Math III · A-SSE.4

Deriving and Using the Finite Geometric Series Formula

Finite geometric series explain repeated multiplicative accumulation, which is the machinery behind savings plans, loans, mortgages, depreciation, and many staged processes.

Concept Algebra
Domain Seeing Structure in Expressions
Read time 6 minutes

What this learning objective is really asking you to learn

This objective asks students to derive and use the finite geometric series formula. A geometric sequence changes by multiplying by a constant ratio. A geometric series is the sum of terms in a geometric sequence. A finite geometric series has a limited number of terms.

For example,

\[3 + 6 + 12 + 24 + 48\]

is a finite geometric series. The first term is 3, the common ratio is 2, and there are 5 terms.

The formula for the sum of the first \(n\) terms of a geometric series is often written as

\[S_{n} = a(1 - r^n)/(1 - r)\]

when \(r \ne 1\), where \(a\) is the first term, \(r\) is the common ratio, and \(n\) is the number of terms.

An equivalent form is

\[S_{n} = a(r^n - 1)/(r - 1)\].

These are the same formula, written with signs adjusted.

The objective asks students to derive the formula, not just use it. The derivation is a classic algebraic move. Let

\[S = a + ar + ar^2 + ... + ar^(n-1)\].

Multiply both sides by \(r\):

\[rS = ar + ar^2 + ar^3 + ... + ar^n\].

Subtract:

\[S - rS = a - ar^n\].

Factor:

\[S(1 - r) = a(1 - r^n)\].

Divide:

\[S = a(1 - r^n)/(1 - r)\].

The cancellation happens because almost all middle terms line up and subtract away. This is the machinery.

This formula is not just a pattern. It is a compact way to sum repeated multiplicative change.

Why students should learn this math

Students should learn finite geometric series because repeated multiplicative accumulation appears in money, growth, decay, and staged processes. If you save the same amount every month and earn interest, each deposit grows for a different number of months. The total future value is a geometric series. If you pay off a loan with regular payments, the present value of payments is related to a geometric series. Mortgage formulas are built from this idea.

This is one of the most practical pieces of advanced algebra. Finance depends heavily on repeated percentage change. Interest compounds. Loan balances grow and shrink. Payments are made periodically. Depreciation happens by a percentage. Investment contributions accumulate at different lengths of time. The finite geometric series formula is the algebra behind many calculators used in banking and personal finance.

The formula also appears outside finance. A bouncing ball that rebounds to a fixed fraction of its previous height creates a geometric series of distances. A signal that loses a fixed fraction at each stage creates a geometric pattern. A medication dosage repeated at intervals can produce accumulated concentration patterns. Computer algorithms may involve repeated scaling and summation.

Students often ask why they need series. The honest answer is that many real totals are not single events. They are sums of repeated events, each scaled by time or decay. A finite geometric series is the exact model for that structure.

The “why” is that the formula turns a long repeated process into a compact expression. It is algebraic compression for accumulation.

The historical machinery: summing repeated growth

Geometric series have been studied for centuries. Ancient mathematicians considered sums of powers and repeated ratios. Problems involving doubling, inheritance, compound growth, and geometric patterns naturally lead to series.

The finite geometric series formula became important because it gives a closed form. Instead of adding many terms one by one, a single formula gives the total. This kind of compression is one of algebra's great achievements.

Finance made geometric series especially practical. Compound interest and annuities require summing payments that grow or discount by constant ratios. Mortgage-payment formulas come from equating a loan amount to the present value of a finite series of payments. Although actual finance can include fees, changing rates, and complicated rules, the core algebra is geometric series.

In later mathematics, infinite geometric series become central to calculus, power series, and approximation. A finite series is the starting point. When \(|r| < 1\), an infinite geometric series approaches \(a/(1 - r)\). Students may see that later, but the finite formula gives the foundation.

Where this fits in the big map of mathematics

This objective connects sequences, exponents, functions, finance, and algebraic manipulation.

It connects backward to geometric sequences. A geometric series is the sum of a geometric sequence.

It connects to exponential functions because the terms involve powers of the common ratio.

It connects to rational expressions because the closed formula is a rational expression involving \(1 - r\).

