain what they mean.

How to execute the skill technically

A good method is to identify three things: the event of interest, the condition, and the comparison.

For \(P(A | B)\), the event of interest is A. The condition is B. The plain-language sentence is “the probability of A among cases where B is true.”

Example: \(P(completes goal | gets reminder)\) means “the probability a student completes the goal among students who get a reminder.”

\(P(gets reminder | completes goal)\) means “the probability a student got a reminder among students who completed the goal.” These are different because the denominator is different.

To explain independence, say: “A and B are independent if knowing B happened does not change the probability of A.” Then connect to notation:

\[P(A | B) = P(A)\].

Example: If \(P(completes goal) = 0.40\) and \(P(completes goal | gets reminder) = 0.55\), then reminder status and completion are not independent. Getting a reminder changes the probability of completion in this data or model.

If \(P(completes goal) = 0.40\) and \(P(completes goal | gets reminder) = 0.40\), then reminder status and completion are independent in the data or model.

A worked example: A school finds that 70% of all students pass a course, but among students who attend tutoring, 85% pass. In notation, \(P(pass) = 0.70\) and \(P(pass | tutoring) = 0.85\). In words: among tutoring students, the pass rate is higher than the overall pass rate. Tutoring status and passing are not independent in this data.

But a responsible interpretation should stop short of claiming tutoring caused the difference unless the data came from a strong experimental design. Conditional probability can show association; causation requires more evidence.

Students should practice writing sentences with the denominator visible: “among students who...,” “given that the customer...,” “out of people who...,” or “within the group that....”

More real-world examples of conditional probability language

In medicine, \(P(disease | positive test)\) means “among people who tested positive, the probability of having the disease.” This is often what patients care about. \(P(positive test | disease)\) means “among people who have the disease, the probability that the test is positive.” This is a property of the test. Confusing these two can create serious misunderstanding.

In app analytics, \(P(renews | used feature)\) means “among users who used the feature, the probability of renewing.” \(P(used feature | renews)\) means “among users who renewed, the probability of having used the feature.” Both are useful, but they answer different business questions.

In education, \(P(pass | completed review)\) means “among students who completed the review, the probability of passing.” \(P(completed review | pass)\) means “among students who passed, the probability of having completed the review.” Again, the direction matters.

For an app or website, this objective should include a notation-to-sentence converter. Give students expressions like \(P(A | B)\), \(P(B | A)\), \(P(A \cap B)\), and \(P(A^c)\), then ask them to select the correct sentence. This builds the language layer that prevents later formula errors.

Common misconceptions and how to avoid them

The biggest misconception is reversing the condition. Students must learn that the event after the bar is the group being looked inside.

Another misconception is thinking dependent means caused by. Dependence means probability changes; it does not automatically prove causation.

A third misconception is thinking independent means mutually exclusive. Independent events can happen together. Mutually exclusive events cannot happen together.

A fourth mistake is interpreting percentages without denominators. “80% passed” is incomplete unless we know 80% of whom.

A fifth mistake is treating probability language as less important than calculation. In applied probability, a correct calculation with the wrong interpretation is still wrong.

The big takeaway

Conditional probability is probability with information. Independence is the special case where that information does not change the probability. Students need to explain these ideas in ordinary language because real-world probability claims are usually written as sentences, not formulas. The key habit is always to ask: among which group, what probability are we measuring, and does the condition change it?

Problem Library

Problems in the App From This Objective

171 problems across 12 archetypes in the app.

identify the given condition and target event.
15 problems Warmup Practice Mixed Review Assessment
Problem 1

Explain the conditional probability statement in everyday language: P(recovery | treatment)=0.80.

Problem 2

Explain the conditional probability statement in everyday language: P(pass | studied)=0.90.

Problem 3

Explain the conditional probability statement in everyday language: P(red | face card)=6/12.

Problem 4

Explain the conditional probability statement in everyday language: P(B | A)=0.25.

Problem 5

Explain the conditional probability statement in everyday language: P(positive test | disease)=0.95.

Problem 6

Explain the conditional probability statement in everyday language: P(rain | cloudy)=0.70.

Problem 7

Explain the conditional probability statement in everyday language: P(even | greater than 3)=2/3.

Problem 8

Explain the conditional probability statement in everyday language: P(spade | black card)=0.5.

Problem 9

Explain the conditional probability statement in everyday language: P(owns car | employed)=0.85.

