Math II · S-CP.7

Applying and Interpreting the Addition Rule for Probability

The Addition Rule prevents double-counting when events overlap, which is essential for interpreting “or” statements correctly.

Concept Statistics and Probability
Domain Conditional Probability and the Rules of Probability
Read time 8 minutes

What this learning objective is really asking you to learn

This objective asks students to apply and interpret the Addition Rule:

\[P(A or B) = P(A) + P(B) - P(A and B)\].

In set notation,

\[P(A \cup B) = P(A) + P(B) - P(A \cap B)\].

This rule is about unions. The union \(A \cup B\) includes outcomes that are in A, in B, or in both. In probability, “or” usually means inclusive or. That means A or B or both.

The reason for the subtraction is double-counting. If you add \(P(A)\) and \(P(B)\), any outcome in both A and B has been counted twice. To fix that, subtract \(P(A \cap B)\) once.

For example, suppose 40% of students take art, 30% take music, and 10% take both. The probability a randomly selected student takes art or music is

\[0.40 + 0.30 - 0.10 = 0.60\].

It is not 0.70 because the 10% who take both were counted in both groups.

This objective is asking students not only to use the formula but to understand why it works. A Venn diagram is the best visual explanation. Circle A includes one group. Circle B includes another. The overlap belongs to both. Adding both circles counts the overlap twice. The Addition Rule corrects the count.

The objective also asks for interpretation. If the answer is 0.60, students should say, “There is a 60% probability the student takes art, music, or both.” Probability statements must be tied back to the real event.

Why students should learn this math

Students should learn the Addition Rule because real-world categories often overlap. People can be both commuters and parents, both subscribers and purchasers, both athletes and musicians, both vaccinated and previously infected, both users of feature A and feature B. If students add category percentages without accounting for overlap, they overcount.

This mistake appears constantly in everyday reasoning. A company may say 50% of users use feature A and 40% use feature B. That does not mean 90% use at least one of them, because some users may use both. A school may say 30% of students are in sports and 25% are in performing arts. That does not mean 55% are in at least one activity unless there is no overlap. A public-health report may list risk factors that overlap. A political poll may group voters by categories that are not mutually exclusive. The Addition Rule is how you reason honestly about “or.”

The rule also helps students understand mutually exclusive events. If A and B cannot both happen, then \(P(A \cap B) = 0\), and the Addition Rule becomes

\[P(A or B) = P(A) + P(B)\].

That simpler rule is a special case, not the general rule. Students often memorize the simple version first and misuse it when events overlap. This objective fixes that.

The Addition Rule also supports decision-making. Suppose an app wants to know the probability that a user either opens a notification or completes a lesson. If some users do both, the overlap must be subtracted. Otherwise the company may overestimate engagement. Suppose an insurance analyst estimates the probability that a home has flood risk or fire risk. Some homes may have both. Overlap matters.

The “why” is that “or” statements are everywhere, and overlap is easy to mishandle. The Addition Rule is the mathematical tool that prevents double-counting.

The historical machinery: counting without double-counting

The Addition Rule is a probability version of a larger counting principle called inclusion-exclusion. The simplest inclusion-exclusion principle says that the size of the union of two sets is

\[|A \cup B| = |A| + |B| - |A \cap B|\].

Probability uses the same logic, but with probabilities instead of counts. The idea is ancient in spirit: if two groups overlap, adding their sizes counts the overlap twice. Correct counting requires subtracting the overlap.

Inclusion-exclusion becomes more complex for three or more sets, but the two-set version is already powerful. It appears in combinatorics, computer science, database queries, survey analysis, and risk modeling. Whenever categories overlap, inclusion-exclusion is the tool for accurate counting.

The historical importance is that probability is built from counting and set logic. The Addition Rule is not an arbitrary formula; it is a direct expression of how overlapping sets work.

Where this fits in the big map of mathematics

This objective follows sample spaces, events, complements, conditional probability, and two-way tables. Students need to know \(A \cup B\) and \(A \cap B\) before the formula makes sense.

It connects to Venn diagrams. A Venn diagram visually shows why the overlap must be subtracted.

It connects to two-way tables. The union of row/column categories can be computed by adding marginal totals and subtracting the joint cell.

It connects to complements. Sometimes \(P(A or B)\) can be found more easily by computing the complement: \(1 - P(neither A nor B)\).

