Math III · F-IF.4

Interpreting Key Features of Rational, Square-Root, Cube-Root, and Other Function Models

Advanced function graphs show starts, restrictions, asymptotes, turning behavior, and long-term patterns that describe real situations.

Concept Functions
Domain Interpreting Functions
Read time 6 minutes

What this learning objective is really asking you to learn

This objective asks students to interpret key features of advanced function models, especially rational, square-root, cube-root, and other Math III function types. Students already learned to interpret intercepts, intervals, maximums, minimums, end behavior, and other graph features for simpler functions. Now the graph vocabulary expands.

A square-root function often has an endpoint and a restricted domain. For example, \(f(x)=\sqrt{x-2}+5\) begins at \((2,5)\) and has domain \(x \ge 2\). That endpoint may represent a minimum input value in context.

A cube-root function has a different shape. \(f(x)=\sqrt[3]{x}\) extends in both directions and has an inflection-like flattening behavior around the origin. It does not have the same domain restriction as a square-root function because cube roots of negative numbers are real.

A rational function may have vertical asymptotes, horizontal asymptotes, slant asymptotes, holes, and domain restrictions. For example, \(f(x)=1/(x-3)+2\) has vertical asymptote \(x=3\) and horizontal asymptote \(y=2\). These features are not decoration. They describe values the function cannot take or values it approaches.

The objective asks students to connect graph features to context. If a rational function models average cost, a horizontal asymptote may represent a long-run cost per unit. If a square-root function models distance from energy, the endpoint may represent the smallest physically meaningful input. If a cube-root model represents reversing a volume relationship, negative inputs may or may not make sense depending on the context.

Students should be able to read graphs, tables, and formulas and say what the features mean: intercepts, endpoints, asymptotes, domain restrictions, range, increasing/decreasing intervals, and long-term behavior.

Why students should learn this math

Students should learn this because advanced function types model behaviors that lines and parabolas cannot. Rational functions describe ratios, averages, rates, inverse variation, and asymptotic behavior. Square-root functions describe inverse square relationships, lengths from areas, physical constraints, and slowing growth. Cube-root functions describe inverse cubic relationships and quantities that can extend through negative values. Exponential and logarithmic functions describe growth, decay, and inverse growth questions.

Each function family has distinctive features. A rational function can blow up near a forbidden input. A square-root function may begin at an endpoint. A logarithmic function has a vertical asymptote and grows slowly. An exponential function may approach a horizontal asymptote. These features often carry real meaning.

For example, average cost \(A(x)=500/x+12\) has a horizontal asymptote at \(y=12\). That means average cost approaches $12 per unit as production grows, but the fixed cost share never becomes exactly zero for finite \(x\). A rational function can therefore describe “approaches but does not reach” behavior.

A square-root function such as \(d=\sqrt{h^2 + 100}\) might describe a distance relationship. Its domain and minimum value are determined by geometry. A cube-root function might undo a volume relationship, such as finding a cube's edge length from volume.

Graph features help students interpret models rather than just compute values. In real contexts, key features answer questions: Where does the model start? What inputs are impossible? What value is approached? When does the output hit zero? Is the output increasing quickly or slowly? Is there a boundary the system cannot cross?

The “why” is that advanced functions are behavior models. Their graph features are the landmarks that make those behaviors understandable.

The historical machinery: function families and graph behavior

As mathematicians studied more relationships, they developed families of functions beyond lines and quadratics. Rational functions emerged naturally from ratios of polynomials. Radical functions emerged from inverse power relationships. Logarithmic functions emerged as inverses of exponentials. Each family brought new graph features.

Coordinate geometry and later calculus made graph behavior central. Asymptotes, endpoints, and long-term behavior became ways to understand functions qualitatively. A rational function's asymptote, for example, describes a limiting behavior. A radical function's endpoint describes a domain boundary.