It connects to modeling because series represent accumulated repeated processes.

It connects forward to logarithms, finance formulas, recurrence relations, and infinite series.

It connects to probability and combinatorics indirectly because series often arise in repeated trials and expected values.

The big-map role is accumulation. Students learn how repeated multiplicative terms add up.

How to execute the skill technically

To use the finite geometric series formula, identify:

  • first term \(a\);
  • common ratio \(r\);
  • number of terms \(n\).

Then apply

\[S_{n} = a(1 - r^n)/(1 - r)\].

Example: sum

\[5 + 15 + 45 + 135\].

Here \(a = 5\), \(r = 3\), and \(n = 4\).

\[S_{4} = 5(1 - 3^4)/(1 - 3)\].

That is

\[5(1 - 81)/(-2) = 5(-80)/(-2) = 200\].

Check by adding: \(5 + 15 + 45 + 135 = 200\).

Example with decay:

\[100 + 80 + 64 + 51.2\].

Here \(a = 100\), \(r = 0.8\), and \(n = 4\).

\[S_{4} = 100(1 - 0.8^4)/(1 - 0.8)\].
\[0.8^4 = 0.4096\].

So

\[S_{4} = 100(0.5904)/0.2 = 295.2\].

This matches the sum.

Students should be careful when \(r = 1\). If the ratio is 1, every term is \(a\), so the sum is simply \(an\). The formula with denominator \(1 - r\) would divide by zero.

Worked example: savings deposits

Suppose a person deposits $200 at the end of each year into an account earning 5% per year. What is the value of the deposits after 4 years, assuming the last deposit is made at the end of year 4 and earns no interest before the total is counted?

The first deposit grows for 3 years: \(200(1.05)^3\). The second grows for 2 years: \(200(1.05)^2\). The third grows for 1 year: \(200(1.05)\). The fourth grows for 0 years: 200.

Total:

\[200[(1.05)^3 + (1.05)^2 + 1.05 + 1]\].

This is a finite geometric series with first written term 1 if ordered from last deposit backward, ratio 1.05, and 4 terms:

\[200[1 + 1.05 + 1.05^2 + 1.05^3]\].

Using the formula:

\[200(1 - 1.05^4)/(1 - 1.05)\].

This gives the accumulated value. The formula is not arbitrary; it sums each deposit after its own growth period.

Mortgage-payment connection

Mortgage-payment formulas are more complicated, but the same idea is underneath. A loan amount can be viewed as the present value of many future payments. Each future payment is discounted by a power of a common ratio related to the interest rate. The sum of those discounted payments is a finite geometric series.

Students do not need to derive a full mortgage formula to understand the machinery: repeated equal payments plus compound interest creates a geometric series. This is one of the clearest real-world reasons to learn the topic.

Deriving the formula with actual cancellation

Students often memorize the finite geometric series formula without seeing why it works. The derivation should be shown with a concrete series first.

Let

\[S = 2 + 2r + 2r^2 + 2r^3 + 2r^4\].

Multiply by \(r\):

\[rS = 2r + 2r^2 + 2r^3 + 2r^4 + 2r^5\].

Subtract:

\[S - rS = 2 - 2r^5\].

All middle terms cancel. Factor:

\[S(1 - r) = 2(1 - r^5)\].

So

\[S = 2(1 - r^5)/(1 - r)\].

Now students can see the general pattern. The cancellation is the whole trick. It is not a formula dropped from the sky.

Present value version

Finance often uses a discount ratio. Suppose a payment of $100 is received each year for 5 years, and the discount factor per year is \(1/(1.05)\). The present value is

\[100/(1.05) + 100/(1.05)^2 + 100/(1.05)^3 + 100/(1.05)^4 + 100/(1.05)^5\].

This is a finite geometric series with ratio \(1/1.05\). It represents the idea that money received later is worth less today than money received now, assuming interest or opportunity cost.

This is the same algebraic structure as savings accumulation, but time is viewed backward instead of forward. That flexibility is exactly why geometric series are so important in finance.

