Math III · A-APR.2

Applying the Remainder Theorem to Connect Values, Remainders, and Factors

The Remainder Theorem turns polynomial division into a shortcut for evaluating functions and detecting factors.

Concept Algebra
Domain Arithmetic with Polynomials and Rational Expressions
Read time 8 minutes

What this learning objective is really asking you to learn

This objective asks students to understand and apply the Remainder Theorem. The theorem says that when a polynomial \(p(x)\) is divided by \(x - a\), the remainder is \(p(a)\).

That is a short statement with a lot of meaning. It connects three ideas that students often experience separately: evaluating a polynomial, dividing a polynomial, and identifying factors.

If you divide \(p(x)\) by \(x - a\), the result can be written as

\[p(x) = (x - a)q(x) + r\]

where \(q(x)\) is the quotient polynomial and \(r\) is the remainder. Since the divisor \(x - a\) has degree 1, the remainder is a constant.

Now plug in \(x = a\):

\[p(a) = (a - a)q(a) + r\].

The first part becomes zero:

\[p(a) = 0 \cdot q(a) + r = r\].

So the remainder is \(p(a)\).

This is the machinery behind the theorem. The value of the polynomial at \(a\) is exactly the remainder after division by \(x - a\).

A closely related result is the Factor Theorem: \(x - a\) is a factor of \(p(x)\) if and only if \(p(a) = 0\). Why? Because if the remainder is zero, the division is exact. If the division is exact, then \(x - a\) is a factor.

For example, let \(p(x) = x^3 - 4x^2 + x + 6\). To know the remainder when dividing by \(x - 2\), compute \(p(2)\):

\[p(2) = 8 - 16 + 2 + 6 = 0\].

The remainder is 0, so \(x - 2\) is a factor. This also means \(x = 2\) is a zero of the polynomial and the graph crosses or touches the x-axis at \(x = 2\).

This objective is asking students to see polynomial division, function values, factors, roots, and graphs as one connected system.

Why students should learn this math

Students should learn the Remainder Theorem because it gives a powerful shortcut and a deeper map of polynomial structure. Without the theorem, checking whether \(x - 3\) is a factor might require full polynomial division. With the theorem, simply evaluate \(p(3)\). If the result is zero, \(x - 3\) is a factor. If the result is not zero, the result is the remainder.

This matters because higher-degree polynomials can be difficult to factor by sight. The Remainder Theorem gives students a way to test possible roots. If a polynomial might have a root at \(x = 2\), plug in 2. If the result is zero, a factor has been found. Then polynomial division can reduce the degree, making the rest of the problem easier.

The theorem also connects algebra to graphing. If \(p(a) = 0\), then the point \((a, 0)\) is on the graph. That means \(a\) is an x-intercept or zero. At the same time, \(x - a\) is a factor. So one fact has three forms: value, graph, and factor. This is one of the big themes of polynomial algebra.

In applied modeling, zeros matter. They can represent break-even points, times when a height reaches ground level, inputs where error is zero, or conditions where a system reaches equilibrium. The Remainder Theorem helps students find and verify those important inputs.

The theorem is also a step toward efficient algorithms. Polynomial evaluation and division are fundamental in computer algebra, numerical methods, coding theory, and engineering. Synthetic division, which students often learn with this topic, is a compact algorithm for dividing by linear factors. Even if a student never uses synthetic division professionally, the idea of using structure to avoid unnecessary work is valuable.

The “why” is that the Remainder Theorem reveals a hidden connection: evaluating a polynomial and dividing by a linear factor are the same story viewed from different angles.

The historical machinery: division, roots, and polynomial structure

Polynomial algebra developed from the need to solve equations and understand expressions. Division of polynomials mirrors division of numbers: a dividend equals divisor times quotient plus remainder. This analogy is powerful because it extends familiar arithmetic into algebra.

The Remainder Theorem is part of the structural theory of polynomials. It shows that the simple linear expression \(x - a\) has a special relationship to the value of a polynomial at \(a\). This connection became central in algebra because roots and factors are the key to solving polynomial equations.