In modern mathematics and science, function-family behavior is essential. Engineers read asymptotes in system response. Economists interpret long-run limits. Scientists interpret thresholds and domains. Data analysts choose models based on shape. Students are learning the early graph language needed for all of that.

Where this fits in the big map of mathematics

This objective extends graph interpretation from earlier courses. Objective 022 introduced key graph features in Math I. Objective 153 applies that skill to Math III function families.

It connects to transformations. Many key features move predictably under shifts and stretches.

It connects to domain. Advanced functions often have natural restrictions from denominators, radicals, or logarithms.

It connects to rational-expression rewriting. Holes and asymptotes can be identified from factored or divided forms.

It connects to inverse functions. Square-root and logarithmic functions often arise as inverses of power or exponential functions.

It connects to modeling. Key graph features become real-world statements.

The big-map role is advanced graph literacy. Students learn to read more than lines and parabolas.

How to execute the skill technically

For a square-root function:

  • Identify the radicand.
  • Find where the radicand is nonnegative.
  • Locate the endpoint.
  • Determine whether the graph increases or decreases.
  • Interpret domain and endpoint in context.

Example:

\[f(x)=\sqrt{x+4}-1\].

Domain: \(x+4 \ge 0\), so \(x \ge -4\). Endpoint: \((-4,-1)\). The graph increases to the right.

For a cube-root function:

  • Domain is often all real numbers unless context restricts it.
  • Identify shifts and stretches.
  • Look for the central point where the inside expression is zero.

Example:

\[g(x)=\sqrt[3]{x-2}+5\].

Central point: \((2,5)\). Domain: all real numbers algebraically.

For a rational function:

  • Identify denominator zeros.
  • Factor to check for holes.
  • Identify vertical asymptotes from non-canceled denominator zeros.
  • Use degree or division to identify horizontal or slant asymptotes.
  • Interpret restrictions and long-term behavior.

Example:

\[h(x)=(x+1)/(x-3)+2\].

Vertical asymptote: \(x=3\). As \(x\) grows large, \((x+1)/(x-3)\) approaches 1, so \(h(x)\) approaches 3. Horizontal asymptote: \(y=3\).

Students should tie each feature to context. If \(x\) is production units, a vertical asymptote at a negative value may be outside the meaningful domain. If \(x=0\) is forbidden, that may represent division by zero in a rate or average.

Worked example: average cost

A company's average cost is

\[A(x)=1000/x+25\]

where \(x\) is units produced.

Domain: \(x > 0\), because production must be positive.

Vertical asymptote: \(x=0\), from the formula. In context, average cost is not defined for zero units because total cost per item cannot be computed when no items are produced.

Horizontal asymptote: \(y=25\). As production increases, average cost approaches $25 per unit. This is the variable cost per unit.

Y-intercept: none in the contextual domain, because \(x=0\) is not allowed.

The graph decreases for positive \(x\) because fixed cost is spread over more units.

This model has a strong business interpretation. The asymptote is not just a graph feature; it is the long-run cost floor.

Worked example: square-root context

Suppose the time \(t\) in seconds for an object to fall distance \(d\) feet under a simplified model is

\[t = \sqrt{d/16}\].

Domain: \(d \ge 0\), because distance fallen cannot be negative.

Endpoint: \((0,0)\), meaning zero falling distance takes zero time.

The graph increases, but not linearly. Larger distances require more time, but distance grows with the square of time, so time grows with the square root of distance.

This feature interpretation helps students avoid thinking every increasing graph represents constant rate.

Rational-function feature checklist

For rational functions, students need a specific checklist:

  1. Factor numerator and denominator.
  2. Identify denominator zeros.
  3. Cancel common factors only if valid, and mark holes.
  4. Non-canceled denominator zeros are vertical asymptotes.
  5. Compare degrees or divide to find horizontal/slant behavior.
  6. Find intercepts if useful.
  7. Interpret all features in context.

