Math III · A-APR.3

Identifying Zeros from Factorizations and Sketching Polynomial Graphs

Factored form turns a polynomial graph into a readable map of zeros, crossings, touches, and end behavior.

Concept Algebra
Domain Arithmetic with Polynomials and Rational Expressions
Read time 8 minutes

What this learning objective is really asking you to learn

This objective asks students to read polynomial graphs from factored form. A polynomial's factorization reveals its zeros. The zeros are the x-values that make the polynomial equal to zero. On the graph, real zeros appear as x-intercepts.

For example, if

\[p(x) = (x - 2)(x + 3)(x - 5)\]

then the zeros are \(x = 2\), \(x = -3\), and \(x = 5\). The graph crosses or touches the x-axis at those values.

This objective goes beyond simply listing zeros. Students must use the zeros to sketch the graph. That means identifying x-intercepts, understanding end behavior from degree and leading coefficient, and recognizing how the graph behaves at zeros. Some zeros are crossings; others are touches or bounces. The multiplicity of a factor helps determine this behavior.

Multiplicity means how many times a factor appears. In

\[p(x) = (x - 2)^2(x + 1)\]

the zero \(x = 2\) has multiplicity 2, and the zero \(x = -1\) has multiplicity 1. A zero with odd multiplicity usually crosses the x-axis. A zero with even multiplicity usually touches the x-axis and turns around. This is not just a visual trick; it comes from the sign behavior of powers. Squared factors do not change sign when passing through zero, while single factors do.

Students also need to consider degree and leading coefficient. The degree tells the broad end behavior. An even-degree polynomial with positive leading coefficient rises on both ends. An even-degree polynomial with negative leading coefficient falls on both ends. An odd-degree polynomial with positive leading coefficient falls left and rises right. An odd-degree polynomial with negative leading coefficient rises left and falls right.

The objective is asking students to turn algebraic structure into a graph sketch. Factored form is a map. The zeros are landmarks. Multiplicity tells behavior at those landmarks. Degree and leading coefficient tell what happens far away.

Why students should learn this math

Students should learn this because graphs reveal behavior that formulas can hide. A polynomial in expanded form may be hard to interpret. For example,

\[x^3 - 4x^2 - x + 4\]

does not immediately reveal its zeros. But factored as

\[(x - 4)(x - 1)(x + 1)\]

it tells us the graph crosses the x-axis at \(x = 4\), \(x = 1\), and \(x = -1\).

Zeros are important in real situations. They can represent break-even points, times when height is zero, inputs where error disappears, values where profit changes sign, or equilibrium states. If a polynomial models profit, zeros show sales levels where profit is zero. If it models height, zeros may show when an object is at ground level. If it models a difference between two quantities, zeros show where the quantities are equal.

Sketching from zeros also helps students understand sign. Between zeros, a polynomial may be positive or negative. In a profit model, positive means profit and negative means loss. In a height model, negative may be physically meaningless. In an error model, sign may show overprediction or underprediction. The graph gives a qualitative story.

This objective is also practical because exact graphing is often unnecessary. A sketch with correct zeros, end behavior, and turning tendencies can reveal the essential behavior. Scientists, engineers, economists, and data analysts often begin by understanding qualitative shape before computing exact values.

The “why” is that factored form turns algebra into visual understanding. Students learn to read a polynomial's structure instead of plotting random points blindly.

The historical machinery: roots, factors, and graphs

The study of polynomial roots is one of the oldest and most important parts of algebra. Solving a polynomial equation means finding values where the polynomial equals zero. Factoring became a central method because factors reveal roots. If a product equals zero, at least one factor must be zero.

Coordinate geometry added the graph interpretation. A root of \(p(x)\) is an x-coordinate where the graph of \(y = p(x)\) meets the x-axis. This connected algebraic solving with visual behavior. Later, calculus added more tools for understanding turning points and curvature, but roots and end behavior remain foundational.

The Fundamental Theorem of Algebra says that a degree \(n\) polynomial has \(n\) complex roots counted with multiplicity. A real graph shows only real roots as x-intercepts, but factored form may reveal both real and complex factors depending on the factorization. In Math III graph sketching, students focus mostly on real zeros and real graph behavior.