The Factor Theorem follows immediately and became one of the most useful tools in polynomial work. If a value makes the polynomial zero, then the corresponding linear factor divides the polynomial. This allowed mathematicians and students to break complicated polynomials into simpler pieces.

Historically, the study of polynomial roots drove major advances, including complex numbers and the Fundamental Theorem of Algebra. The Remainder Theorem is a more elementary but essential piece of that same story. It is one of the first theorems that lets students move systematically between function values and algebraic factorization.

Where this fits in the big map of mathematics

This objective follows polynomial arithmetic and prepares directly for identifying zeros and sketching polynomial graphs. Objective 133 gives students operations on polynomials. Objective 134 gives them a theorem connecting values, remainders, and factors. Objective 135 uses factorizations and zeros to sketch graphs.

It connects backward to function notation. \(p(a)\) means the output of polynomial function \(p\) at input \(a\). The theorem gives that output a division meaning.

It connects to factoring quadratics. Students already know that if \((x - 3)\) is a factor, then \(x = 3\) is a solution. The Remainder Theorem generalizes this to higher-degree polynomials.

It connects to graphing. Zeros are x-intercepts. Testing values helps locate them.

It connects to polynomial division and synthetic division. Dividing by \(x - a\) becomes more meaningful when students know the remainder should be \(p(a)\).

It connects to the Fundamental Theorem of Algebra. Polynomials can be understood through roots and factors, and the Remainder Theorem is one of the tools that links them.

The big-map role is a bridge: value ↔ remainder ↔ factor ↔ zero ↔ graph.

How to execute the skill technically

To find the remainder when dividing \(p(x)\) by \(x - a\), compute \(p(a)\).

Example: Find the remainder when \(p(x) = 2x^3 - 5x^2 + 4x - 7\) is divided by \(x - 3\).

Compute:

\[p(3) = 2(27) - 5(9) + 4(3) - 7\].

That is

\[54 - 45 + 12 - 7 = 14\].

The remainder is 14.

To check whether \(x - a\) is a factor, compute \(p(a)\). If \(p(a) = 0\), then \(x - a\) is a factor. If not, it is not.

Example: Is \(x + 2\) a factor of \(p(x) = x^3 + 4x^2 + x - 6\)?

Rewrite \(x + 2\) as \(x - (-2)\), so \(a = -2\).

Compute:

\[p(-2) = (-8) + 4(4) - 2 - 6 = -8 + 16 - 2 - 6 = 0\].

So \(x + 2\) is a factor.

Students should be careful with signs. Dividing by \(x - 5\) means evaluate at 5. Dividing by \(x + 5\) means evaluate at -5.

Synthetic division can also show the same remainder. But the theorem says the remainder must equal the function value, so evaluation is often faster when only the remainder is needed.

Worked example: from factor to graph

Let

\[p(x) = x^3 - 3x^2 - 4x + 12\].

Test whether \(x - 2\) is a factor.

\[p(2) = 8 - 12 - 8 + 12 = 0\].

So \(x - 2\) is a factor, and \(x = 2\) is a zero. The graph has x-intercept at \((2, 0)\).

Test \(x + 2\).

\[p(-2) = -8 - 12 + 8 + 12 = 0\].

So \(x + 2\) is also a factor, and \(x = -2\) is a zero.

If students divide the polynomial by \((x - 2)(x + 2) = x^2 - 4\), they can find the remaining factor and sketch more of the graph. The point is that evaluating at candidate roots reveals graph and factor information quickly.

Why the theorem is more than a shortcut

The Remainder Theorem is often taught as a quick trick, but it is more than that. It tells students that polynomial functions are structured objects. The value \(p(a)\) is not isolated from division; it is exactly the leftover amount after removing the factor \(x - a\).

This gives students a stronger mental model. If \(p(a)\) is zero, there is no leftover, so \(x - a\) divides evenly. If \(p(a)\) is not zero, the leftover is the remainder. This is the same logic as whole-number division, lifted into polynomial algebra.