Consider

\[f(x)=((x-2)(x+3))/((x-2)(x-5))\].

The factor \(x-2\) cancels, so there is a hole at \(x=2\), not a vertical asymptote there. The remaining denominator \(x-5\) creates a vertical asymptote at \(x=5\). This distinction matters because the graph behaves very differently at holes and asymptotes.

Radical-function feature checklist

For square-root functions, the radicand controls the domain. For

\[f(x)= -2\sqrt{x-4}+7\],

the domain is \(x \ge 4\). The endpoint is \((4,7)\). The negative coefficient makes the graph go downward from the endpoint. The range is \(y \le 7\).

For cube-root functions, the domain is usually all real numbers, but transformations still matter. For

\[g(x)=3\sqrt[3]{x+1}-2\],

the central point is \((-1,-2)\). The graph is stretched vertically by 3 and shifted left 1, down 2.

Context can override algebraic domain

A formula may allow more inputs than the context does. The cube-root function has all real numbers as an algebraic domain, but if \(x\) represents volume, negative values may not make sense. The rational expression \(500/x + 10\) allows negative x-values algebraically except zero, but if \(x\) is number of items, only positive values make sense.

A central idea is that formula domain and contextual domain must both be considered.

Problem Library

Problems in the App From This Objective

195 problems across 15 archetypes in the app.

connect x/y-intercepts to context.
15 problems Warmup Practice Mixed Review Assessment
Problem 1

Interpret the intercepts of rational model P(x)=(x-5)/(x+2) for profit ratio.

Problem 2

Interpret the intercepts of rational model A(x)=8+500/x.

Problem 3

Interpret the intercepts of rational model C(t)=t/(t+4).

Problem 4

Interpret the intercepts of rational model R(x)=(x-3)(x+1)/(x-1).

Problem 5

Interpret the intercepts of rational model f(x) = (x-2)/(x+3).

Problem 6

Interpret the intercepts of rational model g(x) = (x^2 - 4)/(x-2).

Problem 7

Interpret the intercepts of rational model h(x) = 1/(x-5).

Problem 8

Interpret the intercepts of rational model V(t) = 10 + 20/(t+1) for t >= 0.

Problem 9

Interpret the intercepts of rational model f(x) = (x^2 - 9) / (x+1).

Problem 10

Interpret the intercepts of rational model C(r) = (r+5)/r for r > 0.

Problem 11

Interpret the intercepts of rational model M(t) = (t^2 - t) / (t+5).

Problem 12

Interpret the intercepts of rational model f(x) = (x^2 - 1) / (x-1).

Problem 13

Interpret the intercepts of rational model P(s) = (s-10) / (s+1) for s >= 0.

Problem 14

Interpret the intercepts of rational model f(x) = (x^2 + 1) / (x-2).

Open in simulator
Problem 15

Interpret the intercepts of rational model G(x) = (x-1)(x+2)(x-3) / (x+4).

connect denominator restriction to limiting behavior.
15 problems Warmup Practice Mixed Review Assessment
Problem 16

Interpret the vertical asymptote of rational model A(x)=8+500/x for average cost.

Problem 17

Interpret the vertical asymptote of rational model C(x)=20/(x-4)+5.

Problem 18

Interpret the vertical asymptote of rational model D(t)=t/(t-10).

Problem 19

Interpret the vertical asymptote of rational model (x-2)/(x-2)(x+1).

Problem 20

Interpret the vertical asymptote of rational model f(t) = 1/(t+3).

Problem 21

Interpret the vertical asymptote of rational model g(x) = 5/(2x-6).

Problem 22

Interpret the vertical asymptote of rational model h(x) = (x+1)/((x-5)(x+2)).

Open in simulator
Problem 23

Interpret the vertical asymptote of rational model k(x) = 1/(x-1)^2.

Problem 24

Interpret the vertical asymptote of rational model Concentration(t) = 10t / (t-5).