Historically, polynomial graphing became important because equations, curves, and functions are three views of the same object. This objective asks students to coordinate those views.

Where this fits in the big map of mathematics

This objective follows the Remainder Theorem. Objective 134 connects values, remainders, and factors. Objective 135 uses factors to identify zeros and sketch graphs. Together, they build the core polynomial analysis toolkit.

It connects backward to quadratics. Students already know that factored form of a quadratic reveals x-intercepts. Now that idea extends to higher-degree polynomials.

It connects to end behavior and graph features. Students interpret intercepts, increasing/decreasing behavior, and long-term trends.

It connects forward to polynomial identities, the Binomial Theorem, rational expressions, and solving polynomial equations. Factored form remains a central representation.

It connects to calculus. Later, students will use derivatives to find exact turning points, but polynomial zeros and end behavior are already part of qualitative graph analysis.

The big-map role is representation. Students learn to move from factored algebraic form to visual graph behavior.

How to execute the skill technically

Use this routine:

  1. Identify the degree and leading coefficient.
  2. Determine end behavior.
  3. Set each factor equal to zero to find zeros.
  4. Determine multiplicity of each zero.
  5. Decide whether the graph crosses or touches at each zero.
  6. Plot key intercepts and sketch a smooth curve consistent with the behavior.

Example:

\[p(x) = (x + 2)(x - 1)^2(x - 4)\].

Zeros:

\(x = -2\), \(x = 1\), and \(x = 4\).

Multiplicities:

\(x = -2\) has multiplicity 1, so the graph crosses. \(x = 1\) has multiplicity 2, so the graph touches or bounces. \(x = 4\) has multiplicity 1, so the graph crosses.

Degree is \(1 + 2 + 1 = 4\), even. The leading coefficient is positive because the leading terms multiply to positive \(x^4\). So the graph rises on both ends.

To sketch: start high on the left, cross at -2, stay below until touching and bouncing at 1, remain below until crossing at 4, and rise on the right.

Find the y-intercept by evaluating \(p(0)\):

\[p(0) = (2)(-1)^2(-4) = -8\].

So the graph passes through \((0, -8)\).

This sketch will not show exact turning-point heights unless more work is done, but it captures the main structure.

Worked example: profit model

Suppose profit is modeled by

\[P(x) = -2(x - 10)(x - 30)(x - 50)\],

where \(x\) is units sold in hundreds and \(P(x)\) is profit in thousands of dollars.

Zeros occur at \(x = 10\), \(x = 30\), and \(x = 50\). These are break-even points. Since each factor has multiplicity 1, the graph crosses the x-axis at each zero. The degree is 3, and the leading coefficient is negative, so the graph rises on the left and falls on the right.

In context, negative \(x\) values may not make sense, so the meaningful domain is probably \(x \ge 0\). On that domain, the graph tells where profit is positive or negative. Test \(x = 20\): \(P(20) = -2(10)(-10)(-30)\), which is negative. Test \(x = 40\): \(P(40) = -2(30)(10)(-10)\), which is positive. The business loses money between 10 and 30 hundred units and profits between 30 and 50 hundred units, based on this model.

This example shows why graph behavior matters. The zeros alone are important, but the intervals between them tell the profit/loss story.

Why multiplicity changes graph behavior

At a simple zero like \((x - 3)\), the factor changes sign when \(x\) passes through 3. That sign change usually makes the whole polynomial change sign, so the graph crosses the x-axis.

At an even-multiplicity zero like \((x - 3)^2\), the factor is nonnegative on both sides of 3. It does not change sign. If the other factors do not force a sign change, the graph touches the x-axis and turns around.

At higher odd multiplicities, such as \((x - 3)^3\), the graph crosses but may flatten as it crosses. At higher even multiplicities, such as \((x - 3)^4\), the graph touches and may look flatter near the zero. This gives students a more nuanced graph-reading skill.

Sign charts and intervals

Once zeros are known, students can determine where the polynomial is positive or negative by testing intervals. The zeros divide the x-axis into intervals. Choose one test point in each interval, evaluate the sign of the polynomial, and mark whether the graph is above or below the x-axis.

For example,

\[p(x) = (x + 2)(x - 1)(x - 4)\].