It connects to combinatorics. Inclusion-exclusion is a major counting principle.

It connects to real data interpretation. Many survey categories overlap, so union probabilities require overlap correction.

The big-map role is union reasoning. Students learn how to compute the probability that at least one of two events occurs.

How to execute the skill technically

Use this routine:

  1. Identify A and B.
  2. Find \(P(A)\).
  3. Find \(P(B)\).
  4. Find \(P(A \cap B)\).
  5. Compute \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).
  6. Interpret the answer as “A or B or both.”

Example: In a survey, 55% of users use mobile, 35% use desktop, and 20% use both. The probability a user uses mobile or desktop is

\[0.55 + 0.35 - 0.20 = 0.70\].

Interpretation: 70% of users use mobile, desktop, or both.

Card example: Draw one card. Let A be “king” and B be “heart.” \(P(A) = 4/52\), \(P(B) = 13/52\), and \(P(A \cap B) = 1/52\), because one card is both a king and a heart. So

\[P(A \cup B) = 4/52 + 13/52 - 1/52 = 16/52 = 4/13\].

This means the probability of drawing a king or a heart is \(4/13\).

If events are mutually exclusive, such as rolling a 2 or rolling a 5 on one die roll, the overlap is zero. Then

\[P(2 or 5) = 1/6 + 1/6 = 2/6 = 1/3\].

The full Addition Rule still applies; the intersection term is just zero.

Two-way table example

Suppose 100 students are surveyed.

| | Takes music | Does not take music | Total | |---|---:|---:|---:| | Takes art | 12 | 28 | 40 | | Does not take art | 18 | 42 | 60 | | Total | 30 | 70 | 100 |

Let A be takes art. Let B be takes music. \(P(A) = 40/100\). \(P(B) = 30/100\). \(P(A \cap B) = 12/100\).

So

\[P(A \cup B) = 40/100 + 30/100 - 12/100 = 58/100\].

So 58% of students take art or music or both.

Notice that adding 40 and 30 gives 70, which overcounts the 12 students who take both. The correct count is 58.

This example should be interactive in the app. Let students change the overlap cell and see how the union changes. As overlap increases, the union decreases relative to the simple sum because more students are being double-counted before correction.

Addition Rule with complements

Sometimes the easiest way to find \(P(A or B)\) is to find the probability of neither event and subtract from 1. This works because “A or B” and “neither A nor B” are complements.

For example, suppose in a group of 100 students, 40 take art, 30 take music, and 12 take both. We already found that

\[P(art or music) = 40/100 + 30/100 - 12/100 = 58/100\].

That means the probability of neither art nor music is

\[1 - 58/100 = 42/100\].

If a table gives the “neither” cell directly, using the complement may be faster. The complement method is also useful when there are many ways for A or B to occur but only one clean way for neither to occur.

“At least one” problems

The Addition Rule is closely related to “at least one” probability. The phrase “at least one” means one or more. For two events, “at least one of A or B occurs” is the same as \(A \cup B\).

Suppose a student may complete a lesson on the website, in the app, or both. If 45% complete on the website, 50% complete in the app, and 20% complete in both, then the probability the student completes on at least one platform is

\[0.45 + 0.50 - 0.20 = 0.75\].

So 75% completed on the website, in the app, or both. If someone simply added 45% and 50%, they would get 95%, overcounting the students who used both platforms.

This is a very realistic analytics problem. Many product metrics involve overlap: mobile and desktop, email and push, free and paid, search and recommendation, new and returning. The Addition Rule is the math of deduplicating overlapping categories.

Why the Addition Rule is not optional

The Addition Rule is often the difference between honest reporting and inflated reporting. If a company says 60% of customers use feature A and 50% use feature B, it cannot claim 110% engagement across the two features. The overlap must be handled. If 30% use both, then 80% use at least one.

Students should learn to be suspicious of combined percentages that ignore overlap. Whenever categories can overlap, ask for the intersection. Without the intersection, the union cannot be known exactly.

Edge case: when events are mutually exclusive

If two events cannot happen at the same time, their intersection is empty. For example, on one die roll, the event “roll a 2” and the event “roll a 5” are mutually exclusive. Their intersection has probability 0. The Addition Rule becomes

\[P(A \cup B) = P(A) + P(B) - 0\].