Problem 10

Explain the conditional probability statement in everyday language: P(A | completed homework)=0.75.

Open in simulator
Problem 11

Explain the conditional probability statement in everyday language: P(defective | from batch X)=0.02.

Problem 12

Explain the conditional probability statement in everyday language: P(win | home game)=0.60.

Problem 13

Explain the conditional probability statement in everyday language: P(migrate | winter)=0.90.

Problem 14

Explain the conditional probability statement in everyday language: P(default | high credit risk)=0.15.

Problem 15

Explain the conditional probability statement in everyday language: P(Y | X)=0.6.

say one event does not change likelihood of another.
12 problems Warmup Practice Mixed Review Assessment
Problem 16

Explain independence in everyday language for coin flip and die roll.

Problem 17

Explain independence in everyday language for two draws with replacement.

Problem 18

Explain independence in everyday language for weather in two distant cities.

Problem 19

Explain independence in everyday language for A and B.

Problem 20

Explain independence in everyday language for rolling two dice.

Problem 21

Explain independence in everyday language for drawing a card from a deck, replacing it, and drawing again.

Problem 22

Explain independence in everyday language for the gender of two children in a family.

Problem 23

Explain independence in everyday language for whether it rains in New York and whether a specific person in Tokyo eats sushi.

Open in simulator
Problem 24

Explain independence in everyday language for your height and your favorite ice cream flavor.

Problem 25

Explain independence in everyday language for two consecutive coin flips.

Problem 26

Explain independence in everyday language for the outcome of a basketball game and the price of gold.

Problem 27

Explain independence in everyday language for picking a random number and the temperature in a different city.

describe how one event changes likelihood of another.
12 problems Warmup Practice Mixed Review Assessment
Problem 28

Explain dependence in everyday language for drawing two cards without replacement.

Problem 29

Explain dependence in everyday language for height category and shoe size.

Problem 30

Explain dependence in everyday language for student studies and student passes.

Problem 31

Explain dependence in everyday language for choosing two marbles without replacement.

Problem 32

Explain dependence in everyday language for it rains and carrying an umbrella.

Problem 33

Explain dependence in everyday language for smoking and developing lung cancer.

Problem 34

Explain dependence in everyday language for getting a flat tire and arriving late to work.

Problem 35

Explain dependence in everyday language for winning the lottery and becoming rich.

Open in simulator
Problem 36

Explain dependence in everyday language for drawing two red balls from a bag without replacement.

Problem 37

Explain dependence in everyday language for exercising regularly and maintaining a healthy weight.

Problem 38

Explain dependence in everyday language for eating spoiled food and getting sick.

Problem 39

Explain dependence in everyday language for a car's age and its likelihood of breaking down.

compare cannot-both-happen versus no likelihood change.
15 problems Warmup Practice Mixed Review Assessment
Problem 40

Distinguish independent from mutually exclusive in the story: A die roll is even and a die roll is odd.

Problem 41

Distinguish independent from mutually exclusive in the story: coin lands heads and die shows 4.

Problem 42

Distinguish independent from mutually exclusive in the story: student is in band and student is in choir.

Problem 43

Distinguish independent from mutually exclusive in the story: card is a heart and card is black.

Open in simulator
Problem 44

Distinguish independent from mutually exclusive in the story: Drawing a red card and drawing a face card from a standard deck.

Problem 45

Distinguish independent from mutually exclusive in the story: Rolling a 6 on a die and rolling an even number on the same die.

Problem 46

Distinguish independent from mutually exclusive in the story: It rains today and it is sunny today in the same location at the same time.

Problem 47

Distinguish independent from mutually exclusive in the story: A person has brown hair and a person has blue eyes.

Problem 48

Distinguish independent from mutually exclusive in the story: Drawing an Ace from a deck and drawing a King from the same deck on a single draw.

Problem 49

Distinguish independent from mutually exclusive in the story: A student passes a math test and a student passes a science test.

Problem 50

Distinguish independent from mutually exclusive in the story: Flipping a coin and getting heads on the first flip, and getting heads on the second flip.

Problem 51

Distinguish independent from mutually exclusive in the story: A person is left-handed and a person is right-handed.

Problem 52

Distinguish independent from mutually exclusive in the story: A car is red and a car is a sedan.

Problem 53

Distinguish independent from mutually exclusive in the story: A student is absent from school and a student is present at school on the same day.