The zeros are -2, 1, and 4. These divide the number line into four intervals: \(x < -2\), \(-2 < x < 1\), \(1 < x < 4\), and \(x > 4\).

Test \(x = -3\): \((-1)(-4)(-7)\) is negative, so the graph is below the x-axis. Test \(x = 0\): \((2)(-1)(-4)\) is positive, so the graph is above. Test \(x = 2\): \((4)(1)(-2)\) is negative, so below. Test \(x = 5\): \((7)(4)(1)\) is positive, so above.

This sign pattern helps sketch the graph and interpret contexts such as profit/loss, above/below target, or positive/negative error.

Expanded form versus factored form

Expanded form and factored form reveal different information. Expanded form makes degree, leading coefficient, and y-intercept easier to see. Factored form makes zeros and multiplicities easier to see. A strong student does not ask which form is “the answer” in isolation. A strong student asks which form reveals the feature needed.

For example,

\[p(x) = x^3 - 6x^2 + 11x - 6\]

shows degree 3 and leading coefficient 1. But

\[p(x) = (x - 1)(x - 2)(x - 3)\]

shows zeros 1, 2, and 3. Both forms are useful.

Limits of a sketch

A polynomial sketch from factors is qualitative. It shows x-intercepts, general end behavior, and crossing/touching behavior. It may not show exact turning points unless additional methods are used. Later, calculus gives powerful tools for locating maxima, minima, and intervals of increase and decrease exactly. In Math III, the goal is a reasonable structural sketch, not a perfect graph.

Students should understand this distinction. A good sketch is not a random drawing. It is constrained by algebraic facts. But it may not include every exact feature unless more computation is done.

Common misconceptions and how to avoid them

One common mistake is listing factors instead of zeros. The factor \(x - 5\) gives zero \(x = 5\), not \(x = -5\).

Another mistake is ignoring multiplicity. Even and odd multiplicities produce different x-axis behavior.

A third mistake is sketching straight line segments. Polynomial graphs are smooth curves, not connect-the-dot line graphs.

A fourth mistake is ignoring leading coefficient and degree. End behavior must match the polynomial's overall structure.

A fifth mistake is thinking zeros are the whole graph. Zeros are landmarks, but y-intercept, end behavior, and sign intervals also matter.

The big takeaway

Factored form reveals the zeros of a polynomial. Zeros become x-intercepts on the graph. Multiplicity tells whether the graph crosses or touches at each zero. Degree and leading coefficient tell end behavior. This objective teaches students to read polynomial graphs from structure rather than plotting blindly.

Problem Library

Problems in the App From This Objective

180 problems across 15 archetypes in the app.

set each factor equal to zero.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Identify zeros from linear factors in (x-3)(x+2)(2x-1).

Problem 2

Identify zeros from linear factors in x(x+5)(x-4).

Problem 3

Identify zeros from linear factors in a(x-r)(x-s).

Problem 4

Identify zeros from linear factors in (kx+b).

Problem 5

Identify zeros from linear factors in (x-1)(x+1).

Problem 6

Identify zeros from linear factors in (x-5)^2.

Problem 7

Identify zeros from linear factors in (3x-6)(x+2).

Problem 8

Identify zeros from linear factors in (-x+4)(x-7).

Problem 9

Identify zeros from linear factors in (2x+3)(4x-5).

Problem 10

Identify zeros from linear factors in (5x-10).

Problem 11

Identify zeros from linear factors in x(x-1)(x+1)(x-2).

Problem 12

Identify zeros from linear factors in (-2x-4)(3x-9).

Open in simulator
read repeated factor exponents.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Identify multiplicity of zeros from factored form (x-2)^3(x+1)^2.

Problem 14

Identify multiplicity of zeros from factored form x^4(x-5).

Problem 15

Identify multiplicity of zeros from factored form (x-r)^m.

Problem 16

Identify multiplicity of zeros from factored form (2x-1)^2.

Problem 17

Identify multiplicity of zeros from factored form (x+3)^1(x-4)^2.

Problem 18

Identify multiplicity of zeros from factored form x^2(3x+6)^3.

Problem 19

Identify multiplicity of zeros from factored form (x+1/2)^5.

Problem 20

Identify multiplicity of zeros from factored form (x+5)^3(x-1)^1(x+2)^2.