Bouncing-ball example

Suppose a ball is dropped from 10 feet and each bounce rises to 60% of the previous height. If we count only the upward bounce heights for the first 4 bounces, the total upward distance is

\[10(0.6) + 10(0.6)^2 + 10(0.6)^3 + 10(0.6)^4\].

This is a finite geometric series. If total travel distance includes downward motion too, the model must be adjusted carefully. This is a good example for teaching students that modeling requires defining exactly what is being summed.

Problem Library

Problems in the App From This Objective

180 problems across 15 archetypes in the app.

find first term, common ratio, and number of terms.
12 problems Warmup Practice Mixed Review Assessment
Problem 1

Identify the first term, common ratio, and term count for the finite geometric series 4+12+36+108+324.

Problem 2

Identify the first term, common ratio, and term count for the finite geometric series 100+80+64+51.2.

Problem 3

Identify the first term, common ratio, and term count for the finite geometric series 5-10+20-40+80.

Open in simulator
Problem 4

Identify the first term, common ratio, and term count for the finite geometric series a+ar+ar^2+ar^3+ar^4.

Problem 5

Identify the first term, common ratio, and term count for the finite geometric series 81 + 27 + 9 + 3 + 1 + 1/3.

Problem 6

Identify the first term, common ratio, and term count for the finite geometric series -2 - 6 - 18 - 54.

Problem 7

Identify the first term, common ratio, and term count for the finite geometric series 16 - 8 + 4 - 2 + 1.

Problem 8

Identify the first term, common ratio, and term count for the finite geometric series 2.5 + 5 + 10.

Problem 9

Identify the first term, common ratio, and term count for the finite geometric series x + 3x + 9x + 27x.

Problem 10

Identify the first term, common ratio, and term count for the finite geometric series -100 + 50 - 25 + 12.5.

Problem 11

Identify the first term, common ratio, and term count for the finite geometric series 1/2 + 1 + 2 + 4 + 8.

Problem 12

Identify the first term, common ratio, and term count for the finite geometric series b + bc + bc^2 + bc^3 + bc^4 + bc^5.

use `S_n=a(1-r^n)/(1-r)`.
12 problems Warmup Practice Mixed Review Assessment
Problem 13

Find the sum of the finite geometric series with first term 3, ratio 2, and 6 terms.

Open in simulator
Problem 14

Find the sum of the finite geometric series with first term 100, ratio 0.5, and 4 terms.

Problem 15

Find the sum of the finite geometric series with first term 5, ratio -2, and 5 terms.

Problem 16

Find the sum of the finite geometric series with first term 7, ratio 1, and 8 terms.

Problem 17

Find the sum of the finite geometric series with first term 2, ratio 3, and 5 terms.

Problem 18

Find the sum of the finite geometric series with first term 64, ratio 1/2, and 7 terms.

Problem 19

Find the sum of the finite geometric series with first term -4, ratio 2, and 4 terms.

Problem 20

Find the sum of the finite geometric series with first term 10, ratio -3, and 3 terms.

Problem 21

Find the sum of the finite geometric series with first term 15, ratio 1, and 5 terms.

Problem 22

Find the sum of the finite geometric series with first term 2.5, ratio 0.2, and 3 terms.

Problem 23

Find the sum of the finite geometric series with first term -1, ratio -2, and 4 terms.

Problem 24

Find the sum of the finite geometric series with first term 1, ratio 10, and 4 terms.

multiply by r, subtract, and solve for sum.
12 problems Warmup Practice Mixed Review Assessment
Problem 25

Derive the finite geometric series formula for S=a+ar+ar^2+.+ar^(n-1) by subtracting a shifted series.

Problem 26

Derive the finite geometric series formula for S=1+r+r^2+.+r^(n-1) by subtracting a shifted series.

Problem 27

Derive the finite geometric series formula for S=2+2r+2r^2+.+2r^(n-1) by subtracting a shifted series.

Problem 28

Derive the finite geometric series formula for S=a+a+.+a for n terms by subtracting a shifted series.

Problem 29

Derive the finite geometric series formula for S=3+3r+3r^2+.+3r^(n-1) by subtracting a shifted series.

Open in simulator
Problem 30

Derive the finite geometric series formula for S=x+xr+xr^2+.+xr^(n-1) by subtracting a shifted series.