This is why students may have learned a simpler addition rule earlier. But that simple version only works when overlap is impossible. The general Addition Rule always works, and the mutually exclusive rule is just a special case.

Common misconceptions and how to avoid them

One common mistake is forgetting to subtract the overlap. This overcounts outcomes that belong to both events.

Another mistake is thinking “or” excludes “both.” In probability, “or” is usually inclusive unless the problem says exactly one.

A third mistake is subtracting the wrong quantity. Subtract the intersection, not the union.

A fourth mistake is applying the simple addition rule to events that are not mutually exclusive.

A fifth mistake is failing to interpret the result. The answer should describe the probability of A or B or both.

The big takeaway

The Addition Rule is the probability rule for overlapping “or” events. Add the probabilities of A and B, then subtract the overlap because it was counted twice. This rule teaches students to reason accurately about unions, surveys, categories, risks, and any situation where groups can overlap.

Problem Library

Problems in the App From This Objective

165 problems across 12 archetypes in the app.

add probabilities and subtract intersection.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Compute P(A or B) for overlapping events from P(A)=0.50, P(B)=0.30, P(A and B)=0.10.

Problem 2

Compute P(A or B) for overlapping events from P(A)=1/2, P(B)=1/4, P(A and B)=1/8.

Problem 3

Compute P(A or B) for overlapping events from P(A)=40%, P(B)=35%, P(A and B)=15%.

Problem 4

Compute P(A or B) for overlapping events from P(A)=p, P(B)=q, P(A and B)=r.

Problem 5

Compute P(A or B) for overlapping events from P(A)=0.6, P(B)=0.25, P(A and B)=0.1.

Problem 6

Compute P(A or B) for overlapping events from P(A)=0.75, P(B)=0.4, P(A and B)=0.2.

Problem 7

Compute P(A or B) for overlapping events from P(A)=2/3, P(B)=1/6, P(A and B)=1/9.

Problem 8

Compute P(A or B) for overlapping events from P(A)=3/5, P(B)=1/2, P(A and B)=1/4.

Problem 9

Compute P(A or B) for overlapping events from P(A)=60%, P(B)=20%, P(A and B)=10%.

Problem 10

Compute P(A or B) for overlapping events from P(A)=70%, P(B)=30%, P(A and B)=15%.

Problem 11

Compute P(A or B) for overlapping events from P(A)=5/8, P(B)=1/4, P(A and B)=1/16.

Problem 12

Compute P(A or B) for overlapping events from P(A)=0.8, P(B)=0.6, P(A and B)=0.5.

Open in simulator
recognize intersection is zero.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Compute P(A or B) for mutually exclusive events from P(A)=0.20 and P(B)=0.35.

Problem 14

Compute P(A or B) for mutually exclusive events from P(A)=1/6 and P(B)=1/3.

Problem 15

Compute P(A or B) for mutually exclusive events from P(A)=15% and P(B)=25%.

Problem 16

Compute P(A or B) for mutually exclusive events from P(A)=p and P(B)=q.

Problem 17

Compute P(A or B) for mutually exclusive events from P(A)=0.12 and P(B)=0.45.

Problem 18

Compute P(A or B) for mutually exclusive events from P(A)=2/5 and P(B)=1/10.

Open in simulator
Problem 19

Compute P(A or B) for mutually exclusive events from P(A)=30% and P(B)=45%.

Problem 20

Compute P(A or B) for mutually exclusive events from P(A)=2x and P(B)=3y.

Problem 21

Compute P(A or B) for mutually exclusive events from P(A)=0.7 and P(B)=0.15.

Problem 22

Compute P(A or B) for mutually exclusive events from P(A)=1/4 and P(B)=1/8.

Problem 23

Compute P(A or B) for mutually exclusive events from P(A)=5% and P(B)=60%.

Problem 24

Compute P(A or B) for mutually exclusive events from P(A)=0.25 and P(B)=x.

rearrange formula.
15 problems Warmup Practice Mixed Review Assessment
Problem 25

Find missing intersection probability from addition-rule data P(A)=0.60, P(B)=0.50, P(A or B)=0.80.

Problem 26

Find missing intersection probability from addition-rule data P(A)=1/2, P(B)=1/3, P(A or B)=2/3.

Problem 27

Find missing intersection probability from addition-rule data P(A)=45%, P(B)=40%, P(A or B)=70%.