Problem 21

Identify multiplicity of zeros from factored form (x-7)^6.

Open in simulator
Problem 22

Identify multiplicity of zeros from factored form x^3(-x+4)^2.

Problem 23

Identify multiplicity of zeros from factored form (2x+3)^1(x-1/3)^2.

Problem 24

Identify multiplicity of zeros from factored form (x-1)(x+2)(x-3).

determine crossing, touching, or flattening behavior.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Describe graph behavior at zeros by multiplicity for zero x=2 has multiplicity 1.

Problem 26

Describe graph behavior at zeros by multiplicity for zero x=-1 has multiplicity 2.

Open in simulator
Problem 27

Describe graph behavior at zeros by multiplicity for zero x=3 has multiplicity 3.

Problem 28

Describe graph behavior at zeros by multiplicity for even multiplicity zero.

Problem 29

Describe graph behavior at zeros by multiplicity for zero x=0 has multiplicity 4.

Problem 30

Describe graph behavior at zeros by multiplicity for zero x=-5 has multiplicity 5.

Problem 31

Describe graph behavior at zeros by multiplicity for zero x=10 has multiplicity 1.

Problem 32

Describe graph behavior at zeros by multiplicity for zero x=7 has multiplicity 2.

Problem 33

Describe graph behavior at zeros by multiplicity for zero x=-3 has multiplicity 3.

Problem 34

Describe graph behavior at zeros by multiplicity for zero x=1 has multiplicity 6.

Problem 35

Describe graph behavior at zeros by multiplicity for zero x=-2 has multiplicity 7.

Problem 36

Describe graph behavior at zeros by multiplicity for a zero with multiplicity 8.

use degree and leading coefficient.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Determine end behavior from factored polynomial -2(x-1)^3(x+4).

Problem 38

Determine end behavior from factored polynomial 3x(x-2)^2.

Problem 39

Determine end behavior from factored polynomial -(x+1)(x-2)(x-5).

Problem 40

Determine end behavior from factored polynomial a product of factors.

Problem 41

Determine end behavior from factored polynomial (x+1)^2(x-3)^2.

Problem 42

Determine end behavior from factored polynomial -5x^2(x+2)^2.

Problem 43

Determine end behavior from factored polynomial x(x-1)(x+2).

Problem 44

Determine end behavior from factored polynomial -x(x+5)(x-4).

Problem 45

Determine end behavior from factored polynomial (x-1)^4.

Problem 46

Determine end behavior from factored polynomial -3(x+2)^6.

Problem 47

Determine end behavior from factored polynomial 2x^3(x-5)^2.

Open in simulator
Problem 48

Determine end behavior from factored polynomial -(x+1)^3(x-2)(x+3).

combine zeros, multiplicities, and end behavior.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Sketch polynomial graph features from factored form (x+2)(x-1)^2.

Problem 50

Sketch polynomial graph features from factored form -x(x-3)^2.

Problem 51

Sketch polynomial graph features from factored form (x+1)^3(x-2).

Problem 52

Sketch polynomial graph features from factored form a(x-r)^m factors.

Problem 53

Sketch polynomial graph features from factored form (x-1)(x+3).

Problem 54

Sketch polynomial graph features from factored form -(x+2)(x-4).

Problem 55

Sketch polynomial graph features from factored form x(x-1)(x+1).

Problem 56

Sketch polynomial graph features from factored form -2x(x+3)(x-2).

Problem 57

Sketch polynomial graph features from factored form (x-2)^2(x+1)^2.

Problem 58

Sketch polynomial graph features from factored form -(x+1)^3(x-3).

Open in simulator
Problem 59

Sketch polynomial graph features from factored form (x-1)^2(x+2)^3.

Problem 60

Sketch polynomial graph features from factored form -x^2(x-4)(x+1)^2.

compare zeros, multiplicities, and end behavior.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Match factored polynomial to graph using polynomial (x+1)^2(x-3), graph options show touch at -1 and cross at 3.

Problem 62

Match factored polynomial to graph using polynomial -x(x-2)^2.

Problem 63

Match factored polynomial to graph using same zeros but different multiplicities.

Problem 64

Match factored polynomial to graph using same zeros and multiplicities but different leading sign.