Problem 54

Distinguish independent from mutually exclusive in the story: Rolling a number greater than 4 on a die and rolling an even number on the same die.

translate "among those who..." or "given that..."
15 problems Warmup Practice Mixed Review Assessment
Problem 55

Interpret conditional probability from the sentence: Among students who play sports, 30% play soccer.

Problem 56

Interpret conditional probability from the sentence: Given that a card is a face card, the probability it is a king is 1/3.

Problem 57

Interpret conditional probability from the sentence: Of customers who used a coupon, 45% returned.

Problem 58

Interpret conditional probability from the sentence: If a person is in group B, the chance they also have A is 20%.

Problem 59

Interpret conditional probability from the sentence: Among employees who work full-time, 15% are managers.

Problem 60

Interpret conditional probability from the sentence: Given that a student passed the first exam, the probability they pass the second is 0.8.

Problem 61

Interpret conditional probability from the sentence: Of those who own a smartphone, 70% prefer brand X.

Problem 62

Interpret conditional probability from the sentence: If an animal is a cat, the likelihood it has green eyes is 10%.

Problem 63

Interpret conditional probability from the sentence: Among cars produced last year, 5% had a recall.

Problem 64

Interpret conditional probability from the sentence: The probability that a randomly selected person is left-handed, given they are male, is 0.11.

Problem 65

Interpret conditional probability from the sentence: Of those who attended the concert, 60% bought merchandise.

Problem 66

Interpret conditional probability from the sentence: If a student studies for more than 3 hours, the chance they get an A is 75%.

Problem 67

Interpret conditional probability from the sentence: For patients diagnosed with disease X, the chance of full recovery is 85%.

Problem 68

Interpret conditional probability from the sentence: Assuming a customer clicked the ad, the probability they make a purchase is 0.02.

Open in simulator
Problem 69

Interpret conditional probability from the sentence: Among households with children, 90% own a pet.

express `P(A|B)`, `P(A and B)`, and independence clearly.
15 problems Warmup Practice Mixed Review Assessment
Problem 70

Rewrite probability notation as a plain-English claim: P(A|B)=0.70.

Problem 71

Rewrite probability notation as a plain-English claim: P(A and B)=0.20.

Problem 72

Rewrite probability notation as a plain-English claim: P(A or B)=0.65.

Open in simulator
Problem 73

Rewrite probability notation as a plain-English claim: P(A|B)=P(A).

Problem 74

Rewrite probability notation as a plain-English claim: P(Heads|First Toss Heads) = 0.5.

Problem 75

Rewrite probability notation as a plain-English claim: P(Rain and Cold) = 0.15.

Problem 76

Rewrite probability notation as a plain-English claim: P(Pass or Fail) = 1.

Problem 77

Rewrite probability notation as a plain-English claim: P(not A) = 0.3.

Problem 78

Rewrite probability notation as a plain-English claim: P(A and B) = P(A)P(B).

Problem 79

Rewrite probability notation as a plain-English claim: P(A|B) > 0.5.

Problem 80

Rewrite probability notation as a plain-English claim: P(C and D) < 0.1.

Problem 81

Rewrite probability notation as a plain-English claim: P(E or F) >= 0.8.

Problem 82

Rewrite probability notation as a plain-English claim: P(A'|B) = 0.4.

Problem 83

Rewrite probability notation as a plain-English claim: P(Success) = 0.9.

Problem 84

Rewrite probability notation as a plain-English claim: P(A|B)!= P(A).

identify condition, event, and operation.
15 problems Warmup Practice Mixed Review Assessment
Problem 85

Rewrite the plain-English claim in probability notation: 70% of students in band also play sports.

Problem 86

Rewrite the plain-English claim in probability notation: A and B happen together 15% of the time.

Problem 87

Rewrite the plain-English claim in probability notation: neither A nor B occurs.

Problem 88

Rewrite the plain-English claim in probability notation: knowing B does not change the chance of A.

Problem 89

Rewrite the plain-English claim in probability notation: The chance of event X occurring is 0.35.

Problem 90

Rewrite the plain-English claim in probability notation: The probability that it will not rain.

Problem 91

Rewrite the plain-English claim in probability notation: The probability of getting a head or a tail on a coin flip.

Problem 92

Rewrite the plain-English claim in probability notation: The probability of drawing a queen of hearts.