Synthetic division as a companion tool

Synthetic division is often taught alongside the Remainder Theorem because it is a fast way to divide by \(x - a\). If the final number in synthetic division is zero, then the divisor is a factor. If the final number is not zero, that final number is the remainder, and it should match \(p(a)\).

For example, divide

\[p(x) = x^3 - 6x^2 + 11x - 6\]

by \(x - 2\).

Synthetic division uses the coefficients 1, -6, 11, -6 and the value 2. The process produces quotient coefficients 1, -4, 3 and remainder 0. So

\[p(x) = (x - 2)(x^2 - 4x + 3)\].

Because the remainder is zero, \(x - 2\) is a factor. The quotient factors further:

\[x^2 - 4x + 3 = (x - 1)(x - 3)\].

So

\[p(x) = (x - 1)(x - 2)(x - 3)\].

The Remainder Theorem explains why the final synthetic division number equals \(p(2)\). Synthetic division is the algorithm; the theorem is the meaning.

Remainders as function values

Students often think of remainders as leftovers from arithmetic and function values as points on a graph. The Remainder Theorem says these are connected. If dividing by \(x - a\) leaves remainder 7, then \(p(a) = 7\), so the graph passes through \((a, 7)\). If the remainder is zero, the graph passes through \((a, 0)\).

This is a useful graphing insight. Suppose you test \(x - 4\) and get remainder 10. That tells you \(p(4) = 10\). The point \((4, 10)\) is on the graph. Suppose you test \(x + 1\) and get remainder 0. Then \(p(-1) = 0\), so \((-1, 0)\) is an x-intercept.

Candidate roots and efficient search

The Remainder Theorem helps students search for roots efficiently. If a polynomial has integer coefficients, students often test possible rational roots. Each test is just evaluating the polynomial. A zero value means a factor has been found. Once one factor is found, the polynomial's degree can be reduced by division.

This is the practical workflow behind many Math III polynomial problems: test a candidate root, divide out the factor, then factor or solve the reduced polynomial. The theorem turns guessing into a structured search.

Common misconceptions and how to avoid them

One common mistake is using the wrong sign. For divisor \(x - a\), evaluate at \(a\). For \(x + a\), evaluate at -a.

Another mistake is thinking a nonzero remainder means the polynomial division failed. It did not fail; it means the divisor is not a factor.

A third mistake is confusing factor and zero. If \(x - 4\) is a factor, then 4 is a zero. The factor is an expression; the zero is a number.

A fourth mistake is doing long division when only the remainder is needed. The Remainder Theorem gives the remainder directly.

A fifth mistake is forgetting that the theorem applies specifically to division by linear expressions of the form \(x - a\).

The big takeaway

The Remainder Theorem says that dividing \(p(x)\) by \(x - a\) leaves remainder \(p(a)\). If \(p(a) = 0\), then \(x - a\) is a factor and \(a\) is a zero. This theorem connects polynomial evaluation, division, factors, roots, and graph intercepts into one coherent system.

Problem Library

Problems in the App From This Objective

186 problems across 15 archetypes in the app.

compute `p(a)` accurately.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Evaluate polynomial p(x)=x^3-2x+5 at x=2 to find the remainder.

Problem 2

Evaluate polynomial p(x)=2x^4-x^2+3 at x=-1 to find the remainder.

Problem 3

Evaluate polynomial p(x)=x^3+4x^2-x at x=0 to find the remainder.

Problem 4

Evaluate polynomial p(x)=p(x) at x=a to find the remainder.

Problem 5

Evaluate polynomial p(x)=x+3 at x=1 to find the remainder.

Problem 6

Evaluate polynomial p(x)=x^2+3x-1 at x=2 to find the remainder.

Problem 7

Evaluate polynomial p(x)=x^2-x+7 at x=-3 to find the remainder.

Problem 8

Evaluate polynomial p(x)=x^3-5 at x=-2 to find the remainder.

Problem 9

Evaluate polynomial p(x)=2x^2 + 0.5x - 1 at x=4 to find the remainder.