Problem 65

Match factored polynomial to graph using polynomial (x-1)^2(x-3)^2.

Problem 66

Match factored polynomial to graph using polynomial -(x+2)(x-1)(x-3)(x+1).

Problem 67

Match factored polynomial to graph using polynomial x(x+3)(x-2).

Problem 68

Match factored polynomial to graph using polynomial -(x-1)(x+2)^2.

Problem 69

Match factored polynomial to graph using polynomial (x+2)(x-1)^2(x-3).

Problem 70

Match factored polynomial to graph using polynomial -x^2(x-4)(x+1).

Problem 71

Match factored polynomial to graph using polynomial (x-2)^3(x+1).

Open in simulator
Problem 72

Match factored polynomial to graph using polynomial -(x+1)(x-1)(x-2).

identify zeros, multiplicities, and leading coefficient sign.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Write a factored polynomial from graph features crosses at -2, touches at 3, positive leading coefficient.

Problem 74

Write a factored polynomial from graph features touches at 0, crosses at 4, negative right end.

Problem 75

Write a factored polynomial from graph features crosses with flattening at -1 and crosses at 2.

Problem 76

Write a factored polynomial from graph features zeros r_i with multiplicities m_i.

Problem 77

Write a factored polynomial from graph features touches at -1, crosses at 2, negative leading coefficient.

Problem 78

Write a factored polynomial from graph features crosses at -3, 0, and 1, positive leading coefficient.

Open in simulator
Problem 79

Write a factored polynomial from graph features crosses with flattening at 0, touches at 5, negative leading coefficient.

Problem 80

Write a factored polynomial from graph features touches at 4, crosses at -2, positive leading coefficient.

Problem 81

Write a factored polynomial from graph features crosses at -1, touches at 1, crosses at 3, negative leading coefficient.

Problem 82

Write a factored polynomial from graph features crosses with flattening at -2, positive leading coefficient.

Problem 83

Write a factored polynomial from graph features touches at 1 with a flat bottom, negative leading coefficient.

Problem 84

Write a factored polynomial from graph features crosses at -3, touches at 2, crosses at 0, positive leading coefficient.

evaluate `p(0)`.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Find the y-intercept from factored polynomial (x-2)(x+3).

Problem 86

Find the y-intercept from factored polynomial -2x(x-1)^2.

Problem 87

Find the y-intercept from factored polynomial 3(x+1)(x-4).

Problem 88

Find the y-intercept from factored polynomial a product of factors.

Problem 89

Find the y-intercept from factored polynomial (x+1)(x-5).

Problem 90

Find the y-intercept from factored polynomial 2(x-3)(x+2).

Problem 91

Find the y-intercept from factored polynomial (x-1)(x+2)(x-3).

Problem 92

Find the y-intercept from factored polynomial (x+4)^2(x-1).

Problem 93

Find the y-intercept from factored polynomial -3x(x+1)(x-2).

Problem 94

Find the y-intercept from factored polynomial 4(x-1)^3.

Problem 95

Find the y-intercept from factored polynomial -(x+2)(x-3)(x+1).

Open in simulator
Problem 96

Find the y-intercept from factored polynomial 0.5(x-2)(x+4).

divide by corresponding factor and analyze quotient.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Use a known zero to factor and sketch polynomial p(x)=x^3-4x^2+x+6 has known zero 2.

Problem 98

Use a known zero to factor and sketch polynomial p(x)=x^3+x^2-4x-4 has known zero -1.

Problem 99

Use a known zero to factor and sketch polynomial known zero a of p(x).

Problem 100

Use a known zero to factor and sketch polynomial synthetic quotient has irreducible quadratic.

Problem 101

Use a known zero to factor and sketch polynomial p(x)=x^3-6x^2+11x-6 has known zero 1.

Problem 102

Use a known zero to factor and sketch polynomial p(x)=x^3+6x^2+11x+6 has known zero -1.

Problem 103

Use a known zero to factor and sketch polynomial p(x)=x^3-x^2-x-2 has known zero 2.

Problem 104

Use a known zero to factor and sketch polynomial p(x)=x^3+x^2-x+15 has known zero -3.

Problem 105

Use a known zero to factor and sketch polynomial p(x)=x^3-3x+2 has known zero 1.