Problem 28

Find missing intersection probability from addition-rule data P(A)=p, P(B)=q, P(A or B)=u.

Problem 29

Find missing intersection probability from addition-rule data P(A)=0.7, P(B)=0.4, P(A or B)=0.9.

Problem 30

Find missing intersection probability from addition-rule data P(A)=3/4, P(B)=1/2, P(A or B)=7/8.

Problem 31

Find missing intersection probability from addition-rule data P(A)=60%, P(B)=30%, P(A or B)=80%.

Problem 32

Find missing intersection probability from addition-rule data P(A)=0.3, P(B)=0.5, P(A or B)=0.8.

Problem 33

Find missing intersection probability from addition-rule data P(A)=1/4, P(B)=1/2, P(A or B)=3/4.

Problem 34

Find missing intersection probability from addition-rule data P(X)=a, P(Y)=b, P(X or Y)=c.

Open in simulator
Problem 35

Find missing intersection probability from addition-rule data P(A)=0.8, P(B)=0.3, P(A or B)=0.8.

Problem 36

Find missing intersection probability from addition-rule data P(A)=1/4, P(B)=1/2, P(A or B)=1/2.

Problem 37

Find missing intersection probability from addition-rule data P(A)=75%, P(B)=60%, P(A or B)=90%.

Problem 38

Find missing intersection probability from addition-rule data P(A)=0.125, P(B)=0.25, P(A or B)=0.3.

Problem 39

Find missing intersection probability from addition-rule data P(A)=2/5, P(B)=1/3, P(A or B)=11/15.

solve for `P(A)` or `P(B)`.
15 problems Warmup Practice Mixed Review Assessment
Problem 40

Find the missing event probability from addition-rule data P(A or B)=0.70, P(B)=0.30, P(A and B)=0.10.

Problem 41

Find the missing event probability from addition-rule data P(A or B)=5/8, P(A)=1/2, P(A and B)=1/8.

Problem 42

Find the missing event probability from addition-rule data P(A or B)=65%, P(B)=40%, P(A and B)=15%.

Open in simulator
Problem 43

Find the missing event probability from addition-rule data P(A or B)=u, P(B)=q, P(A and B)=r.

Problem 44

Find the missing event probability from addition-rule data P(A or B)=0.8, P(B)=0.4, P(A and B)=0.2.

Problem 45

Find the missing event probability from addition-rule data P(A or B)=0.9, P(A)=0.7, P(A and B)=0.3.

Problem 46

Find the missing event probability from addition-rule data P(A or B)=2/3, P(B)=1/3, P(A and B)=1/6.

Problem 47

Find the missing event probability from addition-rule data P(A or B)=3/4, P(A)=1/2, P(A and B)=1/4.

Problem 48

Find the missing event probability from addition-rule data P(A or B)=75%, P(B)=30%, P(A and B)=10%.

Problem 49

Find the missing event probability from addition-rule data P(A or B)=80%, P(A)=60%, P(A and B)=20%.

Problem 50

Find the missing event probability from addition-rule data P(A or B)=0.6, P(B)=1/4, P(A and B)=0.15.

Problem 51

Find the missing event probability from addition-rule data P(A or B)=0.95, P(A)=70%, P(A and B)=0.2.

Problem 52

Find the missing event probability from addition-rule data P(A or B)=x, P(A)=y, P(A and B)=z.

Problem 53

Find the missing event probability from addition-rule data P(A or B)=0.75, P(B)=0.45, P(A and B)=0.25.

Problem 54

Find the missing event probability from addition-rule data P(A or B)=7/10, P(A)=1/2, P(A and B)=1/5.

connect regions to formula terms.
15 problems Warmup Practice Mixed Review Assessment
Problem 55

Use Venn diagram regions to compute an addition-rule probability from A only 12, overlap 8, B only 10, total 50.

Problem 56

Use Venn diagram regions to compute an addition-rule probability from A only 0.20, overlap 0.15, B only 0.25.

Problem 57

Use Venn diagram regions to compute an addition-rule probability from A total 30, B total 25, overlap 10, total 80.

Problem 58

Use Venn diagram regions to compute an addition-rule probability from A only x, overlap y, B only z, total n.

Problem 59

Use Venn diagram regions to compute an addition-rule probability from A only 15, overlap 5, B only 20, total 60.