Problem 31

Derive the finite geometric series formula for S=a+ax+ax^2+.+ax^(n-1) by subtracting a shifted series.

Problem 32

Derive the finite geometric series formula for S=1+x+x^2+.+x^(n-1) by subtracting a shifted series.

Problem 33

Derive the finite geometric series formula for S=a+ar+ar^2+.+ar^n by subtracting a shifted series.

Problem 34

Derive the finite geometric series formula for S=a+ar+ar^2+ar^3+ar^4 by subtracting a shifted series.

Problem 35

Derive the finite geometric series formula for S=5+5r+5r^2+5r^3+5r^4+5r^5 by subtracting a shifted series.

Problem 36

Derive the finite geometric series formula for S=-1-r-r^2-.-r^(n-1) by subtracting a shifted series.

interpret index, first term, ratio, and bounds.
12 problems Warmup Practice Mixed Review Assessment
Problem 37

Interpret the finite geometric series written in sigma notation: sum from k=0 to 5 of 3(2)^k.

Problem 38

Interpret the finite geometric series written in sigma notation: sum from k=1 to 4 of 5(0.8)^(k-1).

Problem 39

Interpret the finite geometric series written in sigma notation: sum from i=2 to 6 of 7(3)^(i-2).

Problem 40

Interpret the finite geometric series written in sigma notation: sum from n=1 to 10 of 4.

Problem 41

Interpret the finite geometric series written in sigma notation: sum from j=1 to 5 of 10(0.5)^(j-1).

Problem 42

Interpret the finite geometric series written in sigma notation: sum from m=0 to 3 of 2(-4)^m.

Open in simulator
Problem 43

Interpret the finite geometric series written in sigma notation: sum from p=3 to 7 of 6(1/3)^(p-3).

Problem 44

Interpret the finite geometric series written in sigma notation: sum from k=1 to 8 of 9(1)^k.

Problem 45

Interpret the finite geometric series written in sigma notation: sum from i=0 to 4 of 1.5(2.5)^i.

Problem 46

Interpret the finite geometric series written in sigma notation: sum from n=2 to 5 of 8(-0.5)^(n-2).

Problem 47

Interpret the finite geometric series written in sigma notation: sum from x=1 to 3 of 100(0.1)^(x-1).

Problem 48

Interpret the finite geometric series written in sigma notation: sum from y=4 to 6 of 12(2/3)^(y-4).

model payment accumulation over time.
12 problems Warmup Practice Mixed Review Assessment
Problem 49

Model repeated payments with interest as a finite geometric series for deposit 100 at the end of each month for 6 months at monthly growth factor 1.01.

Problem 50

Model repeated payments with interest as a finite geometric series for save 50 weekly for 10 weeks at weekly factor 1.002.

Problem 51

Model repeated payments with interest as a finite geometric series for annual contributions of 500 for 4 years at factor 1.06.

Open in simulator
Problem 52

Model repeated payments with interest as a finite geometric series for monthly payment P for n months at factor b.

Problem 53

Model repeated payments with interest as a finite geometric series for deposit 200 at the end of each quarter for 5 quarters at quarterly growth factor 1.02.

Problem 54

Model repeated payments with interest as a finite geometric series for save 75 bi-weekly for 8 bi-weekly periods at bi-weekly factor 1.005.

Problem 55

Model repeated payments with interest as a finite geometric series for invest 1000 annually for 3 years at an annual interest rate of 5%.

Problem 56

Model repeated payments with interest as a finite geometric series for regular payment R made k times at a periodic factor f.

Problem 57

Model repeated payments with interest as a finite geometric series for deposit 500 at the end of each year for 2 years at annual factor 1.04.

Problem 58

Model repeated payments with interest as a finite geometric series for monthly contributions of 25 for 12 months at monthly factor 1.003.

Problem 59

Model repeated payments with interest as a finite geometric series for euro deposits of 150 at the end of each month for 7 months at monthly growth factor 1.008.

Problem 60

Model repeated payments with interest as a finite geometric series for An amount A is paid periodically for T periods at a growth factor G.

combine principal growth and payment series.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Build a loan balance model using principal 1000, periodic factor 1.01, payment 100, and 6 payments.