Open in simulator
Problem 106

Use a known zero to factor and sketch polynomial p(x)=x^3+x^2-8x-12 has known zero -2.

Problem 107

Use a known zero to factor and sketch polynomial p(x)=x^3-4x^2-x+4 has known zero -1.

Problem 108

Use a known zero to factor and sketch polynomial p(x)=x^3+3x^2-6x-8 has known zero 2.

use at most degree minus one turning points.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Identify possible turning-point count from degree for degree 3 polynomial.

Problem 110

Identify possible turning-point count from degree for degree 4 polynomial.

Open in simulator
Problem 111

Identify possible turning-point count from degree for degree n polynomial.

Problem 112

Identify possible turning-point count from degree for quintic graph with 4 turns.

Problem 113

Identify possible turning-point count from degree for degree 2 polynomial.

Problem 114

Identify possible turning-point count from degree for degree 5 polynomial.

Problem 115

Identify possible turning-point count from degree for quadratic function.

Problem 116

Identify possible turning-point count from degree for sextic polynomial.

Problem 117

Identify possible turning-point count from degree for a polynomial of degree 7 with 6 turning points.

Problem 118

Identify possible turning-point count from degree for a quartic polynomial with 4 turning points.

Problem 119

Identify possible turning-point count from degree for degree 1 polynomial.

Problem 120

Identify possible turning-point count from degree for a degree 6 polynomial with 3 turning points.

identify which roots appear as x-intercepts.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Distinguish real zeros from complex zeros in graph sketching for (x-2)(x^2+1).

Problem 122

Distinguish real zeros from complex zeros in graph sketching for (x+3)(x^2+4).

Problem 123

Distinguish real zeros from complex zeros in graph sketching for (x^2-4)(x^2+9).

Problem 124

Distinguish real zeros from complex zeros in graph sketching for irreducible quadratic factor over reals.

Problem 125

Distinguish real zeros from complex zeros in graph sketching for (x+1)(x^2+25).

Problem 126

Distinguish real zeros from complex zeros in graph sketching for (x-5)(x^2+16).

Problem 127

Distinguish real zeros from complex zeros in graph sketching for (x^2+1)(x^2+4).

Problem 128

Distinguish real zeros from complex zeros in graph sketching for (x-1)(x+1)(x^2+100).

Open in simulator
Problem 129

Distinguish real zeros from complex zeros in graph sketching for (x^2+9)(x-7).

Problem 130

Distinguish real zeros from complex zeros in graph sketching for (x^2+2x+5)(x-4).

Problem 131

Distinguish real zeros from complex zeros in graph sketching for (x^2+x+1)(x+2)(x-2).

Problem 132

Distinguish real zeros from complex zeros in graph sketching for (x^2+36).

test intervals or use multiplicity behavior.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Determine interval sign of polynomial from zeros for p(x)=(x-1)(x+2), intervals around -2 and 1.

Problem 134

Determine interval sign of polynomial from zeros for p(x)=(x-3)^2(x+1).

Problem 135

Determine interval sign of polynomial from zeros for simple odd-multiplicity zeros.

Problem 136

Determine interval sign of polynomial from zeros for even-multiplicity zero.

Open in simulator
Problem 137

Determine interval sign of polynomial from zeros for p(x)=x(x+3)(x-2).

Problem 138

Determine interval sign of polynomial from zeros for p(x)=-(x+1)^2(x-2).

Problem 139

Determine interval sign of polynomial from zeros for p(x)=(x+2)^2(x-1)^2.

Problem 140

Determine interval sign of polynomial from zeros for p(x)=-x(x-1)(x+1).

Problem 141

Determine interval sign of polynomial from zeros for p(x)=x^3(x-4).

Problem 142

Determine interval sign of polynomial from zeros for p(x)=(x+4)^2 x^2 (x-3).

Problem 143

Determine interval sign of polynomial from zeros for p(x)=(x-5)^3.

Problem 144

Determine interval sign of polynomial from zeros for p(x)=-(x+2)^4.

identify intervals above/below x-axis.
12 problems Warmup Practice Mixed Review Assessment
Problem 145

Solve polynomial inequality using zeros and sign behavior: (x-1)(x+2)>0.