Problem 10

Evaluate polynomial p(x)=x^5 - 2x^3 + x at x=1 to find the remainder.

Problem 11

Evaluate polynomial p(x)=x^4 + 2x^2 - 3 at x=-2 to find the remainder.

Problem 12

Evaluate polynomial p(x)=7 at x=5 to find the remainder.

Open in simulator
state remainder equals `p(a)`.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Use the Remainder Theorem for division of p(x)=x^3-2x+5 by x-2.

Problem 14

Use the Remainder Theorem for division of p(x)=2x^3+x-1 by x+1.

Problem 15

Use the Remainder Theorem for division of p(x)=x^4-1 by x-1/2.

Problem 16

Use the Remainder Theorem for division of p(x)=p(x) by x-a.

Problem 17

Use the Remainder Theorem for division of p(x)=x^2+3x+2 by x-1.

Problem 18

Use the Remainder Theorem for division of p(x)=x^3-4x^2+2x-1 by x+2.

Problem 19

Use the Remainder Theorem for division of p(x)=3x^2-5x+7 by x-3.

Problem 20

Use the Remainder Theorem for division of p(x)=2x^4+x^2-3 by x+1.

Problem 21

Use the Remainder Theorem for division of p(x)=x^5-10 by x-2.

Problem 22

Use the Remainder Theorem for division of p(x)=x^2+x+1 by x.

Open in simulator
Problem 23

Use the Remainder Theorem for division of p(x)=4x^3-2x^2+x-5 by x+1/2.

Problem 24

Use the Remainder Theorem for division of p(x)=x^2-9 by x-3.

divide by `x-a` and read final value.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Use synthetic division to find the remainder for (x^3+0x^2-4x+7) divided by x-2.

Problem 26

Use synthetic division to find the remainder for (2x^3-3x^2+0x+5) divided by x+1.

Open in simulator
Problem 27

Use synthetic division to find the remainder for (x^4-2x+1) divided by x-1.

Problem 28

Use synthetic division to find the remainder for coefficients c_n,.,c_0 divided by x-a.

Problem 29

Use synthetic division to find the remainder for (x^2+3x+5) divided by x-1.

Problem 30

Use synthetic division to find the remainder for (3x^3-2x+1) divided by x+2.

Problem 31

Use synthetic division to find the remainder for (x^5-1) divided by x-1.

Problem 32

Use synthetic division to find the remainder for (x^2-5x+6) divided by x+3.

Problem 33

Use synthetic division to find the remainder for (x^3-2x^2+x-5) divided by x-1.

Problem 34

Use synthetic division to find the remainder for (x^4+x^3-2x^2+5) divided by x+3.

Problem 35

Use synthetic division to find the remainder for (x^2-4) divided by x-2.

Problem 36

Use synthetic division to find the remainder for (-x^3+2x^2-3x+10) divided by x-2.

divide and identify remainder term.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Use polynomial long division to find the remainder for (x^3+2x^2-5) divided by x-1.

Problem 38

Use polynomial long division to find the remainder for (2x^4-x^2+3) divided by x+2.

Problem 39

Use polynomial long division to find the remainder for (x^3-8) divided by x-2.

Problem 40

Use polynomial long division to find the remainder for dividend p(x) divided by x-a.

Problem 41

Use polynomial long division to find the remainder for (x^3+3x^2-4x+1) divided by x-1.

Problem 42

Use polynomial long division to find the remainder for (x^2-5x+6) divided by x+1.

Problem 43

Use polynomial long division to find the remainder for (x^4-16) divided by x-2.

Problem 44

Use polynomial long division to find the remainder for (3x^3-2x+5) divided by x-2.

Open in simulator
Problem 45

Use polynomial long division to find the remainder for (2x^3+5x^2-7x-10) divided by x+3.

Problem 46

Use polynomial long division to find the remainder for (x^5-3x^2+7) divided by x.

Problem 47

Use polynomial long division to find the remainder for (x^4-5x^3+2x^2-3x+1) divided by x-1.