Problem 93

Rewrite the plain-English claim in probability notation: The probability of getting a sum of 7, given the first die was a 3.

Problem 94

Rewrite the plain-English claim in probability notation: Events C and D are independent.

Problem 95

Rewrite the plain-English claim in probability notation: The probability that a student passes the exam.

Open in simulator
Problem 96

Rewrite the plain-English claim in probability notation: The probability of not rolling a 6 on a standard die.

Problem 97

Rewrite the plain-English claim in probability notation: The probability of drawing a face card or an ace.

Problem 98

Rewrite the plain-English claim in probability notation: The probability that both events M and N occur.

Problem 99

Rewrite the plain-English claim in probability notation: The probability of event G given event H has occurred.

reason about replacement and unchanged sample space.
12 problems Warmup Practice Mixed Review Assessment
Problem 100

Decide whether the context likely involves independent trials: rolling a die four times.

Problem 101

Decide whether the context likely involves independent trials: drawing cards without replacement.

Problem 102

Decide whether the context likely involves independent trials: drawing marbles with replacement.

Problem 103

Decide whether the context likely involves independent trials: selecting two people from a class without returning the first.

Problem 104

Decide whether the context likely involves independent trials: flipping a fair coin 5 times.

Problem 105

Decide whether the context likely involves independent trials: picking two specific colored candies from a bag without putting the first one back.

Problem 106

Decide whether the context likely involves independent trials: rolling a 6-sided die and then a 4-sided die.

Problem 107

Decide whether the context likely involves independent trials: selecting two students for a committee from a class.

Open in simulator
Problem 108

Decide whether the context likely involves independent trials: drawing a card from a deck with replacement.

Problem 109

Decide whether the context likely involves independent trials: choosing two different toppings for a pizza from a list of 10.

Problem 110

Decide whether the context likely involves independent trials: observing the gender of 10 consecutive newborns.

Problem 111

Decide whether the context likely involves independent trials: removing two light bulbs from a box of 12 to check for defects.

reason about real-world dependence.
15 problems Warmup Practice Mixed Review Assessment
Problem 112

Decide whether the context likely involves associated categories: hours studied and passing a test.

Problem 113

Decide whether the context likely involves associated categories: favorite color and coin flip result.

Problem 114

Decide whether the context likely involves associated categories: grade level and course preference.

Problem 115

Decide whether the context likely involves associated categories: height and shoe size.

Problem 116

Decide whether the context likely involves associated categories: daily exercise and overall health.

Problem 117

Decide whether the context likely involves associated categories: number of pets owned and favorite type of music.

Problem 118

Decide whether the context likely involves associated categories: rainfall amount and crop yield.

Problem 119

Decide whether the context likely involves associated categories: car color and driver's age.

Open in simulator
Problem 120

Decide whether the context likely involves associated categories: ice cream sales and temperature.

Problem 121

Decide whether the context likely involves associated categories: student's birth month and their score on a math test.

Problem 122

Decide whether the context likely involves associated categories: smoking habits and lung cancer incidence.

Problem 123

Decide whether the context likely involves associated categories: amount of sleep and alertness the next day.

Problem 124

Decide whether the context likely involves associated categories: type of breakfast eaten and performance on a morning exam.

Problem 125

Decide whether the context likely involves associated categories: zip code and average income.

Problem 126

Decide whether the context likely involves associated categories: number of siblings and preferred genre of movies.

distinguish `P(A|B)` from `P(B|A)`.
15 problems Warmup Practice Mixed Review Assessment
Problem 127

Explain why conditional probability can be asymmetric in disease and positive test.

Problem 128

Explain why conditional probability can be asymmetric in band members and athletes.

Problem 129

Explain why conditional probability can be asymmetric in kings and face cards.

Problem 130

Explain why conditional probability can be asymmetric in A and B with different totals.

Problem 131

Explain why conditional probability can be asymmetric in students and good grades.

Problem 132

Explain why conditional probability can be asymmetric in rain and clouds.

Problem 133

Explain why conditional probability can be asymmetric in smoking and lung cancer.

Problem 134

Explain why conditional probability can be asymmetric in squares and rectangles.

Problem 135

Explain why conditional probability can be asymmetric in having a driver's license and being over 16.

Problem 136

Explain why conditional probability can be asymmetric in living in California and living in Los Angeles.

Open in simulator
Problem 137

Explain why conditional probability can be asymmetric in having a pet and having a cat.