Problem 146

Solve polynomial inequality using zeros and sign behavior: (x-3)^2(x+1)<=0.

Problem 147

Solve polynomial inequality using zeros and sign behavior: p(x)>=0 from sign chart.

Open in simulator
Problem 148

Solve polynomial inequality using zeros and sign behavior: p(x)<0.

Problem 149

Solve polynomial inequality using zeros and sign behavior: x^2 - 4 <= 0.

Problem 150

Solve polynomial inequality using zeros and sign behavior: x^2 - 9 < 0.

Problem 151

Solve polynomial inequality using zeros and sign behavior: x(x-1)(x+3) > 0.

Problem 152

Solve polynomial inequality using zeros and sign behavior: (x+2)^2(x-1) >= 0.

Problem 153

Solve polynomial inequality using zeros and sign behavior: (x-1)^2(x+1)^2 <= 0.

Problem 154

Solve polynomial inequality using zeros and sign behavior: (x^2+1)(x^2+4) > 0.

Problem 155

Solve polynomial inequality using zeros and sign behavior: (x^2+2)(x^2+3) < 0.

Problem 156

Solve polynomial inequality using zeros and sign behavior: -2(x-1)(x+3) >= 0.

connect roots and signs to modeled situation.
12 problems Warmup Practice Mixed Review Assessment
Problem 157

Interpret zeros and graph behavior in context: profit polynomial zeros at x=2 and x=8, positive between.

Problem 158

Interpret zeros and graph behavior in context: height model has zero at t=5 crossing downward.

Problem 159

Interpret zeros and graph behavior in context: volume expression zero at x=0 and x=4 with physical domain 0<x<4.

Problem 160

Interpret zeros and graph behavior in context: revenue polynomial sign changes from positive to negative at root.

Problem 161

Interpret zeros and graph behavior in context: population model has zeros at t=0 and t=10, positive between.

Open in simulator
Problem 162

Interpret zeros and graph behavior in context: temperature model has a zero at t=7, positive before, negative after.

Problem 163

Interpret zeros and graph behavior in context: cost function has a zero at x=0, positive for x>0.

Problem 164

Interpret zeros and graph behavior in context: drug concentration model has zeros at t=0 and t=8, positive between.

Problem 165

Interpret zeros and graph behavior in context: projectile height model has zeros at t=0 and t=4, positive between.

Problem 166

Interpret zeros and graph behavior in context: budget model has a zero at year 2005, negative before, positive after.

Problem 167

Interpret zeros and graph behavior in context: area function has zeros at x=0 and x=6, positive between, physical domain 0<x<6.

Problem 168

Interpret zeros and graph behavior in context: velocity model has a zero at t=3, positive before, negative after.

catch root, multiplicity, end behavior, and intercept errors.
12 problems Warmup Practice Mixed Review Assessment
Problem 169

Correct the polynomial graph sketch from factorization error: A sketch crosses at a double root.

Problem 170

Correct the polynomial graph sketch from factorization error: A sketch has wrong end behavior for negative leading cubic.

Problem 171

Correct the polynomial graph sketch from factorization error: A sketch shows an x-intercept for x^2+4.

Problem 172

Correct the polynomial graph sketch from factorization error: A sketch omits y-intercept from p(0).

Problem 173

Correct the polynomial graph sketch from factorization error: A sketch crosses linearly at a triple root.

Open in simulator
Problem 174

Correct the polynomial graph sketch from factorization error: A sketch shows a positive even degree polynomial with one end up and one end down.

Problem 175

Correct the polynomial graph sketch from factorization error: A sketch shows an x-intercept for a factor of (x^2+9).

Problem 176

Correct the polynomial graph sketch from factorization error: A sketch shows a positive odd degree polynomial with both ends going up.

Problem 177

Correct the polynomial graph sketch from factorization error: A sketch touches the x-axis at a simple root.

Problem 178

Correct the polynomial graph sketch from factorization error: A sketch shows a negative even degree polynomial with both ends going up.

Problem 179

Correct the polynomial graph sketch from factorization error: A sketch omits an x-intercept at x=5 from the factor (x-5).

Problem 180

Correct the polynomial graph sketch from factorization error: A sketch includes an x-intercept at x=2 when (x-2) is not a factor.