Problem 25

Interpret the vertical asymptote of rational model P(t) = 1000 / (20-t).

Problem 26

Interpret the vertical asymptote of rational model y = (x^2 - 4) / (x^2 - 5x + 6).

Problem 27

Interpret the vertical asymptote of rational model f(x) = (x^2 - 9) / (x^2 - 4x + 3).

Problem 28

Interpret the vertical asymptote of rational model R(x) = (x+1) / (x^2 - 9).

Problem 29

Interpret the vertical asymptote of rational model f(x) = (x+2) / (x^2 + x - 6).

Problem 30

Interpret the vertical asymptote of rational model G(x) = (x^2 - 1) / (x^3 - x^2 - x + 1).

connect long-term behavior to context.
15 problems Warmup Practice Mixed Review Assessment
Problem 31

Interpret the horizontal or slant asymptote of rational model A(x)=8+500/x.

Problem 32

Interpret the horizontal or slant asymptote of rational model R(x)=(2x^2+3)/(x+1).

Problem 33

Interpret the horizontal or slant asymptote of rational model S(x)=100x/(x+20).

Problem 34

Interpret the horizontal or slant asymptote of rational model E(t)=5+2/(t-1).

Problem 35

Interpret the horizontal or slant asymptote of rational model f(x)=1/x.

Problem 36

Interpret the horizontal or slant asymptote of rational model C(t)=5t/(t^2+1).

Problem 37

Interpret the horizontal or slant asymptote of rational model P(n)=(n-1)/(n^2+n+1).

Problem 38

Interpret the horizontal or slant asymptote of rational model G(x)=(3x+2)/(x-4).

Problem 39

Interpret the horizontal or slant asymptote of rational model N(t)=(1000t+500)/(2t+10).

Problem 40

Interpret the horizontal or slant asymptote of rational model L(x)=(x^2-3x+1)/(2x^2+5).

Problem 41

Interpret the horizontal or slant asymptote of rational model V(r)=(2r^2+7)/(r^2+1).

Open in simulator
Problem 42

Interpret the horizontal or slant asymptote of rational model Q(x)=(x^2+1)/x.

Problem 43

Interpret the horizontal or slant asymptote of rational model M(x)=(x^2-4x+3)/(x-2).

Problem 44

Interpret the horizontal or slant asymptote of rational model D(t)=(3t^2+2t+1)/(t+1).

Problem 45

Interpret the horizontal or slant asymptote of rational model F(x)=(4x^2-x+5)/(2x-1).

explain excluded input and simplified behavior.
15 problems Warmup Practice Mixed Review Assessment
Problem 46

Interpret the hole or removable discontinuity in rational model R(x)=(x-3)(x+2)/(x-3).

Problem 47

Interpret the hole or removable discontinuity in rational model A(x)=(x^2-4)/(x-2).

Problem 48

Interpret the hole or removable discontinuity in rational model C(t)=t(t-5)/(t-5)(t+1).

Problem 49

Interpret the hole or removable discontinuity in rational model context excludes zero quantity after simplification.

Problem 50

Interpret the hole or removable discontinuity in rational model f(x)=(x^2-9)/(x-3).

Problem 51

Interpret the hole or removable discontinuity in rational model g(x)=(x+1)(x-2)/(x-2).

Problem 52

Interpret the hole or removable discontinuity in rational model h(x)=(x^2-1)/(x+1).

Open in simulator
Problem 53

Interpret the hole or removable discontinuity in rational model k(x)=(x^2-5x+6)/(x-3).

Problem 54

Interpret the hole or removable discontinuity in rational model m(x)=(x^2+x-2)/(x-1).

Problem 55

Interpret the hole or removable discontinuity in rational model p(x)=(x^3-x)/(x^2-x).

Problem 56

Interpret the hole or removable discontinuity in rational model q(x)=(x^2-16)/(x+4).