Problem 62

Build a loan balance model using principal L, periodic factor b, payment P, and n payments.

Problem 63

Build a loan balance model using principal 25000, periodic factor 1.005, payment 450, and 12 payments.

Problem 64

Build a loan balance model using principal 8000, periodic factor 1, payment 500, and 10 payments.

Problem 65

Build a loan balance model using principal 5000, periodic factor 1.02, payment 200, and 3 payments.

Problem 66

Build a loan balance model using principal 15000, periodic factor 1.0075, payment 300, and 24 payments.

Problem 67

Build a loan balance model using principal 12000, periodic factor 1, payment 1000, and 8 payments.

Problem 68

Build a loan balance model using principal P0, periodic factor r, payment M, and t payments.

Problem 69

Build a loan balance model using principal 10000, periodic factor k, payment 500, and N payments.

Problem 70

Build a loan balance model using principal 3000, periodic factor 1, payment 150, and 20 payments.

Problem 71

Build a loan balance model using principal 100000, periodic factor 1.0025, payment 1200, and 60 payments.

Open in simulator
Problem 72

Build a loan balance model using principal 500, periodic factor 1.05, payment 50, and 2 payments.

solve formula for payment.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Find the periodic payment needed for save 5000 in 24 months at monthly factor 1.004 with end-of-month deposits.

Problem 74

Find the periodic payment needed for pay off loan L over n periods at factor b.

Problem 75

Find the periodic payment needed for accumulate target T with n deposits at factor r.

Problem 76

Find the periodic payment needed for no-interest target T over n payments.

Problem 77

Find the periodic payment needed for save 10000 in 5 years with quarterly deposits at 4% annual interest compounded quarterly.

Problem 78

Find the periodic payment needed for pay off a 25000 car loan in 60 months at 6% annual interest compounded monthly.

Problem 79

Find the periodic payment needed for accumulate 1000000 for equipment replacement in 10 years with annual deposits at 5% annual interest.

Problem 80

Find the periodic payment needed for pay off a 300000 mortgage over 30 years with monthly payments at 4.5% annual interest compounded monthly.

Problem 81

Find the periodic payment needed for accumulate 500000 for retirement in 20 years with annual contributions at an annual growth factor of 1.07.

Open in simulator
Problem 82

Find the periodic payment needed for repay a 15000 personal loan in 36 monthly installments with a monthly interest factor of 1.012.

Problem 83

Find the periodic payment needed for save 75000 for college in 18 years with monthly deposits at 3.6% annual interest compounded monthly.

Problem 84

Find the periodic payment needed for pay off a 40000 equipment lease over 48 months at an implied monthly interest rate of 0.8%.

solve geometric series equation with logs/technology.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Find the number of periods needed to reach 100 deposits grow with series 100[(1.01)^n-1]/0.01 >= 2000.

Problem 86

Find the number of periods needed to reach loan balance L*b^n-P(b^n-1)/(b-1)<=0.

Problem 87

Find the number of periods needed to reach doubling repeated value 50(2^n-1)>=1000.

Problem 88

Find the number of periods needed to reach constant deposits with no interest Pn>=T.

Problem 89

Find the number of periods needed to reach an initial investment of $500 compounded at 5% annually reaches $1500.

Problem 90

Find the number of periods needed to reach monthly deposits of $200 into an account earning 6% annual interest compounded monthly reach $10,000.

Open in simulator
Problem 91

Find the number of periods needed to reach a loan of $20,000 at 8% annual interest compounded monthly is paid off with monthly payments of $300.

Problem 92

Find the number of periods needed to reach a population of 10,000 growing at 2% annually reaches 15,000.

Problem 93

Find the number of periods needed to reach quarterly deposits of $500 into a sinking fund earning 4% annual interest compounded quarterly reach $12,000.

Problem 94

Find the number of periods needed to reach an investment earning 7% annual interest doubles in value.

Problem 95

Find the number of periods needed to reach an asset worth $50,000 depreciates at 10% annually until its value is $10,000 or less.