Problem 48

Use polynomial long division to find the remainder for (4x^3-6x^2+5x-8) divided by x-1/2.

check whether `p(a)=0`.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Determine whether x-2 is a factor of p(x)=x^3-8.

Problem 50

Determine whether x+1 is a factor of p(x)=x^3+2x+1.

Problem 51

Determine whether x-3 is a factor of p(x)=x^2-9.

Open in simulator
Problem 52

Determine whether x-a is a factor of p(x)=p(x).

Problem 53

Determine whether x-1 is a factor of p(x)=x-1.

Problem 54

Determine whether x-1 is a factor of p(x)=x+1.

Problem 55

Determine whether x+2 is a factor of p(x)=x^2+5x+6.

Problem 56

Determine whether x-1 is a factor of p(x)=x^2+x+1.

Problem 57

Determine whether x+3 is a factor of p(x)=x^3+2x^2-5x-6.

Problem 58

Determine whether x-1 is a factor of p(x)=x^3+x^2+x+1.

Problem 59

Determine whether x+1 is a factor of p(x)=x^4-1.

Problem 60

Determine whether x-2 is a factor of p(x)=x^4+x^3+x^2+x+1.

set `p(a)=0` and solve.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Find the missing coefficient so x-2 is a factor of x^3+kx-6.

Problem 62

Find the missing coefficient so x+1 is a factor of 2x^3+ax^2+3.

Problem 63

Find the missing coefficient so x-3 is a factor of x^2+bx-12.

Problem 64

Find the missing coefficient so x-a is a factor of p(x) with coefficient k.

Problem 65

Find the missing coefficient so x-1 is a factor of x^3 - 2x^2 + kx + 1.

Problem 66

Find the missing coefficient so x+2 is a factor of x^3 + ax^2 - 5x + 6.

Problem 67

Find the missing coefficient so x-4 is a factor of x^2 + bx - 20.

Problem 68

Find the missing coefficient so x+3 is a factor of 2x^3 + 5x^2 + cx - 3.

Problem 69

Find the missing coefficient so x-5 is a factor of x^3 - 4x^2 - 7x + m.

Open in simulator
Problem 70

Find the missing coefficient so x+4 is a factor of x^4 + 3x^3 + nx^2 - 2x - 8.

Problem 71

Find the missing coefficient so x-1 is a factor of 3x^3 + kx^2 - 4x + 1.

Problem 72

Find the missing coefficient so x+5 is a factor of x^2 - 2x + p.

set `p(a)=r` and solve.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Find the missing coefficient from the given remainder: p(x)=x^2+kx+1 divided by x-2 has remainder 7.

Problem 74

Find the missing coefficient from the given remainder: p(x)=ax^3+x divided by x+1 has remainder 5.

Problem 75

Find the missing coefficient from the given remainder: p(x)=x^3+cx+4 divided by x-1 has remainder 10.

Problem 76

Find the missing coefficient from the given remainder: p(x) with coefficient k divided by x-a has remainder r.

Problem 77

Find the missing coefficient from the given remainder: p(x)=2x^2-mx+3 divided by x-1 has remainder 4.

Problem 78

Find the missing coefficient from the given remainder: p(x)=x^3+2x^2+kx-5 divided by x+2 has remainder -1.

Problem 79

Find the missing coefficient from the given remainder: p(x)=3x^2+4x+c divided by x-3 has remainder 42.

Open in simulator
Problem 80

Find the missing coefficient from the given remainder: p(x)=ax^3-2x^2+x+1 divided by x+1 has remainder 7.

Problem 81

Find the missing coefficient from the given remainder: p(x)=x^4+kx^2-3x+1 divided by x-1 has remainder -1.

Problem 82

Find the missing coefficient from the given remainder: p(x)=2x^3-x^2+mx-10 divided by x-2 has remainder 0.

Problem 83

Find the missing coefficient from the given remainder: p(x)=x^2+5x+b divided by x+3 has remainder 2.

