Problem 116 of 7
Use a perpendicular from the center to chord KL with radius 26 and center-to-chord distance 10.
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bisect chord and arc; form right triangles.
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Perpendicular from center to chord must bisect the chord and form a right triangle.
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Walkthrough
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1. Use the perpendicular to split the chord into equal halves.
2. Form a right triangle with radius as hypotenuse and center distance as one leg.
3. Find the half-chord and double it.
Use the worked steps, then substitute the final answer back into the original relationship to confirm it satisfies the prompt.
Using the center distance as the full chord length.