Problem 60

Use Venn diagram regions to compute an addition-rule probability from A only 0.30, overlap 0.10, B only 0.20.

Problem 61

Use Venn diagram regions to compute an addition-rule probability from A total 40, B total 30, overlap 15, total 100.

Problem 62

Use Venn diagram regions to compute an addition-rule probability from A only 7, overlap 3, B only 10, total 40.

Problem 63

Use Venn diagram regions to compute an addition-rule probability from A only 0.1, overlap 0.05, B only 0.35.

Open in simulator
Problem 64

Use Venn diagram regions to compute an addition-rule probability from A total 25, B total 20, overlap 5, total 75.

Problem 65

Use Venn diagram regions to compute an addition-rule probability from A only 100, overlap 50, B only 120, total 500.

Problem 66

Use Venn diagram regions to compute an addition-rule probability from P(A)=0.4, P(B)=0.3, P(A and B)=0.1.

Problem 67

Use Venn diagram regions to compute an addition-rule probability from A total 17, B total 13, overlap 5, total 30.

Problem 68

Use Venn diagram regions to compute an addition-rule probability from Probability of A only is 0.25, probability of overlap is 0.15, probability of B only is 0.30.

Problem 69

Use Venn diagram regions to compute an addition-rule probability from A only 2, overlap 1, B only 3, total 12.

identify event totals and overlap cell.
15 problems Warmup Practice Mixed Review Assessment
Problem 70

Use a two-way table to compute union probability from row A total 40, column B total 30, overlap cell 12, grand total 100.

Problem 71

Use a two-way table to compute union probability from seniors 25, band 18, senior and band 7, total 80.

Problem 72

Use a two-way table to compute union probability from row total r, column total c, overlap j, total n.

Problem 73

Use a two-way table to compute union probability from A total 50%, B total 35%, overlap 20%.

Problem 74

Use a two-way table to compute union probability from students who play sports 120, students who play music 80, students who play both 30, total students 200.

Problem 75

Use a two-way table to compute union probability from Event X occurs 45%, Event Y occurs 30%, both occur 10%.

Problem 76

Use a two-way table to compute union probability from total items 60, property A 35, property B 25, both A and B 10.

Problem 77

Use a two-way table to compute union probability from total population 500, characteristic C 280, characteristic D 150, C and D 70.

Open in simulator
Problem 78

Use a two-way table to compute union probability from surveyed 100 people, 60 drink coffee, 40 drink tea, 25 drink both.

Problem 79

Use a two-way table to compute union probability from 150 students, 100 passed Math, 90 passed English, 70 passed both.

Problem 80

Use a two-way table to compute union probability from total population 1000, attribute F 600, attribute G 450, both F and G 200.

Problem 81

Use a two-way table to compute union probability from 250 items, 120 have feature X, 100 have feature Y, 40 have both X and Y.

Problem 82

Use a two-way table to compute union probability from P(M)=0.7, P(N)=0.5, P(M and N)=0.3.

Problem 83

Use a two-way table to compute union probability from 300 households, 180 own dogs, 120 own cats, 60 own both.

Problem 84

Use a two-way table to compute union probability from 40 shapes, 25 are red, 20 are square, 10 are red and square.

explain inclusive "or."
15 problems Warmup Practice Mixed Review Assessment
Problem 85

Interpret the union probability in context: P(senior or band)=0.45.

Problem 86

Interpret the union probability in context: P(red or face card)=22/52.

Problem 87

Interpret the union probability in context: P(A or B)=0.70.

Problem 88

Interpret the union probability in context: P(bus or freshman)=0.55.

Problem 89

Interpret the union probability in context: P(athlete or musician)=0.30.

Problem 90

Interpret the union probability in context: P(heart or king)=16/52.

Problem 91

Interpret the union probability in context: P(even or prime)=5/6.

Problem 92

Interpret the union probability in context: P(likes coffee or likes tea)=0.75.

Problem 93

Interpret the union probability in context: P(rain or cloudy)=0.60.

Problem 94

Interpret the union probability in context: P(defect A or defect B)=0.08.

Problem 95

Interpret the union probability in context: P(A in math or A in science)=0.25.

Problem 96

Interpret the union probability in context: P(cat owner or dog owner)=0.50.