Problem 96

Find the number of periods needed to reach beginning-of-period deposits of $150 into an account earning 3% annual interest compounded semi-annually reach $5,000.

distinguish constant addition from repeated multiplication.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Decide whether payments increase by 25 dollars each month should be modeled with an arithmetic or geometric series.

Problem 98

Decide whether value loses 15% each year should be modeled with an arithmetic or geometric series.

Problem 99

Decide whether account earns 1% interest between equal deposits should be modeled with an arithmetic or geometric series.

Problem 100

Decide whether stair-step cost adds the same fee for each extra item should be modeled with an arithmetic or geometric series.

Problem 101

Decide whether a loan payment reduces the principal by 50 dollars each month should be modeled with an arithmetic or geometric series.

Problem 102

Decide whether bacteria population grows by 20% every hour should be modeled with an arithmetic or geometric series.

Problem 103

Decide whether a runner increases their distance by 0.5 miles each week should be modeled with an arithmetic or geometric series.

Problem 104

Decide whether the remaining amount of a substance halves every 12 hours should be modeled with an arithmetic or geometric series.

Problem 105

Decide whether a child's allowance increases by 2 dollars on each birthday should be modeled with an arithmetic or geometric series.

Problem 106

Decide whether an investment account earns 3% interest compounded annually should be modeled with an arithmetic or geometric series.

Problem 107

Decide whether the air pressure drops by 0.1 atmospheres for every 1000 feet of altitude gain should be modeled with an arithmetic or geometric series.

Problem 108

Decide whether a bouncing ball reaches 75% of its previous height with each bounce should be modeled with an arithmetic or geometric series.

Open in simulator
explain first term, ratio, term count, and sum in context.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Interpret each parameter in the finite geometric series formula S=200(1-1.03^12)/(1-1.03) for monthly deposits growing at 3% per month for 12 months.

Problem 110

Interpret each parameter in the finite geometric series formula S=a(1-r^n)/(1-r) for general finite geometric sum.

Problem 111

Interpret each parameter in the finite geometric series formula B=L*b^n-P(b^n-1)/(b-1) for loan balance.

Problem 112

Interpret each parameter in the finite geometric series formula S=50(1-0.8^6)/(1-0.8) for declining values.

Problem 113

Interpret each parameter in the finite geometric series formula FV = 250 * (1.005^60 - 1) / 0.005 for future value of monthly contributions of $250, earning 0.5% interest per month for 60 months, with contributions made at the end of each month.

Problem 114

Interpret each parameter in the finite geometric series formula S = 150 * (1 - 0.6^7) / (1 - 0.6) for total vertical distance covered by a ball over 7 descents, starting with an initial drop of 150 units and each subsequent rebound being 60% of the previous height.

Problem 115

Interpret each parameter in the finite geometric series formula Total_Contrib = 2000 * (1.03^15 - 1) / (1.03 - 1) for total contributions to a charity over 15 years, starting with $2000 in the first year and increasing by 3% annually.

Problem 116

Interpret each parameter in the finite geometric series formula C_final = 120 * (1 - 0.75^10) / (1 - 0.75) for concentration of a drug in the body immediately after 10 doses, where each dose is 120mg and 25% of the drug is eliminated between doses.

Problem 117

Interpret each parameter in the finite geometric series formula Total_Revenue = 75000 * (1 - 0.9^6) / (1 - 0.9) for total revenue over 6 years for a product, starting with $75,000 in the first year and declining by 10% each subsequent year.

Problem 118

Interpret each parameter in the finite geometric series formula PV = (800/1.007) * (1 - (1/1.007)^24) / (1 - 1/1.007) for present value of a series of 24 monthly payments of $800, with a monthly interest rate of 0.7%, where payments are made at the end of each month.

Problem 119

Interpret each parameter in the finite geometric series formula Cumulative_Cases = 50 * (1 - 2.5^5) / (1 - 2.5) for cumulative number of cases of an infection over 5 periods, where 50 people are initially infected and each infected person infects 2.5 new people in the next period.

Problem 120

Interpret each parameter in the finite geometric series formula Sum_Values = 25000 * (1 - 0.85^4) / (1 - 0.85) for sum of the book values of equipment over 4 years, starting with an initial value of $25,000 and depreciating by 15% each year.