Problem 57

Interpret the hole or removable discontinuity in rational model s(x)=(2x-6)/(x-3).

Problem 58

Interpret the hole or removable discontinuity in rational model t(x)=(x^2-2x)/x.

Problem 59

Interpret the hole or removable discontinuity in rational model u(x)=(3x^2+6x)/(x+2).

Problem 60

Interpret the hole or removable discontinuity in rational model v(x)=(x^2-7x+10)/(x-5).

connect starting input/output to context.
12 problems Warmup Practice Mixed Review Assessment
Problem 61

Interpret the endpoint of square-root model d(t)=sqrt(t-3).

Problem 62

Interpret the endpoint of square-root model h(x)=2sqrt(x+4)+1.

Problem 63

Interpret the endpoint of square-root model v(h)=sqrt(2gh).

Problem 64

Interpret the endpoint of square-root model C(x)=50+10sqrt(x).

Problem 65

Interpret the endpoint of square-root model y=sqrt(x-5).

Problem 66

Interpret the endpoint of square-root model P(t)=100+5sqrt(t-10).

Problem 67

Interpret the endpoint of square-root model T(d)=20-sqrt(d+2).

Problem 68

Interpret the endpoint of square-root model A(r)=sqrt(r-1)/2.

Problem 69

Interpret the endpoint of square-root model W(s)=30+sqrt(s).

Open in simulator
Problem 70

Interpret the endpoint of square-root model L(t)=sqrt(t+7)-1.

Problem 71

Interpret the endpoint of square-root model D(p)=15-3sqrt(p-4).

Problem 72

Interpret the endpoint of square-root model R(x)=2sqrt(x+0.5).

identify valid inputs/outputs from graph/context.
12 problems Warmup Practice Mixed Review Assessment
Problem 73

Interpret the domain and range of root model y=sqrt(x-2)+5.

Problem 74

Interpret the domain and range of root model y=-sqrt(x+1)+3.

Problem 75

Interpret the domain and range of root model y=cuberoot(x-4)-2.

Problem 76

Interpret the domain and range of root model v(h)=sqrt(64h).

Problem 77

Interpret the domain and range of root model y=sqrt(-x+3)+1.

Problem 78

Interpret the domain and range of root model y=-sqrt(-x-2)-4.

Problem 79

Interpret the domain and range of root model y=sqrt(x).

Open in simulator
Problem 80

Interpret the domain and range of root model y=sqrt(2x-6).

Problem 81

Interpret the domain and range of root model y=cuberoot(x).

Problem 82

Interpret the domain and range of root model y=cuberoot(-x+5)+1.

Problem 83

Interpret the domain and range of root model t(d)=sqrt(d/4.9).

Problem 84

Interpret the domain and range of root model r(A)=sqrt(A/pi).

read graph behavior over intervals.
12 problems Warmup Practice Mixed Review Assessment
Problem 85

Interpret increasing and decreasing intervals for advanced function y=sqrt(x-2).

Problem 86

Interpret increasing and decreasing intervals for advanced function y=-sqrt(x)+4.

Open in simulator
Problem 87

Interpret increasing and decreasing intervals for advanced function rational graph with branches increasing on (-infinity,1) and (1,infinity).

Problem 88

Interpret increasing and decreasing intervals for advanced function polynomial with local maximum at x=-1 and local minimum at x=3.

Problem 89

Interpret increasing and decreasing intervals for advanced function y = x^2 - 4x + 3.

Problem 90

Interpret increasing and decreasing intervals for advanced function y = -x^2 + 6x - 5.

Problem 91

Interpret increasing and decreasing intervals for advanced function y = x^3.

Problem 92

Interpret increasing and decreasing intervals for advanced function y = 1/x.

Problem 93

Interpret increasing and decreasing intervals for advanced function y = |x-3|.

Problem 94

Interpret increasing and decreasing intervals for advanced function y = ln(x).