Problem 84

Find the missing coefficient from the given remainder: p(x)=4x^3-3x+c divided by x+1 has remainder -5.

interpret `p(a)=0` across representations.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Connect zeros, factors, and graph x-intercepts for p(3)=0.

Problem 86

Connect zeros, factors, and graph x-intercepts for factor x+2.

Open in simulator
Problem 87

Connect zeros, factors, and graph x-intercepts for graph crosses at x=5.

Problem 88

Connect zeros, factors, and graph x-intercepts for p(a)=0.

Problem 89

Connect zeros, factors, and graph x-intercepts for x = 4 is a zero.

Problem 90

Connect zeros, factors, and graph x-intercepts for the graph has an x-intercept at (-1,0).

Problem 91

Connect zeros, factors, and graph x-intercepts for x-7 is a factor.

Problem 92

Connect zeros, factors, and graph x-intercepts for f(-5)=0.

Problem 93

Connect zeros, factors, and graph x-intercepts for x=b is a zero.

Problem 94

Connect zeros, factors, and graph x-intercepts for the graph has an x-intercept at (c,0).

Problem 95

Connect zeros, factors, and graph x-intercepts for x-d is a factor.

Problem 96

Connect zeros, factors, and graph x-intercepts for the polynomial crosses the x-axis at x=2.

locate input where output is zero.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Use the table of values to identify possible factors: p(-2)=0, p(0)=5, p(3)=0.

Problem 98

Use the table of values to identify possible factors: p(1)=4, p(2)=0, p(4)=-1.

Problem 99

Use the table of values to identify possible factors: p(-1)=0 and p(5)=0.

Problem 100

Use the table of values to identify possible factors: p(a)=0 appears in table.

Problem 101

Use the table of values to identify possible factors: p(5)=0, p(1)=2, p(0)=1.

Problem 102

Use the table of values to identify possible factors: p(-3)=0, p(2)=7, p(-1)=4.

Problem 103

Use the table of values to identify possible factors: p(1)=0, p(4)=0, p(0)=3.

Problem 104

Use the table of values to identify possible factors: p(-4)=0, p(2)=0, p(1)=5.

Problem 105

Use the table of values to identify possible factors: p(-1)=0, p(0)=0, p(3)=0, p(5)=10.

Problem 106

Use the table of values to identify possible factors: p(1/2)=0, p(0)=1, p(1)=3.

Problem 107

Use the table of values to identify possible factors: p(7)=0, p(0)=1, p(-2)=5.

Problem 108

Use the table of values to identify possible factors: p(-5)=0, p(-1)=0, p(0)=10.

Open in simulator
choose efficient evaluation method.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Use the Remainder Theorem to avoid full division for remainder of x^7-3x+2 divided by x-1.

Problem 110

Use the Remainder Theorem to avoid full division for remainder of 2x^5+x^2 divided by x+2.

Problem 111

Use the Remainder Theorem to avoid full division for check whether x-4 is a factor of p(x).

Problem 112

Use the Remainder Theorem to avoid full division for division by x-a.

Problem 113

Use the Remainder Theorem to avoid full division for remainder of x^3 - 4x^2 + 5x - 2 divided by x-3.

Problem 114

Use the Remainder Theorem to avoid full division for remainder of x^4 + 2x^3 - x + 7 divided by x+1.

Problem 115

Use the Remainder Theorem to avoid full division for remainder of 3x^2 - 5x + 8 divided by x-2.

Problem 116

Use the Remainder Theorem to avoid full division for check if x+1 is a factor of x^5 + 1.

Problem 117

Use the Remainder Theorem to avoid full division for remainder of 2x^3 - 7x + 10 divided by x.

Problem 118

Use the Remainder Theorem to avoid full division for determine if x-3 is a factor of -x^2 + 6x - 9.

Open in simulator
Problem 119

Use the Remainder Theorem to avoid full division for find the remainder when x^3 - 3x^2 + 2x - 4 is divided by x-2.

Problem 120

Use the Remainder Theorem to avoid full division for remainder of x^6 - 64 divided by x-2.

verify consistency between methods.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Compare Remainder Theorem and synthetic division results for p(x)=x^3-4x+1, divisor x-2.