Open in simulator
sum declining values.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Use a finite geometric series to model repeated depreciation or discount for equipment worth 1000 loses 20% value each year for 5 years; total year-end values.

Problem 122

Use a finite geometric series to model repeated depreciation or discount for six subscription discounts start at 40 dollars and shrink by 25% each time.

Problem 123

Use a finite geometric series to model repeated depreciation or discount for salvage values 5000, 4000, 3200, 2560.

Problem 124

Use a finite geometric series to model repeated depreciation or discount for declining installment value V for n periods at retention r.

Problem 125

Use a finite geometric series to model repeated depreciation or discount for a car initially worth $20,000 depreciates by 15% annually for 4 years; total value over 4 years.

Problem 126

Use a finite geometric series to model repeated depreciation or discount for five consecutive discounts, starting at $100, each 10% less than the previous.

Problem 127

Use a finite geometric series to model repeated depreciation or discount for a machine valued at $50,000 loses 25% of its value each year for 3 years; sum of its value at the end of each year.

Problem 128

Use a finite geometric series to model repeated depreciation or discount for total value of an asset initially $A, decreasing by 5% each year for 10 years.

Open in simulator
Problem 129

Use a finite geometric series to model repeated depreciation or discount for a series of 7 price reductions, starting at $200, each reduction being 20% less than the previous.

Problem 130

Use a finite geometric series to model repeated depreciation or discount for salvage values of an item: $1200, $960, $768, $614.40, $491.52.

Problem 131

Use a finite geometric series to model repeated depreciation or discount for total accumulated discount for 'k' items, where the first item has a discount of 'D' and each subsequent item's discount is 'p' percent less than the previous.

Problem 132

Use a finite geometric series to model repeated depreciation or discount for a piece of art valued at $15,000 loses 8% of its value each year for 6 years; total value over these 6 years.

enter formula correctly and interpret output.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Evaluate the finite geometric series model 250[(1.006)^60-1]/0.006 with technology and interpret the result.

Problem 134

Evaluate the finite geometric series model 1000(1-0.97^36)/(1-0.97) with technology and interpret the result.

Problem 135

Evaluate the finite geometric series model 5000(1.004)^24-200[(1.004)^24-1]/0.004 with technology and interpret the result.

Problem 136

Evaluate the finite geometric series model 75(1.02^120-1)/0.02 with technology and interpret the result.

Problem 137

Evaluate the finite geometric series model 50[(1.001)^260-1]/0.001 with technology and interpret the result.

Problem 138

Evaluate the finite geometric series model 1500[1-(1.005)^-180]/0.005 with technology and interpret the result.

Open in simulator
Problem 139

Evaluate the finite geometric series model 10000(1.03^10-1)/(1.03-1) with technology and interpret the result.

Problem 140

Evaluate the finite geometric series model 10 + 16 * (1 - 0.8^7) / 0.2 with technology and interpret the result.

Problem 141

Evaluate the finite geometric series model 200000(1.0035)^120 - 1200[(1.0035)^120-1]/0.0035 with technology and interpret the result.

Problem 142

Evaluate the finite geometric series model 700[(1.0075)^60-1]/0.0075 with technology and interpret the result.

Problem 143

Evaluate the finite geometric series model 5000 + 200(1.05^5-1)/(1.05-1) with technology and interpret the result.

Problem 144

Evaluate the finite geometric series model 200 * (1 - 0.75^8) / (1 - 0.75) with technology and interpret the result.

handle constant series separately.
12 problems Warmup Practice Mixed Review Assessment
Problem 145

Determine whether the geometric-series formula applies when the common ratio is 1.

Problem 146

Determine whether the geometric-series formula applies when the common ratio is 1.00.

Problem 147

Determine whether the geometric-series formula applies when the common ratio is 0.

Problem 148

Determine whether the geometric-series formula applies when the common ratio is -1.

Problem 149

Determine whether the geometric-series formula applies when the common ratio is 2.

Problem 150

Determine whether the geometric-series formula applies when the common ratio is 0.5.

Problem 151

Determine whether the geometric-series formula applies when the common ratio is -2.