Problem 95

Interpret increasing and decreasing intervals for advanced function y = e^x.

Problem 96

Interpret increasing and decreasing intervals for advanced function y = (x^2 - 4)/(x-2).

identify maximum/minimum where relevant.
12 problems Warmup Practice Mixed Review Assessment
Problem 97

Interpret the extremum of advanced model profit graph with maximum at (20,1500).

Problem 98

Interpret the extremum of advanced model cost model with minimum at (8,120).

Problem 99

Interpret the extremum of advanced model transformed radical y=-sqrt(x-3)+10.

Problem 100

Interpret the extremum of advanced model rational model with no attained maximum.

Problem 101

Interpret the extremum of advanced model quadratic function f(x) = 3x^2 - 12x + 15.

Problem 102

Interpret the extremum of advanced model parabolic trajectory model h(t) = -5t^2 + 20t + 10.

Problem 103

Interpret the extremum of advanced model absolute value function g(x) = |x - 7| + 5.

Problem 104

Interpret the extremum of advanced model cubic function y = x^3 - 6x^2 + 9x + 1.

Problem 105

Interpret the extremum of advanced model quartic function f(x) = x^4 - 8x^2 + 16.

Problem 106

Interpret the extremum of advanced model transformed radical y = sqrt(x+2) - 4.

Problem 107

Interpret the extremum of advanced model rational function f(x) = (x^2 + 1) / x.

Open in simulator
Problem 108

Interpret the extremum of advanced model trigonometric function y = 3cos(x) + 5 on the interval [0, 2pi].

describe long-term output behavior.
12 problems Warmup Practice Mixed Review Assessment
Problem 109

Interpret the end behavior of advanced model p(x)=2x^3-x.

Problem 110

Interpret the end behavior of advanced model A(x)=8+500/x.

Problem 111

Interpret the end behavior of advanced model y=sqrt(x)+10.

Problem 112

Interpret the end behavior of advanced model R(x)=(3x^2+1)/(x^2+5).

Problem 113

Interpret the end behavior of advanced model f(x)=x^4-2x^2+1.

Problem 114

Interpret the end behavior of advanced model g(x)=-x^2+3x-5.

Problem 115

Interpret the end behavior of advanced model h(x)=(x+1)/(x^2+4).

Problem 116

Interpret the end behavior of advanced model k(x)=(x^2+x+1)/(x+2).

Problem 117

Interpret the end behavior of advanced model m(x)=2^x.

Open in simulator
Problem 118

Interpret the end behavior of advanced model n(x)=e^(-x).

Problem 119

Interpret the end behavior of advanced model L(x)=ln(x).

Problem 120

Interpret the end behavior of advanced model C(x)=x^(1/3)-5.

align asymptotes, endpoints, intercepts, and trends.
12 problems Warmup Practice Mixed Review Assessment
Problem 121

Match graph features to the context story average cost falls toward a per-item material cost as production grows.

Problem 122

Match graph features to the context story object starts moving after a delay and distance follows a square-root pattern.

Problem 123

Match graph features to the context story saturation model approaches a maximum capacity.

Problem 124

Match graph features to the context story restricted input is impossible but nearby trend is smooth.

Problem 125

Match graph features to the context story radioactive decay of a substance over time.

Problem 126

Match graph features to the context story population growth in an environment with limited resources.

Problem 127

Match graph features to the context story height of a ball thrown upwards from the ground.

Problem 128

Match graph features to the context story time taken to travel a fixed distance decreases as speed increases.

Problem 129

Match graph features to the context story total cost of a taxi ride includes a base fare and a per-mile charge.

Problem 130

Match graph features to the context story growth of a plant's height slows down over time after an initial rapid phase.

Open in simulator
Problem 131

Match graph features to the context story shipping cost changes based on weight categories.