Problem 138

Explain why conditional probability can be asymmetric in being a doctor and being a human.

Problem 139

Explain why conditional probability can be asymmetric in having a fever and having the flu.

Problem 140

Explain why conditional probability can be asymmetric in being a fruit and being an apple.

Problem 141

Explain why conditional probability can be asymmetric in passing a test and studying.

detect overstatement or reversed condition.
15 problems Warmup Practice Mixed Review Assessment
Problem 142

Evaluate the real-world probability claim for correct language: 80% of positive tests mean 80% of people with positive tests have the disease, but the statistic was P(positive|disease).

Problem 143

Evaluate the real-world probability claim for correct language: Students in club A had a higher pass rate, so club A caused passing.

Open in simulator
Problem 144

Evaluate the real-world probability claim for correct language: The events are independent because P(A|B)=P(A).

Problem 145

Evaluate the real-world probability claim for correct language: A or B means A happens or B happens or both.

Problem 146

Evaluate the real-world probability claim for correct language: A medical test is 95% sensitive, meaning P(positive|disease) = 0.95. This implies 95% of positive results indicate the disease.

Problem 147

Evaluate the real-world probability claim for correct language: Children who watch more TV tend to have lower test scores. Therefore, watching TV causes lower test scores.

Problem 148

Evaluate the real-world probability claim for correct language: Two events A and B are independent if the occurrence of B does not change the probability of A, which means P(A|B) = P(A).

Problem 149

Evaluate the real-world probability claim for correct language: If the probability of rain given dark clouds is 60%, then the probability of dark clouds given rain is also 60%.

Problem 150

Evaluate the real-world probability claim for correct language: A survey of our most loyal customers showed 98% satisfaction. This means almost all customers are satisfied.

Problem 151

Evaluate the real-world probability claim for correct language: The probability of event A or event B occurring is P(A) + P(B) if A and B are mutually exclusive.

Problem 152

Evaluate the real-world probability claim for correct language: The probability of a car being red given it's a sports car is high, so if you see a red car, it's probably a sports car.

Problem 153

Evaluate the real-world probability claim for correct language: Countries with higher ice cream sales also have higher rates of drowning. Therefore, ice cream causes drowning.

Problem 154

Evaluate the real-world probability claim for correct language: P(B|A) represents the probability of event B occurring given that event A has already occurred.

Problem 155

Evaluate the real-world probability claim for correct language: Based on historical data, there is a 90% chance of a stock market correction this year, so it's guaranteed to happen.

Problem 156

Evaluate the real-world probability claim for correct language: The probability of an event not happening is 1 minus the probability of it happening, P(A') = 1 - P(A).

fix condition, independence, or mutual-exclusivity confusion.
15 problems Warmup Practice Mixed Review Assessment
Problem 157

Correct the everyday-language probability explanation: A student says P(A|B) means probability of B given A.

Problem 158

Correct the everyday-language probability explanation: A student says independent events cannot happen together.

Problem 159

Correct the everyday-language probability explanation: A student says a higher conditional rate proves one variable caused the other.

Open in simulator
Problem 160

Correct the everyday-language probability explanation: A student says without-replacement draws are independent.

Problem 161

Correct the everyday-language probability explanation: The probability of A and B is the same as the probability of A given B.

Problem 162

Correct the everyday-language probability explanation: If P(A|B) = P(A), then A and B must be mutually exclusive.

Problem 163

Correct the everyday-language probability explanation: P(A and B) is the notation for the probability of A happening if B has already happened.

Problem 164

Correct the everyday-language probability explanation: Drawing two cards from a deck without replacement means the draws are independent.

Problem 165

Correct the everyday-language probability explanation: If two events are independent, they cannot occur at the same time.

Problem 166

Correct the everyday-language probability explanation: The outcome of a coin flip affects the outcome of the next coin flip.

Problem 167

Correct the everyday-language probability explanation: If P(A and B) = P(A) * P(B), then A and B are mutually exclusive.

Problem 168

Correct the everyday-language probability explanation: If two events are mutually exclusive, then the probability of both happening is P(A) * P(B).

Problem 169

Correct the everyday-language probability explanation: Mutually exclusive events are always independent.

Problem 170

Correct the everyday-language probability explanation: To find the probability of A or B, you always add P(A) and P(B).

Problem 171

Correct the everyday-language probability explanation: A strong correlation between two variables means one causes the other.