Problem 152

Determine whether the geometric-series formula applies when the common ratio is -0.5.

Problem 153

Determine whether the geometric-series formula applies when the common ratio is 1.0.

Problem 154

Determine whether the geometric-series formula applies when the common ratio is 10.

Problem 155

Determine whether the geometric-series formula applies when the common ratio is 1/3.

Open in simulator
Problem 156

Determine whether the geometric-series formula applies when the common ratio is -3/4.

compute and interpret total value/cost.
12 problems Warmup Practice Mixed Review Assessment
Problem 157

Compare two financing or savings scenarios: deposit 100 monthly for 12 months at factor 1.005 versus deposit 120 monthly for 10 months at factor 1.005.

Problem 158

Compare two financing or savings scenarios: loan 5000 at factor 1.01 with 200 payments for 24 months versus loan 5000 at factor 1.008 with 190 payments for 24 months.

Problem 159

Compare two financing or savings scenarios: save 50 weekly at factor 1.001 for 52 weeks versus save 200 monthly at comparable monthly factor for 12 months.

Problem 160

Compare two financing or savings scenarios: discount stream with ratio 0.9 versus discount stream with ratio 0.85.

Problem 161

Compare two financing or savings scenarios: invest 250 quarterly for 5 years at an annual rate of 4% versus invest 1000 annually for 5 years at an annual rate of 4%.

Problem 162

Compare two financing or savings scenarios: a 10,000 loan at 6% annual interest paid monthly over 3 years versus a 10,000 loan at 5.5% annual interest paid monthly over 3 years.

Problem 163

Compare two financing or savings scenarios: initial deposit of 5000 and 100 monthly for 20 years at 7% annual return versus initial deposit of 0 and 150 monthly for 20 years at 7% annual return.

Problem 164

Compare two financing or savings scenarios: a project generating 1000 annually for 5 years, discounted at 8% versus a project generating 1200 annually for 4 years, discounted at 8%.

Problem 165

Compare two financing or savings scenarios: deposit 500 semi-annually for 10 years at 3% annual interest compounded semi-annually versus deposit 250 quarterly for 10 years at 3% annual interest compounded quarterly.

Problem 166

Compare two financing or savings scenarios: a 200,000 mortgage at 4% interest over 30 years versus a 200,000 mortgage at 4.25% interest over 25 years.

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Problem 167

Compare two financing or savings scenarios: a single deposit of 20,000 earning 5% annually for 18 years versus monthly deposits of 100 earning 5% annually for 18 years.

Problem 168

Compare two financing or savings scenarios: lease equipment for 500 monthly over 3 years with an initial 1000 fee versus purchase equipment for 15,000 with a 3-year loan at 6% annual interest.

catch wrong ratio, term count, time indexing, and finance interpretation mistakes.
12 problems Warmup Practice Mixed Review Assessment
Problem 169

Correct the geometric-series modeling error in using 0.05 as the ratio for 5% growth.

Problem 170

Correct the geometric-series modeling error in counting 12 monthly deposits as exponents 1 through 12 when the newest deposit earns no interest.

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Problem 171

Correct the geometric-series modeling error in using arithmetic sum for values that lose the same percent each year.

Problem 172

Correct the geometric-series modeling error in using S=a(1-r^n)/(1-r) when r=1.

Problem 173

Correct the geometric-series modeling error in using an annual interest rate directly as the monthly growth ratio.

Problem 174

Correct the geometric-series modeling error in calculating the future value of an annuity due as an ordinary annuity.

Problem 175

Correct the geometric-series modeling error in using (1 + depreciation rate) as the common ratio for an asset losing value.

Problem 176

Correct the geometric-series modeling error in assuming the first term of a geometric series is 'a*r' instead of 'a' when 'n' is the number of terms.

Problem 177

Correct the geometric-series modeling error in summing up equal periodic deposits without accounting for compounding interest.

Problem 178

Correct the geometric-series modeling error in using 0.15 as the common ratio for a 15% reduction each period.

Problem 179

Correct the geometric-series modeling error in using the number of years as the exponent for a series compounded quarterly.

Problem 180

Correct the geometric-series modeling error in applying an arithmetic progression formula to model compound interest growth.