Problem 132

Match graph features to the context story depth of water at a harbor entrance over a 24-hour tidal cycle.

select intercept/asymptote/endpoint/extreme/domain.
12 problems Warmup Practice Mixed Review Assessment
Problem 133

Determine which graph feature answers the context question What production level breaks even?.

Problem 134

Determine which graph feature answers the context question What value does average cost approach long-term?.

Problem 135

Determine which graph feature answers the context question When does the process start?.

Problem 136

Determine which graph feature answers the context question What input is impossible because the denominator is zero?.

Problem 137

Determine which graph feature answers the context question What is the maximum height reached by the projectile?.

Problem 138

Determine which graph feature answers the context question What is the minimum cost of production?.

Problem 139

Determine which graph feature answers the context question What is the initial investment amount?.

Problem 140

Determine which graph feature answers the context question When does the observed phenomenon end?.

Open in simulator
Problem 141

Determine which graph feature answers the context question What value does the drug concentration approach after a very long time?.

Problem 142

Determine which graph feature answers the context question At what specific input value does the function become undefined due to division by zero?.

Problem 143

Determine which graph feature answers the context question What are all the possible time values for which the model is valid?.

Problem 144

Determine which graph feature answers the context question At what point does the population reach zero?.

compare graph feature to domain and units.
12 problems Warmup Practice Mixed Review Assessment
Problem 145

Explain whether graph feature x-intercept at x=-4 is meaningful in context number of items produced.

Problem 146

Explain whether graph feature vertical asymptote at x=0 is meaningful in context average cost per item.

Problem 147

Explain whether graph feature endpoint at t=3 is meaningful in context process begins after 3 seconds.

Problem 148

Explain whether graph feature horizontal asymptote y=8 is meaningful in context long-term average cost.

Problem 149

Explain whether graph feature y-intercept at y=100 is meaningful in context initial population of bacteria.

Open in simulator
Problem 150

Explain whether graph feature x-intercept at x=5 is meaningful in context time when a projectile hits the ground, where x is time in seconds and y is height in meters.

Problem 151

Explain whether graph feature local maximum at (10, 500) is meaningful in context peak profit of a company, where x is units sold and y is profit in dollars.

Problem 152

Explain whether graph feature local minimum at (2, 10) is meaningful in context lowest temperature reached during an experiment, where x is time in hours and y is temperature in degrees Celsius.

Problem 153

Explain whether graph feature vertical asymptote at x=5 is meaningful in context cost of producing items, where x is the number of items and y is cost.

Problem 154

Explain whether graph feature horizontal asymptote at y=0 is meaningful in context concentration of a drug in the bloodstream over time.

Problem 155

Explain whether graph feature point of inflection at x=7 is meaningful in context rate of spread of a disease, where x is days and y is the number of new cases per day.

Problem 156

Explain whether graph feature point (-2, 15) is meaningful in context temperature in degrees Celsius over time in hours.

identify similarities and differences in behavior.
15 problems Warmup Practice Mixed Review Assessment
Problem 157

Compare key features across advanced models A(x)=8+500/x and B(x)=10+300/x.

Problem 158

Compare key features across advanced models sqrt(x-2) and sqrt(x+5).

Problem 159

Compare key features across advanced models x^2 and 1/x.

Problem 160

Compare key features across advanced models 100x/(x+5) and 80x/(x+2).

Open in simulator
Problem 161

Compare key features across advanced models y = x^3 and y = x^2 + 5.

Problem 162

Compare key features across advanced models f(x) = (x+1)/(x-2) and g(x) = (x-3)/(x+4).

Problem 163

Compare key features across advanced models y = sqrt(x) and y = 2*sqrt(x-1).

Problem 164

Compare key features across advanced models y = x^2 - 4 and y = 1/(x-1).

Problem 165

Compare key features across advanced models y = x and y = sqrt(x).

Problem 166

Compare key features across advanced models f(x) = 1/(x^2+1) and g(x) = sqrt(x+3).

Problem 167

Compare key features across advanced models y = (x-1)(x+2) and y = (x+1)(x-2).