Problem 122

Compare Remainder Theorem and synthetic division results for p(x)=2x^3+x-3, divisor x+1.

Problem 123

Compare Remainder Theorem and synthetic division results for same polynomial and divisor produce different remainders.

Problem 124

Compare Remainder Theorem and synthetic division results for divisor x-a.

Problem 125

Compare Remainder Theorem and synthetic division results for p(x)=x^2+3x-5, divisor x-1.

Problem 126

Compare Remainder Theorem and synthetic division results for p(x)=x^3-2x+7, divisor x+2.

Problem 127

Compare Remainder Theorem and synthetic division results for p(x)=x^4-3x^2+2x-1, divisor x-3.

Problem 128

Compare Remainder Theorem and synthetic division results for p(x)=3x^2-x+10, divisor x+1.

Problem 129

Compare Remainder Theorem and synthetic division results for p(x)=2x^3+5x^2-x-4, divisor x-1.

Problem 130

Compare Remainder Theorem and synthetic division results for p(x)=x^3+2x^2+3x+4, divisor x+3.

Problem 131

Compare Remainder Theorem and synthetic division results for p(x)=x^2+x+1, divisor x-1, but p(1) is calculated as 1 and synthetic division gives 3.

Open in simulator
Problem 132

Compare Remainder Theorem and synthetic division results for p(x)=5x-7, divisor x-1.

connect input evaluation to modeled output.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Interpret the remainder in polynomial model context: revenue model R(x), divide by x-5 and remainder is 120.

Problem 134

Interpret the remainder in polynomial model context: volume model V(x), remainder after division by x-2 is 48.

Problem 135

Interpret the remainder in polynomial model context: height model h(t), remainder after division by t-3 is 0.

Problem 136

Interpret the remainder in polynomial model context: model p(x) divided by x-a has remainder r.

Problem 137

Interpret the remainder in polynomial model context: cost model C(n), dividing by n-10 yields a remainder of 500.

Problem 138

Interpret the remainder in polynomial model context: population model P(t), when divided by t-7, the remainder is 15000.

Problem 139

Interpret the remainder in polynomial model context: temperature model T(h), division by h-24 results in a remainder of -5.

Open in simulator
Problem 140

Interpret the remainder in polynomial model context: profit model P(x), remainder after dividing by x-100 is 2500.

Problem 141

Interpret the remainder in polynomial model context: distance model D(t), dividing by t-1.5 gives a remainder of 75.

Problem 142

Interpret the remainder in polynomial model context: bacterial growth model B(d), remainder after division by d-3 is 100000.

Problem 143

Interpret the remainder in polynomial model context: fuel consumption model F(s), remainder when divided by s-60 is 15.

Problem 144

Interpret the remainder in polynomial model context: pressure model K(v), dividing by v-10 results in a remainder of 100.

evaluate candidates efficiently.
15 problems Warmup Practice Mixed Review Assessment
Problem 145

Test possible rational roots using the Remainder Theorem for p(x)=x^3-6x^2+11x-6, candidates 1,2,3.

Problem 146

Test possible rational roots using the Remainder Theorem for p(x)=2x^3-x-1, candidates 1, -1, 1/2.

Problem 147

Test possible rational roots using the Remainder Theorem for candidate a gives p(a)=0.

Problem 148

Test possible rational roots using the Remainder Theorem for several candidates.

Problem 149

Test possible rational roots using the Remainder Theorem for p(x)=x^2-5x+6, candidates 1,2,3.

Problem 150

Test possible rational roots using the Remainder Theorem for p(x)=x^3-7x+6, candidates 1,-1,2,-2.

Problem 151

Test possible rational roots using the Remainder Theorem for p(x)=2x^3+3x^2-8x+3, candidates 1,-1,1/2,-3.

Problem 152

Test possible rational roots using the Remainder Theorem for p(x)=x^2+1, candidates 1,-1,2,-2.