Problem 97

Interpret the union probability in context: P(blue car or sedan)=0.35.

Open in simulator
Problem 98

Interpret the union probability in context: P(full-time or manager)=0.40.

Problem 99

Interpret the union probability in context: P(action or comedy)=0.80.

decide whether overlap should be included.
12 problems Warmup Practice Mixed Review Assessment
Problem 100

Distinguish inclusive or from exclusive or in A or B in standard probability notation.

Problem 101

Distinguish inclusive or from exclusive or in A or B but not both.

Problem 102

Distinguish inclusive or from exclusive or in either prize A or prize B, but a person cannot win both.

Problem 103

Distinguish inclusive or from exclusive or in likes tea or coffee in a survey.

Problem 104

Distinguish inclusive or from exclusive or in choosing exactly one of two options.

Problem 105

Distinguish inclusive or from exclusive or in a student qualifies for a scholarship based on academic merit or financial need.

Problem 106

Distinguish inclusive or from exclusive or in at least one of two conditions is met.

Open in simulator
Problem 107

Distinguish inclusive or from exclusive or in rolling a 1 or a 6 on a single die.

Problem 108

Distinguish inclusive or from exclusive or in a customer orders a drink or a dessert, but not both, with their meal deal.

Problem 109

Distinguish inclusive or from exclusive or in a movie is a comedy or a drama.

Problem 110

Distinguish inclusive or from exclusive or in a number is even or a multiple of 3.

Problem 111

Distinguish inclusive or from exclusive or in a job applicant must have experience or a specific certification, but not both, for this entry-level role.

compute "neither" or "not A or B."
12 problems Warmup Practice Mixed Review Assessment
Problem 112

Use complement with the addition rule for P(A or B)=0.72; find neither.

Open in simulator
Problem 113

Use complement with the addition rule for P(A)=0.40, P(B)=0.35, P(A and B)=0.10; find neither.

Problem 114

Use complement with the addition rule for A only 12, overlap 8, B only 10, outside 20; find not A or B.

Problem 115

Use complement with the addition rule for P(A or B)=u.

Problem 116

Use complement with the addition rule for P(X or Y)=0.85; find neither.

Problem 117

Use complement with the addition rule for P(E)=0.60, P(F)=0.25, P(E and F)=0.15; find neither.

Problem 118

Use complement with the addition rule for Only M 25, overlap 15, Only N 30, outside 10; find not M or N.

Problem 119

Use complement with the addition rule for P(C or D)=3/4; find neither.

Problem 120

Use complement with the addition rule for P(G)=1/2, P(H)=1/3, P(G and H)=1/6; find neither.

Problem 121

Use complement with the addition rule for The probability of event J or K occurring is 65%; find the probability that neither occurs.

Problem 122

Use complement with the addition rule for P(R)=0.3, P(S)=0.4, R and S are mutually exclusive; find neither.

Problem 123

Use complement with the addition rule for Students taking Math only: 40, English only: 30, both: 20, neither: 10; find the probability that a student is not taking Math or English.

check union and intersection constraints.
15 problems Warmup Practice Mixed Review Assessment
Problem 124

Determine whether the probabilities are possible under the addition rule: P(A)=0.60, P(B)=0.50, P(A or B)=1.20.

Problem 125

Determine whether the probabilities are possible under the addition rule: P(A)=0.60, P(B)=0.50, P(A and B)=0.20.

Problem 126

Determine whether the probabilities are possible under the addition rule: P(A)=0.20, P(B)=0.30, P(A and B)=0.40.

Problem 127

Determine whether the probabilities are possible under the addition rule: P(A)=0.70, P(B)=0.60, P(A or B)=0.80.

Open in simulator
Problem 128

Determine whether the probabilities are possible under the addition rule: P(A)=0.40, P(B)=0.30, P(A and B)=0.10.

Problem 129

Determine whether the probabilities are possible under the addition rule: P(A)=0.30, P(B)=0.40, P(A and B)=0.

Problem 130

Determine whether the probabilities are possible under the addition rule: P(A)=0.50, P(B)=0.80, P(A and B)=0.50.

Problem 131

Determine whether the probabilities are possible under the addition rule: P(A)=0.20, P(B)=0.50, P(A or B)=0.60.

Problem 132

Determine whether the probabilities are possible under the addition rule: P(A)=0.80, P(B)=0.70, P(A or B)=1.30.