Problem 168

Compare key features across advanced models h(x) = (x^2-4)/(x-2) and k(x) = (x^2-9)/(x+3).

Problem 169

Compare key features across advanced models y = cbrt(x) and y = sqrt(x).

Problem 170

Compare key features across advanced models y = x^3 - x and y = 1/(x^2).

Problem 171

Compare key features across advanced models y = 2x + 3 and y = (2x^2+3x)/x.

synthesize domain, intercepts, asymptotes/end behavior, and intervals.
12 problems Warmup Practice Mixed Review Assessment
Problem 172

Write a contextual summary of the advanced graph with features domain x>0, y-intercept none, horizontal asymptote y=8, decreasing on x>0.

Problem 173

Write a contextual summary of the advanced graph with features endpoint (3,2), increasing for x>=3, range y>=2.

Open in simulator
Problem 174

Write a contextual summary of the advanced graph with features x-intercepts at 2 and 5, maximum at (3,10), context domain 0<=x<=6.

Problem 175

Write a contextual summary of the advanced graph with features domain x!=1, vertical asymptote x=1, increasing on (-inf, 1) and (1, inf).

Problem 176

Write a contextual summary of the advanced graph with features domain x<5, horizontal asymptote y=0, decreasing on x<5.

Problem 177

Write a contextual summary of the advanced graph with features minimum at (-2, -5), range y>=-5.

Problem 178

Write a contextual summary of the advanced graph with features x-intercept at -3, as x->inf, y->inf, as x->-inf, y->-inf.

Problem 179

Write a contextual summary of the advanced graph with features domain [0, 10], maximum at (2, 15), minimum at (8, 1).

Problem 180

Write a contextual summary of the advanced graph with features y-intercept at (0,4), x-intercepts at -2 and 2, symmetric about the y-axis.

Problem 181

Write a contextual summary of the advanced graph with features domain all real numbers, increasing on (-inf, 0), constant on [0, 5], decreasing on (5, inf).

Problem 182

Write a contextual summary of the advanced graph with features hole at (2, 5), domain x!=2.

Problem 183

Write a contextual summary of the advanced graph with features range y<10, horizontal asymptote y=10, increasing on all real numbers.

catch domain, asymptote, endpoint, intercept, and context mistakes.
12 problems Warmup Practice Mixed Review Assessment
Problem 184

Correct the advanced feature interpretation error in The average-cost model A(x)=8+500/x has y-intercept 500.

Problem 185

Correct the advanced feature interpretation error in A hole at x=4 means the graph has a vertical asymptote there.

Problem 186

Correct the advanced feature interpretation error in The endpoint of sqrt(x-3)+2 is (0,2).

Problem 187

Correct the advanced feature interpretation error in A horizontal asymptote is always a maximum value.

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Problem 188

Correct the advanced feature interpretation error in The function f(x) = 1/(x-2) has an x-intercept at x=2.

Problem 189

Correct the advanced feature interpretation error in The function y = (x^2 - 4) / (x - 2) has a vertical asymptote at x=2.

Problem 190

Correct the advanced feature interpretation error in The function f(x) = log(x) has a y-intercept at (0,0).

Problem 191

Correct the advanced feature interpretation error in A horizontal asymptote y=L means the graph never crosses the line y=L.

Problem 192

Correct the advanced feature interpretation error in The graph of f(x) = sqrt(9-x^2) has endpoints at x=3 and x=-3, but not including them.

Problem 193

Correct the advanced feature interpretation error in The rational function f(x) = (x^2+1)/x has a horizontal asymptote at y=0.

Problem 194

Correct the advanced feature interpretation error in The function f(x) = 1/x has an x-intercept at x=0.

Problem 195

Correct the advanced feature interpretation error in For a population model P(t) = 100 * (1.05)^t, the y-intercept of 100 means the population will eventually reach 100.