Problem 153

Test possible rational roots using the Remainder Theorem for p(x)=x^4-5x^2+4, candidates 1,-1,2,-2.

Problem 154

Test possible rational roots using the Remainder Theorem for p(x)=x^3+2x^2-5x-6, candidates 1,-1,2,-2,3,-3.

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Problem 155

Test possible rational roots using the Remainder Theorem for p(x)=3x^2-2x-1, candidates 1,-1,1/3,-1/3.

Problem 156

Test possible rational roots using the Remainder Theorem for p(x)=x^3-8, candidates 1,2,3.

Problem 157

Test possible rational roots using the Remainder Theorem for p(x)=4x^2+4x-3, candidates 1,-1,1/2,-3/2.

Problem 158

Test possible rational roots using the Remainder Theorem for p(x)=3x-1, candidates 1,-1,1/3,-1/3.

Problem 159

Test possible rational roots using the Remainder Theorem for p(x)=6x^3+x^2-4x+1, candidates 1,-1,1/2,-1/3,1/6.

use division identity `p(x)=(x-a)q(x)+r`.
15 problems Warmup Practice Mixed Review Assessment
Problem 160

Complete the Remainder Theorem explanation using p(x)=(x-a)q(x)+r.

Problem 161

Complete the Remainder Theorem explanation using why remainder is constant for division by x-a.

Problem 162

Complete the Remainder Theorem explanation using connect factor theorem.

Problem 163

Complete the Remainder Theorem explanation using symbolic proof.

Problem 164

Complete the Remainder Theorem explanation using the division algorithm.

Problem 165

Complete the Remainder Theorem explanation using evaluating p(x) at x=a.

Problem 166

Complete the Remainder Theorem explanation using the role of (x-a)q(x).

Problem 167

Complete the Remainder Theorem explanation using what happens when x equals the root of the divisor.

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Problem 168

Complete the Remainder Theorem explanation using the general form of polynomial division.

Problem 169

Complete the Remainder Theorem explanation using how to find the remainder without long division.

Problem 170

Complete the Remainder Theorem explanation using the significance of p(a).

Problem 171

Complete the Remainder Theorem explanation using the constant nature of the remainder.

Problem 172

Complete the Remainder Theorem explanation using the algebraic steps involved.

Problem 173

Complete the Remainder Theorem explanation using the relationship between divisor, quotient, and remainder.

Problem 174

Complete the Remainder Theorem explanation using proving p(a)=r.

catch sign of divisor, evaluation, synthetic setup, and factor/remainder confusion.
12 problems Warmup Practice Mixed Review Assessment
Problem 175

Correct the Remainder or Factor Theorem error: A student divides by x+3 but evaluates p(3).

Problem 176

Correct the Remainder or Factor Theorem error: A student says nonzero remainder means x-a is a factor.

Problem 177

Correct the Remainder or Factor Theorem error: A student omits zero placeholder in synthetic division.

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Problem 178

Correct the Remainder or Factor Theorem error: A student uses the quotient as the remainder.

Problem 179

Correct the Remainder or Factor Theorem error: A student divides by x-2 but uses -2 for synthetic division.

Problem 180

Correct the Remainder or Factor Theorem error: A student states that if p(5) = 0, then x+5 is a factor.

Problem 181

Correct the Remainder or Factor Theorem error: A student evaluates p(-4) when checking if x-4 is a factor.

Problem 182

Correct the Remainder or Factor Theorem error: A student performs synthetic division but writes the coefficients in decreasing order of powers, starting from the constant term.

Problem 183

Correct the Remainder or Factor Theorem error: A student concludes that because the remainder is 7, the divisor x-a is not a factor, but then states that x+a must be a factor.

Problem 184

Correct the Remainder or Factor Theorem error: A student uses the Remainder Theorem to find the remainder when dividing by 2x-1 by evaluating p(1).

Problem 185

Correct the Remainder or Factor Theorem error: A student says the remainder is the first number in the last row of synthetic division.

Problem 186

Correct the Remainder or Factor Theorem error: A student states that if x-a is a factor, then p(-a) must be zero.