Problem 133

Determine whether the probabilities are possible under the addition rule: P(A)=0.90, P(B)=0.80, P(A and B)=0.10.

Problem 134

Determine whether the probabilities are possible under the addition rule: P(A)=0.50, P(B)=0.60, P(A and B)=0.70.

Problem 135

Determine whether the probabilities are possible under the addition rule: P(A)=0.70, P(B)=0.80, P(A or B)=1.60.

Problem 136

Determine whether the probabilities are possible under the addition rule: P(A)=1.10, P(B)=0.50, P(A and B)=0.20.

Problem 137

Determine whether the probabilities are possible under the addition rule: P(A)=0.60, P(B)=-0.10, P(A or B)=0.50.

Problem 138

Determine whether the probabilities are possible under the addition rule: P(A)=0.70, P(B)=0.60, P(A and B)=-0.10.

decide addition rule vs simple complement/counting.
15 problems Warmup Practice Mixed Review Assessment
Problem 139

Choose the correct probability rule for the 'or' problem: P(A or B) with known P(A), P(B), and overlap.

Problem 140

Choose the correct probability rule for the 'or' problem: P(A or B) where events are mutually exclusive.

Problem 141

Choose the correct probability rule for the 'or' problem: probability of neither A nor B.

Problem 142

Choose the correct probability rule for the 'or' problem: finite sample space with listed outcomes.

Problem 143

Choose the correct probability rule for the 'or' problem: Probability of drawing a red card or a King from a standard deck.

Problem 144

Choose the correct probability rule for the 'or' problem: Probability of rolling an odd number or a 6 on a single die roll.

Problem 145

Choose the correct probability rule for the 'or' problem: Probability that a randomly chosen person likes coffee or tea, given percentages for each and for both.

Problem 146

Choose the correct probability rule for the 'or' problem: Probability that a student does not play soccer or basketball.

Problem 147

Choose the correct probability rule for the 'or' problem: Probability of selecting a male or a person who prefers apples from a two-way frequency table.

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Problem 148

Choose the correct probability rule for the 'or' problem: P(X U Y) given P(X), P(Y), and P(X ∩ Y).

Problem 149

Choose the correct probability rule for the 'or' problem: P(E or F) when E and F are disjoint events.

Problem 150

Choose the correct probability rule for the 'or' problem: Probability of not getting a 5 or a 6 when rolling a die.

Problem 151

Choose the correct probability rule for the 'or' problem: Probability of an element being in set A or set B, given a Venn diagram with counts.

Problem 152

Choose the correct probability rule for the 'or' problem: Probability of a student being enrolled in English or History, where some students are in both.

Problem 153

Choose the correct probability rule for the 'or' problem: Probability of picking a vowel or a consonant from a given list of letters.

catch double-counting, missing intersection, and exclusive/inclusive confusion.
12 problems Warmup Practice Mixed Review Assessment
Problem 154

Correct the addition-rule error: A student computes P(A or B)=P(A)+P(B) for overlapping events.

Problem 155

Correct the addition-rule error: A student subtracts overlap for mutually exclusive events.

Problem 156

Correct the addition-rule error: A student treats 'neither' as P(A and B).

Problem 157

Correct the addition-rule error: A student says inclusive or excludes both events occurring.

Problem 158

Correct the addition-rule error: A student calculates P(at least one of A or B) as P(A) + P(B).

Problem 159

Correct the addition-rule error: A student calculates P(A or B) as 1 - P(A and B).

Problem 160

Correct the addition-rule error: A student assumes events A and B are mutually exclusive without checking if P(A and B) = 0.

Problem 161

Correct the addition-rule error: A student computes P(not A or not B) as 1 - P(A or B).

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Problem 162

Correct the addition-rule error: A student states that P(A or B) = P(A) + P(B) - P(A and B) is incorrect because P(A and B) is already included in P(A) and P(B).

Problem 163

Correct the addition-rule error: A student uses P(A or B) = P(A) + P(B) - P(A and B) even when P(A) + P(B) > 1 and P(A and B) is unknown.

Problem 164

Correct the addition-rule error: A student computes P(neither A nor B) as P(A') + P(B').

Problem 165

Correct the addition-rule error: A student computes P(exactly one of A or B occurs) as P(A or B).